Metamath Proof Explorer


Theorem tz7.48lem

Description: A way of showing an ordinal function is one-to-one. (Contributed by NM, 9-Feb-1997) Extract onelfvnef1 . (Proof shortened by Matthew House, 6-Sep-2026)

Ref Expression
Hypothesis tz7.48.1 ⊢ F Fn On
Assertion tz7.48lem ⊢ A ⊆ On ∧ ∀ x ∈ A ∀ y ∈ x ¬ F ⁡ x = F ⁡ y → Fun ⁡ F ↾ A -1

Proof

Step Hyp Ref Expression
1 tz7.48.1 ⊢ F Fn On
2 dffn2 ⊢ F Fn On ↔ F : On ⟶ V
3 1 2 mpbi ⊢ F : On ⟶ V
4 fssres ⊢ F : On ⟶ V ∧ A ⊆ On → F ↾ A : A ⟶ V
5 3 4 mpan ⊢ A ⊆ On → F ↾ A : A ⟶ V
6 fvres ⊢ x ∈ A → F ↾ A ⁡ x = F ⁡ x
7 fvres ⊢ y ∈ A → F ↾ A ⁡ y = F ⁡ y
8 6 7 eqeqan12d ⊢ x ∈ A ∧ y ∈ A → F ↾ A ⁡ x = F ↾ A ⁡ y ↔ F ⁡ x = F ⁡ y
9 8 necon3abid ⊢ x ∈ A ∧ y ∈ A → F ↾ A ⁡ x ≠ F ↾ A ⁡ y ↔ ¬ F ⁡ x = F ⁡ y
10 9 imbi2d ⊢ x ∈ A ∧ y ∈ A → y ∈ x → F ↾ A ⁡ x ≠ F ↾ A ⁡ y ↔ y ∈ x → ¬ F ⁡ x = F ⁡ y
11 10 exbiri ⊢ x ∈ A → y ∈ A → y ∈ x → ¬ F ⁡ x = F ⁡ y → y ∈ x → F ↾ A ⁡ x ≠ F ↾ A ⁡ y
12 11 com23 ⊢ x ∈ A → y ∈ x → ¬ F ⁡ x = F ⁡ y → y ∈ A → y ∈ x → F ↾ A ⁡ x ≠ F ↾ A ⁡ y
13 12 ralimdv2 ⊢ x ∈ A → ∀ y ∈ x ¬ F ⁡ x = F ⁡ y → ∀ y ∈ A y ∈ x → F ↾ A ⁡ x ≠ F ↾ A ⁡ y
14 13 ralimia ⊢ ∀ x ∈ A ∀ y ∈ x ¬ F ⁡ x = F ⁡ y → ∀ x ∈ A ∀ y ∈ A y ∈ x → F ↾ A ⁡ x ≠ F ↾ A ⁡ y
15 onelfvnef1 ⊢ F ↾ A : A ⟶ V ∧ A ⊆ On ∧ ∀ x ∈ A ∀ y ∈ A y ∈ x → F ↾ A ⁡ x ≠ F ↾ A ⁡ y → F ↾ A : A ⟶ 1-1 V
16 14 15 syl3an3 ⊢ F ↾ A : A ⟶ V ∧ A ⊆ On ∧ ∀ x ∈ A ∀ y ∈ x ¬ F ⁡ x = F ⁡ y → F ↾ A : A ⟶ 1-1 V
17 5 16 syl3an1 ⊢ A ⊆ On ∧ A ⊆ On ∧ ∀ x ∈ A ∀ y ∈ x ¬ F ⁡ x = F ⁡ y → F ↾ A : A ⟶ 1-1 V
18 17 3anidm12 ⊢ A ⊆ On ∧ ∀ x ∈ A ∀ y ∈ x ¬ F ⁡ x = F ⁡ y → F ↾ A : A ⟶ 1-1 V
19 df-f1 ⊢ F ↾ A : A ⟶ 1-1 V ↔ F ↾ A : A ⟶ V ∧ Fun ⁡ F ↾ A -1
20 19 simprbi ⊢ F ↾ A : A ⟶ 1-1 V → Fun ⁡ F ↾ A -1
21 18 20 syl ⊢ A ⊆ On ∧ ∀ x ∈ A ∀ y ∈ x ¬ F ⁡ x = F ⁡ y → Fun ⁡ F ↾ A -1