Metamath Proof Explorer


Theorem caublcls

Description: The convergent point of a sequence of nested balls is in the closures of any of the balls (i.e. it is in the intersection of the closures). Indeed, it is the only point in the intersection because a metric space is Hausdorff, but we don't prove this here. (Contributed by Mario Carneiro, 21-Jan-2014) (Revised by Mario Carneiro, 1-May-2014)

Ref Expression
Hypotheses caubl.2 ⊢ φ → D ∈ ∞Met ⁡ X
caubl.3 ⊢ φ → F : ℕ ⟶ X × ℝ +
caubl.4 ⊢ φ → ∀ n ∈ ℕ ball ⁡ D ⁡ F ⁡ n + 1 ⊆ ball ⁡ D ⁡ F ⁡ n
caublcls.6 ⊢ J = MetOpen ⁡ D
Assertion caublcls ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → P ∈ cls ⁡ J ⁡ ball ⁡ D ⁡ F ⁡ A

Proof

Step Hyp Ref Expression
1 caubl.2 ⊢ φ → D ∈ ∞Met ⁡ X
2 caubl.3 ⊢ φ → F : ℕ ⟶ X × ℝ +
3 caubl.4 ⊢ φ → ∀ n ∈ ℕ ball ⁡ D ⁡ F ⁡ n + 1 ⊆ ball ⁡ D ⁡ F ⁡ n
4 caublcls.6 ⊢ J = MetOpen ⁡ D
5 eqid ⊢ ℤ ≥ A = ℤ ≥ A
6 1 3ad2ant1 ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → D ∈ ∞Met ⁡ X
7 4 mopntopon ⊢ D ∈ ∞Met ⁡ X → J ∈ TopOn ⁡ X
8 6 7 syl ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → J ∈ TopOn ⁡ X
9 simp3 ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → A ∈ ℕ
10 9 nnzd ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → A ∈ ℤ
11 simp2 ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → 1 st ∘ F ⇝t ⁡ J P
12 2fveq3 ⊢ r = A → ball ⁡ D ⁡ F ⁡ r = ball ⁡ D ⁡ F ⁡ A
13 12 sseq1d ⊢ r = A → ball ⁡ D ⁡ F ⁡ r ⊆ ball ⁡ D ⁡ F ⁡ A ↔ ball ⁡ D ⁡ F ⁡ A ⊆ ball ⁡ D ⁡ F ⁡ A
14 13 imbi2d ⊢ r = A → φ ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ r ⊆ ball ⁡ D ⁡ F ⁡ A ↔ φ ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ A ⊆ ball ⁡ D ⁡ F ⁡ A
15 2fveq3 ⊢ r = k → ball ⁡ D ⁡ F ⁡ r = ball ⁡ D ⁡ F ⁡ k
16 15 sseq1d ⊢ r = k → ball ⁡ D ⁡ F ⁡ r ⊆ ball ⁡ D ⁡ F ⁡ A ↔ ball ⁡ D ⁡ F ⁡ k ⊆ ball ⁡ D ⁡ F ⁡ A
17 16 imbi2d ⊢ r = k → φ ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ r ⊆ ball ⁡ D ⁡ F ⁡ A ↔ φ ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ k ⊆ ball ⁡ D ⁡ F ⁡ A
18 2fveq3 ⊢ r = k + 1 → ball ⁡ D ⁡ F ⁡ r = ball ⁡ D ⁡ F ⁡ k + 1
19 18 sseq1d ⊢ r = k + 1 → ball ⁡ D ⁡ F ⁡ r ⊆ ball ⁡ D ⁡ F ⁡ A ↔ ball ⁡ D ⁡ F ⁡ k + 1 ⊆ ball ⁡ D ⁡ F ⁡ A
20 19 imbi2d ⊢ r = k + 1 → φ ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ r ⊆ ball ⁡ D ⁡ F ⁡ A ↔ φ ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ k + 1 ⊆ ball ⁡ D ⁡ F ⁡ A
21 ssid ⊢ ball ⁡ D ⁡ F ⁡ A ⊆ ball ⁡ D ⁡ F ⁡ A
22 21 2a1i ⊢ A ∈ ℤ → φ ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ A ⊆ ball ⁡ D ⁡ F ⁡ A
23 eluznn ⊢ A ∈ ℕ ∧ k ∈ ℤ ≥ A → k ∈ ℕ
24 fvoveq1 ⊢ n = k → F ⁡ n + 1 = F ⁡ k + 1
25 24 fveq2d ⊢ n = k → ball ⁡ D ⁡ F ⁡ n + 1 = ball ⁡ D ⁡ F ⁡ k + 1
26 2fveq3 ⊢ n = k → ball ⁡ D ⁡ F ⁡ n = ball ⁡ D ⁡ F ⁡ k
27 25 26 sseq12d ⊢ n = k → ball ⁡ D ⁡ F ⁡ n + 1 ⊆ ball ⁡ D ⁡ F ⁡ n ↔ ball ⁡ D ⁡ F ⁡ k + 1 ⊆ ball ⁡ D ⁡ F ⁡ k
28 27 rspccva ⊢ ∀ n ∈ ℕ ball ⁡ D ⁡ F ⁡ n + 1 ⊆ ball ⁡ D ⁡ F ⁡ n ∧ k ∈ ℕ → ball ⁡ D ⁡ F ⁡ k + 1 ⊆ ball ⁡ D ⁡ F ⁡ k
29 3 23 28 syl2an ⊢ φ ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → ball ⁡ D ⁡ F ⁡ k + 1 ⊆ ball ⁡ D ⁡ F ⁡ k
30 29 anassrs ⊢ φ ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → ball ⁡ D ⁡ F ⁡ k + 1 ⊆ ball ⁡ D ⁡ F ⁡ k
31 sstr2 ⊢ ball ⁡ D ⁡ F ⁡ k + 1 ⊆ ball ⁡ D ⁡ F ⁡ k → ball ⁡ D ⁡ F ⁡ k ⊆ ball ⁡ D ⁡ F ⁡ A → ball ⁡ D ⁡ F ⁡ k + 1 ⊆ ball ⁡ D ⁡ F ⁡ A
32 30 31 syl ⊢ φ ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → ball ⁡ D ⁡ F ⁡ k ⊆ ball ⁡ D ⁡ F ⁡ A → ball ⁡ D ⁡ F ⁡ k + 1 ⊆ ball ⁡ D ⁡ F ⁡ A
33 32 expcom ⊢ k ∈ ℤ ≥ A → φ ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ k ⊆ ball ⁡ D ⁡ F ⁡ A → ball ⁡ D ⁡ F ⁡ k + 1 ⊆ ball ⁡ D ⁡ F ⁡ A
34 33 a2d ⊢ k ∈ ℤ ≥ A → φ ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ k ⊆ ball ⁡ D ⁡ F ⁡ A → φ ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ k + 1 ⊆ ball ⁡ D ⁡ F ⁡ A
35 14 17 20 17 22 34 uzind4 ⊢ k ∈ ℤ ≥ A → φ ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ k ⊆ ball ⁡ D ⁡ F ⁡ A
36 35 impcom ⊢ φ ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → ball ⁡ D ⁡ F ⁡ k ⊆ ball ⁡ D ⁡ F ⁡ A
37 36 3adantl2 ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → ball ⁡ D ⁡ F ⁡ k ⊆ ball ⁡ D ⁡ F ⁡ A
38 6 adantr ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → D ∈ ∞Met ⁡ X
39 simpl1 ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → φ
40 39 2 syl ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → F : ℕ ⟶ X × ℝ +
41 23 3ad2antl3 ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → k ∈ ℕ
42 40 41 ffvelcdmd ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → F ⁡ k ∈ X × ℝ +
43 xp1st ⊢ F ⁡ k ∈ X × ℝ + → 1 st ⁡ F ⁡ k ∈ X
44 42 43 syl ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → 1 st ⁡ F ⁡ k ∈ X
45 xp2nd ⊢ F ⁡ k ∈ X × ℝ + → 2 nd ⁡ F ⁡ k ∈ ℝ +
46 42 45 syl ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → 2 nd ⁡ F ⁡ k ∈ ℝ +
47 blcntr ⊢ D ∈ ∞Met ⁡ X ∧ 1 st ⁡ F ⁡ k ∈ X ∧ 2 nd ⁡ F ⁡ k ∈ ℝ + → 1 st ⁡ F ⁡ k ∈ 1 st ⁡ F ⁡ k ball ⁡ D 2 nd ⁡ F ⁡ k
48 38 44 46 47 syl3anc ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → 1 st ⁡ F ⁡ k ∈ 1 st ⁡ F ⁡ k ball ⁡ D 2 nd ⁡ F ⁡ k
49 fvco3 ⊢ F : ℕ ⟶ X × ℝ + ∧ k ∈ ℕ → 1 st ∘ F ⁡ k = 1 st ⁡ F ⁡ k
50 40 41 49 syl2anc ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → 1 st ∘ F ⁡ k = 1 st ⁡ F ⁡ k
51 1st2nd2 ⊢ F ⁡ k ∈ X × ℝ + → F ⁡ k = 1 st ⁡ F ⁡ k 2 nd ⁡ F ⁡ k
52 42 51 syl ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → F ⁡ k = 1 st ⁡ F ⁡ k 2 nd ⁡ F ⁡ k
53 52 fveq2d ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → ball ⁡ D ⁡ F ⁡ k = ball ⁡ D ⁡ 1 st ⁡ F ⁡ k 2 nd ⁡ F ⁡ k
54 df-ov ⊢ 1 st ⁡ F ⁡ k ball ⁡ D 2 nd ⁡ F ⁡ k = ball ⁡ D ⁡ 1 st ⁡ F ⁡ k 2 nd ⁡ F ⁡ k
55 53 54 eqtr4di ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → ball ⁡ D ⁡ F ⁡ k = 1 st ⁡ F ⁡ k ball ⁡ D 2 nd ⁡ F ⁡ k
56 48 50 55 3eltr4d ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → 1 st ∘ F ⁡ k ∈ ball ⁡ D ⁡ F ⁡ k
57 37 56 sseldd ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ ∧ k ∈ ℤ ≥ A → 1 st ∘ F ⁡ k ∈ ball ⁡ D ⁡ F ⁡ A
58 2 ffvelcdmda ⊢ φ ∧ A ∈ ℕ → F ⁡ A ∈ X × ℝ +
59 58 3adant2 ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → F ⁡ A ∈ X × ℝ +
60 1st2nd2 ⊢ F ⁡ A ∈ X × ℝ + → F ⁡ A = 1 st ⁡ F ⁡ A 2 nd ⁡ F ⁡ A
61 59 60 syl ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → F ⁡ A = 1 st ⁡ F ⁡ A 2 nd ⁡ F ⁡ A
62 61 fveq2d ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ A = ball ⁡ D ⁡ 1 st ⁡ F ⁡ A 2 nd ⁡ F ⁡ A
63 df-ov ⊢ 1 st ⁡ F ⁡ A ball ⁡ D 2 nd ⁡ F ⁡ A = ball ⁡ D ⁡ 1 st ⁡ F ⁡ A 2 nd ⁡ F ⁡ A
64 62 63 eqtr4di ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ A = 1 st ⁡ F ⁡ A ball ⁡ D 2 nd ⁡ F ⁡ A
65 xp1st ⊢ F ⁡ A ∈ X × ℝ + → 1 st ⁡ F ⁡ A ∈ X
66 59 65 syl ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → 1 st ⁡ F ⁡ A ∈ X
67 xp2nd ⊢ F ⁡ A ∈ X × ℝ + → 2 nd ⁡ F ⁡ A ∈ ℝ +
68 59 67 syl ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → 2 nd ⁡ F ⁡ A ∈ ℝ +
69 68 rpxrd ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → 2 nd ⁡ F ⁡ A ∈ ℝ *
70 blssm ⊢ D ∈ ∞Met ⁡ X ∧ 1 st ⁡ F ⁡ A ∈ X ∧ 2 nd ⁡ F ⁡ A ∈ ℝ * → 1 st ⁡ F ⁡ A ball ⁡ D 2 nd ⁡ F ⁡ A ⊆ X
71 6 66 69 70 syl3anc ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → 1 st ⁡ F ⁡ A ball ⁡ D 2 nd ⁡ F ⁡ A ⊆ X
72 64 71 eqsstrd ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → ball ⁡ D ⁡ F ⁡ A ⊆ X
73 5 8 10 11 57 72 lmcls ⊢ φ ∧ 1 st ∘ F ⇝t ⁡ J P ∧ A ∈ ℕ → P ∈ cls ⁡ J ⁡ ball ⁡ D ⁡ F ⁡ A