Metamath Proof Explorer


Theorem cnpconn

Description: An image of a path-connected space is path-connected. (Contributed by Mario Carneiro, 24-Mar-2015)

Ref Expression
Hypothesis cnpconn.2 ⊢ Y = ⋃ K
Assertion cnpconn ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K → K ∈ PConn

Proof

Step Hyp Ref Expression
1 cnpconn.2 ⊢ Y = ⋃ K
2 cntop2 ⊢ F ∈ J Cn K → K ∈ Top
3 2 3ad2ant3 ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K → K ∈ Top
4 eqid ⊢ ⋃ J = ⋃ J
5 4 pconncn ⊢ J ∈ PConn ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J → ∃ g ∈ II Cn J g ⁡ 0 = u ∧ g ⁡ 1 = v
6 5 3expb ⊢ J ∈ PConn ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J → ∃ g ∈ II Cn J g ⁡ 0 = u ∧ g ⁡ 1 = v
7 6 3ad2antl1 ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J → ∃ g ∈ II Cn J g ⁡ 0 = u ∧ g ⁡ 1 = v
8 simprl ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → g ∈ II Cn J
9 simpll3 ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → F ∈ J Cn K
10 cnco ⊢ g ∈ II Cn J ∧ F ∈ J Cn K → F ∘ g ∈ II Cn K
11 8 9 10 syl2anc ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → F ∘ g ∈ II Cn K
12 iiuni ⊢ 0 1 = ⋃ II
13 12 4 cnf ⊢ g ∈ II Cn J → g : 0 1 ⟶ ⋃ J
14 8 13 syl ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → g : 0 1 ⟶ ⋃ J
15 0elunit ⊢ 0 ∈ 0 1
16 fvco3 ⊢ g : 0 1 ⟶ ⋃ J ∧ 0 ∈ 0 1 → F ∘ g ⁡ 0 = F ⁡ g ⁡ 0
17 14 15 16 sylancl ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → F ∘ g ⁡ 0 = F ⁡ g ⁡ 0
18 simprrl ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → g ⁡ 0 = u
19 18 fveq2d ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → F ⁡ g ⁡ 0 = F ⁡ u
20 17 19 eqtrd ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → F ∘ g ⁡ 0 = F ⁡ u
21 1elunit ⊢ 1 ∈ 0 1
22 fvco3 ⊢ g : 0 1 ⟶ ⋃ J ∧ 1 ∈ 0 1 → F ∘ g ⁡ 1 = F ⁡ g ⁡ 1
23 14 21 22 sylancl ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → F ∘ g ⁡ 1 = F ⁡ g ⁡ 1
24 simprrr ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → g ⁡ 1 = v
25 24 fveq2d ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → F ⁡ g ⁡ 1 = F ⁡ v
26 23 25 eqtrd ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → F ∘ g ⁡ 1 = F ⁡ v
27 fveq1 ⊢ f = F ∘ g → f ⁡ 0 = F ∘ g ⁡ 0
28 27 eqeq1d ⊢ f = F ∘ g → f ⁡ 0 = F ⁡ u ↔ F ∘ g ⁡ 0 = F ⁡ u
29 fveq1 ⊢ f = F ∘ g → f ⁡ 1 = F ∘ g ⁡ 1
30 29 eqeq1d ⊢ f = F ∘ g → f ⁡ 1 = F ⁡ v ↔ F ∘ g ⁡ 1 = F ⁡ v
31 28 30 anbi12d ⊢ f = F ∘ g → f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = F ⁡ v ↔ F ∘ g ⁡ 0 = F ⁡ u ∧ F ∘ g ⁡ 1 = F ⁡ v
32 31 rspcev ⊢ F ∘ g ∈ II Cn K ∧ F ∘ g ⁡ 0 = F ⁡ u ∧ F ∘ g ⁡ 1 = F ⁡ v → ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = F ⁡ v
33 11 20 26 32 syl12anc ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J ∧ g ∈ II Cn J ∧ g ⁡ 0 = u ∧ g ⁡ 1 = v → ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = F ⁡ v
34 7 33 rexlimddv ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K ∧ u ∈ ⋃ J ∧ v ∈ ⋃ J → ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = F ⁡ v
35 34 ralrimivva ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K → ∀ u ∈ ⋃ J ∀ v ∈ ⋃ J ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = F ⁡ v
36 4 1 cnf ⊢ F ∈ J Cn K → F : ⋃ J ⟶ Y
37 36 3ad2ant3 ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K → F : ⋃ J ⟶ Y
38 forn ⊢ F : X ⟶ onto Y → ran ⁡ F = Y
39 38 3ad2ant2 ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K → ran ⁡ F = Y
40 dffo2 ⊢ F : ⋃ J ⟶ onto Y ↔ F : ⋃ J ⟶ Y ∧ ran ⁡ F = Y
41 37 39 40 sylanbrc ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K → F : ⋃ J ⟶ onto Y
42 eqeq2 ⊢ F ⁡ v = y → f ⁡ 1 = F ⁡ v ↔ f ⁡ 1 = y
43 42 anbi2d ⊢ F ⁡ v = y → f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = F ⁡ v ↔ f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = y
44 43 rexbidv ⊢ F ⁡ v = y → ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = F ⁡ v ↔ ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = y
45 44 cbvfo ⊢ F : ⋃ J ⟶ onto Y → ∀ v ∈ ⋃ J ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = F ⁡ v ↔ ∀ y ∈ Y ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = y
46 41 45 syl ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K → ∀ v ∈ ⋃ J ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = F ⁡ v ↔ ∀ y ∈ Y ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = y
47 46 ralbidv ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K → ∀ u ∈ ⋃ J ∀ v ∈ ⋃ J ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = F ⁡ v ↔ ∀ u ∈ ⋃ J ∀ y ∈ Y ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = y
48 35 47 mpbid ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K → ∀ u ∈ ⋃ J ∀ y ∈ Y ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = y
49 eqeq2 ⊢ F ⁡ u = x → f ⁡ 0 = F ⁡ u ↔ f ⁡ 0 = x
50 49 anbi1d ⊢ F ⁡ u = x → f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = y ↔ f ⁡ 0 = x ∧ f ⁡ 1 = y
51 50 rexbidv ⊢ F ⁡ u = x → ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = y ↔ ∃ f ∈ II Cn K f ⁡ 0 = x ∧ f ⁡ 1 = y
52 51 ralbidv ⊢ F ⁡ u = x → ∀ y ∈ Y ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = y ↔ ∀ y ∈ Y ∃ f ∈ II Cn K f ⁡ 0 = x ∧ f ⁡ 1 = y
53 52 cbvfo ⊢ F : ⋃ J ⟶ onto Y → ∀ u ∈ ⋃ J ∀ y ∈ Y ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = y ↔ ∀ x ∈ Y ∀ y ∈ Y ∃ f ∈ II Cn K f ⁡ 0 = x ∧ f ⁡ 1 = y
54 41 53 syl ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K → ∀ u ∈ ⋃ J ∀ y ∈ Y ∃ f ∈ II Cn K f ⁡ 0 = F ⁡ u ∧ f ⁡ 1 = y ↔ ∀ x ∈ Y ∀ y ∈ Y ∃ f ∈ II Cn K f ⁡ 0 = x ∧ f ⁡ 1 = y
55 48 54 mpbid ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K → ∀ x ∈ Y ∀ y ∈ Y ∃ f ∈ II Cn K f ⁡ 0 = x ∧ f ⁡ 1 = y
56 1 ispconn ⊢ K ∈ PConn ↔ K ∈ Top ∧ ∀ x ∈ Y ∀ y ∈ Y ∃ f ∈ II Cn K f ⁡ 0 = x ∧ f ⁡ 1 = y
57 3 55 56 sylanbrc ⊢ J ∈ PConn ∧ F : X ⟶ onto Y ∧ F ∈ J Cn K → K ∈ PConn