Metamath Proof Explorer


Theorem dochexmidlem8

Description: Lemma for dochexmid . The contradiction of dochexmidlem6 and dochexmidlem7 shows that there can be no atom p that is not in X + ( ._|_X ) , which is therefore the whole atom space. (Contributed by NM, 15-Jan-2015)

Ref Expression
Hypotheses dochexmidlem1.h ⊢ H = LHyp ⁡ K
dochexmidlem1.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
dochexmidlem1.u ⊢ U = DVecH ⁡ K ⁡ W
dochexmidlem1.v ⊢ V = Base U
dochexmidlem1.s ⊢ S = LSubSp ⁡ U
dochexmidlem1.n ⊢ N = LSpan ⁡ U
dochexmidlem1.p ⊢ ⊕ ˙ = LSSum ⁡ U
dochexmidlem1.a ⊢ A = LSAtoms ⁡ U
dochexmidlem1.k ⊢ φ → K ∈ HL ∧ W ∈ H
dochexmidlem1.x ⊢ φ → X ∈ S
dochexmidlem8.z ⊢ 0 ˙ = 0 U
dochexmidlem8.xn ⊢ φ → X ≠ 0 ˙
dochexmidlem8.c ⊢ φ → ⊥ ˙ ⁡ ⊥ ˙ ⁡ X = X
Assertion dochexmidlem8 ⊢ φ → X ⊕ ˙ ⊥ ˙ ⁡ X = V

Proof

Step Hyp Ref Expression
1 dochexmidlem1.h ⊢ H = LHyp ⁡ K
2 dochexmidlem1.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
3 dochexmidlem1.u ⊢ U = DVecH ⁡ K ⁡ W
4 dochexmidlem1.v ⊢ V = Base U
5 dochexmidlem1.s ⊢ S = LSubSp ⁡ U
6 dochexmidlem1.n ⊢ N = LSpan ⁡ U
7 dochexmidlem1.p ⊢ ⊕ ˙ = LSSum ⁡ U
8 dochexmidlem1.a ⊢ A = LSAtoms ⁡ U
9 dochexmidlem1.k ⊢ φ → K ∈ HL ∧ W ∈ H
10 dochexmidlem1.x ⊢ φ → X ∈ S
11 dochexmidlem8.z ⊢ 0 ˙ = 0 U
12 dochexmidlem8.xn ⊢ φ → X ≠ 0 ˙
13 dochexmidlem8.c ⊢ φ → ⊥ ˙ ⁡ ⊥ ˙ ⁡ X = X
14 nonconne ⊢ ¬ X = X ∧ X ≠ X
15 1 3 9 dvhlmod ⊢ φ → U ∈ LMod
16 4 5 lssss ⊢ X ∈ S → X ⊆ V
17 10 16 syl ⊢ φ → X ⊆ V
18 1 3 4 5 2 dochlss ⊢ K ∈ HL ∧ W ∈ H ∧ X ⊆ V → ⊥ ˙ ⁡ X ∈ S
19 9 17 18 syl2anc ⊢ φ → ⊥ ˙ ⁡ X ∈ S
20 5 7 lsmcl ⊢ U ∈ LMod ∧ X ∈ S ∧ ⊥ ˙ ⁡ X ∈ S → X ⊕ ˙ ⊥ ˙ ⁡ X ∈ S
21 15 10 19 20 syl3anc ⊢ φ → X ⊕ ˙ ⊥ ˙ ⁡ X ∈ S
22 4 5 lssss ⊢ X ⊕ ˙ ⊥ ˙ ⁡ X ∈ S → X ⊕ ˙ ⊥ ˙ ⁡ X ⊆ V
23 21 22 syl ⊢ φ → X ⊕ ˙ ⊥ ˙ ⁡ X ⊆ V
24 15 adantr ⊢ φ ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ⊆ V ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ≠ V → U ∈ LMod
25 21 adantr ⊢ φ ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ⊆ V ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ≠ V → X ⊕ ˙ ⊥ ˙ ⁡ X ∈ S
26 4 5 lss1 ⊢ U ∈ LMod → V ∈ S
27 15 26 syl ⊢ φ → V ∈ S
28 27 adantr ⊢ φ ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ⊆ V ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ≠ V → V ∈ S
29 df-pss ⊢ X ⊕ ˙ ⊥ ˙ ⁡ X ⊂ V ↔ X ⊕ ˙ ⊥ ˙ ⁡ X ⊆ V ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ≠ V
30 29 bilanri ⊢ φ ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ⊆ V ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ≠ V → X ⊕ ˙ ⊥ ˙ ⁡ X ⊂ V
31 5 8 24 25 28 30 lpssat ⊢ φ ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ⊆ V ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ≠ V → ∃ p ∈ A p ⊆ V ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X
32 31 ex ⊢ φ → X ⊕ ˙ ⊥ ˙ ⁡ X ⊆ V ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ≠ V → ∃ p ∈ A p ⊆ V ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X
33 9 3ad2ant1 ⊢ φ ∧ p ∈ A ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X → K ∈ HL ∧ W ∈ H
34 10 3ad2ant1 ⊢ φ ∧ p ∈ A ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X → X ∈ S
35 simp2 ⊢ φ ∧ p ∈ A ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X → p ∈ A
36 eqid ⊢ X ⊕ ˙ p = X ⊕ ˙ p
37 12 3ad2ant1 ⊢ φ ∧ p ∈ A ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X → X ≠ 0 ˙
38 13 3ad2ant1 ⊢ φ ∧ p ∈ A ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X → ⊥ ˙ ⁡ ⊥ ˙ ⁡ X = X
39 simp3 ⊢ φ ∧ p ∈ A ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X → ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X
40 1 2 3 4 5 6 7 8 33 34 35 11 36 37 38 39 dochexmidlem6 ⊢ φ ∧ p ∈ A ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X → X ⊕ ˙ p = X
41 1 2 3 4 5 6 7 8 33 34 35 11 36 37 38 39 dochexmidlem7 ⊢ φ ∧ p ∈ A ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X → X ⊕ ˙ p ≠ X
42 40 41 pm2.21ddne ⊢ φ ∧ p ∈ A ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X → X = X ∧ X ≠ X
43 42 3adant3l ⊢ φ ∧ p ∈ A ∧ p ⊆ V ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X → X = X ∧ X ≠ X
44 43 rexlimdv3a ⊢ φ → ∃ p ∈ A p ⊆ V ∧ ¬ p ⊆ X ⊕ ˙ ⊥ ˙ ⁡ X → X = X ∧ X ≠ X
45 32 44 syld ⊢ φ → X ⊕ ˙ ⊥ ˙ ⁡ X ⊆ V ∧ X ⊕ ˙ ⊥ ˙ ⁡ X ≠ V → X = X ∧ X ≠ X
46 23 45 mpand ⊢ φ → X ⊕ ˙ ⊥ ˙ ⁡ X ≠ V → X = X ∧ X ≠ X
47 46 necon1bd ⊢ φ → ¬ X = X ∧ X ≠ X → X ⊕ ˙ ⊥ ˙ ⁡ X = V
48 14 47 mpi ⊢ φ → X ⊕ ˙ ⊥ ˙ ⁡ X = V