Metamath Proof Explorer


Theorem expaddzlem

Description: Lemma for expaddz . (Contributed by Mario Carneiro, 4-Jun-2014)

Ref Expression
Assertion expaddzlem ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A M + N = A M ⁢ A N

Proof

Step Hyp Ref Expression
1 simp1l ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A ∈ ℂ
2 simp3 ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → N ∈ ℕ 0
3 expcl ⊢ A ∈ ℂ ∧ N ∈ ℕ 0 → A N ∈ ℂ
4 1 2 3 syl2anc ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A N ∈ ℂ
5 simp2r ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → − M ∈ ℕ
6 5 nnnn0d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → − M ∈ ℕ 0
7 expcl ⊢ A ∈ ℂ ∧ − M ∈ ℕ 0 → A − M ∈ ℂ
8 1 6 7 syl2anc ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A − M ∈ ℂ
9 simp1r ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A ≠ 0
10 5 nnzd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → − M ∈ ℤ
11 expne0i ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ − M ∈ ℤ → A − M ≠ 0
12 1 9 10 11 syl3anc ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A − M ≠ 0
13 4 8 12 divrec2d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A N A − M = 1 A − M ⁢ A N
14 simp2l ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → M ∈ ℝ
15 14 recnd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → M ∈ ℂ
16 15 negnegd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → − -M = M
17 nnnegz ⊢ − M ∈ ℕ → − -M ∈ ℤ
18 5 17 syl ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → − -M ∈ ℤ
19 16 18 eqeltrrd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → M ∈ ℤ
20 2 nn0zd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → N ∈ ℤ
21 19 20 zaddcld ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → M + N ∈ ℤ
22 expclz ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M + N ∈ ℤ → A M + N ∈ ℂ
23 1 9 21 22 syl3anc ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A M + N ∈ ℂ
24 23 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → A M + N ∈ ℂ
25 8 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → A − M ∈ ℂ
26 12 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → A − M ≠ 0
27 24 25 26 divcan4d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → A M + N ⁢ A − M A − M = A M + N
28 1 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → A ∈ ℂ
29 simpr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → M + N ∈ ℕ 0
30 6 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → − M ∈ ℕ 0
31 expadd ⊢ A ∈ ℂ ∧ M + N ∈ ℕ 0 ∧ − M ∈ ℕ 0 → A M + N + -M = A M + N ⁢ A − M
32 28 29 30 31 syl3anc ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → A M + N + -M = A M + N ⁢ A − M
33 21 zcnd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → M + N ∈ ℂ
34 33 15 negsubd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → M + N + -M = M + N - M
35 2 nn0cnd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → N ∈ ℂ
36 15 35 pncan2d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → M + N - M = N
37 34 36 eqtrd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → M + N + -M = N
38 37 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → M + N + -M = N
39 38 oveq2d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → A M + N + -M = A N
40 32 39 eqtr3d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → A M + N ⁢ A − M = A N
41 40 oveq1d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → A M + N ⁢ A − M A − M = A N A − M
42 27 41 eqtr3d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ M + N ∈ ℕ 0 → A M + N = A N A − M
43 1 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → A ∈ ℂ
44 33 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → M + N ∈ ℂ
45 simpr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → − M + N ∈ ℕ 0
46 expneg2 ⊢ A ∈ ℂ ∧ M + N ∈ ℂ ∧ − M + N ∈ ℕ 0 → A M + N = 1 A − M + N
47 43 44 45 46 syl3anc ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → A M + N = 1 A − M + N
48 21 znegcld ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → − M + N ∈ ℤ
49 expclz ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ − M + N ∈ ℤ → A − M + N ∈ ℂ
50 1 9 48 49 syl3anc ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A − M + N ∈ ℂ
51 50 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → A − M + N ∈ ℂ
52 4 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → A N ∈ ℂ
53 expne0i ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ N ∈ ℤ → A N ≠ 0
54 1 9 20 53 syl3anc ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A N ≠ 0
55 54 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → A N ≠ 0
56 51 52 55 divcan4d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → A − M + N ⁢ A N A N = A − M + N
57 2 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → N ∈ ℕ 0
58 expadd ⊢ A ∈ ℂ ∧ − M + N ∈ ℕ 0 ∧ N ∈ ℕ 0 → A - M + N + N = A − M + N ⁢ A N
59 43 45 57 58 syl3anc ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → A - M + N + N = A − M + N ⁢ A N
60 15 negcld ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → − M ∈ ℂ
61 15 35 negdi2d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → − M + N = - M - N
62 60 35 61 mvrrsubd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → - M + N + N = − M
63 62 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → - M + N + N = − M
64 63 oveq2d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → A - M + N + N = A − M
65 59 64 eqtr3d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → A − M + N ⁢ A N = A − M
66 65 oveq1d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → A − M + N ⁢ A N A N = A − M A N
67 56 66 eqtr3d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → A − M + N = A − M A N
68 67 oveq2d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → 1 A − M + N = 1 A − M A N
69 8 4 12 54 recdivd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → 1 A − M A N = A N A − M
70 69 adantr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → 1 A − M A N = A N A − M
71 47 68 70 3eqtrd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 ∧ − M + N ∈ ℕ 0 → A M + N = A N A − M
72 elznn0 ⊢ M + N ∈ ℤ ↔ M + N ∈ ℝ ∧ M + N ∈ ℕ 0 ∨ − M + N ∈ ℕ 0
73 72 simprbi ⊢ M + N ∈ ℤ → M + N ∈ ℕ 0 ∨ − M + N ∈ ℕ 0
74 21 73 syl ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → M + N ∈ ℕ 0 ∨ − M + N ∈ ℕ 0
75 42 71 74 mpjaodan ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A M + N = A N A − M
76 expneg2 ⊢ A ∈ ℂ ∧ M ∈ ℂ ∧ − M ∈ ℕ 0 → A M = 1 A − M
77 1 15 6 76 syl3anc ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A M = 1 A − M
78 77 oveq1d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A M ⁢ A N = 1 A − M ⁢ A N
79 13 75 78 3eqtr4d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ M ∈ ℝ ∧ − M ∈ ℕ ∧ N ∈ ℕ 0 → A M + N = A M ⁢ A N