Metamath Proof Explorer


Theorem fucpropd

Description: If two categories have the same set of objects, morphisms, and compositions, then they have the same functor categories. (Contributed by Mario Carneiro, 26-Jan-2017)

Ref Expression
Hypotheses fucpropd.1 ⊢ φ → Hom 𝑓 ⁡ A = Hom 𝑓 ⁡ B
fucpropd.2 ⊢ φ → comp 𝑓 ⁡ A = comp 𝑓 ⁡ B
fucpropd.3 ⊢ φ → Hom 𝑓 ⁡ C = Hom 𝑓 ⁡ D
fucpropd.4 ⊢ φ → comp 𝑓 ⁡ C = comp 𝑓 ⁡ D
fucpropd.a ⊢ φ → A ∈ Cat
fucpropd.b ⊢ φ → B ∈ Cat
fucpropd.c ⊢ φ → C ∈ Cat
fucpropd.d ⊢ φ → D ∈ Cat
Assertion fucpropd ⊢ φ → A FuncCat C = B FuncCat D

Proof

Step Hyp Ref Expression
1 fucpropd.1 ⊢ φ → Hom 𝑓 ⁡ A = Hom 𝑓 ⁡ B
2 fucpropd.2 ⊢ φ → comp 𝑓 ⁡ A = comp 𝑓 ⁡ B
3 fucpropd.3 ⊢ φ → Hom 𝑓 ⁡ C = Hom 𝑓 ⁡ D
4 fucpropd.4 ⊢ φ → comp 𝑓 ⁡ C = comp 𝑓 ⁡ D
5 fucpropd.a ⊢ φ → A ∈ Cat
6 fucpropd.b ⊢ φ → B ∈ Cat
7 fucpropd.c ⊢ φ → C ∈ Cat
8 fucpropd.d ⊢ φ → D ∈ Cat
9 1 2 3 4 5 6 7 8 funcpropd ⊢ φ → A Func C = B Func D
10 9 opeq2d ⊢ φ → Base ndx A Func C = Base ndx B Func D
11 1 2 3 4 5 6 7 8 natpropd ⊢ φ → A Nat C = B Nat D
12 11 opeq2d ⊢ φ → Hom ⁡ ndx A Nat C = Hom ⁡ ndx B Nat D
13 9 sqxpeqd ⊢ φ → A Func C × A Func C = B Func D × B Func D
14 9 adantr ⊢ φ ∧ v ∈ A Func C × A Func C → A Func C = B Func D
15 nfv ⊢ Ⅎ f φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C
16 nfcsb1v ⊢ Ⅎ _ f ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
17 16 a1i ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C → Ⅎ _ f ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
18 fvexd ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C → 1 st ⁡ v ∈ V
19 nfv ⊢ Ⅎ g φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v
20 nfcsb1v ⊢ Ⅎ _ g ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
21 20 a1i ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v → Ⅎ _ g ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
22 fvexd ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v → 2 nd ⁡ v ∈ V
23 11 ad3antrrr ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v → A Nat C = B Nat D
24 23 oveqd ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v → g A Nat C h = g B Nat D h
25 23 oveqdr ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h → f A Nat C g = f B Nat D g
26 1 homfeqbas ⊢ φ → Base A = Base B
27 26 ad4antr ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → Base A = Base B
28 eqid ⊢ Base C = Base C
29 eqid ⊢ Hom ⁡ C = Hom ⁡ C
30 eqid ⊢ comp ⁡ C = comp ⁡ C
31 eqid ⊢ comp ⁡ D = comp ⁡ D
32 3 ad5antr ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → Hom 𝑓 ⁡ C = Hom 𝑓 ⁡ D
33 4 ad5antr ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → comp 𝑓 ⁡ C = comp 𝑓 ⁡ D
34 eqid ⊢ Base A = Base A
35 relfunc ⊢ Rel ⁡ A Func C
36 simpllr ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → f = 1 st ⁡ v
37 simp-4r ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → v ∈ A Func C × A Func C ∧ h ∈ A Func C
38 37 simpld ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → v ∈ A Func C × A Func C
39 xp1st ⊢ v ∈ A Func C × A Func C → 1 st ⁡ v ∈ A Func C
40 38 39 syl ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → 1 st ⁡ v ∈ A Func C
41 36 40 eqeltrd ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → f ∈ A Func C
42 1st2ndbr ⊢ Rel ⁡ A Func C ∧ f ∈ A Func C → 1 st ⁡ f A Func C 2 nd ⁡ f
43 35 41 42 sylancr ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → 1 st ⁡ f A Func C 2 nd ⁡ f
44 34 28 43 funcf1 ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → 1 st ⁡ f : Base A ⟶ Base C
45 44 ffvelcdmda ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → 1 st ⁡ f ⁡ x ∈ Base C
46 simplr ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → g = 2 nd ⁡ v
47 xp2nd ⊢ v ∈ A Func C × A Func C → 2 nd ⁡ v ∈ A Func C
48 38 47 syl ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → 2 nd ⁡ v ∈ A Func C
49 46 48 eqeltrd ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → g ∈ A Func C
50 1st2ndbr ⊢ Rel ⁡ A Func C ∧ g ∈ A Func C → 1 st ⁡ g A Func C 2 nd ⁡ g
51 35 49 50 sylancr ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → 1 st ⁡ g A Func C 2 nd ⁡ g
52 34 28 51 funcf1 ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → 1 st ⁡ g : Base A ⟶ Base C
53 52 ffvelcdmda ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → 1 st ⁡ g ⁡ x ∈ Base C
54 37 simprd ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → h ∈ A Func C
55 1st2ndbr ⊢ Rel ⁡ A Func C ∧ h ∈ A Func C → 1 st ⁡ h A Func C 2 nd ⁡ h
56 35 54 55 sylancr ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → 1 st ⁡ h A Func C 2 nd ⁡ h
57 34 28 56 funcf1 ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → 1 st ⁡ h : Base A ⟶ Base C
58 57 ffvelcdmda ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → 1 st ⁡ h ⁡ x ∈ Base C
59 eqid ⊢ A Nat C = A Nat C
60 simplrr ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → a ∈ f A Nat C g
61 59 60 nat1st2nd ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → a ∈ 1 st ⁡ f 2 nd ⁡ f A Nat C 1 st ⁡ g 2 nd ⁡ g
62 simpr ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → x ∈ Base A
63 59 61 34 29 62 natcl ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → a ⁡ x ∈ 1 st ⁡ f ⁡ x Hom ⁡ C 1 st ⁡ g ⁡ x
64 simplrl ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → b ∈ g A Nat C h
65 59 64 nat1st2nd ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → b ∈ 1 st ⁡ g 2 nd ⁡ g A Nat C 1 st ⁡ h 2 nd ⁡ h
66 59 65 34 29 62 natcl ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → b ⁡ x ∈ 1 st ⁡ g ⁡ x Hom ⁡ C 1 st ⁡ h ⁡ x
67 28 29 30 31 32 33 45 53 58 63 66 comfeqval ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g ∧ x ∈ Base A → b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x = b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
68 27 67 mpteq12dva ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v ∧ b ∈ g A Nat C h ∧ a ∈ f A Nat C g → x ∈ Base A ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x = x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
69 24 25 68 mpoeq123dva ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v → b ∈ g A Nat C h , a ∈ f A Nat C g ⟼ x ∈ Base A ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x = b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
70 csbeq1a ⊢ g = 2 nd ⁡ v → b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x = ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
71 70 adantl ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v → b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x = ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
72 69 71 eqtrd ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v ∧ g = 2 nd ⁡ v → b ∈ g A Nat C h , a ∈ f A Nat C g ⟼ x ∈ Base A ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x = ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
73 19 21 22 72 csbiedf ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v → ⦋ 2 nd ⁡ v / g⦌ b ∈ g A Nat C h , a ∈ f A Nat C g ⟼ x ∈ Base A ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x = ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
74 csbeq1a ⊢ f = 1 st ⁡ v → ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x = ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
75 74 adantl ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v → ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x = ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
76 73 75 eqtrd ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C ∧ f = 1 st ⁡ v → ⦋ 2 nd ⁡ v / g⦌ b ∈ g A Nat C h , a ∈ f A Nat C g ⟼ x ∈ Base A ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x = ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
77 15 17 18 76 csbiedf ⊢ φ ∧ v ∈ A Func C × A Func C ∧ h ∈ A Func C → ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g A Nat C h , a ∈ f A Nat C g ⟼ x ∈ Base A ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x = ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
78 13 14 77 mpoeq123dva ⊢ φ → v ∈ A Func C × A Func C , h ∈ A Func C ⟼ ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g A Nat C h , a ∈ f A Nat C g ⟼ x ∈ Base A ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x = v ∈ B Func D × B Func D , h ∈ B Func D ⟼ ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
79 78 opeq2d ⊢ φ → comp ⁡ ndx v ∈ A Func C × A Func C , h ∈ A Func C ⟼ ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g A Nat C h , a ∈ f A Nat C g ⟼ x ∈ Base A ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x = comp ⁡ ndx v ∈ B Func D × B Func D , h ∈ B Func D ⟼ ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
80 10 12 79 tpeq123d ⊢ φ → Base ndx A Func C Hom ⁡ ndx A Nat C comp ⁡ ndx v ∈ A Func C × A Func C , h ∈ A Func C ⟼ ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g A Nat C h , a ∈ f A Nat C g ⟼ x ∈ Base A ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x = Base ndx B Func D Hom ⁡ ndx B Nat D comp ⁡ ndx v ∈ B Func D × B Func D , h ∈ B Func D ⟼ ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
81 eqid ⊢ A FuncCat C = A FuncCat C
82 eqid ⊢ A Func C = A Func C
83 eqidd ⊢ φ → v ∈ A Func C × A Func C , h ∈ A Func C ⟼ ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g A Nat C h , a ∈ f A Nat C g ⟼ x ∈ Base A ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x = v ∈ A Func C × A Func C , h ∈ A Func C ⟼ ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g A Nat C h , a ∈ f A Nat C g ⟼ x ∈ Base A ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x
84 81 82 59 34 30 5 7 83 fucval ⊢ φ → A FuncCat C = Base ndx A Func C Hom ⁡ ndx A Nat C comp ⁡ ndx v ∈ A Func C × A Func C , h ∈ A Func C ⟼ ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g A Nat C h , a ∈ f A Nat C g ⟼ x ∈ Base A ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ C 1 st ⁡ h ⁡ x a ⁡ x
85 eqid ⊢ B FuncCat D = B FuncCat D
86 eqid ⊢ B Func D = B Func D
87 eqid ⊢ B Nat D = B Nat D
88 eqid ⊢ Base B = Base B
89 eqidd ⊢ φ → v ∈ B Func D × B Func D , h ∈ B Func D ⟼ ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x = v ∈ B Func D × B Func D , h ∈ B Func D ⟼ ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
90 85 86 87 88 31 6 8 89 fucval ⊢ φ → B FuncCat D = Base ndx B Func D Hom ⁡ ndx B Nat D comp ⁡ ndx v ∈ B Func D × B Func D , h ∈ B Func D ⟼ ⦋ 1 st ⁡ v / f⦌ ⦋ 2 nd ⁡ v / g⦌ b ∈ g B Nat D h , a ∈ f B Nat D g ⟼ x ∈ Base B ⟼ b ⁡ x 1 st ⁡ f ⁡ x 1 st ⁡ g ⁡ x comp ⁡ D 1 st ⁡ h ⁡ x a ⁡ x
91 80 84 90 3eqtr4d ⊢ φ → A FuncCat C = B FuncCat D