Metamath Proof Explorer


Theorem hgmaprnlem2N

Description: Lemma for hgmaprnN . Part 15 of Baer p. 50 line 20. We only require a subset relation, rather than equality, so that the case of zero z is taken care of automatically. (Contributed by NM, 7-Jun-2015) (New usage is discouraged.)

Ref Expression
Hypotheses hgmaprnlem1.h ⊢ H = LHyp ⁡ K
hgmaprnlem1.u ⊢ U = DVecH ⁡ K ⁡ W
hgmaprnlem1.v ⊢ V = Base U
hgmaprnlem1.r ⊢ R = Scalar ⁡ U
hgmaprnlem1.b ⊢ B = Base R
hgmaprnlem1.t ⊢ · ˙ = ⋅ U
hgmaprnlem1.o ⊢ 0 ˙ = 0 U
hgmaprnlem1.c ⊢ C = LCDual ⁡ K ⁡ W
hgmaprnlem1.d ⊢ D = Base C
hgmaprnlem1.p ⊢ P = Scalar ⁡ C
hgmaprnlem1.a ⊢ A = Base P
hgmaprnlem1.e ⊢ ∙ ˙ = ⋅ C
hgmaprnlem1.q ⊢ Q = 0 C
hgmaprnlem1.s ⊢ S = HDMap ⁡ K ⁡ W
hgmaprnlem1.g ⊢ G = HGMap ⁡ K ⁡ W
hgmaprnlem1.k ⊢ φ → K ∈ HL ∧ W ∈ H
hgmaprnlem1.z ⊢ φ → z ∈ A
hgmaprnlem1.t2 ⊢ φ → t ∈ V ∖ 0 ˙
hgmaprnlem1.s2 ⊢ φ → s ∈ V
hgmaprnlem1.sz ⊢ φ → S ⁡ s = z ∙ ˙ S ⁡ t
hgmaprnlem1.m ⊢ M = mapd ⁡ K ⁡ W
hgmaprnlem1.n ⊢ N = LSpan ⁡ U
hgmaprnlem1.l ⊢ L = LSpan ⁡ C
Assertion hgmaprnlem2N ⊢ φ → N ⁡ s ⊆ N ⁡ t

Proof

Step Hyp Ref Expression
1 hgmaprnlem1.h ⊢ H = LHyp ⁡ K
2 hgmaprnlem1.u ⊢ U = DVecH ⁡ K ⁡ W
3 hgmaprnlem1.v ⊢ V = Base U
4 hgmaprnlem1.r ⊢ R = Scalar ⁡ U
5 hgmaprnlem1.b ⊢ B = Base R
6 hgmaprnlem1.t ⊢ · ˙ = ⋅ U
7 hgmaprnlem1.o ⊢ 0 ˙ = 0 U
8 hgmaprnlem1.c ⊢ C = LCDual ⁡ K ⁡ W
9 hgmaprnlem1.d ⊢ D = Base C
10 hgmaprnlem1.p ⊢ P = Scalar ⁡ C
11 hgmaprnlem1.a ⊢ A = Base P
12 hgmaprnlem1.e ⊢ ∙ ˙ = ⋅ C
13 hgmaprnlem1.q ⊢ Q = 0 C
14 hgmaprnlem1.s ⊢ S = HDMap ⁡ K ⁡ W
15 hgmaprnlem1.g ⊢ G = HGMap ⁡ K ⁡ W
16 hgmaprnlem1.k ⊢ φ → K ∈ HL ∧ W ∈ H
17 hgmaprnlem1.z ⊢ φ → z ∈ A
18 hgmaprnlem1.t2 ⊢ φ → t ∈ V ∖ 0 ˙
19 hgmaprnlem1.s2 ⊢ φ → s ∈ V
20 hgmaprnlem1.sz ⊢ φ → S ⁡ s = z ∙ ˙ S ⁡ t
21 hgmaprnlem1.m ⊢ M = mapd ⁡ K ⁡ W
22 hgmaprnlem1.n ⊢ N = LSpan ⁡ U
23 hgmaprnlem1.l ⊢ L = LSpan ⁡ C
24 1 8 16 lcdlmod ⊢ φ → C ∈ LMod
25 18 eldifad ⊢ φ → t ∈ V
26 1 2 3 8 9 14 16 25 hdmapcl ⊢ φ → S ⁡ t ∈ D
27 10 11 9 12 23 lspsnvsi ⊢ C ∈ LMod ∧ z ∈ A ∧ S ⁡ t ∈ D → L ⁡ z ∙ ˙ S ⁡ t ⊆ L ⁡ S ⁡ t
28 24 17 26 27 syl3anc ⊢ φ → L ⁡ z ∙ ˙ S ⁡ t ⊆ L ⁡ S ⁡ t
29 1 2 3 22 8 23 21 14 16 19 hdmap10 ⊢ φ → M ⁡ N ⁡ s = L ⁡ S ⁡ s
30 20 sneqd ⊢ φ → S ⁡ s = z ∙ ˙ S ⁡ t
31 30 fveq2d ⊢ φ → L ⁡ S ⁡ s = L ⁡ z ∙ ˙ S ⁡ t
32 29 31 eqtrd ⊢ φ → M ⁡ N ⁡ s = L ⁡ z ∙ ˙ S ⁡ t
33 1 2 3 22 8 23 21 14 16 25 hdmap10 ⊢ φ → M ⁡ N ⁡ t = L ⁡ S ⁡ t
34 28 32 33 3sstr4d ⊢ φ → M ⁡ N ⁡ s ⊆ M ⁡ N ⁡ t
35 eqid ⊢ LSubSp ⁡ U = LSubSp ⁡ U
36 1 2 16 dvhlmod ⊢ φ → U ∈ LMod
37 3 35 22 lspsncl ⊢ U ∈ LMod ∧ s ∈ V → N ⁡ s ∈ LSubSp ⁡ U
38 36 19 37 syl2anc ⊢ φ → N ⁡ s ∈ LSubSp ⁡ U
39 3 35 22 lspsncl ⊢ U ∈ LMod ∧ t ∈ V → N ⁡ t ∈ LSubSp ⁡ U
40 36 25 39 syl2anc ⊢ φ → N ⁡ t ∈ LSubSp ⁡ U
41 1 2 35 21 16 38 40 mapdord ⊢ φ → M ⁡ N ⁡ s ⊆ M ⁡ N ⁡ t ↔ N ⁡ s ⊆ N ⁡ t
42 34 41 mpbid ⊢ φ → N ⁡ s ⊆ N ⁡ t