Metamath Proof Explorer


Theorem lediv23

Description: Swap denominator with other side of 'less than or equal to'. (Contributed by NM, 30-May-2005)

Ref Expression
Assertion lediv23 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B ∧ C ∈ ℝ ∧ 0 < C → A B ≤ C ↔ A C ≤ B

Proof

Step Hyp Ref Expression
1 simpl ⊢ B ∈ ℝ ∧ 0 < B → B ∈ ℝ
2 gt0ne0 ⊢ B ∈ ℝ ∧ 0 < B → B ≠ 0
3 1 2 jca ⊢ B ∈ ℝ ∧ 0 < B → B ∈ ℝ ∧ B ≠ 0
4 redivcl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → A B ∈ ℝ
5 4 3expb ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → A B ∈ ℝ
6 3 5 sylan2 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B → A B ∈ ℝ
7 6 3adant3 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B ∧ C ∈ ℝ → A B ∈ ℝ
8 simp3 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B ∧ C ∈ ℝ → C ∈ ℝ
9 simp2 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B ∧ C ∈ ℝ → B ∈ ℝ ∧ 0 < B
10 lemul1 ⊢ A B ∈ ℝ ∧ C ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B → A B ≤ C ↔ A B ⁢ B ≤ C ⁢ B
11 7 8 9 10 syl3anc ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B ∧ C ∈ ℝ → A B ≤ C ↔ A B ⁢ B ≤ C ⁢ B
12 11 3adant3r ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B ∧ C ∈ ℝ ∧ 0 < C → A B ≤ C ↔ A B ⁢ B ≤ C ⁢ B
13 recn ⊢ A ∈ ℝ → A ∈ ℂ
14 13 adantr ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B → A ∈ ℂ
15 recn ⊢ B ∈ ℝ → B ∈ ℂ
16 15 ad2antrl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B → B ∈ ℂ
17 2 adantl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B → B ≠ 0
18 14 16 17 divcan1d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B → A B ⁢ B = A
19 18 3adant3 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B ∧ C ∈ ℝ ∧ 0 < C → A B ⁢ B = A
20 19 breq1d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B ∧ C ∈ ℝ ∧ 0 < C → A B ⁢ B ≤ C ⁢ B ↔ A ≤ C ⁢ B
21 remulcl ⊢ C ∈ ℝ ∧ B ∈ ℝ → C ⁢ B ∈ ℝ
22 21 ancoms ⊢ B ∈ ℝ ∧ C ∈ ℝ → C ⁢ B ∈ ℝ
23 22 adantrr ⊢ B ∈ ℝ ∧ C ∈ ℝ ∧ 0 < C → C ⁢ B ∈ ℝ
24 23 3adant1 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ 0 < C → C ⁢ B ∈ ℝ
25 lediv1 ⊢ A ∈ ℝ ∧ C ⁢ B ∈ ℝ ∧ C ∈ ℝ ∧ 0 < C → A ≤ C ⁢ B ↔ A C ≤ C ⁢ B C
26 24 25 syld3an2 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ 0 < C → A ≤ C ⁢ B ↔ A C ≤ C ⁢ B C
27 recn ⊢ C ∈ ℝ → C ∈ ℂ
28 27 adantr ⊢ C ∈ ℝ ∧ 0 < C → C ∈ ℂ
29 gt0ne0 ⊢ C ∈ ℝ ∧ 0 < C → C ≠ 0
30 28 29 jca ⊢ C ∈ ℝ ∧ 0 < C → C ∈ ℂ ∧ C ≠ 0
31 divcan3 ⊢ B ∈ ℂ ∧ C ∈ ℂ ∧ C ≠ 0 → C ⁢ B C = B
32 31 3expb ⊢ B ∈ ℂ ∧ C ∈ ℂ ∧ C ≠ 0 → C ⁢ B C = B
33 15 30 32 syl2an ⊢ B ∈ ℝ ∧ C ∈ ℝ ∧ 0 < C → C ⁢ B C = B
34 33 3adant1 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ 0 < C → C ⁢ B C = B
35 34 breq2d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ 0 < C → A C ≤ C ⁢ B C ↔ A C ≤ B
36 26 35 bitrd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ 0 < C → A ≤ C ⁢ B ↔ A C ≤ B
37 36 3adant2r ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B ∧ C ∈ ℝ ∧ 0 < C → A ≤ C ⁢ B ↔ A C ≤ B
38 12 20 37 3bitrd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ 0 < B ∧ C ∈ ℝ ∧ 0 < C → A B ≤ C ↔ A C ≤ B