Metamath Proof Explorer


Theorem mhpvscacl

Description: Homogeneous polynomials are closed under scalar multiplication. (Contributed by SN, 25-Sep-2023) Remove closure hypotheses. (Revised by SN, 4-Sep-2025)

Ref Expression
Hypotheses mhpvscacl.h ⊢ H = I mHomP R
mhpvscacl.p ⊢ P = I mPoly R
mhpvscacl.t ⊢ · ˙ = ⋅ P
mhpvscacl.k ⊢ K = Base R
mhpvscacl.r ⊢ φ → R ∈ Ring
mhpvscacl.x ⊢ φ → X ∈ K
mhpvscacl.f ⊢ φ → F ∈ H ⁡ N
Assertion mhpvscacl ⊢ φ → X · ˙ F ∈ H ⁡ N

Proof

Step Hyp Ref Expression
1 mhpvscacl.h ⊢ H = I mHomP R
2 mhpvscacl.p ⊢ P = I mPoly R
3 mhpvscacl.t ⊢ · ˙ = ⋅ P
4 mhpvscacl.k ⊢ K = Base R
5 mhpvscacl.r ⊢ φ → R ∈ Ring
6 mhpvscacl.x ⊢ φ → X ∈ K
7 mhpvscacl.f ⊢ φ → F ∈ H ⁡ N
8 eqid ⊢ Base P = Base P
9 eqid ⊢ 0 R = 0 R
10 eqid ⊢ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin = h ∈ ℕ 0 I | h -1 ℕ ∈ Fin
11 1 7 mhprcl ⊢ φ → N ∈ ℕ 0
12 eqid ⊢ Scalar ⁡ P = Scalar ⁡ P
13 eqid ⊢ Base Scalar ⁡ P = Base Scalar ⁡ P
14 reldmmhp ⊢ Rel ⁡ dom ⁡ mHomP
15 14 1 7 elfvov1 ⊢ φ → I ∈ V
16 2 15 5 mpllmodd ⊢ φ → P ∈ LMod
17 6 4 eleqtrdi ⊢ φ → X ∈ Base R
18 2 15 5 mplsca ⊢ φ → R = Scalar ⁡ P
19 18 fveq2d ⊢ φ → Base R = Base Scalar ⁡ P
20 17 19 eleqtrd ⊢ φ → X ∈ Base Scalar ⁡ P
21 1 2 8 7 mhpmpl ⊢ φ → F ∈ Base P
22 8 12 3 13 16 20 21 lmodvscld ⊢ φ → X · ˙ F ∈ Base P
23 2 4 8 10 22 mplelf ⊢ φ → X · ˙ F : h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ⟶ K
24 eqid ⊢ ⋅ R = ⋅ R
25 6 adantr ⊢ φ ∧ k ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ∖ supp 0 R⁡ F → X ∈ K
26 21 adantr ⊢ φ ∧ k ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ∖ supp 0 R⁡ F → F ∈ Base P
27 eldifi ⊢ k ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ∖ supp 0 R⁡ F → k ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin
28 27 adantl ⊢ φ ∧ k ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ∖ supp 0 R⁡ F → k ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin
29 2 3 4 8 24 10 25 26 28 mplvscaval ⊢ φ ∧ k ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ∖ supp 0 R⁡ F → X · ˙ F ⁡ k = X ⋅ R F ⁡ k
30 2 4 8 10 21 mplelf ⊢ φ → F : h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ⟶ K
31 ssidd ⊢ φ → F supp 0 R ⊆ F supp 0 R
32 fvexd ⊢ φ → 0 R ∈ V
33 30 31 7 32 suppssrg ⊢ φ ∧ k ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ∖ supp 0 R⁡ F → F ⁡ k = 0 R
34 33 oveq2d ⊢ φ ∧ k ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ∖ supp 0 R⁡ F → X ⋅ R F ⁡ k = X ⋅ R 0 R
35 4 24 9 5 6 ringrzd ⊢ φ → X ⋅ R 0 R = 0 R
36 35 adantr ⊢ φ ∧ k ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ∖ supp 0 R⁡ F → X ⋅ R 0 R = 0 R
37 29 34 36 3eqtrd ⊢ φ ∧ k ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ∖ supp 0 R⁡ F → X · ˙ F ⁡ k = 0 R
38 23 37 suppss ⊢ φ → X · ˙ F supp 0 R ⊆ F supp 0 R
39 1 9 10 7 mhpdeg ⊢ φ → F supp 0 R ⊆ g ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin | ∑ ℂ fld ↾ 𝑠 ℕ 0 g = N
40 38 39 sstrd ⊢ φ → X · ˙ F supp 0 R ⊆ g ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin | ∑ ℂ fld ↾ 𝑠 ℕ 0 g = N
41 1 2 8 9 10 11 22 40 ismhp2 ⊢ φ → X · ˙ F ∈ H ⁡ N