Metamath Proof Explorer


Theorem pzriprnglem12

Description: Lemma 12 for pzriprng : Q has a ring unity. (Contributed by AV, 23-Mar-2025)

Ref Expression
Hypotheses pzriprng.r ⊢ R = ℤ ring × 𝑠 ℤ ring
pzriprng.i ⊢ I = ℤ × 0
pzriprng.j ⊢ J = R ↾ 𝑠 I
pzriprng.1 ⊢ 1 ˙ = 1 J
pzriprng.g ⊢ ∼ ˙ = R ~ QG I
pzriprng.q ⊢ Q = R / 𝑠 ∼ ˙
Assertion pzriprnglem12 ⊢ X ∈ Base Q → ℤ × 1 ⋅ Q X = X ∧ X ⋅ Q ℤ × 1 = X

Proof

Step Hyp Ref Expression
1 pzriprng.r ⊢ R = ℤ ring × 𝑠 ℤ ring
2 pzriprng.i ⊢ I = ℤ × 0
3 pzriprng.j ⊢ J = R ↾ 𝑠 I
4 pzriprng.1 ⊢ 1 ˙ = 1 J
5 pzriprng.g ⊢ ∼ ˙ = R ~ QG I
6 pzriprng.q ⊢ Q = R / 𝑠 ∼ ˙
7 1 2 3 4 5 6 pzriprnglem11 ⊢ Base Q = ⋃ y ∈ ℤ ℤ × y
8 7 eleq2i ⊢ X ∈ Base Q ↔ X ∈ ⋃ y ∈ ℤ ℤ × y
9 eliun ⊢ X ∈ ⋃ y ∈ ℤ ℤ × y ↔ ∃ y ∈ ℤ X ∈ ℤ × y
10 8 9 bitri ⊢ X ∈ Base Q ↔ ∃ y ∈ ℤ X ∈ ℤ × y
11 elsni ⊢ X ∈ ℤ × y → X = ℤ × y
12 1z ⊢ 1 ∈ ℤ
13 1 2 3 4 5 pzriprnglem10 ⊢ 1 ∈ ℤ ∧ y ∈ ℤ → 1 y ∼ ˙ = ℤ × y
14 12 13 mpan ⊢ y ∈ ℤ → 1 y ∼ ˙ = ℤ × y
15 14 eqcomd ⊢ y ∈ ℤ → ℤ × y = 1 y ∼ ˙
16 15 eqeq2d ⊢ y ∈ ℤ → X = ℤ × y ↔ X = 1 y ∼ ˙
17 1 pzriprnglem1 ⊢ R ∈ Rng
18 17 a1i ⊢ y ∈ ℤ → R ∈ Rng
19 1 2 3 pzriprnglem8 ⊢ I ∈ 2Ideal ⁡ R
20 19 a1i ⊢ y ∈ ℤ → I ∈ 2Ideal ⁡ R
21 1 2 pzriprnglem4 ⊢ I ∈ SubGrp ⁡ R
22 21 a1i ⊢ y ∈ ℤ → I ∈ SubGrp ⁡ R
23 12 a1i ⊢ y ∈ ℤ → 1 ∈ ℤ
24 23 23 opelxpd ⊢ y ∈ ℤ → 1 1 ∈ ℤ × ℤ
25 id ⊢ y ∈ ℤ → y ∈ ℤ
26 23 25 opelxpd ⊢ y ∈ ℤ → 1 y ∈ ℤ × ℤ
27 1 pzriprnglem2 ⊢ Base R = ℤ × ℤ
28 27 eqcomi ⊢ ℤ × ℤ = Base R
29 eqid ⊢ ⋅ R = ⋅ R
30 eqid ⊢ ⋅ Q = ⋅ Q
31 5 6 28 29 30 qusmulrng ⊢ R ∈ Rng ∧ I ∈ 2Ideal ⁡ R ∧ I ∈ SubGrp ⁡ R ∧ 1 1 ∈ ℤ × ℤ ∧ 1 y ∈ ℤ × ℤ → 1 1 ∼ ˙ ⋅ Q 1 y ∼ ˙ = 1 1 ⋅ R 1 y ∼ ˙
32 18 20 22 24 26 31 syl32anc ⊢ y ∈ ℤ → 1 1 ∼ ˙ ⋅ Q 1 y ∼ ˙ = 1 1 ⋅ R 1 y ∼ ˙
33 zringbas ⊢ ℤ = Base ℤ ring
34 zringring ⊢ ℤ ring ∈ Ring
35 34 a1i ⊢ y ∈ ℤ → ℤ ring ∈ Ring
36 23 23 zmulcld ⊢ y ∈ ℤ → 1 ⋅ 1 ∈ ℤ
37 23 25 zmulcld ⊢ y ∈ ℤ → 1 ⁢ y ∈ ℤ
38 zringmulr ⊢ × = ⋅ ℤ ring
39 1 33 33 35 35 23 23 23 25 36 37 38 38 29 xpsmul ⊢ y ∈ ℤ → 1 1 ⋅ R 1 y = 1 ⋅ 1 1 ⁢ y
40 1cnd ⊢ y ∈ ℤ → 1 ∈ ℂ
41 40 mulridd ⊢ y ∈ ℤ → 1 ⋅ 1 = 1
42 zcn ⊢ y ∈ ℤ → y ∈ ℂ
43 42 mullidd ⊢ y ∈ ℤ → 1 ⁢ y = y
44 41 43 opeq12d ⊢ y ∈ ℤ → 1 ⋅ 1 1 ⁢ y = 1 y
45 39 44 eqtrd ⊢ y ∈ ℤ → 1 1 ⋅ R 1 y = 1 y
46 45 eceq1d ⊢ y ∈ ℤ → 1 1 ⋅ R 1 y ∼ ˙ = 1 y ∼ ˙
47 32 46 eqtrd ⊢ y ∈ ℤ → 1 1 ∼ ˙ ⋅ Q 1 y ∼ ˙ = 1 y ∼ ˙
48 5 6 28 29 30 qusmulrng ⊢ R ∈ Rng ∧ I ∈ 2Ideal ⁡ R ∧ I ∈ SubGrp ⁡ R ∧ 1 y ∈ ℤ × ℤ ∧ 1 1 ∈ ℤ × ℤ → 1 y ∼ ˙ ⋅ Q 1 1 ∼ ˙ = 1 y ⋅ R 1 1 ∼ ˙
49 18 20 22 26 24 48 syl32anc ⊢ y ∈ ℤ → 1 y ∼ ˙ ⋅ Q 1 1 ∼ ˙ = 1 y ⋅ R 1 1 ∼ ˙
50 25 23 zmulcld ⊢ y ∈ ℤ → y ⋅ 1 ∈ ℤ
51 1 33 33 35 35 23 25 23 23 36 50 38 38 29 xpsmul ⊢ y ∈ ℤ → 1 y ⋅ R 1 1 = 1 ⋅ 1 y ⋅ 1
52 42 mulridd ⊢ y ∈ ℤ → y ⋅ 1 = y
53 41 52 opeq12d ⊢ y ∈ ℤ → 1 ⋅ 1 y ⋅ 1 = 1 y
54 51 53 eqtrd ⊢ y ∈ ℤ → 1 y ⋅ R 1 1 = 1 y
55 54 eceq1d ⊢ y ∈ ℤ → 1 y ⋅ R 1 1 ∼ ˙ = 1 y ∼ ˙
56 49 55 eqtrd ⊢ y ∈ ℤ → 1 y ∼ ˙ ⋅ Q 1 1 ∼ ˙ = 1 y ∼ ˙
57 47 56 jca ⊢ y ∈ ℤ → 1 1 ∼ ˙ ⋅ Q 1 y ∼ ˙ = 1 y ∼ ˙ ∧ 1 y ∼ ˙ ⋅ Q 1 1 ∼ ˙ = 1 y ∼ ˙
58 1 2 3 4 5 pzriprnglem10 ⊢ 1 ∈ ℤ ∧ 1 ∈ ℤ → 1 1 ∼ ˙ = ℤ × 1
59 12 12 58 mp2an ⊢ 1 1 ∼ ˙ = ℤ × 1
60 59 eqcomi ⊢ ℤ × 1 = 1 1 ∼ ˙
61 60 a1i ⊢ X = 1 y ∼ ˙ → ℤ × 1 = 1 1 ∼ ˙
62 id ⊢ X = 1 y ∼ ˙ → X = 1 y ∼ ˙
63 61 62 oveq12d ⊢ X = 1 y ∼ ˙ → ℤ × 1 ⋅ Q X = 1 1 ∼ ˙ ⋅ Q 1 y ∼ ˙
64 63 62 eqeq12d ⊢ X = 1 y ∼ ˙ → ℤ × 1 ⋅ Q X = X ↔ 1 1 ∼ ˙ ⋅ Q 1 y ∼ ˙ = 1 y ∼ ˙
65 62 61 oveq12d ⊢ X = 1 y ∼ ˙ → X ⋅ Q ℤ × 1 = 1 y ∼ ˙ ⋅ Q 1 1 ∼ ˙
66 65 62 eqeq12d ⊢ X = 1 y ∼ ˙ → X ⋅ Q ℤ × 1 = X ↔ 1 y ∼ ˙ ⋅ Q 1 1 ∼ ˙ = 1 y ∼ ˙
67 64 66 anbi12d ⊢ X = 1 y ∼ ˙ → ℤ × 1 ⋅ Q X = X ∧ X ⋅ Q ℤ × 1 = X ↔ 1 1 ∼ ˙ ⋅ Q 1 y ∼ ˙ = 1 y ∼ ˙ ∧ 1 y ∼ ˙ ⋅ Q 1 1 ∼ ˙ = 1 y ∼ ˙
68 57 67 syl5ibrcom ⊢ y ∈ ℤ → X = 1 y ∼ ˙ → ℤ × 1 ⋅ Q X = X ∧ X ⋅ Q ℤ × 1 = X
69 16 68 sylbid ⊢ y ∈ ℤ → X = ℤ × y → ℤ × 1 ⋅ Q X = X ∧ X ⋅ Q ℤ × 1 = X
70 11 69 syl5 ⊢ y ∈ ℤ → X ∈ ℤ × y → ℤ × 1 ⋅ Q X = X ∧ X ⋅ Q ℤ × 1 = X
71 70 rexlimiv ⊢ ∃ y ∈ ℤ X ∈ ℤ × y → ℤ × 1 ⋅ Q X = X ∧ X ⋅ Q ℤ × 1 = X
72 10 71 sylbi ⊢ X ∈ Base Q → ℤ × 1 ⋅ Q X = X ∧ X ⋅ Q ℤ × 1 = X