Metamath Proof Explorer


Theorem pzriprnglem4

Description: Lemma 4 for pzriprng : I is a subgroup of R . (Contributed by AV, 18-Mar-2025)

Ref Expression
Hypotheses pzriprng.r ⊢ R = ℤ ring × 𝑠 ℤ ring
pzriprng.i ⊢ I = ℤ × 0
Assertion pzriprnglem4 ⊢ I ∈ SubGrp ⁡ R

Proof

Step Hyp Ref Expression
1 pzriprng.r ⊢ R = ℤ ring × 𝑠 ℤ ring
2 pzriprng.i ⊢ I = ℤ × 0
3 0z ⊢ 0 ∈ ℤ
4 c0ex ⊢ 0 ∈ V
5 4 snss ⊢ 0 ∈ ℤ ↔ 0 ⊆ ℤ
6 3 5 mpbi ⊢ 0 ⊆ ℤ
7 xpss2 ⊢ 0 ⊆ ℤ → ℤ × 0 ⊆ ℤ × ℤ
8 6 7 ax-mp ⊢ ℤ × 0 ⊆ ℤ × ℤ
9 1 pzriprnglem2 ⊢ Base R = ℤ × ℤ
10 8 2 9 3sstr4i ⊢ I ⊆ Base R
11 3 ne0ii ⊢ ℤ ≠ ∅
12 4 snnz ⊢ 0 ≠ ∅
13 11 12 pm3.2i ⊢ ℤ ≠ ∅ ∧ 0 ≠ ∅
14 xpnz ⊢ ℤ ≠ ∅ ∧ 0 ≠ ∅ ↔ ℤ × 0 ≠ ∅
15 13 14 mpbi ⊢ ℤ × 0 ≠ ∅
16 2 15 eqnetri ⊢ I ≠ ∅
17 1 2 pzriprnglem3 ⊢ x ∈ I ↔ ∃ a ∈ ℤ x = a 0
18 1 2 pzriprnglem3 ⊢ y ∈ I ↔ ∃ b ∈ ℤ y = b 0
19 simpr ⊢ a ∈ ℤ ∧ x = a 0 → x = a 0
20 19 adantr ⊢ a ∈ ℤ ∧ x = a 0 ∧ b ∈ ℤ → x = a 0
21 id ⊢ y = b 0 → y = b 0
22 20 21 oveqan12d ⊢ a ∈ ℤ ∧ x = a 0 ∧ b ∈ ℤ ∧ y = b 0 → x + R y = a 0 + R b 0
23 zringbas ⊢ ℤ = Base ℤ ring
24 zringring ⊢ ℤ ring ∈ Ring
25 24 a1i ⊢ a ∈ ℤ ∧ b ∈ ℤ → ℤ ring ∈ Ring
26 simpl ⊢ a ∈ ℤ ∧ b ∈ ℤ → a ∈ ℤ
27 3 a1i ⊢ a ∈ ℤ ∧ b ∈ ℤ → 0 ∈ ℤ
28 simpr ⊢ a ∈ ℤ ∧ b ∈ ℤ → b ∈ ℤ
29 zaddcl ⊢ a ∈ ℤ ∧ b ∈ ℤ → a + b ∈ ℤ
30 00id ⊢ 0 + 0 = 0
31 30 3 eqeltri ⊢ 0 + 0 ∈ ℤ
32 31 a1i ⊢ a ∈ ℤ ∧ b ∈ ℤ → 0 + 0 ∈ ℤ
33 zringplusg ⊢ + = + ℤ ring
34 eqid ⊢ + R = + R
35 1 23 23 25 25 26 27 28 27 29 32 33 33 34 xpsadd ⊢ a ∈ ℤ ∧ b ∈ ℤ → a 0 + R b 0 = a + b 0 + 0
36 4 snid ⊢ 0 ∈ 0
37 30 36 eqeltri ⊢ 0 + 0 ∈ 0
38 2 eleq2i ⊢ a + b 0 + 0 ∈ I ↔ a + b 0 + 0 ∈ ℤ × 0
39 opelxp ⊢ a + b 0 + 0 ∈ ℤ × 0 ↔ a + b ∈ ℤ ∧ 0 + 0 ∈ 0
40 38 39 bitri ⊢ a + b 0 + 0 ∈ I ↔ a + b ∈ ℤ ∧ 0 + 0 ∈ 0
41 29 37 40 sylanblrc ⊢ a ∈ ℤ ∧ b ∈ ℤ → a + b 0 + 0 ∈ I
42 35 41 eqeltrd ⊢ a ∈ ℤ ∧ b ∈ ℤ → a 0 + R b 0 ∈ I
43 42 ad4ant13 ⊢ a ∈ ℤ ∧ x = a 0 ∧ b ∈ ℤ ∧ y = b 0 → a 0 + R b 0 ∈ I
44 22 43 eqeltrd ⊢ a ∈ ℤ ∧ x = a 0 ∧ b ∈ ℤ ∧ y = b 0 → x + R y ∈ I
45 44 rexlimdva2 ⊢ a ∈ ℤ ∧ x = a 0 → ∃ b ∈ ℤ y = b 0 → x + R y ∈ I
46 18 45 biimtrid ⊢ a ∈ ℤ ∧ x = a 0 → y ∈ I → x + R y ∈ I
47 46 ralrimiv ⊢ a ∈ ℤ ∧ x = a 0 → ∀ y ∈ I x + R y ∈ I
48 zringgrp ⊢ ℤ ring ∈ Grp
49 48 a1i ⊢ a ∈ ℤ → ℤ ring ∈ Grp
50 id ⊢ a ∈ ℤ → a ∈ ℤ
51 3 a1i ⊢ a ∈ ℤ → 0 ∈ ℤ
52 eqid ⊢ inv g ⁡ ℤ ring = inv g ⁡ ℤ ring
53 eqid ⊢ inv g ⁡ R = inv g ⁡ R
54 1 23 23 49 49 50 51 52 52 53 xpsinv ⊢ a ∈ ℤ → inv g ⁡ R ⁡ a 0 = inv g ⁡ ℤ ring ⁡ a inv g ⁡ ℤ ring ⁡ 0
55 zringinvg ⊢ a ∈ ℤ → − a = inv g ⁡ ℤ ring ⁡ a
56 znegcl ⊢ a ∈ ℤ → − a ∈ ℤ
57 55 56 eqeltrrd ⊢ a ∈ ℤ → inv g ⁡ ℤ ring ⁡ a ∈ ℤ
58 neg0 ⊢ − 0 = 0
59 58 36 eqeltri ⊢ − 0 ∈ 0
60 zringinvg ⊢ 0 ∈ ℤ → − 0 = inv g ⁡ ℤ ring ⁡ 0
61 60 eleq1d ⊢ 0 ∈ ℤ → − 0 ∈ 0 ↔ inv g ⁡ ℤ ring ⁡ 0 ∈ 0
62 3 61 mp1i ⊢ a ∈ ℤ → − 0 ∈ 0 ↔ inv g ⁡ ℤ ring ⁡ 0 ∈ 0
63 59 62 mpbii ⊢ a ∈ ℤ → inv g ⁡ ℤ ring ⁡ 0 ∈ 0
64 57 63 opelxpd ⊢ a ∈ ℤ → inv g ⁡ ℤ ring ⁡ a inv g ⁡ ℤ ring ⁡ 0 ∈ ℤ × 0
65 54 64 eqeltrd ⊢ a ∈ ℤ → inv g ⁡ R ⁡ a 0 ∈ ℤ × 0
66 65 adantr ⊢ a ∈ ℤ ∧ x = a 0 → inv g ⁡ R ⁡ a 0 ∈ ℤ × 0
67 fveq2 ⊢ x = a 0 → inv g ⁡ R ⁡ x = inv g ⁡ R ⁡ a 0
68 67 adantl ⊢ a ∈ ℤ ∧ x = a 0 → inv g ⁡ R ⁡ x = inv g ⁡ R ⁡ a 0
69 2 a1i ⊢ a ∈ ℤ ∧ x = a 0 → I = ℤ × 0
70 66 68 69 3eltr4d ⊢ a ∈ ℤ ∧ x = a 0 → inv g ⁡ R ⁡ x ∈ I
71 47 70 jca ⊢ a ∈ ℤ ∧ x = a 0 → ∀ y ∈ I x + R y ∈ I ∧ inv g ⁡ R ⁡ x ∈ I
72 71 rexlimiva ⊢ ∃ a ∈ ℤ x = a 0 → ∀ y ∈ I x + R y ∈ I ∧ inv g ⁡ R ⁡ x ∈ I
73 17 72 sylbi ⊢ x ∈ I → ∀ y ∈ I x + R y ∈ I ∧ inv g ⁡ R ⁡ x ∈ I
74 73 rgen ⊢ ∀ x ∈ I ∀ y ∈ I x + R y ∈ I ∧ inv g ⁡ R ⁡ x ∈ I
75 1 pzriprnglem1 ⊢ R ∈ Rng
76 rnggrp ⊢ R ∈ Rng → R ∈ Grp
77 75 76 ax-mp ⊢ R ∈ Grp
78 eqid ⊢ Base R = Base R
79 78 34 53 issubg2 ⊢ R ∈ Grp → I ∈ SubGrp ⁡ R ↔ I ⊆ Base R ∧ I ≠ ∅ ∧ ∀ x ∈ I ∀ y ∈ I x + R y ∈ I ∧ inv g ⁡ R ⁡ x ∈ I
80 77 79 ax-mp ⊢ I ∈ SubGrp ⁡ R ↔ I ⊆ Base R ∧ I ≠ ∅ ∧ ∀ x ∈ I ∀ y ∈ I x + R y ∈ I ∧ inv g ⁡ R ⁡ x ∈ I
81 10 16 74 80 mpbir3an ⊢ I ∈ SubGrp ⁡ R