Metamath Proof Explorer


Theorem ballotlemfrcn0

Description: Value of F for a reversed counting ( RC ) , before the first tie, cannot be zero . (Contributed by Thierry Arnoux, 25-Apr-2017) (Revised by AV, 6-Oct-2020)

Ref Expression
Hypotheses ballotth.m M
ballotth.n N
ballotth.o O = c 𝒫 1 M + N | c = M
ballotth.p P = x 𝒫 O x O
ballotth.f F = c O i 1 i c 1 i c
ballotth.e E = c O | i 1 M + N 0 < F c i
ballotth.mgtn N < M
ballotth.i I = c O E sup k 1 M + N | F c k = 0 <
ballotth.s S = c O E i 1 M + N if i I c I c + 1 - i i
ballotth.r R = c O E S c c
Assertion ballotlemfrcn0 C O E J 1 M + N J < I C F R C J 0

Proof

Step Hyp Ref Expression
1 ballotth.m M
2 ballotth.n N
3 ballotth.o O = c 𝒫 1 M + N | c = M
4 ballotth.p P = x 𝒫 O x O
5 ballotth.f F = c O i 1 i c 1 i c
6 ballotth.e E = c O | i 1 M + N 0 < F c i
7 ballotth.mgtn N < M
8 ballotth.i I = c O E sup k 1 M + N | F c k = 0 <
9 ballotth.s S = c O E i 1 M + N if i I c I c + 1 - i i
10 ballotth.r R = c O E S c c
11 1zzd C O E J 1 M + N J < I C 1
12 nnaddcl M N M + N
13 1 2 12 mp2an M + N
14 13 nnzi M + N
15 14 a1i C O E J 1 M + N J < I C M + N
16 1 2 3 4 5 6 7 8 9 ballotlemsdom C O E J 1 M + N S C J 1 M + N
17 elfzelz S C J 1 M + N S C J
18 16 17 syl C O E J 1 M + N S C J
19 18 3adant3 C O E J 1 M + N J < I C S C J
20 19 11 zsubcld C O E J 1 M + N J < I C S C J 1
21 1 2 3 4 5 6 7 8 9 ballotlemsgt1 C O E J 1 M + N J < I C 1 < S C J
22 zltlem1 1 S C J 1 < S C J 1 S C J 1
23 22 biimpa 1 S C J 1 < S C J 1 S C J 1
24 11 19 21 23 syl21anc C O E J 1 M + N J < I C 1 S C J 1
25 19 zred C O E J 1 M + N J < I C S C J
26 1red C O E J 1 M + N J < I C 1
27 25 26 resubcld C O E J 1 M + N J < I C S C J 1
28 simp1 C O E J 1 M + N J < I C C O E
29 1 2 3 4 5 6 7 8 ballotlemiex C O E I C 1 M + N F C I C = 0
30 29 simpld C O E I C 1 M + N
31 elfzelz I C 1 M + N I C
32 28 30 31 3syl C O E J 1 M + N J < I C I C
33 32 zred C O E J 1 M + N J < I C I C
34 15 zred C O E J 1 M + N J < I C M + N
35 elfzelz J 1 M + N J
36 35 3ad2ant2 C O E J 1 M + N J < I C J
37 elfzle1 J 1 M + N 1 J
38 37 3ad2ant2 C O E J 1 M + N J < I C 1 J
39 36 zred C O E J 1 M + N J < I C J
40 simp3 C O E J 1 M + N J < I C J < I C
41 39 33 40 ltled C O E J 1 M + N J < I C J I C
42 elfz4 1 I C J 1 J J I C J 1 I C
43 11 32 36 38 41 42 syl32anc C O E J 1 M + N J < I C J 1 I C
44 1 2 3 4 5 6 7 8 9 ballotlemsel1i C O E J 1 I C S C J 1 I C
45 28 43 44 syl2anc C O E J 1 M + N J < I C S C J 1 I C
46 elfzle2 S C J 1 I C S C J I C
47 45 46 syl C O E J 1 M + N J < I C S C J I C
48 zlem1lt S C J I C S C J I C S C J 1 < I C
49 19 32 48 syl2anc C O E J 1 M + N J < I C S C J I C S C J 1 < I C
50 47 49 mpbid C O E J 1 M + N J < I C S C J 1 < I C
51 27 33 50 ltled C O E J 1 M + N J < I C S C J 1 I C
52 elfzle2 I C 1 M + N I C M + N
53 28 30 52 3syl C O E J 1 M + N J < I C I C M + N
54 27 33 34 51 53 letrd C O E J 1 M + N J < I C S C J 1 M + N
55 elfz4 1 M + N S C J 1 1 S C J 1 S C J 1 M + N S C J 1 1 M + N
56 11 15 20 24 54 55 syl32anc C O E J 1 M + N J < I C S C J 1 1 M + N
57 biid S C J 1 < I C S C J 1 < I C
58 50 57 sylibr C O E J 1 M + N J < I C S C J 1 < I C
59 1 2 3 4 5 6 7 8 ballotlemi C O E I C = sup k 1 M + N | F C k = 0 <
60 59 breq2d C O E S C J 1 < I C S C J 1 < sup k 1 M + N | F C k = 0 <
61 60 3ad2ant1 C O E J 1 M + N J < I C S C J 1 < I C S C J 1 < sup k 1 M + N | F C k = 0 <
62 58 61 mpbid C O E J 1 M + N J < I C S C J 1 < sup k 1 M + N | F C k = 0 <
63 ltso < Or
64 63 a1i C O E < Or
65 1 2 3 4 5 6 7 8 ballotlemsup C O E z w k 1 M + N | F C k = 0 ¬ w < z w z < w y k 1 M + N | F C k = 0 y < w
66 64 65 inflb C O E S C J 1 k 1 M + N | F C k = 0 ¬ S C J 1 < sup k 1 M + N | F C k = 0 <
67 66 con2d C O E S C J 1 < sup k 1 M + N | F C k = 0 < ¬ S C J 1 k 1 M + N | F C k = 0
68 28 62 67 sylc C O E J 1 M + N J < I C ¬ S C J 1 k 1 M + N | F C k = 0
69 fveqeq2 k = S C J 1 F C k = 0 F C S C J 1 = 0
70 69 elrab S C J 1 k 1 M + N | F C k = 0 S C J 1 1 M + N F C S C J 1 = 0
71 68 70 sylnib C O E J 1 M + N J < I C ¬ S C J 1 1 M + N F C S C J 1 = 0
72 imnan S C J 1 1 M + N ¬ F C S C J 1 = 0 ¬ S C J 1 1 M + N F C S C J 1 = 0
73 71 72 sylibr C O E J 1 M + N J < I C S C J 1 1 M + N ¬ F C S C J 1 = 0
74 56 73 mpd C O E J 1 M + N J < I C ¬ F C S C J 1 = 0
75 74 neqned C O E J 1 M + N J < I C F C S C J 1 0
76 1 2 3 4 5 6 7 8 9 10 ballotlemro C O E R C O
77 76 adantr C O E J 1 I C R C O
78 elfzelz J 1 I C J
79 78 adantl C O E J 1 I C J
80 1 2 3 4 5 77 79 ballotlemfelz C O E J 1 I C F R C J
81 80 zcnd C O E J 1 I C F R C J
82 81 negeq0d C O E J 1 I C F R C J = 0 F R C J = 0
83 eqid u Fin , v Fin v u v u = u Fin , v Fin v u v u
84 1 2 3 4 5 6 7 8 9 10 83 ballotlemfrceq C O E J 1 I C F C S C J 1 = F R C J
85 84 eqeq1d C O E J 1 I C F C S C J 1 = 0 F R C J = 0
86 82 85 bitr4d C O E J 1 I C F R C J = 0 F C S C J 1 = 0
87 86 necon3bid C O E J 1 I C F R C J 0 F C S C J 1 0
88 28 43 87 syl2anc C O E J 1 M + N J < I C F R C J 0 F C S C J 1 0
89 75 88 mpbird C O E J 1 M + N J < I C F R C J 0