Metamath Proof Explorer


Theorem brimg

Description: Binary relation form of the Img function. (Contributed by Scott Fenton, 12-Apr-2014) (Revised by Mario Carneiro, 19-Apr-2014) (Proof shortened by Peter Mazsa, 2-Oct-2022)

Ref Expression
Hypotheses brimg.1 ⊢ A ∈ V
brimg.2 ⊢ B ∈ V
brimg.3 ⊢ C ∈ V
Assertion brimg ⊢ A B 𝖨𝗆𝗀 C ↔ C = A B

Proof

Step Hyp Ref Expression
1 brimg.1 ⊢ A ∈ V
2 brimg.2 ⊢ B ∈ V
3 brimg.3 ⊢ C ∈ V
4 df-img ⊢ 𝖨𝗆𝗀 = 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V ∘ 𝖢𝖺𝗋𝗍
5 4 breqi ⊢ A B 𝖨𝗆𝗀 C ↔ A B 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V ∘ 𝖢𝖺𝗋𝗍 C
6 opex ⊢ A B ∈ V
7 6 3 brco ⊢ A B 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V ∘ 𝖢𝖺𝗋𝗍 C ↔ ∃ a A B 𝖢𝖺𝗋𝗍 a ∧ a 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V C
8 vex ⊢ a ∈ V
9 1 2 8 brcart ⊢ A B 𝖢𝖺𝗋𝗍 a ↔ a = A × B
10 9 anbi1i ⊢ A B 𝖢𝖺𝗋𝗍 a ∧ a 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V C ↔ a = A × B ∧ a 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V C
11 10 exbii ⊢ ∃ a A B 𝖢𝖺𝗋𝗍 a ∧ a 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V C ↔ ∃ a a = A × B ∧ a 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V C
12 1 2 xpex ⊢ A × B ∈ V
13 breq1 ⊢ a = A × B → a 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V C ↔ A × B 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V C
14 12 13 ceqsexv ⊢ ∃ a a = A × B ∧ a 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V C ↔ A × B 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V C
15 7 11 14 3bitri ⊢ A B 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V ∘ 𝖢𝖺𝗋𝗍 C ↔ A × B 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V C
16 12 3 brimage ⊢ A × B 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V C ↔ C = 2 nd ∘ 1 st ↾ 1 st ↾ V × V A × B
17 19.42v ⊢ ∃ a b ∈ B ∧ a ∈ A ∧ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ b ∈ B ∧ ∃ a a ∈ A ∧ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
18 anass ⊢ p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
19 an21 ⊢ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ b ∈ B ∧ a ∈ A ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
20 19 anbi2i ⊢ p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ p = a b ∧ b ∈ B ∧ a ∈ A ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
21 18 20 bitri ⊢ p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ p = a b ∧ b ∈ B ∧ a ∈ A ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
22 21 2exbii ⊢ ∃ p ∃ a p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ ∃ p ∃ a p = a b ∧ b ∈ B ∧ a ∈ A ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
23 excom ⊢ ∃ p ∃ a p = a b ∧ b ∈ B ∧ a ∈ A ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ ∃ a ∃ p p = a b ∧ b ∈ B ∧ a ∈ A ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
24 opex ⊢ a b ∈ V
25 breq1 ⊢ p = a b → p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
26 25 anbi2d ⊢ p = a b → a ∈ A ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ a ∈ A ∧ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
27 26 anbi2d ⊢ p = a b → b ∈ B ∧ a ∈ A ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ b ∈ B ∧ a ∈ A ∧ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
28 24 27 ceqsexv ⊢ ∃ p p = a b ∧ b ∈ B ∧ a ∈ A ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ b ∈ B ∧ a ∈ A ∧ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
29 28 exbii ⊢ ∃ a ∃ p p = a b ∧ b ∈ B ∧ a ∈ A ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ ∃ a b ∈ B ∧ a ∈ A ∧ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
30 22 23 29 3bitri ⊢ ∃ p ∃ a p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ ∃ a b ∈ B ∧ a ∈ A ∧ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
31 df-br ⊢ b A x ↔ b x ∈ A
32 risset ⊢ b x ∈ A ↔ ∃ a ∈ A a = b x
33 vex ⊢ b ∈ V
34 33 brresi ⊢ a 1 st ↾ V × V b ↔ a ∈ V × V ∧ a 1 st b
35 df-br ⊢ a 1 st ↾ V × V b ↔ a b ∈ 1 st ↾ V × V
36 34 35 bitr3i ⊢ a ∈ V × V ∧ a 1 st b ↔ a b ∈ 1 st ↾ V × V
37 36 anbi1i ⊢ a ∈ V × V ∧ a 1 st b ∧ a b 2 nd ∘ 1 st x ↔ a b ∈ 1 st ↾ V × V ∧ a b 2 nd ∘ 1 st x
38 elvv ⊢ a ∈ V × V ↔ ∃ p ∃ q a = p q
39 38 anbi1i ⊢ a ∈ V × V ∧ a 1 st b ∧ a b 2 nd ∘ 1 st x ↔ ∃ p ∃ q a = p q ∧ a 1 st b ∧ a b 2 nd ∘ 1 st x
40 anass ⊢ a ∈ V × V ∧ a 1 st b ∧ a b 2 nd ∘ 1 st x ↔ a ∈ V × V ∧ a 1 st b ∧ a b 2 nd ∘ 1 st x
41 ancom ⊢ a = p q ∧ p = b ∧ q = x ↔ p = b ∧ q = x ∧ a = p q
42 breq1 ⊢ a = p q → a 1 st b ↔ p q 1 st b
43 opeq1 ⊢ a = p q → a b = p q b
44 43 breq1d ⊢ a = p q → a b 2 nd ∘ 1 st x ↔ p q b 2 nd ∘ 1 st x
45 42 44 anbi12d ⊢ a = p q → a 1 st b ∧ a b 2 nd ∘ 1 st x ↔ p q 1 st b ∧ p q b 2 nd ∘ 1 st x
46 vex ⊢ p ∈ V
47 vex ⊢ q ∈ V
48 46 47 br1steq ⊢ p q 1 st b ↔ b = p
49 equcom ⊢ b = p ↔ p = b
50 48 49 bitri ⊢ p q 1 st b ↔ p = b
51 opex ⊢ p q b ∈ V
52 vex ⊢ x ∈ V
53 51 52 brco ⊢ p q b 2 nd ∘ 1 st x ↔ ∃ a p q b 1 st a ∧ a 2 nd x
54 opex ⊢ p q ∈ V
55 54 33 br1steq ⊢ p q b 1 st a ↔ a = p q
56 55 anbi1i ⊢ p q b 1 st a ∧ a 2 nd x ↔ a = p q ∧ a 2 nd x
57 56 exbii ⊢ ∃ a p q b 1 st a ∧ a 2 nd x ↔ ∃ a a = p q ∧ a 2 nd x
58 53 57 bitri ⊢ p q b 2 nd ∘ 1 st x ↔ ∃ a a = p q ∧ a 2 nd x
59 breq1 ⊢ a = p q → a 2 nd x ↔ p q 2 nd x
60 54 59 ceqsexv ⊢ ∃ a a = p q ∧ a 2 nd x ↔ p q 2 nd x
61 46 47 br2ndeq ⊢ p q 2 nd x ↔ x = q
62 60 61 bitri ⊢ ∃ a a = p q ∧ a 2 nd x ↔ x = q
63 equcom ⊢ x = q ↔ q = x
64 58 62 63 3bitri ⊢ p q b 2 nd ∘ 1 st x ↔ q = x
65 50 64 anbi12i ⊢ p q 1 st b ∧ p q b 2 nd ∘ 1 st x ↔ p = b ∧ q = x
66 45 65 bitrdi ⊢ a = p q → a 1 st b ∧ a b 2 nd ∘ 1 st x ↔ p = b ∧ q = x
67 66 pm5.32i ⊢ a = p q ∧ a 1 st b ∧ a b 2 nd ∘ 1 st x ↔ a = p q ∧ p = b ∧ q = x
68 df-3an ⊢ p = b ∧ q = x ∧ a = p q ↔ p = b ∧ q = x ∧ a = p q
69 41 67 68 3bitr4i ⊢ a = p q ∧ a 1 st b ∧ a b 2 nd ∘ 1 st x ↔ p = b ∧ q = x ∧ a = p q
70 69 2exbii ⊢ ∃ p ∃ q a = p q ∧ a 1 st b ∧ a b 2 nd ∘ 1 st x ↔ ∃ p ∃ q p = b ∧ q = x ∧ a = p q
71 19.41vv ⊢ ∃ p ∃ q a = p q ∧ a 1 st b ∧ a b 2 nd ∘ 1 st x ↔ ∃ p ∃ q a = p q ∧ a 1 st b ∧ a b 2 nd ∘ 1 st x
72 opeq1 ⊢ p = b → p q = b q
73 72 eqeq2d ⊢ p = b → a = p q ↔ a = b q
74 opeq2 ⊢ q = x → b q = b x
75 74 eqeq2d ⊢ q = x → a = b q ↔ a = b x
76 33 52 73 75 ceqsex2v ⊢ ∃ p ∃ q p = b ∧ q = x ∧ a = p q ↔ a = b x
77 70 71 76 3bitr3ri ⊢ a = b x ↔ ∃ p ∃ q a = p q ∧ a 1 st b ∧ a b 2 nd ∘ 1 st x
78 39 40 77 3bitr4ri ⊢ a = b x ↔ a ∈ V × V ∧ a 1 st b ∧ a b 2 nd ∘ 1 st x
79 52 brresi ⊢ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ a b ∈ 1 st ↾ V × V ∧ a b 2 nd ∘ 1 st x
80 37 78 79 3bitr4i ⊢ a = b x ↔ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
81 80 rexbii ⊢ ∃ a ∈ A a = b x ↔ ∃ a ∈ A a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
82 32 81 bitri ⊢ b x ∈ A ↔ ∃ a ∈ A a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
83 df-rex ⊢ ∃ a ∈ A a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ ∃ a a ∈ A ∧ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
84 31 82 83 3bitri ⊢ b A x ↔ ∃ a a ∈ A ∧ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
85 84 anbi2i ⊢ b ∈ B ∧ b A x ↔ b ∈ B ∧ ∃ a a ∈ A ∧ a b 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
86 17 30 85 3bitr4ri ⊢ b ∈ B ∧ b A x ↔ ∃ p ∃ a p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
87 86 exbii ⊢ ∃ b b ∈ B ∧ b A x ↔ ∃ b ∃ p ∃ a p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
88 52 elima2 ⊢ x ∈ A B ↔ ∃ b b ∈ B ∧ b A x
89 52 elima2 ⊢ x ∈ 2 nd ∘ 1 st ↾ 1 st ↾ V × V A × B ↔ ∃ p p ∈ A × B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
90 elxp ⊢ p ∈ A × B ↔ ∃ a ∃ b p = a b ∧ a ∈ A ∧ b ∈ B
91 90 anbi1i ⊢ p ∈ A × B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ ∃ a ∃ b p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
92 19.41vv ⊢ ∃ a ∃ b p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ ∃ a ∃ b p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
93 91 92 bitr4i ⊢ p ∈ A × B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ ∃ a ∃ b p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
94 93 exbii ⊢ ∃ p p ∈ A × B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ ∃ p ∃ a ∃ b p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
95 exrot3 ⊢ ∃ p ∃ a ∃ b p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ ∃ a ∃ b ∃ p p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
96 exrot3 ⊢ ∃ a ∃ b ∃ p p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ ∃ b ∃ p ∃ a p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
97 95 96 bitri ⊢ ∃ p ∃ a ∃ b p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x ↔ ∃ b ∃ p ∃ a p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
98 89 94 97 3bitri ⊢ x ∈ 2 nd ∘ 1 st ↾ 1 st ↾ V × V A × B ↔ ∃ b ∃ p ∃ a p = a b ∧ a ∈ A ∧ b ∈ B ∧ p 2 nd ∘ 1 st ↾ 1 st ↾ V × V x
99 87 88 98 3bitr4ri ⊢ x ∈ 2 nd ∘ 1 st ↾ 1 st ↾ V × V A × B ↔ x ∈ A B
100 99 eqriv ⊢ 2 nd ∘ 1 st ↾ 1 st ↾ V × V A × B = A B
101 100 eqeq2i ⊢ C = 2 nd ∘ 1 st ↾ 1 st ↾ V × V A × B ↔ C = A B
102 16 101 bitri ⊢ A × B 𝖨𝗆𝖺𝗀𝖾 2 nd ∘ 1 st ↾ 1 st ↾ V × V C ↔ C = A B
103 5 15 102 3bitri ⊢ A B 𝖨𝗆𝗀 C ↔ C = A B