Metamath Proof Explorer


Theorem dif1ennnALT

Description: Alternate proof of dif1ennn using ax-pow . (Contributed by Jeff Madsen, 2-Sep-2009) (Revised by Stefan O'Rear, 16-Aug-2015) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion dif1ennnALT ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ X ∈ A → A ∖ X ≈ M

Proof

Step Hyp Ref Expression
1 peano2 ⊢ M ∈ ω → suc ⁡ M ∈ ω
2 breq2 ⊢ x = suc ⁡ M → A ≈ x ↔ A ≈ suc ⁡ M
3 2 rspcev ⊢ suc ⁡ M ∈ ω ∧ A ≈ suc ⁡ M → ∃ x ∈ ω A ≈ x
4 isfi ⊢ A ∈ Fin ↔ ∃ x ∈ ω A ≈ x
5 3 4 sylibr ⊢ suc ⁡ M ∈ ω ∧ A ≈ suc ⁡ M → A ∈ Fin
6 1 5 sylan ⊢ M ∈ ω ∧ A ≈ suc ⁡ M → A ∈ Fin
7 diffi ⊢ A ∈ Fin → A ∖ X ∈ Fin
8 isfi ⊢ A ∖ X ∈ Fin ↔ ∃ x ∈ ω A ∖ X ≈ x
9 7 8 sylib ⊢ A ∈ Fin → ∃ x ∈ ω A ∖ X ≈ x
10 6 9 syl ⊢ M ∈ ω ∧ A ≈ suc ⁡ M → ∃ x ∈ ω A ∖ X ≈ x
11 10 3adant3 ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ X ∈ A → ∃ x ∈ ω A ∖ X ≈ x
12 en2sn ⊢ X ∈ A ∧ x ∈ V → X ≈ x
13 12 elvd ⊢ X ∈ A → X ≈ x
14 nnord ⊢ x ∈ ω → Ord ⁡ x
15 orddisj ⊢ Ord ⁡ x → x ∩ x = ∅
16 14 15 syl ⊢ x ∈ ω → x ∩ x = ∅
17 incom ⊢ A ∖ X ∩ X = X ∩ A ∖ X
18 disjdif ⊢ X ∩ A ∖ X = ∅
19 17 18 eqtri ⊢ A ∖ X ∩ X = ∅
20 unen ⊢ A ∖ X ≈ x ∧ X ≈ x ∧ A ∖ X ∩ X = ∅ ∧ x ∩ x = ∅ → A ∖ X ∪ X ≈ x ∪ x
21 20 an4s ⊢ A ∖ X ≈ x ∧ A ∖ X ∩ X = ∅ ∧ X ≈ x ∧ x ∩ x = ∅ → A ∖ X ∪ X ≈ x ∪ x
22 19 21 mpanl2 ⊢ A ∖ X ≈ x ∧ X ≈ x ∧ x ∩ x = ∅ → A ∖ X ∪ X ≈ x ∪ x
23 22 expcom ⊢ X ≈ x ∧ x ∩ x = ∅ → A ∖ X ≈ x → A ∖ X ∪ X ≈ x ∪ x
24 13 16 23 syl2an ⊢ X ∈ A ∧ x ∈ ω → A ∖ X ≈ x → A ∖ X ∪ X ≈ x ∪ x
25 24 3ad2antl3 ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ X ∈ A ∧ x ∈ ω → A ∖ X ≈ x → A ∖ X ∪ X ≈ x ∪ x
26 difsnid ⊢ X ∈ A → A ∖ X ∪ X = A
27 df-suc ⊢ suc ⁡ x = x ∪ x
28 27 eqcomi ⊢ x ∪ x = suc ⁡ x
29 28 a1i ⊢ X ∈ A → x ∪ x = suc ⁡ x
30 26 29 breq12d ⊢ X ∈ A → A ∖ X ∪ X ≈ x ∪ x ↔ A ≈ suc ⁡ x
31 30 3ad2ant3 ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ X ∈ A → A ∖ X ∪ X ≈ x ∪ x ↔ A ≈ suc ⁡ x
32 31 adantr ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ X ∈ A ∧ x ∈ ω → A ∖ X ∪ X ≈ x ∪ x ↔ A ≈ suc ⁡ x
33 ensym ⊢ A ≈ suc ⁡ M → suc ⁡ M ≈ A
34 entr ⊢ suc ⁡ M ≈ A ∧ A ≈ suc ⁡ x → suc ⁡ M ≈ suc ⁡ x
35 peano2 ⊢ x ∈ ω → suc ⁡ x ∈ ω
36 nneneq ⊢ suc ⁡ M ∈ ω ∧ suc ⁡ x ∈ ω → suc ⁡ M ≈ suc ⁡ x ↔ suc ⁡ M = suc ⁡ x
37 35 36 sylan2 ⊢ suc ⁡ M ∈ ω ∧ x ∈ ω → suc ⁡ M ≈ suc ⁡ x ↔ suc ⁡ M = suc ⁡ x
38 34 37 imbitrid ⊢ suc ⁡ M ∈ ω ∧ x ∈ ω → suc ⁡ M ≈ A ∧ A ≈ suc ⁡ x → suc ⁡ M = suc ⁡ x
39 38 expd ⊢ suc ⁡ M ∈ ω ∧ x ∈ ω → suc ⁡ M ≈ A → A ≈ suc ⁡ x → suc ⁡ M = suc ⁡ x
40 33 39 syl5 ⊢ suc ⁡ M ∈ ω ∧ x ∈ ω → A ≈ suc ⁡ M → A ≈ suc ⁡ x → suc ⁡ M = suc ⁡ x
41 1 40 sylan ⊢ M ∈ ω ∧ x ∈ ω → A ≈ suc ⁡ M → A ≈ suc ⁡ x → suc ⁡ M = suc ⁡ x
42 41 imp ⊢ M ∈ ω ∧ x ∈ ω ∧ A ≈ suc ⁡ M → A ≈ suc ⁡ x → suc ⁡ M = suc ⁡ x
43 42 an32s ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ x ∈ ω → A ≈ suc ⁡ x → suc ⁡ M = suc ⁡ x
44 43 3adantl3 ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ X ∈ A ∧ x ∈ ω → A ≈ suc ⁡ x → suc ⁡ M = suc ⁡ x
45 32 44 sylbid ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ X ∈ A ∧ x ∈ ω → A ∖ X ∪ X ≈ x ∪ x → suc ⁡ M = suc ⁡ x
46 peano4 ⊢ M ∈ ω ∧ x ∈ ω → suc ⁡ M = suc ⁡ x ↔ M = x
47 46 biimpd ⊢ M ∈ ω ∧ x ∈ ω → suc ⁡ M = suc ⁡ x → M = x
48 47 3ad2antl1 ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ X ∈ A ∧ x ∈ ω → suc ⁡ M = suc ⁡ x → M = x
49 25 45 48 3syld ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ X ∈ A ∧ x ∈ ω → A ∖ X ≈ x → M = x
50 breq2 ⊢ M = x → A ∖ X ≈ M ↔ A ∖ X ≈ x
51 50 biimprcd ⊢ A ∖ X ≈ x → M = x → A ∖ X ≈ M
52 49 51 sylcom ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ X ∈ A ∧ x ∈ ω → A ∖ X ≈ x → A ∖ X ≈ M
53 52 rexlimdva ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ X ∈ A → ∃ x ∈ ω A ∖ X ≈ x → A ∖ X ≈ M
54 11 53 mpd ⊢ M ∈ ω ∧ A ≈ suc ⁡ M ∧ X ∈ A → A ∖ X ≈ M