Metamath Proof Explorer


Theorem eceqoveq

Description: Equality of equivalence relation in terms of an operation. (Contributed by NM, 15-Feb-1996) (Proof shortened by Mario Carneiro, 12-Aug-2015)

Ref Expression
Hypotheses eceqoveq.5 ⊢ ∼ ˙ Er S × S
eceqoveq.7 ⊢ dom ⁡ + ˙ = S × S
eceqoveq.8 ⊢ ¬ ∅ ∈ S
eceqoveq.9 ⊢ x ∈ S ∧ y ∈ S → x + ˙ y ∈ S
eceqoveq.10 ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ∧ D ∈ S → A B ∼ ˙ C D ↔ A + ˙ D = B + ˙ C
Assertion eceqoveq ⊢ A ∈ S ∧ C ∈ S → A B ∼ ˙ = C D ∼ ˙ ↔ A + ˙ D = B + ˙ C

Proof

Step Hyp Ref Expression
1 eceqoveq.5 ⊢ ∼ ˙ Er S × S
2 eceqoveq.7 ⊢ dom ⁡ + ˙ = S × S
3 eceqoveq.8 ⊢ ¬ ∅ ∈ S
4 eceqoveq.9 ⊢ x ∈ S ∧ y ∈ S → x + ˙ y ∈ S
5 eceqoveq.10 ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ∧ D ∈ S → A B ∼ ˙ C D ↔ A + ˙ D = B + ˙ C
6 opelxpi ⊢ A ∈ S ∧ B ∈ S → A B ∈ S × S
7 6 ad2antrr ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ∧ A B ∼ ˙ = C D ∼ ˙ → A B ∈ S × S
8 1 a1i ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ∧ A B ∼ ˙ = C D ∼ ˙ → ∼ ˙ Er S × S
9 simpr ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ∧ A B ∼ ˙ = C D ∼ ˙ → A B ∼ ˙ = C D ∼ ˙
10 8 9 ereldm ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ∧ A B ∼ ˙ = C D ∼ ˙ → A B ∈ S × S ↔ C D ∈ S × S
11 7 10 mpbid ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ∧ A B ∼ ˙ = C D ∼ ˙ → C D ∈ S × S
12 opelxp2 ⊢ C D ∈ S × S → D ∈ S
13 11 12 syl ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ∧ A B ∼ ˙ = C D ∼ ˙ → D ∈ S
14 13 ex ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S → A B ∼ ˙ = C D ∼ ˙ → D ∈ S
15 4 caovcl ⊢ B ∈ S ∧ C ∈ S → B + ˙ C ∈ S
16 eleq1 ⊢ A + ˙ D = B + ˙ C → A + ˙ D ∈ S ↔ B + ˙ C ∈ S
17 15 16 imbitrrid ⊢ A + ˙ D = B + ˙ C → B ∈ S ∧ C ∈ S → A + ˙ D ∈ S
18 2 3 ndmovrcl ⊢ A + ˙ D ∈ S → A ∈ S ∧ D ∈ S
19 18 simprd ⊢ A + ˙ D ∈ S → D ∈ S
20 17 19 syl6com ⊢ B ∈ S ∧ C ∈ S → A + ˙ D = B + ˙ C → D ∈ S
21 20 adantll ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S → A + ˙ D = B + ˙ C → D ∈ S
22 1 a1i ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ∧ D ∈ S → ∼ ˙ Er S × S
23 6 adantr ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ∧ D ∈ S → A B ∈ S × S
24 22 23 erth ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ∧ D ∈ S → A B ∼ ˙ C D ↔ A B ∼ ˙ = C D ∼ ˙
25 24 5 bitr3d ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ∧ D ∈ S → A B ∼ ˙ = C D ∼ ˙ ↔ A + ˙ D = B + ˙ C
26 25 expr ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S → D ∈ S → A B ∼ ˙ = C D ∼ ˙ ↔ A + ˙ D = B + ˙ C
27 14 21 26 pm5.21ndd ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S → A B ∼ ˙ = C D ∼ ˙ ↔ A + ˙ D = B + ˙ C
28 27 an32s ⊢ A ∈ S ∧ C ∈ S ∧ B ∈ S → A B ∼ ˙ = C D ∼ ˙ ↔ A + ˙ D = B + ˙ C
29 eqcom ⊢ ∅ = C D ∼ ˙ ↔ C D ∼ ˙ = ∅
30 erdm ⊢ ∼ ˙ Er S × S → dom ⁡ ∼ ˙ = S × S
31 1 30 ax-mp ⊢ dom ⁡ ∼ ˙ = S × S
32 31 eleq2i ⊢ C D ∈ dom ⁡ ∼ ˙ ↔ C D ∈ S × S
33 ecdmn0 ⊢ C D ∈ dom ⁡ ∼ ˙ ↔ C D ∼ ˙ ≠ ∅
34 opelxp ⊢ C D ∈ S × S ↔ C ∈ S ∧ D ∈ S
35 32 33 34 3bitr3i ⊢ C D ∼ ˙ ≠ ∅ ↔ C ∈ S ∧ D ∈ S
36 35 simplbi2 ⊢ C ∈ S → D ∈ S → C D ∼ ˙ ≠ ∅
37 36 ad2antlr ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → D ∈ S → C D ∼ ˙ ≠ ∅
38 37 necon2bd ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → C D ∼ ˙ = ∅ → ¬ D ∈ S
39 simpr ⊢ A ∈ S ∧ D ∈ S → D ∈ S
40 2 ndmov ⊢ ¬ A ∈ S ∧ D ∈ S → A + ˙ D = ∅
41 39 40 nsyl5 ⊢ ¬ D ∈ S → A + ˙ D = ∅
42 38 41 syl6 ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → C D ∼ ˙ = ∅ → A + ˙ D = ∅
43 eleq1 ⊢ A + ˙ D = ∅ → A + ˙ D ∈ S ↔ ∅ ∈ S
44 3 43 mtbiri ⊢ A + ˙ D = ∅ → ¬ A + ˙ D ∈ S
45 35 simprbi ⊢ C D ∼ ˙ ≠ ∅ → D ∈ S
46 4 caovcl ⊢ A ∈ S ∧ D ∈ S → A + ˙ D ∈ S
47 46 ex ⊢ A ∈ S → D ∈ S → A + ˙ D ∈ S
48 47 ad2antrr ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → D ∈ S → A + ˙ D ∈ S
49 45 48 syl5 ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → C D ∼ ˙ ≠ ∅ → A + ˙ D ∈ S
50 49 necon1bd ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → ¬ A + ˙ D ∈ S → C D ∼ ˙ = ∅
51 44 50 syl5 ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → A + ˙ D = ∅ → C D ∼ ˙ = ∅
52 42 51 impbid ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → C D ∼ ˙ = ∅ ↔ A + ˙ D = ∅
53 29 52 bitrid ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → ∅ = C D ∼ ˙ ↔ A + ˙ D = ∅
54 31 eleq2i ⊢ A B ∈ dom ⁡ ∼ ˙ ↔ A B ∈ S × S
55 ecdmn0 ⊢ A B ∈ dom ⁡ ∼ ˙ ↔ A B ∼ ˙ ≠ ∅
56 opelxp ⊢ A B ∈ S × S ↔ A ∈ S ∧ B ∈ S
57 54 55 56 3bitr3i ⊢ A B ∼ ˙ ≠ ∅ ↔ A ∈ S ∧ B ∈ S
58 57 simprbi ⊢ A B ∼ ˙ ≠ ∅ → B ∈ S
59 58 necon1bi ⊢ ¬ B ∈ S → A B ∼ ˙ = ∅
60 59 adantl ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → A B ∼ ˙ = ∅
61 60 eqeq1d ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → A B ∼ ˙ = C D ∼ ˙ ↔ ∅ = C D ∼ ˙
62 simpl ⊢ B ∈ S ∧ C ∈ S → B ∈ S
63 2 ndmov ⊢ ¬ B ∈ S ∧ C ∈ S → B + ˙ C = ∅
64 62 63 nsyl5 ⊢ ¬ B ∈ S → B + ˙ C = ∅
65 64 adantl ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → B + ˙ C = ∅
66 65 eqeq2d ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → A + ˙ D = B + ˙ C ↔ A + ˙ D = ∅
67 53 61 66 3bitr4d ⊢ A ∈ S ∧ C ∈ S ∧ ¬ B ∈ S → A B ∼ ˙ = C D ∼ ˙ ↔ A + ˙ D = B + ˙ C
68 28 67 pm2.61dan ⊢ A ∈ S ∧ C ∈ S → A B ∼ ˙ = C D ∼ ˙ ↔ A + ˙ D = B + ˙ C