Metamath Proof Explorer


Theorem axcnre

Description: A complex number can be expressed in terms of two reals. Definition 10-1.1(v) of Gleason p. 130. Axiom 17 of 22 for real and complex numbers, derived from ZF set theory. This construction-dependent theorem should not be referenced directly; instead, use ax-cnre . (Contributed by NM, 13-May-1996) (New usage is discouraged.)

Ref Expression
Assertion axcnre ⊢ A ∈ ℂ → ∃ x ∈ ℝ ∃ y ∈ ℝ A = x + i ⁢ y

Proof

Step Hyp Ref Expression
1 df-c ⊢ ℂ = 𝑹 × 𝑹
2 eqeq1 ⊢ z w = A → z w = x + i ⁢ y ↔ A = x + i ⁢ y
3 2 2rexbidv ⊢ z w = A → ∃ x ∈ ℝ ∃ y ∈ ℝ z w = x + i ⁢ y ↔ ∃ x ∈ ℝ ∃ y ∈ ℝ A = x + i ⁢ y
4 opelreal ⊢ z 0 𝑹 ∈ ℝ ↔ z ∈ 𝑹
5 opelreal ⊢ w 0 𝑹 ∈ ℝ ↔ w ∈ 𝑹
6 4 5 anbi12i ⊢ z 0 𝑹 ∈ ℝ ∧ w 0 𝑹 ∈ ℝ ↔ z ∈ 𝑹 ∧ w ∈ 𝑹
7 6 biimpri ⊢ z ∈ 𝑹 ∧ w ∈ 𝑹 → z 0 𝑹 ∈ ℝ ∧ w 0 𝑹 ∈ ℝ
8 df-i ⊢ i = 0 𝑹 1 𝑹
9 8 oveq1i ⊢ i ⁢ w 0 𝑹 = 0 𝑹 1 𝑹 ⁢ w 0 𝑹
10 0r ⊢ 0 𝑹 ∈ 𝑹
11 1sr ⊢ 1 𝑹 ∈ 𝑹
12 mulcnsr ⊢ 0 𝑹 ∈ 𝑹 ∧ 1 𝑹 ∈ 𝑹 ∧ w ∈ 𝑹 ∧ 0 𝑹 ∈ 𝑹 → 0 𝑹 1 𝑹 ⁢ w 0 𝑹 = 0 𝑹 ⋅ 𝑹 w + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 1 𝑹 ⋅ 𝑹 w + 𝑹 0 𝑹 ⋅ 𝑹 0 𝑹
13 10 11 12 mpanl12 ⊢ w ∈ 𝑹 ∧ 0 𝑹 ∈ 𝑹 → 0 𝑹 1 𝑹 ⁢ w 0 𝑹 = 0 𝑹 ⋅ 𝑹 w + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 1 𝑹 ⋅ 𝑹 w + 𝑹 0 𝑹 ⋅ 𝑹 0 𝑹
14 10 13 mpan2 ⊢ w ∈ 𝑹 → 0 𝑹 1 𝑹 ⁢ w 0 𝑹 = 0 𝑹 ⋅ 𝑹 w + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 1 𝑹 ⋅ 𝑹 w + 𝑹 0 𝑹 ⋅ 𝑹 0 𝑹
15 mulcomsr ⊢ 0 𝑹 ⋅ 𝑹 w = w ⋅ 𝑹 0 𝑹
16 00sr ⊢ w ∈ 𝑹 → w ⋅ 𝑹 0 𝑹 = 0 𝑹
17 15 16 eqtrid ⊢ w ∈ 𝑹 → 0 𝑹 ⋅ 𝑹 w = 0 𝑹
18 17 oveq1d ⊢ w ∈ 𝑹 → 0 𝑹 ⋅ 𝑹 w + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹 + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹
19 00sr ⊢ 1 𝑹 ∈ 𝑹 → 1 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
20 11 19 ax-mp ⊢ 1 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
21 20 oveq2i ⊢ -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 = -1 𝑹 ⋅ 𝑹 0 𝑹
22 m1r ⊢ -1 𝑹 ∈ 𝑹
23 00sr ⊢ -1 𝑹 ∈ 𝑹 → -1 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
24 22 23 ax-mp ⊢ -1 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
25 21 24 eqtri ⊢ -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
26 25 oveq2i ⊢ 0 𝑹 + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹 + 𝑹 0 𝑹
27 0idsr ⊢ 0 𝑹 ∈ 𝑹 → 0 𝑹 + 𝑹 0 𝑹 = 0 𝑹
28 10 27 ax-mp ⊢ 0 𝑹 + 𝑹 0 𝑹 = 0 𝑹
29 26 28 eqtri ⊢ 0 𝑹 + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
30 18 29 eqtrdi ⊢ w ∈ 𝑹 → 0 𝑹 ⋅ 𝑹 w + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
31 mulcomsr ⊢ 1 𝑹 ⋅ 𝑹 w = w ⋅ 𝑹 1 𝑹
32 1idsr ⊢ w ∈ 𝑹 → w ⋅ 𝑹 1 𝑹 = w
33 31 32 eqtrid ⊢ w ∈ 𝑹 → 1 𝑹 ⋅ 𝑹 w = w
34 33 oveq1d ⊢ w ∈ 𝑹 → 1 𝑹 ⋅ 𝑹 w + 𝑹 0 𝑹 ⋅ 𝑹 0 𝑹 = w + 𝑹 0 𝑹 ⋅ 𝑹 0 𝑹
35 00sr ⊢ 0 𝑹 ∈ 𝑹 → 0 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
36 10 35 ax-mp ⊢ 0 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹
37 36 oveq2i ⊢ w + 𝑹 0 𝑹 ⋅ 𝑹 0 𝑹 = w + 𝑹 0 𝑹
38 0idsr ⊢ w ∈ 𝑹 → w + 𝑹 0 𝑹 = w
39 37 38 eqtrid ⊢ w ∈ 𝑹 → w + 𝑹 0 𝑹 ⋅ 𝑹 0 𝑹 = w
40 34 39 eqtrd ⊢ w ∈ 𝑹 → 1 𝑹 ⋅ 𝑹 w + 𝑹 0 𝑹 ⋅ 𝑹 0 𝑹 = w
41 30 40 opeq12d ⊢ w ∈ 𝑹 → 0 𝑹 ⋅ 𝑹 w + 𝑹 -1 𝑹 ⋅ 𝑹 1 𝑹 ⋅ 𝑹 0 𝑹 1 𝑹 ⋅ 𝑹 w + 𝑹 0 𝑹 ⋅ 𝑹 0 𝑹 = 0 𝑹 w
42 14 41 eqtrd ⊢ w ∈ 𝑹 → 0 𝑹 1 𝑹 ⁢ w 0 𝑹 = 0 𝑹 w
43 9 42 eqtrid ⊢ w ∈ 𝑹 → i ⁢ w 0 𝑹 = 0 𝑹 w
44 43 oveq2d ⊢ w ∈ 𝑹 → z 0 𝑹 + i ⁢ w 0 𝑹 = z 0 𝑹 + 0 𝑹 w
45 44 adantl ⊢ z ∈ 𝑹 ∧ w ∈ 𝑹 → z 0 𝑹 + i ⁢ w 0 𝑹 = z 0 𝑹 + 0 𝑹 w
46 addcnsr ⊢ z ∈ 𝑹 ∧ 0 𝑹 ∈ 𝑹 ∧ 0 𝑹 ∈ 𝑹 ∧ w ∈ 𝑹 → z 0 𝑹 + 0 𝑹 w = z + 𝑹 0 𝑹 0 𝑹 + 𝑹 w
47 10 46 mpanl2 ⊢ z ∈ 𝑹 ∧ 0 𝑹 ∈ 𝑹 ∧ w ∈ 𝑹 → z 0 𝑹 + 0 𝑹 w = z + 𝑹 0 𝑹 0 𝑹 + 𝑹 w
48 10 47 mpanr1 ⊢ z ∈ 𝑹 ∧ w ∈ 𝑹 → z 0 𝑹 + 0 𝑹 w = z + 𝑹 0 𝑹 0 𝑹 + 𝑹 w
49 0idsr ⊢ z ∈ 𝑹 → z + 𝑹 0 𝑹 = z
50 addcomsr ⊢ 0 𝑹 + 𝑹 w = w + 𝑹 0 𝑹
51 50 38 eqtrid ⊢ w ∈ 𝑹 → 0 𝑹 + 𝑹 w = w
52 opeq12 ⊢ z + 𝑹 0 𝑹 = z ∧ 0 𝑹 + 𝑹 w = w → z + 𝑹 0 𝑹 0 𝑹 + 𝑹 w = z w
53 49 51 52 syl2an ⊢ z ∈ 𝑹 ∧ w ∈ 𝑹 → z + 𝑹 0 𝑹 0 𝑹 + 𝑹 w = z w
54 45 48 53 3eqtrrd ⊢ z ∈ 𝑹 ∧ w ∈ 𝑹 → z w = z 0 𝑹 + i ⁢ w 0 𝑹
55 opex ⊢ z 0 𝑹 ∈ V
56 opex ⊢ w 0 𝑹 ∈ V
57 eleq1 ⊢ x = z 0 𝑹 → x ∈ ℝ ↔ z 0 𝑹 ∈ ℝ
58 eleq1 ⊢ y = w 0 𝑹 → y ∈ ℝ ↔ w 0 𝑹 ∈ ℝ
59 57 58 bi2anan9 ⊢ x = z 0 𝑹 ∧ y = w 0 𝑹 → x ∈ ℝ ∧ y ∈ ℝ ↔ z 0 𝑹 ∈ ℝ ∧ w 0 𝑹 ∈ ℝ
60 oveq1 ⊢ x = z 0 𝑹 → x + i ⁢ y = z 0 𝑹 + i ⁢ y
61 oveq2 ⊢ y = w 0 𝑹 → i ⁢ y = i ⁢ w 0 𝑹
62 61 oveq2d ⊢ y = w 0 𝑹 → z 0 𝑹 + i ⁢ y = z 0 𝑹 + i ⁢ w 0 𝑹
63 60 62 sylan9eq ⊢ x = z 0 𝑹 ∧ y = w 0 𝑹 → x + i ⁢ y = z 0 𝑹 + i ⁢ w 0 𝑹
64 63 eqeq2d ⊢ x = z 0 𝑹 ∧ y = w 0 𝑹 → z w = x + i ⁢ y ↔ z w = z 0 𝑹 + i ⁢ w 0 𝑹
65 59 64 anbi12d ⊢ x = z 0 𝑹 ∧ y = w 0 𝑹 → x ∈ ℝ ∧ y ∈ ℝ ∧ z w = x + i ⁢ y ↔ z 0 𝑹 ∈ ℝ ∧ w 0 𝑹 ∈ ℝ ∧ z w = z 0 𝑹 + i ⁢ w 0 𝑹
66 55 56 65 spc2ev ⊢ z 0 𝑹 ∈ ℝ ∧ w 0 𝑹 ∈ ℝ ∧ z w = z 0 𝑹 + i ⁢ w 0 𝑹 → ∃ x ∃ y x ∈ ℝ ∧ y ∈ ℝ ∧ z w = x + i ⁢ y
67 7 54 66 syl2anc ⊢ z ∈ 𝑹 ∧ w ∈ 𝑹 → ∃ x ∃ y x ∈ ℝ ∧ y ∈ ℝ ∧ z w = x + i ⁢ y
68 r2ex ⊢ ∃ x ∈ ℝ ∃ y ∈ ℝ z w = x + i ⁢ y ↔ ∃ x ∃ y x ∈ ℝ ∧ y ∈ ℝ ∧ z w = x + i ⁢ y
69 67 68 sylibr ⊢ z ∈ 𝑹 ∧ w ∈ 𝑹 → ∃ x ∈ ℝ ∃ y ∈ ℝ z w = x + i ⁢ y
70 1 3 69 optocl ⊢ A ∈ ℂ → ∃ x ∈ ℝ ∃ y ∈ ℝ A = x + i ⁢ y