Metamath Proof Explorer


Theorem knoppndvlem19

Description: Lemma for knoppndv . (Contributed by Asger C. Ipsen, 17-Aug-2021)

Ref Expression
Hypotheses knoppndvlem19.a ⊢ A = 2 ⋅ N − J 2 ⁢ m
knoppndvlem19.b ⊢ B = 2 ⋅ N − J 2 ⁢ m + 1
knoppndvlem19.j ⊢ φ → J ∈ ℕ 0
knoppndvlem19.h ⊢ φ → H ∈ ℝ
knoppndvlem19.n ⊢ φ → N ∈ ℕ
Assertion knoppndvlem19 ⊢ φ → ∃ m ∈ ℤ A ≤ H ∧ H ≤ B

Proof

Step Hyp Ref Expression
1 knoppndvlem19.a ⊢ A = 2 ⋅ N − J 2 ⁢ m
2 knoppndvlem19.b ⊢ B = 2 ⋅ N − J 2 ⁢ m + 1
3 knoppndvlem19.j ⊢ φ → J ∈ ℕ 0
4 knoppndvlem19.h ⊢ φ → H ∈ ℝ
5 knoppndvlem19.n ⊢ φ → N ∈ ℕ
6 2re ⊢ 2 ∈ ℝ
7 6 a1i ⊢ φ → 2 ∈ ℝ
8 5 nnred ⊢ φ → N ∈ ℝ
9 7 8 remulcld ⊢ φ → 2 ⋅ N ∈ ℝ
10 2pos ⊢ 0 < 2
11 10 a1i ⊢ φ → 0 < 2
12 5 nngt0d ⊢ φ → 0 < N
13 7 8 11 12 mulgt0d ⊢ φ → 0 < 2 ⋅ N
14 13 gt0ne0d ⊢ φ → 2 ⋅ N ≠ 0
15 3 nn0zd ⊢ φ → J ∈ ℤ
16 15 znegcld ⊢ φ → − J ∈ ℤ
17 9 14 16 reexpclzd ⊢ φ → 2 ⋅ N − J ∈ ℝ
18 7 recnd ⊢ φ → 2 ∈ ℂ
19 8 recnd ⊢ φ → N ∈ ℂ
20 18 19 14 mulne0bad ⊢ φ → 2 ≠ 0
21 17 7 20 redivcld ⊢ φ → 2 ⋅ N − J 2 ∈ ℝ
22 9 16 13 3jca ⊢ φ → 2 ⋅ N ∈ ℝ ∧ − J ∈ ℤ ∧ 0 < 2 ⋅ N
23 expgt0 ⊢ 2 ⋅ N ∈ ℝ ∧ − J ∈ ℤ ∧ 0 < 2 ⋅ N → 0 < 2 ⋅ N − J
24 22 23 syl ⊢ φ → 0 < 2 ⋅ N − J
25 17 7 24 11 divgt0d ⊢ φ → 0 < 2 ⋅ N − J 2
26 25 gt0ne0d ⊢ φ → 2 ⋅ N − J 2 ≠ 0
27 4 21 26 redivcld ⊢ φ → H 2 ⋅ N − J 2 ∈ ℝ
28 27 flcld ⊢ φ → H 2 ⋅ N − J 2 ∈ ℤ
29 1 a1i ⊢ m = H 2 ⋅ N − J 2 → A = 2 ⋅ N − J 2 ⁢ m
30 id ⊢ m = H 2 ⋅ N − J 2 → m = H 2 ⋅ N − J 2
31 30 oveq2d ⊢ m = H 2 ⋅ N − J 2 → 2 ⋅ N − J 2 ⁢ m = 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2
32 29 31 eqtrd ⊢ m = H 2 ⋅ N − J 2 → A = 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2
33 32 breq1d ⊢ m = H 2 ⋅ N − J 2 → A ≤ H ↔ 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 ≤ H
34 2 a1i ⊢ m = H 2 ⋅ N − J 2 → B = 2 ⋅ N − J 2 ⁢ m + 1
35 30 oveq1d ⊢ m = H 2 ⋅ N − J 2 → m + 1 = H 2 ⋅ N − J 2 + 1
36 35 oveq2d ⊢ m = H 2 ⋅ N − J 2 → 2 ⋅ N − J 2 ⁢ m + 1 = 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 + 1
37 34 36 eqtrd ⊢ m = H 2 ⋅ N − J 2 → B = 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 + 1
38 37 breq2d ⊢ m = H 2 ⋅ N − J 2 → H ≤ B ↔ H ≤ 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 + 1
39 33 38 anbi12d ⊢ m = H 2 ⋅ N − J 2 → A ≤ H ∧ H ≤ B ↔ 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 ≤ H ∧ H ≤ 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 + 1
40 39 adantl ⊢ φ ∧ m = H 2 ⋅ N − J 2 → A ≤ H ∧ H ≤ B ↔ 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 ≤ H ∧ H ≤ 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 + 1
41 28 zred ⊢ φ → H 2 ⋅ N − J 2 ∈ ℝ
42 0red ⊢ φ → 0 ∈ ℝ
43 42 21 25 ltled ⊢ φ → 0 ≤ 2 ⋅ N − J 2
44 flle ⊢ H 2 ⋅ N − J 2 ∈ ℝ → H 2 ⋅ N − J 2 ≤ H 2 ⋅ N − J 2
45 27 44 syl ⊢ φ → H 2 ⋅ N − J 2 ≤ H 2 ⋅ N − J 2
46 41 27 21 43 45 lemul2ad ⊢ φ → 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 ≤ 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2
47 4 recnd ⊢ φ → H ∈ ℂ
48 21 recnd ⊢ φ → 2 ⋅ N − J 2 ∈ ℂ
49 47 48 26 divcan2d ⊢ φ → 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 = H
50 46 49 breqtrd ⊢ φ → 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 ≤ H
51 49 eqcomd ⊢ φ → H = 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2
52 peano2re ⊢ H 2 ⋅ N − J 2 ∈ ℝ → H 2 ⋅ N − J 2 + 1 ∈ ℝ
53 41 52 syl ⊢ φ → H 2 ⋅ N − J 2 + 1 ∈ ℝ
54 fllep1 ⊢ H 2 ⋅ N − J 2 ∈ ℝ → H 2 ⋅ N − J 2 ≤ H 2 ⋅ N − J 2 + 1
55 27 54 syl ⊢ φ → H 2 ⋅ N − J 2 ≤ H 2 ⋅ N − J 2 + 1
56 27 53 21 43 55 lemul2ad ⊢ φ → 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 ≤ 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 + 1
57 51 56 eqbrtrd ⊢ φ → H ≤ 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 + 1
58 50 57 jca ⊢ φ → 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 ≤ H ∧ H ≤ 2 ⋅ N − J 2 ⁢ H 2 ⋅ N − J 2 + 1
59 28 40 58 rspcedvd ⊢ φ → ∃ m ∈ ℤ A ≤ H ∧ H ≤ B