Metamath Proof Explorer


Theorem proot1hash

Description: If an integral domain has a primitive N -th root of unity, it has exactly ( phiN ) of them. (Contributed by Stefan O'Rear, 12-Sep-2015)

Ref Expression
Hypotheses proot1hash.g ⊢ G = mulGrp R ↾ 𝑠 Unit ⁡ R
proot1hash.o ⊢ O = od ⁡ G
Assertion proot1hash ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → O -1 N = ϕ ⁡ N

Proof

Step Hyp Ref Expression
1 proot1hash.g ⊢ G = mulGrp R ↾ 𝑠 Unit ⁡ R
2 proot1hash.o ⊢ O = od ⁡ G
3 eqid ⊢ Base G = Base G
4 3 2 odf ⊢ O : Base G ⟶ ℕ 0
5 ffn ⊢ O : Base G ⟶ ℕ 0 → O Fn Base G
6 fniniseg2 ⊢ O Fn Base G → O -1 N = x ∈ Base G | O ⁡ x = N
7 4 5 6 mp2b ⊢ O -1 N = x ∈ Base G | O ⁡ x = N
8 simp3 ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → X ∈ O -1 N
9 fniniseg ⊢ O Fn Base G → X ∈ O -1 N ↔ X ∈ Base G ∧ O ⁡ X = N
10 4 5 9 mp2b ⊢ X ∈ O -1 N ↔ X ∈ Base G ∧ O ⁡ X = N
11 8 10 sylib ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → X ∈ Base G ∧ O ⁡ X = N
12 11 simprd ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → O ⁡ X = N
13 12 eqeq2d ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → O ⁡ x = O ⁡ X ↔ O ⁡ x = N
14 13 rabbidv ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → x ∈ mrCls ⁡ SubGrp ⁡ G ⁡ X | O ⁡ x = O ⁡ X = x ∈ mrCls ⁡ SubGrp ⁡ G ⁡ X | O ⁡ x = N
15 isidom ⊢ R ∈ IDomn ↔ R ∈ CRing ∧ R ∈ Domn
16 15 simprbi ⊢ R ∈ IDomn → R ∈ Domn
17 16 3ad2ant1 ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → R ∈ Domn
18 domnring ⊢ R ∈ Domn → R ∈ Ring
19 eqid ⊢ Unit ⁡ R = Unit ⁡ R
20 19 1 unitgrp ⊢ R ∈ Ring → G ∈ Grp
21 17 18 20 3syl ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → G ∈ Grp
22 3 subgacs ⊢ G ∈ Grp → SubGrp ⁡ G ∈ ACS ⁡ Base G
23 acsmre ⊢ SubGrp ⁡ G ∈ ACS ⁡ Base G → SubGrp ⁡ G ∈ Moore ⁡ Base G
24 21 22 23 3syl ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → SubGrp ⁡ G ∈ Moore ⁡ Base G
25 eqid ⊢ mrCls ⁡ SubGrp ⁡ G = mrCls ⁡ SubGrp ⁡ G
26 25 mrcssv ⊢ SubGrp ⁡ G ∈ Moore ⁡ Base G → mrCls ⁡ SubGrp ⁡ G ⁡ X ⊆ Base G
27 dfrab3ss ⊢ mrCls ⁡ SubGrp ⁡ G ⁡ X ⊆ Base G → x ∈ mrCls ⁡ SubGrp ⁡ G ⁡ X | O ⁡ x = N = mrCls ⁡ SubGrp ⁡ G ⁡ X ∩ x ∈ Base G | O ⁡ x = N
28 24 26 27 3syl ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → x ∈ mrCls ⁡ SubGrp ⁡ G ⁡ X | O ⁡ x = N = mrCls ⁡ SubGrp ⁡ G ⁡ X ∩ x ∈ Base G | O ⁡ x = N
29 incom ⊢ mrCls ⁡ SubGrp ⁡ G ⁡ X ∩ x ∈ Base G | O ⁡ x = N = x ∈ Base G | O ⁡ x = N ∩ mrCls ⁡ SubGrp ⁡ G ⁡ X
30 simpl1 ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N ∧ x ∈ O -1 N → R ∈ IDomn
31 simpl2 ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N ∧ x ∈ O -1 N → N ∈ ℕ
32 simpr ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N ∧ x ∈ O -1 N → x ∈ O -1 N
33 simpl3 ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N ∧ x ∈ O -1 N → X ∈ O -1 N
34 1 2 25 proot1mul ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ x ∈ O -1 N ∧ X ∈ O -1 N → x ∈ mrCls ⁡ SubGrp ⁡ G ⁡ X
35 30 31 32 33 34 syl22anc ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N ∧ x ∈ O -1 N → x ∈ mrCls ⁡ SubGrp ⁡ G ⁡ X
36 35 ex ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → x ∈ O -1 N → x ∈ mrCls ⁡ SubGrp ⁡ G ⁡ X
37 36 ssrdv ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → O -1 N ⊆ mrCls ⁡ SubGrp ⁡ G ⁡ X
38 7 37 eqsstrrid ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → x ∈ Base G | O ⁡ x = N ⊆ mrCls ⁡ SubGrp ⁡ G ⁡ X
39 dfss2 ⊢ x ∈ Base G | O ⁡ x = N ⊆ mrCls ⁡ SubGrp ⁡ G ⁡ X ↔ x ∈ Base G | O ⁡ x = N ∩ mrCls ⁡ SubGrp ⁡ G ⁡ X = x ∈ Base G | O ⁡ x = N
40 38 39 sylib ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → x ∈ Base G | O ⁡ x = N ∩ mrCls ⁡ SubGrp ⁡ G ⁡ X = x ∈ Base G | O ⁡ x = N
41 29 40 eqtrid ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → mrCls ⁡ SubGrp ⁡ G ⁡ X ∩ x ∈ Base G | O ⁡ x = N = x ∈ Base G | O ⁡ x = N
42 14 28 41 3eqtrrd ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → x ∈ Base G | O ⁡ x = N = x ∈ mrCls ⁡ SubGrp ⁡ G ⁡ X | O ⁡ x = O ⁡ X
43 7 42 eqtrid ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → O -1 N = x ∈ mrCls ⁡ SubGrp ⁡ G ⁡ X | O ⁡ x = O ⁡ X
44 43 fveq2d ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → O -1 N = x ∈ mrCls ⁡ SubGrp ⁡ G ⁡ X | O ⁡ x = O ⁡ X
45 11 simpld ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → X ∈ Base G
46 simp2 ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → N ∈ ℕ
47 12 46 eqeltrd ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → O ⁡ X ∈ ℕ
48 3 2 25 odngen ⊢ G ∈ Grp ∧ X ∈ Base G ∧ O ⁡ X ∈ ℕ → x ∈ mrCls ⁡ SubGrp ⁡ G ⁡ X | O ⁡ x = O ⁡ X = ϕ ⁡ O ⁡ X
49 21 45 47 48 syl3anc ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → x ∈ mrCls ⁡ SubGrp ⁡ G ⁡ X | O ⁡ x = O ⁡ X = ϕ ⁡ O ⁡ X
50 12 fveq2d ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → ϕ ⁡ O ⁡ X = ϕ ⁡ N
51 44 49 50 3eqtrd ⊢ R ∈ IDomn ∧ N ∈ ℕ ∧ X ∈ O -1 N → O -1 N = ϕ ⁡ N