Metamath Proof Explorer


Theorem rankeq1o

Description: The only set with rank 1o is the singleton of the empty set. (Contributed by Scott Fenton, 17-Jul-2015)

Ref Expression
Assertion rankeq1o ⊢ rank ⁡ A = 1 𝑜 ↔ A = ∅

Proof

Step Hyp Ref Expression
1 1n0 ⊢ 1 𝑜 ≠ ∅
2 neeq1 ⊢ rank ⁡ A = 1 𝑜 → rank ⁡ A ≠ ∅ ↔ 1 𝑜 ≠ ∅
3 1 2 mpbiri ⊢ rank ⁡ A = 1 𝑜 → rank ⁡ A ≠ ∅
4 3 neneqd ⊢ rank ⁡ A = 1 𝑜 → ¬ rank ⁡ A = ∅
5 fvprc ⊢ ¬ A ∈ V → rank ⁡ A = ∅
6 4 5 nsyl2 ⊢ rank ⁡ A = 1 𝑜 → A ∈ V
7 fveqeq2 ⊢ x = A → rank ⁡ x = 1 𝑜 ↔ rank ⁡ A = 1 𝑜
8 eqeq1 ⊢ x = A → x = 1 𝑜 ↔ A = 1 𝑜
9 7 8 imbi12d ⊢ x = A → rank ⁡ x = 1 𝑜 → x = 1 𝑜 ↔ rank ⁡ A = 1 𝑜 → A = 1 𝑜
10 neeq1 ⊢ rank ⁡ x = 1 𝑜 → rank ⁡ x ≠ ∅ ↔ 1 𝑜 ≠ ∅
11 1 10 mpbiri ⊢ rank ⁡ x = 1 𝑜 → rank ⁡ x ≠ ∅
12 vex ⊢ x ∈ V
13 12 rankeq0 ⊢ x = ∅ ↔ rank ⁡ x = ∅
14 13 necon3bii ⊢ x ≠ ∅ ↔ rank ⁡ x ≠ ∅
15 11 14 sylibr ⊢ rank ⁡ x = 1 𝑜 → x ≠ ∅
16 12 rankval ⊢ rank ⁡ x = ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y
17 16 eqeq1i ⊢ rank ⁡ x = 1 𝑜 ↔ ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = 1 𝑜
18 ssrab2 ⊢ y ∈ On | x ∈ R1 ⁡ suc ⁡ y ⊆ On
19 elirr ⊢ ¬ 1 𝑜 ∈ 1 𝑜
20 1oex ⊢ 1 𝑜 ∈ V
21 id ⊢ V = 1 𝑜 → V = 1 𝑜
22 20 21 eleqtrid ⊢ V = 1 𝑜 → 1 𝑜 ∈ 1 𝑜
23 19 22 mto ⊢ ¬ V = 1 𝑜
24 inteq ⊢ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = ∅ → ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = ⋂ ∅
25 int0 ⊢ ⋂ ∅ = V
26 24 25 eqtrdi ⊢ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = ∅ → ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = V
27 26 eqeq1d ⊢ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = ∅ → ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = 1 𝑜 ↔ V = 1 𝑜
28 23 27 mtbiri ⊢ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = ∅ → ¬ ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = 1 𝑜
29 28 necon2ai ⊢ ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = 1 𝑜 → y ∈ On | x ∈ R1 ⁡ suc ⁡ y ≠ ∅
30 onint ⊢ y ∈ On | x ∈ R1 ⁡ suc ⁡ y ⊆ On ∧ y ∈ On | x ∈ R1 ⁡ suc ⁡ y ≠ ∅ → ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y ∈ y ∈ On | x ∈ R1 ⁡ suc ⁡ y
31 18 29 30 sylancr ⊢ ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = 1 𝑜 → ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y ∈ y ∈ On | x ∈ R1 ⁡ suc ⁡ y
32 eleq1 ⊢ ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = 1 𝑜 → ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y ∈ y ∈ On | x ∈ R1 ⁡ suc ⁡ y ↔ 1 𝑜 ∈ y ∈ On | x ∈ R1 ⁡ suc ⁡ y
33 31 32 mpbid ⊢ ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = 1 𝑜 → 1 𝑜 ∈ y ∈ On | x ∈ R1 ⁡ suc ⁡ y
34 suceq ⊢ y = 1 𝑜 → suc ⁡ y = suc ⁡ 1 𝑜
35 34 fveq2d ⊢ y = 1 𝑜 → R1 ⁡ suc ⁡ y = R1 ⁡ suc ⁡ 1 𝑜
36 df-1o ⊢ 1 𝑜 = suc ⁡ ∅
37 36 fveq2i ⊢ R1 ⁡ 1 𝑜 = R1 ⁡ suc ⁡ ∅
38 0elon ⊢ ∅ ∈ On
39 r1suc ⊢ ∅ ∈ On → R1 ⁡ suc ⁡ ∅ = 𝒫 R1 ⁡ ∅
40 38 39 ax-mp ⊢ R1 ⁡ suc ⁡ ∅ = 𝒫 R1 ⁡ ∅
41 r10 ⊢ R1 ⁡ ∅ = ∅
42 41 pweqi ⊢ 𝒫 R1 ⁡ ∅ = 𝒫 ∅
43 37 40 42 3eqtri ⊢ R1 ⁡ 1 𝑜 = 𝒫 ∅
44 43 pweqi ⊢ 𝒫 R1 ⁡ 1 𝑜 = 𝒫 𝒫 ∅
45 pw0 ⊢ 𝒫 ∅ = ∅
46 45 pweqi ⊢ 𝒫 𝒫 ∅ = 𝒫 ∅
47 pwpw0 ⊢ 𝒫 ∅ = ∅ ∅
48 44 46 47 3eqtrri ⊢ ∅ ∅ = 𝒫 R1 ⁡ 1 𝑜
49 1on ⊢ 1 𝑜 ∈ On
50 r1suc ⊢ 1 𝑜 ∈ On → R1 ⁡ suc ⁡ 1 𝑜 = 𝒫 R1 ⁡ 1 𝑜
51 49 50 ax-mp ⊢ R1 ⁡ suc ⁡ 1 𝑜 = 𝒫 R1 ⁡ 1 𝑜
52 48 51 eqtr4i ⊢ ∅ ∅ = R1 ⁡ suc ⁡ 1 𝑜
53 35 52 eqtr4di ⊢ y = 1 𝑜 → R1 ⁡ suc ⁡ y = ∅ ∅
54 53 eleq2d ⊢ y = 1 𝑜 → x ∈ R1 ⁡ suc ⁡ y ↔ x ∈ ∅ ∅
55 54 elrab ⊢ 1 𝑜 ∈ y ∈ On | x ∈ R1 ⁡ suc ⁡ y ↔ 1 𝑜 ∈ On ∧ x ∈ ∅ ∅
56 33 55 sylib ⊢ ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = 1 𝑜 → 1 𝑜 ∈ On ∧ x ∈ ∅ ∅
57 12 elpr ⊢ x ∈ ∅ ∅ ↔ x = ∅ ∨ x = ∅
58 df-ne ⊢ x ≠ ∅ ↔ ¬ x = ∅
59 orel1 ⊢ ¬ x = ∅ → x = ∅ ∨ x = ∅ → x = ∅
60 58 59 sylbi ⊢ x ≠ ∅ → x = ∅ ∨ x = ∅ → x = ∅
61 df1o2 ⊢ 1 𝑜 = ∅
62 eqeq2 ⊢ x = ∅ → 1 𝑜 = x ↔ 1 𝑜 = ∅
63 61 62 mpbiri ⊢ x = ∅ → 1 𝑜 = x
64 63 eqcomd ⊢ x = ∅ → x = 1 𝑜
65 60 64 syl6com ⊢ x = ∅ ∨ x = ∅ → x ≠ ∅ → x = 1 𝑜
66 57 65 sylbi ⊢ x ∈ ∅ ∅ → x ≠ ∅ → x = 1 𝑜
67 56 66 simpl2im ⊢ ⋂ y ∈ On | x ∈ R1 ⁡ suc ⁡ y = 1 𝑜 → x ≠ ∅ → x = 1 𝑜
68 17 67 sylbi ⊢ rank ⁡ x = 1 𝑜 → x ≠ ∅ → x = 1 𝑜
69 15 68 mpd ⊢ rank ⁡ x = 1 𝑜 → x = 1 𝑜
70 9 69 vtoclg ⊢ A ∈ V → rank ⁡ A = 1 𝑜 → A = 1 𝑜
71 6 70 mpcom ⊢ rank ⁡ A = 1 𝑜 → A = 1 𝑜
72 fveq2 ⊢ A = 1 𝑜 → rank ⁡ A = rank ⁡ 1 𝑜
73 r1fnon ⊢ R1 Fn On
74 73 fndmi ⊢ dom ⁡ R1 = On
75 49 74 eleqtrri ⊢ 1 𝑜 ∈ dom ⁡ R1
76 rankonid ⊢ 1 𝑜 ∈ dom ⁡ R1 ↔ rank ⁡ 1 𝑜 = 1 𝑜
77 75 76 mpbi ⊢ rank ⁡ 1 𝑜 = 1 𝑜
78 72 77 eqtrdi ⊢ A = 1 𝑜 → rank ⁡ A = 1 𝑜
79 71 78 impbii ⊢ rank ⁡ A = 1 𝑜 ↔ A = 1 𝑜
80 61 eqeq2i ⊢ A = 1 𝑜 ↔ A = ∅
81 79 80 bitri ⊢ rank ⁡ A = 1 𝑜 ↔ A = ∅