Metamath Proof Explorer


Theorem vonsn

Description: The n-dimensional Lebesgue measure of a singleton is zero. This is the first statement in Proposition 115G (e) of Fremlin1 p. 32. (Contributed by Glauco Siliprandi, 8-Apr-2021)

Ref Expression
Hypotheses vonsn.1 ⊢ φ → X ∈ Fin
vonsn.2 ⊢ φ → A ∈ ℝ X
Assertion vonsn ⊢ φ → voln ⁡ X ⁡ A = 0

Proof

Step Hyp Ref Expression
1 vonsn.1 ⊢ φ → X ∈ Fin
2 vonsn.2 ⊢ φ → A ∈ ℝ X
3 fveq2 ⊢ X = ∅ → voln ⁡ X = voln ⁡ ∅
4 3 fveq1d ⊢ X = ∅ → voln ⁡ X ⁡ A = voln ⁡ ∅ ⁡ A
5 4 adantl ⊢ φ ∧ X = ∅ → voln ⁡ X ⁡ A = voln ⁡ ∅ ⁡ A
6 0fi ⊢ ∅ ∈ Fin
7 6 a1i ⊢ φ ∧ X = ∅ → ∅ ∈ Fin
8 2 adantr ⊢ φ ∧ X = ∅ → A ∈ ℝ X
9 oveq2 ⊢ X = ∅ → ℝ X = ℝ ∅
10 9 adantl ⊢ φ ∧ X = ∅ → ℝ X = ℝ ∅
11 8 10 eleqtrd ⊢ φ ∧ X = ∅ → A ∈ ℝ ∅
12 7 11 snvonmbl ⊢ φ ∧ X = ∅ → A ∈ dom ⁡ voln ⁡ ∅
13 12 von0val ⊢ φ ∧ X = ∅ → voln ⁡ ∅ ⁡ A = 0
14 5 13 eqtrd ⊢ φ ∧ X = ∅ → voln ⁡ X ⁡ A = 0
15 neqne ⊢ ¬ X = ∅ → X ≠ ∅
16 15 adantl ⊢ φ ∧ ¬ X = ∅ → X ≠ ∅
17 2 rrxsnicc ⊢ φ → ⨉ k ∈ X A ⁡ k A ⁡ k = A
18 17 eqcomd ⊢ φ → A = ⨉ k ∈ X A ⁡ k A ⁡ k
19 18 fveq2d ⊢ φ → voln ⁡ X ⁡ A = voln ⁡ X ⁡ ⨉ k ∈ X A ⁡ k A ⁡ k
20 19 adantr ⊢ φ ∧ X ≠ ∅ → voln ⁡ X ⁡ A = voln ⁡ X ⁡ ⨉ k ∈ X A ⁡ k A ⁡ k
21 1 adantr ⊢ φ ∧ X ≠ ∅ → X ∈ Fin
22 simpr ⊢ φ ∧ X ≠ ∅ → X ≠ ∅
23 elmapi ⊢ A ∈ ℝ X → A : X ⟶ ℝ
24 2 23 syl ⊢ φ → A : X ⟶ ℝ
25 24 adantr ⊢ φ ∧ X ≠ ∅ → A : X ⟶ ℝ
26 eqid ⊢ ⨉ k ∈ X A ⁡ k A ⁡ k = ⨉ k ∈ X A ⁡ k A ⁡ k
27 21 22 25 25 26 vonn0icc ⊢ φ ∧ X ≠ ∅ → voln ⁡ X ⁡ ⨉ k ∈ X A ⁡ k A ⁡ k = ∏ k ∈ X vol ⁡ A ⁡ k A ⁡ k
28 24 ffvelcdmda ⊢ φ ∧ k ∈ X → A ⁡ k ∈ ℝ
29 28 rexrd ⊢ φ ∧ k ∈ X → A ⁡ k ∈ ℝ *
30 iccid ⊢ A ⁡ k ∈ ℝ * → A ⁡ k A ⁡ k = A ⁡ k
31 29 30 syl ⊢ φ ∧ k ∈ X → A ⁡ k A ⁡ k = A ⁡ k
32 31 fveq2d ⊢ φ ∧ k ∈ X → vol ⁡ A ⁡ k A ⁡ k = vol ⁡ A ⁡ k
33 volsn ⊢ A ⁡ k ∈ ℝ → vol ⁡ A ⁡ k = 0
34 28 33 syl ⊢ φ ∧ k ∈ X → vol ⁡ A ⁡ k = 0
35 32 34 eqtrd ⊢ φ ∧ k ∈ X → vol ⁡ A ⁡ k A ⁡ k = 0
36 35 prodeq2dv ⊢ φ → ∏ k ∈ X vol ⁡ A ⁡ k A ⁡ k = ∏ k ∈ X 0
37 36 adantr ⊢ φ ∧ X ≠ ∅ → ∏ k ∈ X vol ⁡ A ⁡ k A ⁡ k = ∏ k ∈ X 0
38 0cnd ⊢ φ → 0 ∈ ℂ
39 fprodconst ⊢ X ∈ Fin ∧ 0 ∈ ℂ → ∏ k ∈ X 0 = 0 X
40 1 38 39 syl2anc ⊢ φ → ∏ k ∈ X 0 = 0 X
41 40 adantr ⊢ φ ∧ X ≠ ∅ → ∏ k ∈ X 0 = 0 X
42 hashnncl ⊢ X ∈ Fin → X ∈ ℕ ↔ X ≠ ∅
43 1 42 syl ⊢ φ → X ∈ ℕ ↔ X ≠ ∅
44 43 adantr ⊢ φ ∧ X ≠ ∅ → X ∈ ℕ ↔ X ≠ ∅
45 22 44 mpbird ⊢ φ ∧ X ≠ ∅ → X ∈ ℕ
46 0exp ⊢ X ∈ ℕ → 0 X = 0
47 45 46 syl ⊢ φ ∧ X ≠ ∅ → 0 X = 0
48 37 41 47 3eqtrd ⊢ φ ∧ X ≠ ∅ → ∏ k ∈ X vol ⁡ A ⁡ k A ⁡ k = 0
49 20 27 48 3eqtrd ⊢ φ ∧ X ≠ ∅ → voln ⁡ X ⁡ A = 0
50 16 49 syldan ⊢ φ ∧ ¬ X = ∅ → voln ⁡ X ⁡ A = 0
51 14 50 pm2.61dan ⊢ φ → voln ⁡ X ⁡ A = 0