Metamath Proof Explorer


Theorem lcfl6lem

Description: Lemma for lcfl6 . A functional G (whose kernel is closed by dochsnkr ) is completely determined by a vector X in the orthocomplement in its kernel at which the functional value is 1. Note that the \ { .0. } in the X hypothesis is redundant by the last hypothesis but allows easier use of other theorems. (Contributed by NM, 3-Jan-2015)

Ref Expression
Hypotheses lcfl6lem.h ⊢ H = LHyp ⁡ K
lcfl6lem.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
lcfl6lem.u ⊢ U = DVecH ⁡ K ⁡ W
lcfl6lem.v ⊢ V = Base U
lcfl6lem.a ⊢ + ˙ = + U
lcfl6lem.t ⊢ · ˙ = ⋅ U
lcfl6lem.s ⊢ S = Scalar ⁡ U
lcfl6lem.i ⊢ 1 ˙ = 1 S
lcfl6lem.r ⊢ R = Base S
lcfl6lem.z ⊢ 0 ˙ = 0 U
lcfl6lem.f ⊢ F = LFnl ⁡ U
lcfl6lem.l ⊢ L = LKer ⁡ U
lcfl6lem.k ⊢ φ → K ∈ HL ∧ W ∈ H
lcfl6lem.g ⊢ φ → G ∈ F
lcfl6lem.x ⊢ φ → X ∈ ⊥ ˙ ⁡ L ⁡ G ∖ 0 ˙
lcfl6lem.y ⊢ φ → G ⁡ X = 1 ˙
Assertion lcfl6lem ⊢ φ → G = v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X

Proof

Step Hyp Ref Expression
1 lcfl6lem.h ⊢ H = LHyp ⁡ K
2 lcfl6lem.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
3 lcfl6lem.u ⊢ U = DVecH ⁡ K ⁡ W
4 lcfl6lem.v ⊢ V = Base U
5 lcfl6lem.a ⊢ + ˙ = + U
6 lcfl6lem.t ⊢ · ˙ = ⋅ U
7 lcfl6lem.s ⊢ S = Scalar ⁡ U
8 lcfl6lem.i ⊢ 1 ˙ = 1 S
9 lcfl6lem.r ⊢ R = Base S
10 lcfl6lem.z ⊢ 0 ˙ = 0 U
11 lcfl6lem.f ⊢ F = LFnl ⁡ U
12 lcfl6lem.l ⊢ L = LKer ⁡ U
13 lcfl6lem.k ⊢ φ → K ∈ HL ∧ W ∈ H
14 lcfl6lem.g ⊢ φ → G ∈ F
15 lcfl6lem.x ⊢ φ → X ∈ ⊥ ˙ ⁡ L ⁡ G ∖ 0 ˙
16 lcfl6lem.y ⊢ φ → G ⁡ X = 1 ˙
17 eqid ⊢ 0 S = 0 S
18 1 3 13 dvhlvec ⊢ φ → U ∈ LVec
19 1 3 13 dvhlmod ⊢ φ → U ∈ LMod
20 4 11 12 19 14 lkrssv ⊢ φ → L ⁡ G ⊆ V
21 1 3 4 2 dochssv ⊢ K ∈ HL ∧ W ∈ H ∧ L ⁡ G ⊆ V → ⊥ ˙ ⁡ L ⁡ G ⊆ V
22 13 20 21 syl2anc ⊢ φ → ⊥ ˙ ⁡ L ⁡ G ⊆ V
23 15 eldifad ⊢ φ → X ∈ ⊥ ˙ ⁡ L ⁡ G
24 22 23 sseldd ⊢ φ → X ∈ V
25 eqid ⊢ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X = v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X
26 eldifsni ⊢ X ∈ ⊥ ˙ ⁡ L ⁡ G ∖ 0 ˙ → X ≠ 0 ˙
27 15 26 syl ⊢ φ → X ≠ 0 ˙
28 eldifsn ⊢ X ∈ V ∖ 0 ˙ ↔ X ∈ V ∧ X ≠ 0 ˙
29 24 27 28 sylanbrc ⊢ φ → X ∈ V ∖ 0 ˙
30 1 2 3 4 10 5 6 11 7 9 25 13 29 dochflcl ⊢ φ → v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X ∈ F
31 1 2 3 4 10 11 12 13 14 15 dochsnkr ⊢ φ → L ⁡ G = ⊥ ˙ ⁡ X
32 1 2 3 4 10 5 6 12 7 9 25 13 29 dochsnkr2 ⊢ φ → L ⁡ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X = ⊥ ˙ ⁡ X
33 31 32 eqtr4d ⊢ φ → L ⁡ G = L ⁡ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X
34 1 2 3 4 5 6 10 7 9 8 13 29 25 dochfl1 ⊢ φ → v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X ⁡ X = 1 ˙
35 16 34 eqtr4d ⊢ φ → G ⁡ X = v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X ⁡ X
36 1 2 3 4 7 17 10 11 12 13 14 15 dochfln0 ⊢ φ → G ⁡ X ≠ 0 S
37 4 7 9 17 11 12 18 24 14 30 33 35 36 eqlkr3 ⊢ φ → G = v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ X v = w + ˙ k · ˙ X