Metamath Proof Explorer


Theorem lgamcvglem

Description: Lemma for lgamf and lgamcvg . (Contributed by Mario Carneiro, 8-Jul-2017)

Ref Expression
Hypotheses lgamucov.u ⊢ U = x ∈ ℂ | x ≤ r ∧ ∀ k ∈ ℕ 0 1 r ≤ x + k
lgamucov.a ⊢ φ → A ∈ ℂ ∖ ℤ ∖ ℕ
lgamcvglem.g ⊢ G = m ∈ ℕ ⟼ A ⁢ log ⁡ m + 1 m − log ⁡ A m + 1
Assertion lgamcvglem ⊢ φ → log Γ ⁡ A ∈ ℂ ∧ seq 1 + G ⇝ log Γ ⁡ A + log ⁡ A

Proof

Step Hyp Ref Expression
1 lgamucov.u ⊢ U = x ∈ ℂ | x ≤ r ∧ ∀ k ∈ ℕ 0 1 r ≤ x + k
2 lgamucov.a ⊢ φ → A ∈ ℂ ∖ ℤ ∖ ℕ
3 lgamcvglem.g ⊢ G = m ∈ ℕ ⟼ A ⁢ log ⁡ m + 1 m − log ⁡ A m + 1
4 1 2 lgamucov2 ⊢ φ → ∃ r ∈ ℕ A ∈ U
5 fveq2 ⊢ z = A → log Γ ⁡ z = log Γ ⁡ A
6 5 eleq1d ⊢ z = A → log Γ ⁡ z ∈ ℂ ↔ log Γ ⁡ A ∈ ℂ
7 simprl ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → r ∈ ℕ
8 fveq2 ⊢ x = t → x = t
9 8 breq1d ⊢ x = t → x ≤ r ↔ t ≤ r
10 fvoveq1 ⊢ x = t → x + k = t + k
11 10 breq2d ⊢ x = t → 1 r ≤ x + k ↔ 1 r ≤ t + k
12 11 ralbidv ⊢ x = t → ∀ k ∈ ℕ 0 1 r ≤ x + k ↔ ∀ k ∈ ℕ 0 1 r ≤ t + k
13 9 12 anbi12d ⊢ x = t → x ≤ r ∧ ∀ k ∈ ℕ 0 1 r ≤ x + k ↔ t ≤ r ∧ ∀ k ∈ ℕ 0 1 r ≤ t + k
14 13 cbvrabv ⊢ x ∈ ℂ | x ≤ r ∧ ∀ k ∈ ℕ 0 1 r ≤ x + k = t ∈ ℂ | t ≤ r ∧ ∀ k ∈ ℕ 0 1 r ≤ t + k
15 1 14 eqtri ⊢ U = t ∈ ℂ | t ≤ r ∧ ∀ k ∈ ℕ 0 1 r ≤ t + k
16 eqid ⊢ m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 = m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1
17 7 15 16 lgamgulm2 ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → ∀ z ∈ U log Γ ⁡ z ∈ ℂ ∧ seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 ⇝u ⁡ U z ∈ U ⟼ log Γ ⁡ z + log ⁡ z
18 17 simpld ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → ∀ z ∈ U log Γ ⁡ z ∈ ℂ
19 simprr ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → A ∈ U
20 6 18 19 rspcdva ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → log Γ ⁡ A ∈ ℂ
21 nnuz ⊢ ℕ = ℤ ≥ 1
22 1zzd ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → 1 ∈ ℤ
23 1z ⊢ 1 ∈ ℤ
24 seqfn ⊢ 1 ∈ ℤ → seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 Fn ℤ ≥ 1
25 23 24 ax-mp ⊢ seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 Fn ℤ ≥ 1
26 21 fneq2i ⊢ seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 Fn ℕ ↔ seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 Fn ℤ ≥ 1
27 25 26 mpbir ⊢ seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 Fn ℕ
28 17 simprd ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 ⇝u ⁡ U z ∈ U ⟼ log Γ ⁡ z + log ⁡ z
29 ulmf2 ⊢ seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 Fn ℕ ∧ seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 ⇝u ⁡ U z ∈ U ⟼ log Γ ⁡ z + log ⁡ z → seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 : ℕ ⟶ ℂ U
30 27 28 29 sylancr ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 : ℕ ⟶ ℂ U
31 seqex ⊢ seq 1 + G ∈ V
32 31 a1i ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → seq 1 + G ∈ V
33 cnex ⊢ ℂ ∈ V
34 1 33 rabex2 ⊢ U ∈ V
35 34 a1i ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ → U ∈ V
36 simpr ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ → n ∈ ℕ
37 36 21 eleqtrdi ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ → n ∈ ℤ ≥ 1
38 fz1ssnn ⊢ 1 … n ⊆ ℕ
39 38 a1i ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ → 1 … n ⊆ ℕ
40 ovexd ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ ∧ m ∈ ℕ ∧ z ∈ U → z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 ∈ V
41 35 37 39 40 seqof2 ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ → seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 ⁡ n = z ∈ U ⟼ seq 1 + m ∈ ℕ ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 ⁡ n
42 simplr ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ ∧ z = A ∧ m ∈ ℕ → z = A
43 42 oveq1d ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ ∧ z = A ∧ m ∈ ℕ → z ⁢ log ⁡ m + 1 m = A ⁢ log ⁡ m + 1 m
44 42 oveq1d ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ ∧ z = A ∧ m ∈ ℕ → z m = A m
45 44 fvoveq1d ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ ∧ z = A ∧ m ∈ ℕ → log ⁡ z m + 1 = log ⁡ A m + 1
46 43 45 oveq12d ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ ∧ z = A ∧ m ∈ ℕ → z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 = A ⁢ log ⁡ m + 1 m − log ⁡ A m + 1
47 46 mpteq2dva ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ ∧ z = A → m ∈ ℕ ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 = m ∈ ℕ ⟼ A ⁢ log ⁡ m + 1 m − log ⁡ A m + 1
48 47 3 eqtr4di ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ ∧ z = A → m ∈ ℕ ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 = G
49 48 seqeq3d ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ ∧ z = A → seq 1 + m ∈ ℕ ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 = seq 1 + G
50 49 fveq1d ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ ∧ z = A → seq 1 + m ∈ ℕ ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 ⁡ n = seq 1 + G ⁡ n
51 simplrr ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ → A ∈ U
52 fvexd ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ → seq 1 + G ⁡ n ∈ V
53 41 50 51 52 fvmptd ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U ∧ n ∈ ℕ → seq 1 ∘ f ⁡ + m ∈ ℕ ⟼ z ∈ U ⟼ z ⁢ log ⁡ m + 1 m − log ⁡ z m + 1 ⁡ n ⁡ A = seq 1 + G ⁡ n
54 21 22 30 19 32 53 28 ulmclm ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → seq 1 + G ⇝ z ∈ U ⟼ log Γ ⁡ z + log ⁡ z ⁡ A
55 fveq2 ⊢ z = A → log ⁡ z = log ⁡ A
56 5 55 oveq12d ⊢ z = A → log Γ ⁡ z + log ⁡ z = log Γ ⁡ A + log ⁡ A
57 eqid ⊢ z ∈ U ⟼ log Γ ⁡ z + log ⁡ z = z ∈ U ⟼ log Γ ⁡ z + log ⁡ z
58 ovex ⊢ log Γ ⁡ A + log ⁡ A ∈ V
59 56 57 58 fvmpt ⊢ A ∈ U → z ∈ U ⟼ log Γ ⁡ z + log ⁡ z ⁡ A = log Γ ⁡ A + log ⁡ A
60 19 59 syl ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → z ∈ U ⟼ log Γ ⁡ z + log ⁡ z ⁡ A = log Γ ⁡ A + log ⁡ A
61 54 60 breqtrd ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → seq 1 + G ⇝ log Γ ⁡ A + log ⁡ A
62 20 61 jca ⊢ φ ∧ r ∈ ℕ ∧ A ∈ U → log Γ ⁡ A ∈ ℂ ∧ seq 1 + G ⇝ log Γ ⁡ A + log ⁡ A
63 4 62 rexlimddv ⊢ φ → log Γ ⁡ A ∈ ℂ ∧ seq 1 + G ⇝ log Γ ⁡ A + log ⁡ A