Metamath Proof Explorer


Theorem mhpsclcl

Description: A scalar (or constant) polynomial has degree 0. Compare deg1scl . In other contexts, there may be an exception for the zero polynomial, but under df-mhp the zero polynomial can be any degree (see mhp0cl ) so there is no exception. (Contributed by SN, 25-May-2024)

Ref Expression
Hypotheses mhpsclcl.h ⊢ H = I mHomP R
mhpsclcl.p ⊢ P = I mPoly R
mhpsclcl.a ⊢ A = algSc ⁡ P
mhpsclcl.k ⊢ K = Base R
mhpsclcl.i ⊢ φ → I ∈ V
mhpsclcl.r ⊢ φ → R ∈ Ring
mhpsclcl.c ⊢ φ → C ∈ K
Assertion mhpsclcl ⊢ φ → A ⁡ C ∈ H ⁡ 0

Proof

Step Hyp Ref Expression
1 mhpsclcl.h ⊢ H = I mHomP R
2 mhpsclcl.p ⊢ P = I mPoly R
3 mhpsclcl.a ⊢ A = algSc ⁡ P
4 mhpsclcl.k ⊢ K = Base R
5 mhpsclcl.i ⊢ φ → I ∈ V
6 mhpsclcl.r ⊢ φ → R ∈ Ring
7 mhpsclcl.c ⊢ φ → C ∈ K
8 eqid ⊢ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin = h ∈ ℕ 0 I | h -1 ℕ ∈ Fin
9 eqid ⊢ 0 R = 0 R
10 5 adantr ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → I ∈ V
11 6 adantr ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → R ∈ Ring
12 7 adantr ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → C ∈ K
13 2 8 9 4 3 10 11 12 mplascl ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → A ⁡ C = y ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ⟼ if y = I × 0 C 0 R
14 eqeq1 ⊢ y = d → y = I × 0 ↔ d = I × 0
15 14 ifbid ⊢ y = d → if y = I × 0 C 0 R = if d = I × 0 C 0 R
16 15 adantl ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin ∧ y = d → if y = I × 0 C 0 R = if d = I × 0 C 0 R
17 simpr ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin
18 fvexd ⊢ φ → 0 R ∈ V
19 7 18 ifexd ⊢ φ → if d = I × 0 C 0 R ∈ V
20 19 adantr ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → if d = I × 0 C 0 R ∈ V
21 13 16 17 20 fvmptd ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → A ⁡ C ⁡ d = if d = I × 0 C 0 R
22 21 neeq1d ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → A ⁡ C ⁡ d ≠ 0 R ↔ if d = I × 0 C 0 R ≠ 0 R
23 iffalse ⊢ ¬ d = I × 0 → if d = I × 0 C 0 R = 0 R
24 23 necon1ai ⊢ if d = I × 0 C 0 R ≠ 0 R → d = I × 0
25 fconstmpt ⊢ I × 0 = k ∈ I ⟼ 0
26 25 oveq2i ⊢ ∑ ℂ fld ↾ 𝑠 ℕ 0 I × 0 = ∑ ℂ fld ↾ 𝑠 ℕ 0 k ∈ I 0
27 nn0subm ⊢ ℕ 0 ∈ SubMnd ⁡ ℂ fld
28 eqid ⊢ ℂ fld ↾ 𝑠 ℕ 0 = ℂ fld ↾ 𝑠 ℕ 0
29 28 submmnd ⊢ ℕ 0 ∈ SubMnd ⁡ ℂ fld → ℂ fld ↾ 𝑠 ℕ 0 ∈ Mnd
30 27 29 ax-mp ⊢ ℂ fld ↾ 𝑠 ℕ 0 ∈ Mnd
31 cnfld0 ⊢ 0 = 0 ℂ fld
32 28 31 subm0 ⊢ ℕ 0 ∈ SubMnd ⁡ ℂ fld → 0 = 0 ℂ fld ↾ 𝑠 ℕ 0
33 27 32 ax-mp ⊢ 0 = 0 ℂ fld ↾ 𝑠 ℕ 0
34 33 gsumz ⊢ ℂ fld ↾ 𝑠 ℕ 0 ∈ Mnd ∧ I ∈ V → ∑ ℂ fld ↾ 𝑠 ℕ 0 k ∈ I 0 = 0
35 30 10 34 sylancr ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → ∑ ℂ fld ↾ 𝑠 ℕ 0 k ∈ I 0 = 0
36 26 35 eqtrid ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → ∑ ℂ fld ↾ 𝑠 ℕ 0 I × 0 = 0
37 oveq2 ⊢ d = I × 0 → ∑ ℂ fld ↾ 𝑠 ℕ 0 d = ∑ ℂ fld ↾ 𝑠 ℕ 0 I × 0
38 37 eqeq1d ⊢ d = I × 0 → ∑ ℂ fld ↾ 𝑠 ℕ 0 d = 0 ↔ ∑ ℂ fld ↾ 𝑠 ℕ 0 I × 0 = 0
39 36 38 syl5ibrcom ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → d = I × 0 → ∑ ℂ fld ↾ 𝑠 ℕ 0 d = 0
40 24 39 syl5 ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → if d = I × 0 C 0 R ≠ 0 R → ∑ ℂ fld ↾ 𝑠 ℕ 0 d = 0
41 22 40 sylbid ⊢ φ ∧ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin → A ⁡ C ⁡ d ≠ 0 R → ∑ ℂ fld ↾ 𝑠 ℕ 0 d = 0
42 41 ralrimiva ⊢ φ → ∀ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin A ⁡ C ⁡ d ≠ 0 R → ∑ ℂ fld ↾ 𝑠 ℕ 0 d = 0
43 eqid ⊢ Base P = Base P
44 0nn0 ⊢ 0 ∈ ℕ 0
45 44 a1i ⊢ φ → 0 ∈ ℕ 0
46 2 43 4 3 5 6 mplasclf ⊢ φ → A : K ⟶ Base P
47 46 7 ffvelcdmd ⊢ φ → A ⁡ C ∈ Base P
48 1 2 43 9 8 45 47 ismhp3 ⊢ φ → A ⁡ C ∈ H ⁡ 0 ↔ ∀ d ∈ h ∈ ℕ 0 I | h -1 ℕ ∈ Fin A ⁡ C ⁡ d ≠ 0 R → ∑ ℂ fld ↾ 𝑠 ℕ 0 d = 0
49 42 48 mpbird ⊢ φ → A ⁡ C ∈ H ⁡ 0