Metamath Proof Explorer


Theorem sinnpoly

Description: Sine function is not a polynomial with complex coefficients. Indeed, it has infinitely many zeros but is not constant zero, contrary to fta1 . (Contributed by Ender Ting, 10-Dec-2025)

Ref Expression
Assertion sinnpoly ⊢ ¬ sin ∈ Poly ⁡ ℂ

Proof

Step Hyp Ref Expression
1 nnnfi ⊢ ¬ ℕ ∈ Fin
2 4re ⊢ 4 ∈ ℝ
3 resincl ⊢ 4 ∈ ℝ → sin ⁡ 4 ∈ ℝ
4 2 3 ax-mp ⊢ sin ⁡ 4 ∈ ℝ
5 sin4lt0 ⊢ sin ⁡ 4 < 0
6 df-0p ⊢ 0 𝑝 = ℂ × 0
7 6 fveq1i ⊢ 0 𝑝 ⁡ 4 = ℂ × 0 ⁡ 4
8 4cn ⊢ 4 ∈ ℂ
9 c0ex ⊢ 0 ∈ V
10 9 fvconst2 ⊢ 4 ∈ ℂ → ℂ × 0 ⁡ 4 = 0
11 8 10 ax-mp ⊢ ℂ × 0 ⁡ 4 = 0
12 7 11 eqtri ⊢ 0 𝑝 ⁡ 4 = 0
13 5 12 breqtrri ⊢ sin ⁡ 4 < 0 𝑝 ⁡ 4
14 4 13 ltneii ⊢ sin ⁡ 4 ≠ 0 𝑝 ⁡ 4
15 fveq1 ⊢ sin = 0 𝑝 → sin ⁡ 4 = 0 𝑝 ⁡ 4
16 15 necon3i ⊢ sin ⁡ 4 ≠ 0 𝑝 ⁡ 4 → sin ≠ 0 𝑝
17 14 16 ax-mp ⊢ sin ≠ 0 𝑝
18 eqid ⊢ sin -1 0 = sin -1 0
19 18 fta1 ⊢ sin ∈ Poly ⁡ ℂ ∧ sin ≠ 0 𝑝 → sin -1 0 ∈ Fin ∧ sin -1 0 ≤ deg ⁡ sin
20 17 19 mpan2 ⊢ sin ∈ Poly ⁡ ℂ → sin -1 0 ∈ Fin ∧ sin -1 0 ≤ deg ⁡ sin
21 20 simpld ⊢ sin ∈ Poly ⁡ ℂ → sin -1 0 ∈ Fin
22 eqid ⊢ z ∈ ℤ ⟼ z ⁢ π = z ∈ ℤ ⟼ z ⁢ π
23 sinkpi ⊢ z ∈ ℤ → sin ⁡ z ⁢ π = 0
24 9 snid ⊢ 0 ∈ 0
25 23 24 eqeltrdi ⊢ z ∈ ℤ → sin ⁡ z ⁢ π ∈ 0
26 sinf ⊢ sin : ℂ ⟶ ℂ
27 ffun ⊢ sin : ℂ ⟶ ℂ → Fun ⁡ sin
28 26 27 ax-mp ⊢ Fun ⁡ sin
29 zcn ⊢ z ∈ ℤ → z ∈ ℂ
30 picn ⊢ π ∈ ℂ
31 mulcl ⊢ z ∈ ℂ ∧ π ∈ ℂ → z ⁢ π ∈ ℂ
32 29 30 31 sylancl ⊢ z ∈ ℤ → z ⁢ π ∈ ℂ
33 26 fdmi ⊢ dom ⁡ sin = ℂ
34 32 33 eleqtrrdi ⊢ z ∈ ℤ → z ⁢ π ∈ dom ⁡ sin
35 fvimacnv ⊢ Fun ⁡ sin ∧ z ⁢ π ∈ dom ⁡ sin → sin ⁡ z ⁢ π ∈ 0 ↔ z ⁢ π ∈ sin -1 0
36 28 34 35 sylancr ⊢ z ∈ ℤ → sin ⁡ z ⁢ π ∈ 0 ↔ z ⁢ π ∈ sin -1 0
37 25 36 mpbid ⊢ z ∈ ℤ → z ⁢ π ∈ sin -1 0
38 22 37 fmpti ⊢ z ∈ ℤ ⟼ z ⁢ π : ℤ ⟶ sin -1 0
39 vex ⊢ x ∈ V
40 vex ⊢ y ∈ V
41 eleq1w ⊢ z = x → z ∈ ℤ ↔ x ∈ ℤ
42 41 adantr ⊢ z = x ∧ t = y → z ∈ ℤ ↔ x ∈ ℤ
43 eqeq1 ⊢ t = y → t = z ⁢ π ↔ y = z ⁢ π
44 oveq1 ⊢ z = x → z ⁢ π = x ⁢ π
45 44 eqeq2d ⊢ z = x → y = z ⁢ π ↔ y = x ⁢ π
46 43 45 sylan9bbr ⊢ z = x ∧ t = y → t = z ⁢ π ↔ y = x ⁢ π
47 42 46 anbi12d ⊢ z = x ∧ t = y → z ∈ ℤ ∧ t = z ⁢ π ↔ x ∈ ℤ ∧ y = x ⁢ π
48 df-mpt ⊢ z ∈ ℤ ⟼ z ⁢ π = z t | z ∈ ℤ ∧ t = z ⁢ π
49 39 40 47 48 braba ⊢ x z ∈ ℤ ⟼ z ⁢ π y ↔ x ∈ ℤ ∧ y = x ⁢ π
50 49 mobii ⊢ ∃* x x z ∈ ℤ ⟼ z ⁢ π y ↔ ∃* x x ∈ ℤ ∧ y = x ⁢ π
51 50 albii ⊢ ∀ y ∃* x x z ∈ ℤ ⟼ z ⁢ π y ↔ ∀ y ∃* x x ∈ ℤ ∧ y = x ⁢ π
52 moeq ⊢ ∃* x x = y π
53 simpr ⊢ x ∈ ℤ ∧ y = x ⁢ π → y = x ⁢ π
54 53 oveq1d ⊢ x ∈ ℤ ∧ y = x ⁢ π → y π = x ⁢ π π
55 zcn ⊢ x ∈ ℤ → x ∈ ℂ
56 55 adantr ⊢ x ∈ ℤ ∧ y = x ⁢ π → x ∈ ℂ
57 pine0 ⊢ π ≠ 0
58 divcan4 ⊢ x ∈ ℂ ∧ π ∈ ℂ ∧ π ≠ 0 → x ⁢ π π = x
59 30 57 58 mp3an23 ⊢ x ∈ ℂ → x ⁢ π π = x
60 56 59 syl ⊢ x ∈ ℤ ∧ y = x ⁢ π → x ⁢ π π = x
61 54 60 eqtr2d ⊢ x ∈ ℤ ∧ y = x ⁢ π → x = y π
62 61 moimi ⊢ ∃* x x = y π → ∃* x x ∈ ℤ ∧ y = x ⁢ π
63 52 62 ax-mp ⊢ ∃* x x ∈ ℤ ∧ y = x ⁢ π
64 51 63 mpgbir ⊢ ∀ y ∃* x x z ∈ ℤ ⟼ z ⁢ π y
65 dff12 ⊢ z ∈ ℤ ⟼ z ⁢ π : ℤ ⟶ 1-1 sin -1 0 ↔ z ∈ ℤ ⟼ z ⁢ π : ℤ ⟶ sin -1 0 ∧ ∀ y ∃* x x z ∈ ℤ ⟼ z ⁢ π y
66 38 64 65 mpbir2an ⊢ z ∈ ℤ ⟼ z ⁢ π : ℤ ⟶ 1-1 sin -1 0
67 f1fi ⊢ sin -1 0 ∈ Fin ∧ z ∈ ℤ ⟼ z ⁢ π : ℤ ⟶ 1-1 sin -1 0 → ℤ ∈ Fin
68 nnssz ⊢ ℕ ⊆ ℤ
69 ssfi ⊢ ℤ ∈ Fin ∧ ℕ ⊆ ℤ → ℕ ∈ Fin
70 67 68 69 sylancl ⊢ sin -1 0 ∈ Fin ∧ z ∈ ℤ ⟼ z ⁢ π : ℤ ⟶ 1-1 sin -1 0 → ℕ ∈ Fin
71 21 66 70 sylancl ⊢ sin ∈ Poly ⁡ ℂ → ℕ ∈ Fin
72 1 71 mto ⊢ ¬ sin ∈ Poly ⁡ ℂ