Metamath Proof Explorer


Theorem tfsconcat0i

Description: The concatentation with the empty series leaves the series unchanged. (Contributed by RP, 28-Feb-2025)

Ref Expression
Hypothesis tfsconcat.op + ˙ = a V , b V a x y | x dom a + 𝑜 dom b dom a z dom b x = dom a + 𝑜 z y = b z
Assertion tfsconcat0i A Fn C B Fn D C On D On A = A + ˙ B = B

Proof

Step Hyp Ref Expression
1 tfsconcat.op + ˙ = a V , b V a x y | x dom a + 𝑜 dom b dom a z dom b x = dom a + 𝑜 z y = b z
2 simpr A Fn C B Fn D C On D On A = A =
3 fnrel A Fn C Rel A
4 reldm0 Rel A A = dom A =
5 3 4 syl A Fn C A = dom A =
6 fndm A Fn C dom A = C
7 6 eqeq1d A Fn C dom A = C =
8 5 7 bitrd A Fn C A = C =
9 8 ad2antrr A Fn C B Fn D C On D On A = C =
10 simpr A Fn C B Fn D B Fn D
11 simpr C On D On D On
12 10 11 anim12i A Fn C B Fn D C On D On B Fn D D On
13 12 anim1i A Fn C B Fn D C On D On C = B Fn D D On C =
14 9 13 sylbida A Fn C B Fn D C On D On A = B Fn D D On C =
15 oveq1 C = C + 𝑜 D = + 𝑜 D
16 id C = C =
17 15 16 difeq12d C = C + 𝑜 D C = + 𝑜 D
18 dif0 + 𝑜 D = + 𝑜 D
19 17 18 eqtrdi C = C + 𝑜 D C = + 𝑜 D
20 19 eleq2d C = x C + 𝑜 D C x + 𝑜 D
21 oveq1 C = C + 𝑜 z = + 𝑜 z
22 21 eqeq2d C = x = C + 𝑜 z x = + 𝑜 z
23 22 anbi1d C = x = C + 𝑜 z y = B z x = + 𝑜 z y = B z
24 23 rexbidv C = z D x = C + 𝑜 z y = B z z D x = + 𝑜 z y = B z
25 20 24 anbi12d C = x C + 𝑜 D C z D x = C + 𝑜 z y = B z x + 𝑜 D z D x = + 𝑜 z y = B z
26 oa0r D On + 𝑜 D = D
27 26 eleq2d D On x + 𝑜 D x D
28 onelon D On z D z On
29 oa0r z On + 𝑜 z = z
30 29 eqeq2d z On x = + 𝑜 z x = z
31 30 anbi1d z On x = + 𝑜 z y = B z x = z y = B z
32 28 31 syl D On z D x = + 𝑜 z y = B z x = z y = B z
33 32 rexbidva D On z D x = + 𝑜 z y = B z z D x = z y = B z
34 27 33 anbi12d D On x + 𝑜 D z D x = + 𝑜 z y = B z x D z D x = z y = B z
35 df-rex z D x = z y = B z z z D x = z y = B z
36 an12 z D x = z y = B z x = z z D y = B z
37 eqcom x = z z = x
38 37 anbi1i x = z z D y = B z z = x z D y = B z
39 36 38 bitri z D x = z y = B z z = x z D y = B z
40 39 exbii z z D x = z y = B z z z = x z D y = B z
41 eleq1w z = x z D x D
42 fveq2 z = x B z = B x
43 42 eqeq2d z = x y = B z y = B x
44 41 43 anbi12d z = x z D y = B z x D y = B x
45 44 equsexvw z z = x z D y = B z x D y = B x
46 35 40 45 3bitri z D x = z y = B z x D y = B x
47 46 baib x D z D x = z y = B z y = B x
48 47 adantl B Fn D x D z D x = z y = B z y = B x
49 eqcom y = B x B x = y
50 48 49 bitrdi B Fn D x D z D x = z y = B z B x = y
51 fnbrfvb B Fn D x D B x = y x B y
52 50 51 bitrd B Fn D x D z D x = z y = B z x B y
53 52 pm5.32da B Fn D x D z D x = z y = B z x D x B y
54 fnbr B Fn D x B y x D
55 54 ex B Fn D x B y x D
56 55 pm4.71rd B Fn D x B y x D x B y
57 df-br x B y x y B
58 56 57 bitr3di B Fn D x D x B y x y B
59 53 58 bitrd B Fn D x D z D x = z y = B z x y B
60 34 59 sylan9bbr B Fn D D On x + 𝑜 D z D x = + 𝑜 z y = B z x y B
61 25 60 sylan9bbr B Fn D D On C = x C + 𝑜 D C z D x = C + 𝑜 z y = B z x y B
62 61 opabbidv B Fn D D On C = x y | x C + 𝑜 D C z D x = C + 𝑜 z y = B z = x y | x y B
63 14 62 syl A Fn C B Fn D C On D On A = x y | x C + 𝑜 D C z D x = C + 𝑜 z y = B z = x y | x y B
64 fnrel B Fn D Rel B
65 opabid2 Rel B x y | x y B = B
66 64 65 syl B Fn D x y | x y B = B
67 66 adantl A Fn C B Fn D x y | x y B = B
68 67 ad2antrr A Fn C B Fn D C On D On A = x y | x y B = B
69 63 68 eqtrd A Fn C B Fn D C On D On A = x y | x C + 𝑜 D C z D x = C + 𝑜 z y = B z = B
70 2 69 uneq12d A Fn C B Fn D C On D On A = A x y | x C + 𝑜 D C z D x = C + 𝑜 z y = B z = B
71 0un B = B
72 70 71 eqtrdi A Fn C B Fn D C On D On A = A x y | x C + 𝑜 D C z D x = C + 𝑜 z y = B z = B
73 72 ex A Fn C B Fn D C On D On A = A x y | x C + 𝑜 D C z D x = C + 𝑜 z y = B z = B
74 1 tfsconcatun A Fn C B Fn D C On D On A + ˙ B = A x y | x C + 𝑜 D C z D x = C + 𝑜 z y = B z
75 74 eqeq1d A Fn C B Fn D C On D On A + ˙ B = B A x y | x C + 𝑜 D C z D x = C + 𝑜 z y = B z = B
76 73 75 sylibrd A Fn C B Fn D C On D On A = A + ˙ B = B