Metamath Proof Explorer


Theorem dihlspsnat

Description: The inverse isomorphism H of the span of a singleton is a Hilbert lattice atom. (Contributed by NM, 27-Apr-2014)

Ref Expression
Hypotheses dihlspsnat.a ⊢ A = Atoms ⁡ K
dihlspsnat.h ⊢ H = LHyp ⁡ K
dihlspsnat.u ⊢ U = DVecH ⁡ K ⁡ W
dihlspsnat.v ⊢ V = Base U
dihlspsnat.o ⊢ 0 ˙ = 0 U
dihlspsnat.n ⊢ N = LSpan ⁡ U
dihlspsnat.i ⊢ I = DIsoH ⁡ K ⁡ W
Assertion dihlspsnat ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ → I -1 ⁡ N ⁡ X ∈ A

Proof

Step Hyp Ref Expression
1 dihlspsnat.a ⊢ A = Atoms ⁡ K
2 dihlspsnat.h ⊢ H = LHyp ⁡ K
3 dihlspsnat.u ⊢ U = DVecH ⁡ K ⁡ W
4 dihlspsnat.v ⊢ V = Base U
5 dihlspsnat.o ⊢ 0 ˙ = 0 U
6 dihlspsnat.n ⊢ N = LSpan ⁡ U
7 dihlspsnat.i ⊢ I = DIsoH ⁡ K ⁡ W
8 eqid ⊢ Base K = Base K
9 eqid ⊢ LSubSp ⁡ U = LSubSp ⁡ U
10 8 2 7 3 9 dihf11 ⊢ K ∈ HL ∧ W ∈ H → I : Base K ⟶ 1-1 LSubSp ⁡ U
11 10 3ad2ant1 ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ → I : Base K ⟶ 1-1 LSubSp ⁡ U
12 f1f1orn ⊢ I : Base K ⟶ 1-1 LSubSp ⁡ U → I : Base K ⟶ 1-1 onto ran ⁡ I
13 11 12 syl ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ → I : Base K ⟶ 1-1 onto ran ⁡ I
14 2 3 4 6 7 dihlsprn ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V → N ⁡ X ∈ ran ⁡ I
15 14 3adant3 ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ → N ⁡ X ∈ ran ⁡ I
16 f1ocnvdm ⊢ I : Base K ⟶ 1-1 onto ran ⁡ I ∧ N ⁡ X ∈ ran ⁡ I → I -1 ⁡ N ⁡ X ∈ Base K
17 13 15 16 syl2anc ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ → I -1 ⁡ N ⁡ X ∈ Base K
18 fveq2 ⊢ I -1 ⁡ N ⁡ X = 0. ⁡ K → I ⁡ I -1 ⁡ N ⁡ X = I ⁡ 0. ⁡ K
19 2 7 dihcnvid2 ⊢ K ∈ HL ∧ W ∈ H ∧ N ⁡ X ∈ ran ⁡ I → I ⁡ I -1 ⁡ N ⁡ X = N ⁡ X
20 14 19 syldan ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V → I ⁡ I -1 ⁡ N ⁡ X = N ⁡ X
21 eqid ⊢ 0. ⁡ K = 0. ⁡ K
22 21 2 7 3 5 dih0 ⊢ K ∈ HL ∧ W ∈ H → I ⁡ 0. ⁡ K = 0 ˙
23 22 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V → I ⁡ 0. ⁡ K = 0 ˙
24 20 23 eqeq12d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V → I ⁡ I -1 ⁡ N ⁡ X = I ⁡ 0. ⁡ K ↔ N ⁡ X = 0 ˙
25 id ⊢ K ∈ HL ∧ W ∈ H → K ∈ HL ∧ W ∈ H
26 2 3 25 dvhlmod ⊢ K ∈ HL ∧ W ∈ H → U ∈ LMod
27 4 5 6 lspsneq0 ⊢ U ∈ LMod ∧ X ∈ V → N ⁡ X = 0 ˙ ↔ X = 0 ˙
28 26 27 sylan ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V → N ⁡ X = 0 ˙ ↔ X = 0 ˙
29 24 28 bitrd ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V → I ⁡ I -1 ⁡ N ⁡ X = I ⁡ 0. ⁡ K ↔ X = 0 ˙
30 18 29 imbitrid ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V → I -1 ⁡ N ⁡ X = 0. ⁡ K → X = 0 ˙
31 30 necon3d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V → X ≠ 0 ˙ → I -1 ⁡ N ⁡ X ≠ 0. ⁡ K
32 31 3impia ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ → I -1 ⁡ N ⁡ X ≠ 0. ⁡ K
33 simpll1 ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K ∧ I ⁡ x ⊆ N ⁡ X → K ∈ HL ∧ W ∈ H
34 2 3 33 dvhlvec ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K ∧ I ⁡ x ⊆ N ⁡ X → U ∈ LVec
35 simplr ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K ∧ I ⁡ x ⊆ N ⁡ X → x ∈ Base K
36 8 2 7 3 9 dihlss ⊢ K ∈ HL ∧ W ∈ H ∧ x ∈ Base K → I ⁡ x ∈ LSubSp ⁡ U
37 33 35 36 syl2anc ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K ∧ I ⁡ x ⊆ N ⁡ X → I ⁡ x ∈ LSubSp ⁡ U
38 simpll2 ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K ∧ I ⁡ x ⊆ N ⁡ X → X ∈ V
39 simpr ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K ∧ I ⁡ x ⊆ N ⁡ X → I ⁡ x ⊆ N ⁡ X
40 4 5 9 6 lspsnat ⊢ U ∈ LVec ∧ I ⁡ x ∈ LSubSp ⁡ U ∧ X ∈ V ∧ I ⁡ x ⊆ N ⁡ X → I ⁡ x = N ⁡ X ∨ I ⁡ x = 0 ˙
41 34 37 38 39 40 syl31anc ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K ∧ I ⁡ x ⊆ N ⁡ X → I ⁡ x = N ⁡ X ∨ I ⁡ x = 0 ˙
42 41 ex ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ x ⊆ N ⁡ X → I ⁡ x = N ⁡ X ∨ I ⁡ x = 0 ˙
43 simp1 ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ → K ∈ HL ∧ W ∈ H
44 43 15 19 syl2anc ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ → I ⁡ I -1 ⁡ N ⁡ X = N ⁡ X
45 44 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ I -1 ⁡ N ⁡ X = N ⁡ X
46 45 sseq2d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ x ⊆ I ⁡ I -1 ⁡ N ⁡ X ↔ I ⁡ x ⊆ N ⁡ X
47 simpl1 ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → K ∈ HL ∧ W ∈ H
48 simpr ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → x ∈ Base K
49 17 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I -1 ⁡ N ⁡ X ∈ Base K
50 eqid ⊢ ≤ K = ≤ K
51 8 50 2 7 dihord ⊢ K ∈ HL ∧ W ∈ H ∧ x ∈ Base K ∧ I -1 ⁡ N ⁡ X ∈ Base K → I ⁡ x ⊆ I ⁡ I -1 ⁡ N ⁡ X ↔ x ≤ K I -1 ⁡ N ⁡ X
52 47 48 49 51 syl3anc ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ x ⊆ I ⁡ I -1 ⁡ N ⁡ X ↔ x ≤ K I -1 ⁡ N ⁡ X
53 46 52 bitr3d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ x ⊆ N ⁡ X ↔ x ≤ K I -1 ⁡ N ⁡ X
54 45 eqeq2d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ x = I ⁡ I -1 ⁡ N ⁡ X ↔ I ⁡ x = N ⁡ X
55 8 2 7 dih11 ⊢ K ∈ HL ∧ W ∈ H ∧ x ∈ Base K ∧ I -1 ⁡ N ⁡ X ∈ Base K → I ⁡ x = I ⁡ I -1 ⁡ N ⁡ X ↔ x = I -1 ⁡ N ⁡ X
56 47 48 49 55 syl3anc ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ x = I ⁡ I -1 ⁡ N ⁡ X ↔ x = I -1 ⁡ N ⁡ X
57 54 56 bitr3d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ x = N ⁡ X ↔ x = I -1 ⁡ N ⁡ X
58 47 22 syl ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ 0. ⁡ K = 0 ˙
59 58 eqeq2d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ x = I ⁡ 0. ⁡ K ↔ I ⁡ x = 0 ˙
60 simpl1l ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → K ∈ HL
61 hlop ⊢ K ∈ HL → K ∈ OP
62 8 21 op0cl ⊢ K ∈ OP → 0. ⁡ K ∈ Base K
63 60 61 62 3syl ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → 0. ⁡ K ∈ Base K
64 8 2 7 dih11 ⊢ K ∈ HL ∧ W ∈ H ∧ x ∈ Base K ∧ 0. ⁡ K ∈ Base K → I ⁡ x = I ⁡ 0. ⁡ K ↔ x = 0. ⁡ K
65 47 48 63 64 syl3anc ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ x = I ⁡ 0. ⁡ K ↔ x = 0. ⁡ K
66 59 65 bitr3d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ x = 0 ˙ ↔ x = 0. ⁡ K
67 57 66 orbi12d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → I ⁡ x = N ⁡ X ∨ I ⁡ x = 0 ˙ ↔ x = I -1 ⁡ N ⁡ X ∨ x = 0. ⁡ K
68 42 53 67 3imtr3d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ ∧ x ∈ Base K → x ≤ K I -1 ⁡ N ⁡ X → x = I -1 ⁡ N ⁡ X ∨ x = 0. ⁡ K
69 68 ralrimiva ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ → ∀ x ∈ Base K x ≤ K I -1 ⁡ N ⁡ X → x = I -1 ⁡ N ⁡ X ∨ x = 0. ⁡ K
70 simp1l ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ → K ∈ HL
71 hlatl ⊢ K ∈ HL → K ∈ AtLat
72 8 50 21 1 isat3 ⊢ K ∈ AtLat → I -1 ⁡ N ⁡ X ∈ A ↔ I -1 ⁡ N ⁡ X ∈ Base K ∧ I -1 ⁡ N ⁡ X ≠ 0. ⁡ K ∧ ∀ x ∈ Base K x ≤ K I -1 ⁡ N ⁡ X → x = I -1 ⁡ N ⁡ X ∨ x = 0. ⁡ K
73 70 71 72 3syl ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ → I -1 ⁡ N ⁡ X ∈ A ↔ I -1 ⁡ N ⁡ X ∈ Base K ∧ I -1 ⁡ N ⁡ X ≠ 0. ⁡ K ∧ ∀ x ∈ Base K x ≤ K I -1 ⁡ N ⁡ X → x = I -1 ⁡ N ⁡ X ∨ x = 0. ⁡ K
74 17 32 69 73 mpbir3and ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ V ∧ X ≠ 0 ˙ → I -1 ⁡ N ⁡ X ∈ A