Metamath Proof Explorer


Theorem hdmapip0

Description: Zero property that will be used for inner product. (Contributed by NM, 9-Jun-2015)

Ref Expression
Hypotheses hdmapip0.h ⊢ H = LHyp ⁡ K
hdmapip0.u ⊢ U = DVecH ⁡ K ⁡ W
hdmapip0.v ⊢ V = Base U
hdmapip0.o ⊢ 0 ˙ = 0 U
hdmapip0.r ⊢ R = Scalar ⁡ U
hdmapip0.z ⊢ Z = 0 R
hdmapip0.s ⊢ S = HDMap ⁡ K ⁡ W
hdmapip0.k ⊢ φ → K ∈ HL ∧ W ∈ H
hdmapip0.x ⊢ φ → X ∈ V
Assertion hdmapip0 ⊢ φ → S ⁡ X ⁡ X = Z ↔ X = 0 ˙

Proof

Step Hyp Ref Expression
1 hdmapip0.h ⊢ H = LHyp ⁡ K
2 hdmapip0.u ⊢ U = DVecH ⁡ K ⁡ W
3 hdmapip0.v ⊢ V = Base U
4 hdmapip0.o ⊢ 0 ˙ = 0 U
5 hdmapip0.r ⊢ R = Scalar ⁡ U
6 hdmapip0.z ⊢ Z = 0 R
7 hdmapip0.s ⊢ S = HDMap ⁡ K ⁡ W
8 hdmapip0.k ⊢ φ → K ∈ HL ∧ W ∈ H
9 hdmapip0.x ⊢ φ → X ∈ V
10 eqid ⊢ ocH ⁡ K ⁡ W = ocH ⁡ K ⁡ W
11 8 adantr ⊢ φ ∧ X ≠ 0 ˙ → K ∈ HL ∧ W ∈ H
12 9 anim1i ⊢ φ ∧ X ≠ 0 ˙ → X ∈ V ∧ X ≠ 0 ˙
13 eldifsn ⊢ X ∈ V ∖ 0 ˙ ↔ X ∈ V ∧ X ≠ 0 ˙
14 12 13 sylibr ⊢ φ ∧ X ≠ 0 ˙ → X ∈ V ∖ 0 ˙
15 1 10 2 3 4 11 14 dochnel ⊢ φ ∧ X ≠ 0 ˙ → ¬ X ∈ ocH ⁡ K ⁡ W ⁡ X
16 eqid ⊢ LFnl ⁡ U = LFnl ⁡ U
17 eqid ⊢ LKer ⁡ U = LKer ⁡ U
18 1 2 8 dvhlmod ⊢ φ → U ∈ LMod
19 eqid ⊢ LCDual ⁡ K ⁡ W = LCDual ⁡ K ⁡ W
20 eqid ⊢ Base LCDual ⁡ K ⁡ W = Base LCDual ⁡ K ⁡ W
21 1 2 3 19 20 7 8 9 hdmapcl ⊢ φ → S ⁡ X ∈ Base LCDual ⁡ K ⁡ W
22 1 19 20 2 16 8 21 lcdvbaselfl ⊢ φ → S ⁡ X ∈ LFnl ⁡ U
23 3 5 6 16 17 18 22 9 ellkr2 ⊢ φ → X ∈ LKer ⁡ U ⁡ S ⁡ X ↔ S ⁡ X ⁡ X = Z
24 23 biimpar ⊢ φ ∧ S ⁡ X ⁡ X = Z → X ∈ LKer ⁡ U ⁡ S ⁡ X
25 1 10 2 3 16 17 7 8 9 hdmaplkr ⊢ φ → LKer ⁡ U ⁡ S ⁡ X = ocH ⁡ K ⁡ W ⁡ X
26 25 adantr ⊢ φ ∧ S ⁡ X ⁡ X = Z → LKer ⁡ U ⁡ S ⁡ X = ocH ⁡ K ⁡ W ⁡ X
27 24 26 eleqtrd ⊢ φ ∧ S ⁡ X ⁡ X = Z → X ∈ ocH ⁡ K ⁡ W ⁡ X
28 27 ex ⊢ φ → S ⁡ X ⁡ X = Z → X ∈ ocH ⁡ K ⁡ W ⁡ X
29 28 adantr ⊢ φ ∧ X ≠ 0 ˙ → S ⁡ X ⁡ X = Z → X ∈ ocH ⁡ K ⁡ W ⁡ X
30 15 29 mtod ⊢ φ ∧ X ≠ 0 ˙ → ¬ S ⁡ X ⁡ X = Z
31 30 neqned ⊢ φ ∧ X ≠ 0 ˙ → S ⁡ X ⁡ X ≠ Z
32 31 ex ⊢ φ → X ≠ 0 ˙ → S ⁡ X ⁡ X ≠ Z
33 32 necon4d ⊢ φ → S ⁡ X ⁡ X = Z → X = 0 ˙
34 33 imp ⊢ φ ∧ S ⁡ X ⁡ X = Z → X = 0 ˙
35 fveq2 ⊢ X = 0 ˙ → S ⁡ X ⁡ X = S ⁡ X ⁡ 0 ˙
36 5 6 4 16 lfl0 ⊢ U ∈ LMod ∧ S ⁡ X ∈ LFnl ⁡ U → S ⁡ X ⁡ 0 ˙ = Z
37 18 22 36 syl2anc ⊢ φ → S ⁡ X ⁡ 0 ˙ = Z
38 35 37 sylan9eqr ⊢ φ ∧ X = 0 ˙ → S ⁡ X ⁡ X = Z
39 34 38 impbida ⊢ φ → S ⁡ X ⁡ X = Z ↔ X = 0 ˙