Metamath Proof Explorer


Theorem lshpkrlem1

Description: Lemma for lshpkrex . The value of tentative functional G is zero iff its argument belongs to hyperplane U . (Contributed by NM, 14-Jul-2014)

Ref Expression
Hypotheses lshpkrlem.v ⊢ V = Base W
lshpkrlem.a ⊢ + ˙ = + W
lshpkrlem.n ⊢ N = LSpan ⁡ W
lshpkrlem.p ⊢ ⊕ ˙ = LSSum ⁡ W
lshpkrlem.h ⊢ H = LSHyp ⁡ W
lshpkrlem.w ⊢ φ → W ∈ LVec
lshpkrlem.u ⊢ φ → U ∈ H
lshpkrlem.z ⊢ φ → Z ∈ V
lshpkrlem.x ⊢ φ → X ∈ V
lshpkrlem.e ⊢ φ → U ⊕ ˙ N ⁡ Z = V
lshpkrlem.d ⊢ D = Scalar ⁡ W
lshpkrlem.k ⊢ K = Base D
lshpkrlem.t ⊢ · ˙ = ⋅ W
lshpkrlem.o ⊢ 0 ˙ = 0 D
lshpkrlem.g ⊢ G = x ∈ V ⟼ ι k ∈ K | ∃ y ∈ U x = y + ˙ k · ˙ Z
Assertion lshpkrlem1 ⊢ φ → X ∈ U ↔ G ⁡ X = 0 ˙

Proof

Step Hyp Ref Expression
1 lshpkrlem.v ⊢ V = Base W
2 lshpkrlem.a ⊢ + ˙ = + W
3 lshpkrlem.n ⊢ N = LSpan ⁡ W
4 lshpkrlem.p ⊢ ⊕ ˙ = LSSum ⁡ W
5 lshpkrlem.h ⊢ H = LSHyp ⁡ W
6 lshpkrlem.w ⊢ φ → W ∈ LVec
7 lshpkrlem.u ⊢ φ → U ∈ H
8 lshpkrlem.z ⊢ φ → Z ∈ V
9 lshpkrlem.x ⊢ φ → X ∈ V
10 lshpkrlem.e ⊢ φ → U ⊕ ˙ N ⁡ Z = V
11 lshpkrlem.d ⊢ D = Scalar ⁡ W
12 lshpkrlem.k ⊢ K = Base D
13 lshpkrlem.t ⊢ · ˙ = ⋅ W
14 lshpkrlem.o ⊢ 0 ˙ = 0 D
15 lshpkrlem.g ⊢ G = x ∈ V ⟼ ι k ∈ K | ∃ y ∈ U x = y + ˙ k · ˙ Z
16 lveclmod ⊢ W ∈ LVec → W ∈ LMod
17 6 16 syl ⊢ φ → W ∈ LMod
18 11 lmodfgrp ⊢ W ∈ LMod → D ∈ Grp
19 12 14 grpidcl ⊢ D ∈ Grp → 0 ˙ ∈ K
20 17 18 19 3syl ⊢ φ → 0 ˙ ∈ K
21 1 2 3 4 5 6 7 8 9 10 11 12 13 lshpsmreu ⊢ φ → ∃! k ∈ K ∃ b ∈ U X = b + ˙ k · ˙ Z
22 oveq1 ⊢ k = 0 ˙ → k · ˙ Z = 0 ˙ · ˙ Z
23 22 oveq2d ⊢ k = 0 ˙ → b + ˙ k · ˙ Z = b + ˙ 0 ˙ · ˙ Z
24 23 eqeq2d ⊢ k = 0 ˙ → X = b + ˙ k · ˙ Z ↔ X = b + ˙ 0 ˙ · ˙ Z
25 24 rexbidv ⊢ k = 0 ˙ → ∃ b ∈ U X = b + ˙ k · ˙ Z ↔ ∃ b ∈ U X = b + ˙ 0 ˙ · ˙ Z
26 25 riota2 ⊢ 0 ˙ ∈ K ∧ ∃! k ∈ K ∃ b ∈ U X = b + ˙ k · ˙ Z → ∃ b ∈ U X = b + ˙ 0 ˙ · ˙ Z ↔ ι k ∈ K | ∃ b ∈ U X = b + ˙ k · ˙ Z = 0 ˙
27 20 21 26 syl2anc ⊢ φ → ∃ b ∈ U X = b + ˙ 0 ˙ · ˙ Z ↔ ι k ∈ K | ∃ b ∈ U X = b + ˙ k · ˙ Z = 0 ˙
28 simpr ⊢ φ ∧ X ∈ U → X ∈ U
29 eqidd ⊢ φ ∧ X ∈ U → X = X
30 eqeq2 ⊢ b = X → X = b ↔ X = X
31 30 rspcev ⊢ X ∈ U ∧ X = X → ∃ b ∈ U X = b
32 28 29 31 syl2anc ⊢ φ ∧ X ∈ U → ∃ b ∈ U X = b
33 32 ex ⊢ φ → X ∈ U → ∃ b ∈ U X = b
34 eleq1a ⊢ b ∈ U → X = b → X ∈ U
35 34 a1i ⊢ φ → b ∈ U → X = b → X ∈ U
36 35 rexlimdv ⊢ φ → ∃ b ∈ U X = b → X ∈ U
37 33 36 impbid ⊢ φ → X ∈ U ↔ ∃ b ∈ U X = b
38 eqid ⊢ 0 W = 0 W
39 1 11 13 14 38 lmod0vs ⊢ W ∈ LMod ∧ Z ∈ V → 0 ˙ · ˙ Z = 0 W
40 17 8 39 syl2anc ⊢ φ → 0 ˙ · ˙ Z = 0 W
41 40 adantr ⊢ φ ∧ b ∈ U → 0 ˙ · ˙ Z = 0 W
42 41 oveq2d ⊢ φ ∧ b ∈ U → b + ˙ 0 ˙ · ˙ Z = b + ˙ 0 W
43 6 adantr ⊢ φ ∧ b ∈ U → W ∈ LVec
44 43 16 syl ⊢ φ ∧ b ∈ U → W ∈ LMod
45 eqid ⊢ LSubSp ⁡ W = LSubSp ⁡ W
46 45 5 17 7 lshplss ⊢ φ → U ∈ LSubSp ⁡ W
47 1 45 lssel ⊢ U ∈ LSubSp ⁡ W ∧ b ∈ U → b ∈ V
48 46 47 sylan ⊢ φ ∧ b ∈ U → b ∈ V
49 1 2 38 lmod0vrid ⊢ W ∈ LMod ∧ b ∈ V → b + ˙ 0 W = b
50 44 48 49 syl2anc ⊢ φ ∧ b ∈ U → b + ˙ 0 W = b
51 42 50 eqtrd ⊢ φ ∧ b ∈ U → b + ˙ 0 ˙ · ˙ Z = b
52 51 eqeq2d ⊢ φ ∧ b ∈ U → X = b + ˙ 0 ˙ · ˙ Z ↔ X = b
53 52 bicomd ⊢ φ ∧ b ∈ U → X = b ↔ X = b + ˙ 0 ˙ · ˙ Z
54 53 rexbidva ⊢ φ → ∃ b ∈ U X = b ↔ ∃ b ∈ U X = b + ˙ 0 ˙ · ˙ Z
55 37 54 bitrd ⊢ φ → X ∈ U ↔ ∃ b ∈ U X = b + ˙ 0 ˙ · ˙ Z
56 eqeq1 ⊢ x = X → x = y + ˙ k · ˙ Z ↔ X = y + ˙ k · ˙ Z
57 56 rexbidv ⊢ x = X → ∃ y ∈ U x = y + ˙ k · ˙ Z ↔ ∃ y ∈ U X = y + ˙ k · ˙ Z
58 57 riotabidv ⊢ x = X → ι k ∈ K | ∃ y ∈ U x = y + ˙ k · ˙ Z = ι k ∈ K | ∃ y ∈ U X = y + ˙ k · ˙ Z
59 riotaex ⊢ ι k ∈ K | ∃ y ∈ U X = y + ˙ k · ˙ Z ∈ V
60 58 15 59 fvmpt ⊢ X ∈ V → G ⁡ X = ι k ∈ K | ∃ y ∈ U X = y + ˙ k · ˙ Z
61 oveq1 ⊢ y = b → y + ˙ k · ˙ Z = b + ˙ k · ˙ Z
62 61 eqeq2d ⊢ y = b → X = y + ˙ k · ˙ Z ↔ X = b + ˙ k · ˙ Z
63 62 cbvrexvw ⊢ ∃ y ∈ U X = y + ˙ k · ˙ Z ↔ ∃ b ∈ U X = b + ˙ k · ˙ Z
64 63 a1i ⊢ k ∈ K → ∃ y ∈ U X = y + ˙ k · ˙ Z ↔ ∃ b ∈ U X = b + ˙ k · ˙ Z
65 64 riotabiia ⊢ ι k ∈ K | ∃ y ∈ U X = y + ˙ k · ˙ Z = ι k ∈ K | ∃ b ∈ U X = b + ˙ k · ˙ Z
66 60 65 eqtrdi ⊢ X ∈ V → G ⁡ X = ι k ∈ K | ∃ b ∈ U X = b + ˙ k · ˙ Z
67 9 66 syl ⊢ φ → G ⁡ X = ι k ∈ K | ∃ b ∈ U X = b + ˙ k · ˙ Z
68 67 eqeq1d ⊢ φ → G ⁡ X = 0 ˙ ↔ ι k ∈ K | ∃ b ∈ U X = b + ˙ k · ˙ Z = 0 ˙
69 27 55 68 3bitr4d ⊢ φ → X ∈ U ↔ G ⁡ X = 0 ˙