Metamath Proof Explorer


Theorem noseqrdgsuc

Description: Successor value of a recursive definition generator on surreal sequences. (Contributed by Scott Fenton, 19-Apr-2025)

Ref Expression
Hypotheses om2noseq.1 ⊢ φ → C ∈ No
om2noseq.2 ⊢ φ → G = rec ⁡ x ∈ V ⟼ x + s 1 s C ↾ ω
om2noseq.3 ⊢ φ → Z = rec ⁡ x ∈ V ⟼ x + s 1 s C ω
noseqrdg.1 ⊢ φ → A ∈ V
noseqrdg.2 ⊢ φ → R = rec ⁡ x ∈ V , y ∈ V ⟼ x + s 1 s x F y C A ↾ ω
noseqrdg.3 ⊢ φ → S = ran ⁡ R
Assertion noseqrdgsuc ⊢ φ ∧ B ∈ Z → S ⁡ B + s 1 s = B F S ⁡ B

Proof

Step Hyp Ref Expression
1 om2noseq.1 ⊢ φ → C ∈ No
2 om2noseq.2 ⊢ φ → G = rec ⁡ x ∈ V ⟼ x + s 1 s C ↾ ω
3 om2noseq.3 ⊢ φ → Z = rec ⁡ x ∈ V ⟼ x + s 1 s C ω
4 noseqrdg.1 ⊢ φ → A ∈ V
5 noseqrdg.2 ⊢ φ → R = rec ⁡ x ∈ V , y ∈ V ⟼ x + s 1 s x F y C A ↾ ω
6 noseqrdg.3 ⊢ φ → S = ran ⁡ R
7 1 2 3 4 5 6 noseqrdgfn ⊢ φ → S Fn Z
8 7 adantr ⊢ φ ∧ B ∈ Z → S Fn Z
9 8 fnfund ⊢ φ ∧ B ∈ Z → Fun ⁡ S
10 3 adantr ⊢ φ ∧ B ∈ Z → Z = rec ⁡ x ∈ V ⟼ x + s 1 s C ω
11 1 adantr ⊢ φ ∧ B ∈ Z → C ∈ No
12 simpr ⊢ φ ∧ B ∈ Z → B ∈ Z
13 10 11 12 noseqp1 ⊢ φ ∧ B ∈ Z → B + s 1 s ∈ Z
14 1 2 3 4 5 noseqrdglem ⊢ φ ∧ B + s 1 s ∈ Z → B + s 1 s 2 nd ⁡ R ⁡ G -1 ⁡ B + s 1 s ∈ ran ⁡ R
15 13 14 syldan ⊢ φ ∧ B ∈ Z → B + s 1 s 2 nd ⁡ R ⁡ G -1 ⁡ B + s 1 s ∈ ran ⁡ R
16 6 adantr ⊢ φ ∧ B ∈ Z → S = ran ⁡ R
17 15 16 eleqtrrd ⊢ φ ∧ B ∈ Z → B + s 1 s 2 nd ⁡ R ⁡ G -1 ⁡ B + s 1 s ∈ S
18 funopfv ⊢ Fun ⁡ S → B + s 1 s 2 nd ⁡ R ⁡ G -1 ⁡ B + s 1 s ∈ S → S ⁡ B + s 1 s = 2 nd ⁡ R ⁡ G -1 ⁡ B + s 1 s
19 9 17 18 sylc ⊢ φ ∧ B ∈ Z → S ⁡ B + s 1 s = 2 nd ⁡ R ⁡ G -1 ⁡ B + s 1 s
20 1 2 3 om2noseqf1o ⊢ φ → G : ω ⟶ 1-1 onto Z
21 20 adantr ⊢ φ ∧ B ∈ Z → G : ω ⟶ 1-1 onto Z
22 f1ocnvdm ⊢ G : ω ⟶ 1-1 onto Z ∧ B ∈ Z → G -1 ⁡ B ∈ ω
23 20 22 sylan ⊢ φ ∧ B ∈ Z → G -1 ⁡ B ∈ ω
24 peano2 ⊢ G -1 ⁡ B ∈ ω → suc ⁡ G -1 ⁡ B ∈ ω
25 23 24 syl ⊢ φ ∧ B ∈ Z → suc ⁡ G -1 ⁡ B ∈ ω
26 21 25 jca ⊢ φ ∧ B ∈ Z → G : ω ⟶ 1-1 onto Z ∧ suc ⁡ G -1 ⁡ B ∈ ω
27 2 adantr ⊢ φ ∧ B ∈ Z → G = rec ⁡ x ∈ V ⟼ x + s 1 s C ↾ ω
28 11 27 23 om2noseqsuc ⊢ φ ∧ B ∈ Z → G ⁡ suc ⁡ G -1 ⁡ B = G ⁡ G -1 ⁡ B + s 1 s
29 f1ocnvfv2 ⊢ G : ω ⟶ 1-1 onto Z ∧ B ∈ Z → G ⁡ G -1 ⁡ B = B
30 20 29 sylan ⊢ φ ∧ B ∈ Z → G ⁡ G -1 ⁡ B = B
31 30 oveq1d ⊢ φ ∧ B ∈ Z → G ⁡ G -1 ⁡ B + s 1 s = B + s 1 s
32 28 31 eqtrd ⊢ φ ∧ B ∈ Z → G ⁡ suc ⁡ G -1 ⁡ B = B + s 1 s
33 f1ocnvfv ⊢ G : ω ⟶ 1-1 onto Z ∧ suc ⁡ G -1 ⁡ B ∈ ω → G ⁡ suc ⁡ G -1 ⁡ B = B + s 1 s → G -1 ⁡ B + s 1 s = suc ⁡ G -1 ⁡ B
34 26 32 33 sylc ⊢ φ ∧ B ∈ Z → G -1 ⁡ B + s 1 s = suc ⁡ G -1 ⁡ B
35 34 fveq2d ⊢ φ ∧ B ∈ Z → R ⁡ G -1 ⁡ B + s 1 s = R ⁡ suc ⁡ G -1 ⁡ B
36 35 fveq2d ⊢ φ ∧ B ∈ Z → 2 nd ⁡ R ⁡ G -1 ⁡ B + s 1 s = 2 nd ⁡ R ⁡ suc ⁡ G -1 ⁡ B
37 19 36 eqtrd ⊢ φ ∧ B ∈ Z → S ⁡ B + s 1 s = 2 nd ⁡ R ⁡ suc ⁡ G -1 ⁡ B
38 frsuc ⊢ G -1 ⁡ B ∈ ω → rec ⁡ x ∈ V , y ∈ V ⟼ x + s 1 s x F y C A ↾ ω ⁡ suc ⁡ G -1 ⁡ B = x ∈ V , y ∈ V ⟼ x + s 1 s x F y ⁡ rec ⁡ x ∈ V , y ∈ V ⟼ x + s 1 s x F y C A ↾ ω ⁡ G -1 ⁡ B
39 38 adantl ⊢ φ ∧ G -1 ⁡ B ∈ ω → rec ⁡ x ∈ V , y ∈ V ⟼ x + s 1 s x F y C A ↾ ω ⁡ suc ⁡ G -1 ⁡ B = x ∈ V , y ∈ V ⟼ x + s 1 s x F y ⁡ rec ⁡ x ∈ V , y ∈ V ⟼ x + s 1 s x F y C A ↾ ω ⁡ G -1 ⁡ B
40 5 fveq1d ⊢ φ → R ⁡ suc ⁡ G -1 ⁡ B = rec ⁡ x ∈ V , y ∈ V ⟼ x + s 1 s x F y C A ↾ ω ⁡ suc ⁡ G -1 ⁡ B
41 40 adantr ⊢ φ ∧ G -1 ⁡ B ∈ ω → R ⁡ suc ⁡ G -1 ⁡ B = rec ⁡ x ∈ V , y ∈ V ⟼ x + s 1 s x F y C A ↾ ω ⁡ suc ⁡ G -1 ⁡ B
42 5 fveq1d ⊢ φ → R ⁡ G -1 ⁡ B = rec ⁡ x ∈ V , y ∈ V ⟼ x + s 1 s x F y C A ↾ ω ⁡ G -1 ⁡ B
43 42 fveq2d ⊢ φ → x ∈ V , y ∈ V ⟼ x + s 1 s x F y ⁡ R ⁡ G -1 ⁡ B = x ∈ V , y ∈ V ⟼ x + s 1 s x F y ⁡ rec ⁡ x ∈ V , y ∈ V ⟼ x + s 1 s x F y C A ↾ ω ⁡ G -1 ⁡ B
44 43 adantr ⊢ φ ∧ G -1 ⁡ B ∈ ω → x ∈ V , y ∈ V ⟼ x + s 1 s x F y ⁡ R ⁡ G -1 ⁡ B = x ∈ V , y ∈ V ⟼ x + s 1 s x F y ⁡ rec ⁡ x ∈ V , y ∈ V ⟼ x + s 1 s x F y C A ↾ ω ⁡ G -1 ⁡ B
45 39 41 44 3eqtr4d ⊢ φ ∧ G -1 ⁡ B ∈ ω → R ⁡ suc ⁡ G -1 ⁡ B = x ∈ V , y ∈ V ⟼ x + s 1 s x F y ⁡ R ⁡ G -1 ⁡ B
46 1 2 3 4 5 om2noseqrdg ⊢ φ ∧ G -1 ⁡ B ∈ ω → R ⁡ G -1 ⁡ B = G ⁡ G -1 ⁡ B 2 nd ⁡ R ⁡ G -1 ⁡ B
47 46 fveq2d ⊢ φ ∧ G -1 ⁡ B ∈ ω → x ∈ V , y ∈ V ⟼ x + s 1 s x F y ⁡ R ⁡ G -1 ⁡ B = x ∈ V , y ∈ V ⟼ x + s 1 s x F y ⁡ G ⁡ G -1 ⁡ B 2 nd ⁡ R ⁡ G -1 ⁡ B
48 df-ov ⊢ G ⁡ G -1 ⁡ B x ∈ V , y ∈ V ⟼ x + s 1 s x F y 2 nd ⁡ R ⁡ G -1 ⁡ B = x ∈ V , y ∈ V ⟼ x + s 1 s x F y ⁡ G ⁡ G -1 ⁡ B 2 nd ⁡ R ⁡ G -1 ⁡ B
49 47 48 eqtr4di ⊢ φ ∧ G -1 ⁡ B ∈ ω → x ∈ V , y ∈ V ⟼ x + s 1 s x F y ⁡ R ⁡ G -1 ⁡ B = G ⁡ G -1 ⁡ B x ∈ V , y ∈ V ⟼ x + s 1 s x F y 2 nd ⁡ R ⁡ G -1 ⁡ B
50 45 49 eqtrd ⊢ φ ∧ G -1 ⁡ B ∈ ω → R ⁡ suc ⁡ G -1 ⁡ B = G ⁡ G -1 ⁡ B x ∈ V , y ∈ V ⟼ x + s 1 s x F y 2 nd ⁡ R ⁡ G -1 ⁡ B
51 fvex ⊢ G ⁡ G -1 ⁡ B ∈ V
52 fvex ⊢ 2 nd ⁡ R ⁡ G -1 ⁡ B ∈ V
53 oveq1 ⊢ z = G ⁡ G -1 ⁡ B → z + s 1 s = G ⁡ G -1 ⁡ B + s 1 s
54 oveq1 ⊢ z = G ⁡ G -1 ⁡ B → z F w = G ⁡ G -1 ⁡ B F w
55 53 54 opeq12d ⊢ z = G ⁡ G -1 ⁡ B → z + s 1 s z F w = G ⁡ G -1 ⁡ B + s 1 s G ⁡ G -1 ⁡ B F w
56 oveq2 ⊢ w = 2 nd ⁡ R ⁡ G -1 ⁡ B → G ⁡ G -1 ⁡ B F w = G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B
57 56 opeq2d ⊢ w = 2 nd ⁡ R ⁡ G -1 ⁡ B → G ⁡ G -1 ⁡ B + s 1 s G ⁡ G -1 ⁡ B F w = G ⁡ G -1 ⁡ B + s 1 s G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B
58 oveq1 ⊢ x = z → x + s 1 s = z + s 1 s
59 oveq1 ⊢ x = z → x F y = z F y
60 58 59 opeq12d ⊢ x = z → x + s 1 s x F y = z + s 1 s z F y
61 oveq2 ⊢ y = w → z F y = z F w
62 61 opeq2d ⊢ y = w → z + s 1 s z F y = z + s 1 s z F w
63 60 62 cbvmpov ⊢ x ∈ V , y ∈ V ⟼ x + s 1 s x F y = z ∈ V , w ∈ V ⟼ z + s 1 s z F w
64 opex ⊢ G ⁡ G -1 ⁡ B + s 1 s G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B ∈ V
65 55 57 63 64 ovmpo ⊢ G ⁡ G -1 ⁡ B ∈ V ∧ 2 nd ⁡ R ⁡ G -1 ⁡ B ∈ V → G ⁡ G -1 ⁡ B x ∈ V , y ∈ V ⟼ x + s 1 s x F y 2 nd ⁡ R ⁡ G -1 ⁡ B = G ⁡ G -1 ⁡ B + s 1 s G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B
66 51 52 65 mp2an ⊢ G ⁡ G -1 ⁡ B x ∈ V , y ∈ V ⟼ x + s 1 s x F y 2 nd ⁡ R ⁡ G -1 ⁡ B = G ⁡ G -1 ⁡ B + s 1 s G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B
67 50 66 eqtrdi ⊢ φ ∧ G -1 ⁡ B ∈ ω → R ⁡ suc ⁡ G -1 ⁡ B = G ⁡ G -1 ⁡ B + s 1 s G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B
68 67 fveq2d ⊢ φ ∧ G -1 ⁡ B ∈ ω → 2 nd ⁡ R ⁡ suc ⁡ G -1 ⁡ B = 2 nd ⁡ G ⁡ G -1 ⁡ B + s 1 s G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B
69 ovex ⊢ G ⁡ G -1 ⁡ B + s 1 s ∈ V
70 ovex ⊢ G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B ∈ V
71 69 70 op2nd ⊢ 2 nd ⁡ G ⁡ G -1 ⁡ B + s 1 s G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B = G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B
72 68 71 eqtrdi ⊢ φ ∧ G -1 ⁡ B ∈ ω → 2 nd ⁡ R ⁡ suc ⁡ G -1 ⁡ B = G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B
73 23 72 syldan ⊢ φ ∧ B ∈ Z → 2 nd ⁡ R ⁡ suc ⁡ G -1 ⁡ B = G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B
74 1 2 3 4 5 noseqrdglem ⊢ φ ∧ B ∈ Z → B 2 nd ⁡ R ⁡ G -1 ⁡ B ∈ ran ⁡ R
75 74 16 eleqtrrd ⊢ φ ∧ B ∈ Z → B 2 nd ⁡ R ⁡ G -1 ⁡ B ∈ S
76 funopfv ⊢ Fun ⁡ S → B 2 nd ⁡ R ⁡ G -1 ⁡ B ∈ S → S ⁡ B = 2 nd ⁡ R ⁡ G -1 ⁡ B
77 9 75 76 sylc ⊢ φ ∧ B ∈ Z → S ⁡ B = 2 nd ⁡ R ⁡ G -1 ⁡ B
78 77 eqcomd ⊢ φ ∧ B ∈ Z → 2 nd ⁡ R ⁡ G -1 ⁡ B = S ⁡ B
79 30 78 oveq12d ⊢ φ ∧ B ∈ Z → G ⁡ G -1 ⁡ B F 2 nd ⁡ R ⁡ G -1 ⁡ B = B F S ⁡ B
80 37 73 79 3eqtrd ⊢ φ ∧ B ∈ Z → S ⁡ B + s 1 s = B F S ⁡ B