Metamath Proof Explorer


Theorem dvef

Description: Derivative of the exponential function. (Contributed by Mario Carneiro, 9-Aug-2014) (Proof shortened by Mario Carneiro, 10-Feb-2015)

Ref Expression
Assertion dvef ⊢ ℂ D exp = exp

Proof

Step Hyp Ref Expression
1 dvfcn ⊢ exp ℂ ′ : dom ⁡ exp ℂ ′ ⟶ ℂ
2 dvbsss ⊢ dom ⁡ exp ℂ ′ ⊆ ℂ
3 subcl ⊢ z ∈ ℂ ∧ x ∈ ℂ → z − x ∈ ℂ
4 3 ancoms ⊢ x ∈ ℂ ∧ z ∈ ℂ → z − x ∈ ℂ
5 efadd ⊢ x ∈ ℂ ∧ z − x ∈ ℂ → e x + z - x = e x ⁢ e z − x
6 4 5 syldan ⊢ x ∈ ℂ ∧ z ∈ ℂ → e x + z - x = e x ⁢ e z − x
7 pncan3 ⊢ x ∈ ℂ ∧ z ∈ ℂ → x + z - x = z
8 7 fveq2d ⊢ x ∈ ℂ ∧ z ∈ ℂ → e x + z - x = e z
9 6 8 eqtr3d ⊢ x ∈ ℂ ∧ z ∈ ℂ → e x ⁢ e z − x = e z
10 9 mpteq2dva ⊢ x ∈ ℂ → z ∈ ℂ ⟼ e x ⁢ e z − x = z ∈ ℂ ⟼ e z
11 cnex ⊢ ℂ ∈ V
12 11 a1i ⊢ x ∈ ℂ → ℂ ∈ V
13 fvexd ⊢ x ∈ ℂ ∧ z ∈ ℂ → e x ∈ V
14 fvexd ⊢ x ∈ ℂ ∧ z ∈ ℂ → e z − x ∈ V
15 fconstmpt ⊢ ℂ × e x = z ∈ ℂ ⟼ e x
16 15 a1i ⊢ x ∈ ℂ → ℂ × e x = z ∈ ℂ ⟼ e x
17 eqidd ⊢ x ∈ ℂ → z ∈ ℂ ⟼ e z − x = z ∈ ℂ ⟼ e z − x
18 12 13 14 16 17 offval2 ⊢ x ∈ ℂ → ℂ × e x × f z ∈ ℂ ⟼ e z − x = z ∈ ℂ ⟼ e x ⁢ e z − x
19 eff ⊢ exp : ℂ ⟶ ℂ
20 19 a1i ⊢ x ∈ ℂ → exp : ℂ ⟶ ℂ
21 20 feqmptd ⊢ x ∈ ℂ → exp = z ∈ ℂ ⟼ e z
22 10 18 21 3eqtr4d ⊢ x ∈ ℂ → ℂ × e x × f z ∈ ℂ ⟼ e z − x = exp
23 22 oveq2d ⊢ x ∈ ℂ → ℂ D ℂ × e x × f z ∈ ℂ ⟼ e z − x = ℂ D exp
24 efcl ⊢ x ∈ ℂ → e x ∈ ℂ
25 fconstg ⊢ e x ∈ ℂ → ℂ × e x : ℂ ⟶ e x
26 24 25 syl ⊢ x ∈ ℂ → ℂ × e x : ℂ ⟶ e x
27 24 snssd ⊢ x ∈ ℂ → e x ⊆ ℂ
28 26 27 fssd ⊢ x ∈ ℂ → ℂ × e x : ℂ ⟶ ℂ
29 ssidd ⊢ x ∈ ℂ → ℂ ⊆ ℂ
30 efcl ⊢ z − x ∈ ℂ → e z − x ∈ ℂ
31 4 30 syl ⊢ x ∈ ℂ ∧ z ∈ ℂ → e z − x ∈ ℂ
32 31 fmpttd ⊢ x ∈ ℂ → z ∈ ℂ ⟼ e z − x : ℂ ⟶ ℂ
33 c0ex ⊢ 0 ∈ V
34 33 snid ⊢ 0 ∈ 0
35 opelxpi ⊢ x ∈ ℂ ∧ 0 ∈ 0 → x 0 ∈ ℂ × 0
36 34 35 mpan2 ⊢ x ∈ ℂ → x 0 ∈ ℂ × 0
37 dvconst ⊢ e x ∈ ℂ → ℂ D ℂ × e x = ℂ × 0
38 24 37 syl ⊢ x ∈ ℂ → ℂ D ℂ × e x = ℂ × 0
39 36 38 eleqtrrd ⊢ x ∈ ℂ → x 0 ∈ ℂ × e x ℂ ′
40 df-br ⊢ x ℂ × e x ℂ ′ 0 ↔ x 0 ∈ ℂ × e x ℂ ′
41 39 40 sylibr ⊢ x ∈ ℂ → x ℂ × e x ℂ ′ 0
42 20 4 cofmpt ⊢ x ∈ ℂ → exp ∘ z ∈ ℂ ⟼ z − x = z ∈ ℂ ⟼ e z − x
43 42 oveq2d ⊢ x ∈ ℂ → ℂ D exp ∘ z ∈ ℂ ⟼ z − x = dz ∈ ℂ e z − x d ℂ z
44 4 fmpttd ⊢ x ∈ ℂ → z ∈ ℂ ⟼ z − x : ℂ ⟶ ℂ
45 oveq1 ⊢ z = x → z − x = x − x
46 eqid ⊢ z ∈ ℂ ⟼ z − x = z ∈ ℂ ⟼ z − x
47 ovex ⊢ x − x ∈ V
48 45 46 47 fvmpt ⊢ x ∈ ℂ → z ∈ ℂ ⟼ z − x ⁡ x = x − x
49 subid ⊢ x ∈ ℂ → x − x = 0
50 48 49 eqtrd ⊢ x ∈ ℂ → z ∈ ℂ ⟼ z − x ⁡ x = 0
51 dveflem ⊢ 0 exp ℂ ′ 1
52 50 51 eqbrtrdi ⊢ x ∈ ℂ → z ∈ ℂ ⟼ z − x ⁡ x exp ℂ ′ 1
53 1ex ⊢ 1 ∈ V
54 53 snid ⊢ 1 ∈ 1
55 opelxpi ⊢ x ∈ ℂ ∧ 1 ∈ 1 → x 1 ∈ ℂ × 1
56 54 55 mpan2 ⊢ x ∈ ℂ → x 1 ∈ ℂ × 1
57 cnelprrecn ⊢ ℂ ∈ ℝ ℂ
58 57 a1i ⊢ x ∈ ℂ → ℂ ∈ ℝ ℂ
59 simpr ⊢ x ∈ ℂ ∧ z ∈ ℂ → z ∈ ℂ
60 1cnd ⊢ x ∈ ℂ ∧ z ∈ ℂ → 1 ∈ ℂ
61 58 dvmptid ⊢ x ∈ ℂ → dz ∈ ℂ z d ℂ z = z ∈ ℂ ⟼ 1
62 simpl ⊢ x ∈ ℂ ∧ z ∈ ℂ → x ∈ ℂ
63 0cnd ⊢ x ∈ ℂ ∧ z ∈ ℂ → 0 ∈ ℂ
64 id ⊢ x ∈ ℂ → x ∈ ℂ
65 58 64 dvmptc ⊢ x ∈ ℂ → dz ∈ ℂ x d ℂ z = z ∈ ℂ ⟼ 0
66 58 59 60 61 62 63 65 dvmptsub ⊢ x ∈ ℂ → dz ∈ ℂ z − x d ℂ z = z ∈ ℂ ⟼ 1 − 0
67 1m0e1 ⊢ 1 − 0 = 1
68 67 mpteq2i ⊢ z ∈ ℂ ⟼ 1 − 0 = z ∈ ℂ ⟼ 1
69 fconstmpt ⊢ ℂ × 1 = z ∈ ℂ ⟼ 1
70 68 69 eqtr4i ⊢ z ∈ ℂ ⟼ 1 − 0 = ℂ × 1
71 66 70 eqtrdi ⊢ x ∈ ℂ → dz ∈ ℂ z − x d ℂ z = ℂ × 1
72 56 71 eleqtrrd ⊢ x ∈ ℂ → x 1 ∈ dz ∈ ℂ z − x d ℂ z
73 df-br ⊢ x dz ∈ ℂ z − x d ℂ z 1 ↔ x 1 ∈ dz ∈ ℂ z − x d ℂ z
74 72 73 sylibr ⊢ x ∈ ℂ → x dz ∈ ℂ z − x d ℂ z 1
75 eqid ⊢ TopOpen ⁡ ℂ fld = TopOpen ⁡ ℂ fld
76 20 29 44 29 29 29 52 74 75 dvcobr ⊢ x ∈ ℂ → x exp ∘ z ∈ ℂ ⟼ z − x ℂ ′ 1 ⋅ 1
77 1t1e1 ⊢ 1 ⋅ 1 = 1
78 76 77 breqtrdi ⊢ x ∈ ℂ → x exp ∘ z ∈ ℂ ⟼ z − x ℂ ′ 1
79 43 78 breqdi ⊢ x ∈ ℂ → x dz ∈ ℂ e z − x d ℂ z 1
80 28 29 32 29 29 41 79 75 dvmulbr ⊢ x ∈ ℂ → x ℂ × e x × f z ∈ ℂ ⟼ e z − x ℂ ′ 0 ⋅ z ∈ ℂ ⟼ e z − x ⁡ x + 1 ⁢ ℂ × e x ⁡ x
81 32 64 ffvelcdmd ⊢ x ∈ ℂ → z ∈ ℂ ⟼ e z − x ⁡ x ∈ ℂ
82 81 mul02d ⊢ x ∈ ℂ → 0 ⋅ z ∈ ℂ ⟼ e z − x ⁡ x = 0
83 fvex ⊢ e x ∈ V
84 83 fvconst2 ⊢ x ∈ ℂ → ℂ × e x ⁡ x = e x
85 84 oveq2d ⊢ x ∈ ℂ → 1 ⁢ ℂ × e x ⁡ x = 1 ⁢ e x
86 24 mullidd ⊢ x ∈ ℂ → 1 ⁢ e x = e x
87 85 86 eqtrd ⊢ x ∈ ℂ → 1 ⁢ ℂ × e x ⁡ x = e x
88 82 87 oveq12d ⊢ x ∈ ℂ → 0 ⋅ z ∈ ℂ ⟼ e z − x ⁡ x + 1 ⁢ ℂ × e x ⁡ x = 0 + e x
89 24 addlidd ⊢ x ∈ ℂ → 0 + e x = e x
90 88 89 eqtrd ⊢ x ∈ ℂ → 0 ⋅ z ∈ ℂ ⟼ e z − x ⁡ x + 1 ⁢ ℂ × e x ⁡ x = e x
91 80 90 breqtrd ⊢ x ∈ ℂ → x ℂ × e x × f z ∈ ℂ ⟼ e z − x ℂ ′ e x
92 23 91 breqdi ⊢ x ∈ ℂ → x exp ℂ ′ e x
93 vex ⊢ x ∈ V
94 93 83 breldm ⊢ x exp ℂ ′ e x → x ∈ dom ⁡ exp ℂ ′
95 92 94 syl ⊢ x ∈ ℂ → x ∈ dom ⁡ exp ℂ ′
96 95 ssriv ⊢ ℂ ⊆ dom ⁡ exp ℂ ′
97 2 96 eqssi ⊢ dom ⁡ exp ℂ ′ = ℂ
98 97 feq2i ⊢ exp ℂ ′ : dom ⁡ exp ℂ ′ ⟶ ℂ ↔ exp ℂ ′ : ℂ ⟶ ℂ
99 1 98 mpbi ⊢ exp ℂ ′ : ℂ ⟶ ℂ
100 99 a1i ⊢ ⊤ → exp ℂ ′ : ℂ ⟶ ℂ
101 100 feqmptd ⊢ ⊤ → ℂ D exp = x ∈ ℂ ⟼ exp ℂ ′ ⁡ x
102 ffun ⊢ exp ℂ ′ : dom ⁡ exp ℂ ′ ⟶ ℂ → Fun ⁡ exp ℂ ′
103 1 102 ax-mp ⊢ Fun ⁡ exp ℂ ′
104 funbrfv ⊢ Fun ⁡ exp ℂ ′ → x exp ℂ ′ e x → exp ℂ ′ ⁡ x = e x
105 103 92 104 mpsyl ⊢ x ∈ ℂ → exp ℂ ′ ⁡ x = e x
106 105 mpteq2ia ⊢ x ∈ ℂ ⟼ exp ℂ ′ ⁡ x = x ∈ ℂ ⟼ e x
107 101 106 eqtrdi ⊢ ⊤ → ℂ D exp = x ∈ ℂ ⟼ e x
108 19 a1i ⊢ ⊤ → exp : ℂ ⟶ ℂ
109 108 feqmptd ⊢ ⊤ → exp = x ∈ ℂ ⟼ e x
110 107 109 eqtr4d ⊢ ⊤ → ℂ D exp = exp
111 110 mptru ⊢ ℂ D exp = exp