Metamath Proof Explorer


Theorem msrval

Description: Value of the reduct of a pre-statement. (Contributed by Mario Carneiro, 18-Jul-2016)

Ref Expression
Hypotheses msrfval.v ⊢ V = mVars ⁡ T
msrfval.p ⊢ P = mPreSt ⁡ T
msrfval.r ⊢ R = mStRed ⁡ T
msrval.z ⊢ Z = ⋃ V H ∪ A
Assertion msrval ⊢ D H A ∈ P → R ⁡ D H A = D ∩ Z × Z H A

Proof

Step Hyp Ref Expression
1 msrfval.v ⊢ V = mVars ⁡ T
2 msrfval.p ⊢ P = mPreSt ⁡ T
3 msrfval.r ⊢ R = mStRed ⁡ T
4 msrval.z ⊢ Z = ⋃ V H ∪ A
5 1 2 3 msrfval ⊢ R = s ∈ P ⟼ ⦋ 2 nd ⁡ 1 st ⁡ s / h⦌ ⦋ 2 nd ⁡ s / a⦌ 1 st ⁡ 1 st ⁡ s ∩ ⦋ ⋃ V h ∪ a / z⦌ z × z h a
6 5 a1i ⊢ D H A ∈ P → R = s ∈ P ⟼ ⦋ 2 nd ⁡ 1 st ⁡ s / h⦌ ⦋ 2 nd ⁡ s / a⦌ 1 st ⁡ 1 st ⁡ s ∩ ⦋ ⋃ V h ∪ a / z⦌ z × z h a
7 fvexd ⊢ D H A ∈ P ∧ s = D H A → 2 nd ⁡ 1 st ⁡ s ∈ V
8 fvexd ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s → 2 nd ⁡ s ∈ V
9 simpllr ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → s = D H A
10 9 fveq2d ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → 1 st ⁡ s = 1 st ⁡ D H A
11 10 fveq2d ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → 1 st ⁡ 1 st ⁡ s = 1 st ⁡ 1 st ⁡ D H A
12 eqid ⊢ mDV ⁡ T = mDV ⁡ T
13 eqid ⊢ mEx ⁡ T = mEx ⁡ T
14 12 13 2 elmpst ⊢ D H A ∈ P ↔ D ⊆ mDV ⁡ T ∧ D -1 = D ∧ H ⊆ mEx ⁡ T ∧ H ∈ Fin ∧ A ∈ mEx ⁡ T
15 14 simp1bi ⊢ D H A ∈ P → D ⊆ mDV ⁡ T ∧ D -1 = D
16 15 simpld ⊢ D H A ∈ P → D ⊆ mDV ⁡ T
17 16 ad3antrrr ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → D ⊆ mDV ⁡ T
18 fvex ⊢ mDV ⁡ T ∈ V
19 18 ssex ⊢ D ⊆ mDV ⁡ T → D ∈ V
20 17 19 syl ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → D ∈ V
21 14 simp2bi ⊢ D H A ∈ P → H ⊆ mEx ⁡ T ∧ H ∈ Fin
22 21 simprd ⊢ D H A ∈ P → H ∈ Fin
23 22 ad3antrrr ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → H ∈ Fin
24 14 simp3bi ⊢ D H A ∈ P → A ∈ mEx ⁡ T
25 24 ad3antrrr ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → A ∈ mEx ⁡ T
26 ot1stg ⊢ D ∈ V ∧ H ∈ Fin ∧ A ∈ mEx ⁡ T → 1 st ⁡ 1 st ⁡ D H A = D
27 20 23 25 26 syl3anc ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → 1 st ⁡ 1 st ⁡ D H A = D
28 11 27 eqtrd ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → 1 st ⁡ 1 st ⁡ s = D
29 1 fvexi ⊢ V ∈ V
30 imaexg ⊢ V ∈ V → V h ∪ a ∈ V
31 29 30 ax-mp ⊢ V h ∪ a ∈ V
32 31 uniex ⊢ ⋃ V h ∪ a ∈ V
33 32 a1i ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → ⋃ V h ∪ a ∈ V
34 id ⊢ z = ⋃ V h ∪ a → z = ⋃ V h ∪ a
35 simplr ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → h = 2 nd ⁡ 1 st ⁡ s
36 10 fveq2d ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → 2 nd ⁡ 1 st ⁡ s = 2 nd ⁡ 1 st ⁡ D H A
37 ot2ndg ⊢ D ∈ V ∧ H ∈ Fin ∧ A ∈ mEx ⁡ T → 2 nd ⁡ 1 st ⁡ D H A = H
38 20 23 25 37 syl3anc ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → 2 nd ⁡ 1 st ⁡ D H A = H
39 35 36 38 3eqtrd ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → h = H
40 simpr ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → a = 2 nd ⁡ s
41 9 fveq2d ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → 2 nd ⁡ s = 2 nd ⁡ D H A
42 ot3rdg ⊢ A ∈ mEx ⁡ T → 2 nd ⁡ D H A = A
43 25 42 syl ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → 2 nd ⁡ D H A = A
44 40 41 43 3eqtrd ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → a = A
45 44 sneqd ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → a = A
46 39 45 uneq12d ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → h ∪ a = H ∪ A
47 46 imaeq2d ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → V h ∪ a = V H ∪ A
48 47 unieqd ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → ⋃ V h ∪ a = ⋃ V H ∪ A
49 48 4 eqtr4di ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → ⋃ V h ∪ a = Z
50 34 49 sylan9eqr ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s ∧ z = ⋃ V h ∪ a → z = Z
51 50 sqxpeqd ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s ∧ z = ⋃ V h ∪ a → z × z = Z × Z
52 33 51 csbied ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → ⦋ ⋃ V h ∪ a / z⦌ z × z = Z × Z
53 28 52 ineq12d ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → 1 st ⁡ 1 st ⁡ s ∩ ⦋ ⋃ V h ∪ a / z⦌ z × z = D ∩ Z × Z
54 53 39 44 oteq123d ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s ∧ a = 2 nd ⁡ s → 1 st ⁡ 1 st ⁡ s ∩ ⦋ ⋃ V h ∪ a / z⦌ z × z h a = D ∩ Z × Z H A
55 8 54 csbied ⊢ D H A ∈ P ∧ s = D H A ∧ h = 2 nd ⁡ 1 st ⁡ s → ⦋ 2 nd ⁡ s / a⦌ 1 st ⁡ 1 st ⁡ s ∩ ⦋ ⋃ V h ∪ a / z⦌ z × z h a = D ∩ Z × Z H A
56 7 55 csbied ⊢ D H A ∈ P ∧ s = D H A → ⦋ 2 nd ⁡ 1 st ⁡ s / h⦌ ⦋ 2 nd ⁡ s / a⦌ 1 st ⁡ 1 st ⁡ s ∩ ⦋ ⋃ V h ∪ a / z⦌ z × z h a = D ∩ Z × Z H A
57 id ⊢ D H A ∈ P → D H A ∈ P
58 otex ⊢ D ∩ Z × Z H A ∈ V
59 58 a1i ⊢ D H A ∈ P → D ∩ Z × Z H A ∈ V
60 6 56 57 59 fvmptd ⊢ D H A ∈ P → R ⁡ D H A = D ∩ Z × Z H A