Metamath Proof Explorer


Theorem lcfrlem1

Description: Lemma for lcfr . Note that X is z in Mario's notes. (Contributed by NM, 27-Feb-2015)

Ref Expression
Hypotheses lcfrlem1.v ⊢ V = Base U
lcfrlem1.s ⊢ S = Scalar ⁡ U
lcfrlem1.q ⊢ × ˙ = ⋅ S
lcfrlem1.z ⊢ 0 ˙ = 0 S
lcfrlem1.i ⊢ I = inv r ⁡ S
lcfrlem1.f ⊢ F = LFnl ⁡ U
lcfrlem1.d ⊢ D = LDual ⁡ U
lcfrlem1.t ⊢ · ˙ = ⋅ D
lcfrlem1.m ⊢ - ˙ = - D
lcfrlem1.u ⊢ φ → U ∈ LVec
lcfrlem1.e ⊢ φ → E ∈ F
lcfrlem1.g ⊢ φ → G ∈ F
lcfrlem1.x ⊢ φ → X ∈ V
lcfrlem1.n ⊢ φ → G ⁡ X ≠ 0 ˙
lcfrlem1.h ⊢ H = E - ˙ I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G
Assertion lcfrlem1 ⊢ φ → H ⁡ X = 0 ˙

Proof

Step Hyp Ref Expression
1 lcfrlem1.v ⊢ V = Base U
2 lcfrlem1.s ⊢ S = Scalar ⁡ U
3 lcfrlem1.q ⊢ × ˙ = ⋅ S
4 lcfrlem1.z ⊢ 0 ˙ = 0 S
5 lcfrlem1.i ⊢ I = inv r ⁡ S
6 lcfrlem1.f ⊢ F = LFnl ⁡ U
7 lcfrlem1.d ⊢ D = LDual ⁡ U
8 lcfrlem1.t ⊢ · ˙ = ⋅ D
9 lcfrlem1.m ⊢ - ˙ = - D
10 lcfrlem1.u ⊢ φ → U ∈ LVec
11 lcfrlem1.e ⊢ φ → E ∈ F
12 lcfrlem1.g ⊢ φ → G ∈ F
13 lcfrlem1.x ⊢ φ → X ∈ V
14 lcfrlem1.n ⊢ φ → G ⁡ X ≠ 0 ˙
15 lcfrlem1.h ⊢ H = E - ˙ I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G
16 15 fveq1i ⊢ H ⁡ X = E - ˙ I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G ⁡ X
17 eqid ⊢ - S = - S
18 lveclmod ⊢ U ∈ LVec → U ∈ LMod
19 10 18 syl ⊢ φ → U ∈ LMod
20 eqid ⊢ Base S = Base S
21 2 lvecdrng ⊢ U ∈ LVec → S ∈ DivRing
22 10 21 syl ⊢ φ → S ∈ DivRing
23 2 20 1 6 lflcl ⊢ U ∈ LVec ∧ G ∈ F ∧ X ∈ V → G ⁡ X ∈ Base S
24 10 12 13 23 syl3anc ⊢ φ → G ⁡ X ∈ Base S
25 20 4 5 drnginvrcl ⊢ S ∈ DivRing ∧ G ⁡ X ∈ Base S ∧ G ⁡ X ≠ 0 ˙ → I ⁡ G ⁡ X ∈ Base S
26 22 24 14 25 syl3anc ⊢ φ → I ⁡ G ⁡ X ∈ Base S
27 2 20 1 6 lflcl ⊢ U ∈ LVec ∧ E ∈ F ∧ X ∈ V → E ⁡ X ∈ Base S
28 10 11 13 27 syl3anc ⊢ φ → E ⁡ X ∈ Base S
29 2 20 3 lmodmcl ⊢ U ∈ LMod ∧ I ⁡ G ⁡ X ∈ Base S ∧ E ⁡ X ∈ Base S → I ⁡ G ⁡ X × ˙ E ⁡ X ∈ Base S
30 19 26 28 29 syl3anc ⊢ φ → I ⁡ G ⁡ X × ˙ E ⁡ X ∈ Base S
31 6 2 20 7 8 19 30 12 ldualvscl ⊢ φ → I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G ∈ F
32 1 2 17 6 7 9 19 11 31 13 ldualvsubval ⊢ φ → E - ˙ I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G ⁡ X = E ⁡ X - S I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G ⁡ X
33 6 1 2 20 3 7 8 10 30 12 13 ldualvsval ⊢ φ → I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G ⁡ X = G ⁡ X × ˙ I ⁡ G ⁡ X × ˙ E ⁡ X
34 eqid ⊢ 1 S = 1 S
35 20 4 3 34 5 drnginvrr ⊢ S ∈ DivRing ∧ G ⁡ X ∈ Base S ∧ G ⁡ X ≠ 0 ˙ → G ⁡ X × ˙ I ⁡ G ⁡ X = 1 S
36 22 24 14 35 syl3anc ⊢ φ → G ⁡ X × ˙ I ⁡ G ⁡ X = 1 S
37 36 oveq1d ⊢ φ → G ⁡ X × ˙ I ⁡ G ⁡ X × ˙ E ⁡ X = 1 S × ˙ E ⁡ X
38 2 lmodring ⊢ U ∈ LMod → S ∈ Ring
39 19 38 syl ⊢ φ → S ∈ Ring
40 20 3 ringass ⊢ S ∈ Ring ∧ G ⁡ X ∈ Base S ∧ I ⁡ G ⁡ X ∈ Base S ∧ E ⁡ X ∈ Base S → G ⁡ X × ˙ I ⁡ G ⁡ X × ˙ E ⁡ X = G ⁡ X × ˙ I ⁡ G ⁡ X × ˙ E ⁡ X
41 39 24 26 28 40 syl13anc ⊢ φ → G ⁡ X × ˙ I ⁡ G ⁡ X × ˙ E ⁡ X = G ⁡ X × ˙ I ⁡ G ⁡ X × ˙ E ⁡ X
42 20 3 34 ringlidm ⊢ S ∈ Ring ∧ E ⁡ X ∈ Base S → 1 S × ˙ E ⁡ X = E ⁡ X
43 39 28 42 syl2anc ⊢ φ → 1 S × ˙ E ⁡ X = E ⁡ X
44 37 41 43 3eqtr3d ⊢ φ → G ⁡ X × ˙ I ⁡ G ⁡ X × ˙ E ⁡ X = E ⁡ X
45 33 44 eqtrd ⊢ φ → I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G ⁡ X = E ⁡ X
46 45 oveq2d ⊢ φ → E ⁡ X - S I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G ⁡ X = E ⁡ X - S E ⁡ X
47 2 lmodfgrp ⊢ U ∈ LMod → S ∈ Grp
48 19 47 syl ⊢ φ → S ∈ Grp
49 20 4 17 grpsubid ⊢ S ∈ Grp ∧ E ⁡ X ∈ Base S → E ⁡ X - S E ⁡ X = 0 ˙
50 48 28 49 syl2anc ⊢ φ → E ⁡ X - S E ⁡ X = 0 ˙
51 32 46 50 3eqtrd ⊢ φ → E - ˙ I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G ⁡ X = 0 ˙
52 16 51 eqtrid ⊢ φ → H ⁡ X = 0 ˙