Metamath Proof Explorer


Theorem setc1onsubc

Description: Construct a category with one object and two morphisms and prove that category ( SetCat1o ) satisfies all conditions for a subcategory but the compatibility of identity morphisms, showing the necessity of the latter condition in defining a subcategory. Exercise 4A of Adamek p. 58. (Contributed by Zhi Wang, 6-Nov-2025)

Ref Expression
Hypotheses setc1onsubc.c C = Base ndx Hom ndx 2 𝑜 comp ndx · ˙
setc1onsubc.x · ˙ = f 2 𝑜 , g 2 𝑜 f g
setc1onsubc.e E = SetCat 1 𝑜
setc1onsubc.j J = Hom 𝑓 E
setc1onsubc.s S = 1 𝑜
setc1onsubc.h H = Hom 𝑓 C
setc1onsubc.i 1 ˙ = Id C
setc1onsubc.d D = C cat J
Assertion setc1onsubc C Cat J Fn S × S J cat H ¬ x S 1 ˙ x x J x D Cat

Proof

Step Hyp Ref Expression
1 setc1onsubc.c C = Base ndx Hom ndx 2 𝑜 comp ndx · ˙
2 setc1onsubc.x · ˙ = f 2 𝑜 , g 2 𝑜 f g
3 setc1onsubc.e E = SetCat 1 𝑜
4 setc1onsubc.j J = Hom 𝑓 E
5 setc1onsubc.s S = 1 𝑜
6 setc1onsubc.h H = Hom 𝑓 C
7 setc1onsubc.i 1 ˙ = Id C
8 setc1onsubc.d D = C cat J
9 0ss 1 𝑜
10 1oex 1 𝑜 V
11 df2o3 2 𝑜 = 1 𝑜
12 1 11 2 incat 1 𝑜 1 𝑜 V C Cat Id C = y 1 𝑜
13 9 10 12 mp2an C Cat Id C = y 1 𝑜
14 13 simpli C Cat
15 3 setc1obas 1 𝑜 = Base E
16 5 15 eqtri S = Base E
17 4 16 homffn J Fn S × S
18 ssid
19 snsspr1 1 𝑜
20 3 setc1ohomfval 1 𝑜 = Hom E
21 0lt1o 1 𝑜
22 21 a1i 1 𝑜
23 4 15 20 22 22 homfval J = 1 𝑜
24 23 mptru J = 1 𝑜
25 10 ovsn2 1 𝑜 = 1 𝑜
26 df1o2 1 𝑜 =
27 24 25 26 3eqtri J =
28 snex V
29 1 28 catbas = Base C
30 snex 2 𝑜 V
31 1 30 cathomfval 2 𝑜 = Hom C
32 0ex V
33 32 snid
34 33 a1i
35 6 29 31 34 34 homfval H = 2 𝑜
36 35 mptru H = 2 𝑜
37 2oex 2 𝑜 V
38 37 ovsn2 2 𝑜 = 2 𝑜
39 36 38 11 3eqtri H = 1 𝑜
40 19 27 39 3sstr4i J H
41 oveq1 p = p J q = J q
42 oveq1 p = p H q = H q
43 41 42 sseq12d p = p J q p H q J q H q
44 43 ralbidv p = q p J q p H q q J q H q
45 32 44 ralsn p q p J q p H q q J q H q
46 oveq2 q = J q = J
47 oveq2 q = H q = H
48 46 47 sseq12d q = J q H q J H
49 32 48 ralsn q J q H q J H
50 45 49 bitri p q p J q p H q J H
51 40 50 mpbir p q p J q p H q
52 26 15 eqtr3i = Base E
53 4 52 homffn J Fn ×
54 53 a1i J Fn ×
55 6 29 homffn H Fn ×
56 55 a1i H Fn ×
57 28 a1i V
58 54 56 57 isssc J cat H p q p J q p H q
59 58 mptru J cat H p q p J q p H q
60 18 51 59 mpbir2an J cat H
61 1on 1 𝑜 On
62 26 61 eqeltrri On
63 62 onirri ¬
64 5 26 eqtri S =
65 biid ¬ 1 ˙ x x J x ¬ 1 ˙ x x J x
66 64 65 rexeqbii x S ¬ 1 ˙ x x J x x ¬ 1 ˙ x x J x
67 rexnal x S ¬ 1 ˙ x x J x ¬ x S 1 ˙ x x J x
68 fveq2 x = 1 ˙ x = 1 ˙
69 26 a1i y = 1 𝑜 =
70 13 simpri Id C = y 1 𝑜
71 7 70 eqtri 1 ˙ = y 1 𝑜
72 69 71 28 fvmpt 1 ˙ =
73 33 72 ax-mp 1 ˙ =
74 68 73 eqtrdi x = 1 ˙ x =
75 oveq12 x = x = x J x = J
76 75 anidms x = x J x = J
77 76 27 eqtrdi x = x J x =
78 74 77 eleq12d x = 1 ˙ x x J x
79 78 notbid x = ¬ 1 ˙ x x J x ¬
80 32 79 rexsn x ¬ 1 ˙ x x J x ¬
81 66 67 80 3bitr3ri ¬ ¬ x S 1 ˙ x x J x
82 63 81 mpbi ¬ x S 1 ˙ x x J x
83 setc1oterm Could not format ( SetCat ` 1o ) e. TermCat : No typesetting found for |- ( SetCat ` 1o ) e. TermCat with typecode |-
84 83 a1i Could not format ( T. -> ( SetCat ` 1o ) e. TermCat ) : No typesetting found for |- ( T. -> ( SetCat ` 1o ) e. TermCat ) with typecode |-
85 84 termccd SetCat 1 𝑜 Cat
86 85 mptru SetCat 1 𝑜 Cat
87 3 86 eqeltri E Cat
88 snex · ˙ V
89 1 88 catcofval · ˙ = comp C
90 3 setc1ocofval = comp E
91 velsn a a =
92 velsn b b =
93 velsn c c =
94 91 92 93 3anbi123i a b c a = b = c =
95 94 anbi1i a b c m a J b n b J c a = b = c = m a J b n b J c
96 simp1 a = b = c = a =
97 simp2 a = b = c = b =
98 96 97 oveq12d a = b = c = a J b = J
99 98 27 eqtrdi a = b = c = a J b =
100 99 eleq2d a = b = c = m a J b m
101 velsn m m =
102 100 101 bitrdi a = b = c = m a J b m =
103 simp3 a = b = c = c =
104 97 103 oveq12d a = b = c = b J c = J
105 104 27 eqtrdi a = b = c = b J c =
106 105 eleq2d a = b = c = n b J c n
107 velsn n n =
108 106 107 bitrdi a = b = c = n b J c n =
109 102 108 anbi12d a = b = c = m a J b n b J c m = n =
110 109 pm5.32i a = b = c = m a J b n b J c a = b = c = m = n =
111 95 110 bitri a b c m a J b n b J c a = b = c = m = n =
112 32 prid1 1 𝑜
113 112 11 eleqtrri 2 𝑜
114 ineq12 f = g = f g =
115 0in =
116 114 115 eqtrdi f = g = f g =
117 116 2 32 ovmpoa 2 𝑜 2 𝑜 · ˙ =
118 113 113 117 mp2an · ˙ =
119 32 ovsn2 =
120 118 119 eqtr4i · ˙ =
121 simpl1 a = b = c = m = n = a =
122 simpl2 a = b = c = m = n = b =
123 121 122 opeq12d a = b = c = m = n = a b =
124 simpl3 a = b = c = m = n = c =
125 123 124 oveq12d a = b = c = m = n = a b · ˙ c = · ˙
126 37 37 mpoex f 2 𝑜 , g 2 𝑜 f g V
127 2 126 eqeltri · ˙ V
128 127 ovsn2 · ˙ = · ˙
129 125 128 eqtrdi a = b = c = m = n = a b · ˙ c = · ˙
130 simprr a = b = c = m = n = n =
131 simprl a = b = c = m = n = m =
132 129 130 131 oveq123d a = b = c = m = n = n a b · ˙ c m = · ˙
133 123 124 oveq12d a = b = c = m = n = a b c =
134 snex V
135 134 ovsn2 =
136 133 135 eqtrdi a = b = c = m = n = a b c =
137 136 130 131 oveq123d a = b = c = m = n = n a b c m =
138 120 132 137 3eqtr4a a = b = c = m = n = n a b · ˙ c m = n a b c m
139 111 138 sylbi a b c m a J b n b J c n a b · ˙ c m = n a b c m
140 139 adantll a b c m a J b n b J c n a b · ˙ c m = n a b c m
141 87 a1i E Cat
142 18 a1i
143 8 29 52 4 89 90 140 141 142 resccat D Cat E Cat
144 143 mptru D Cat E Cat
145 87 144 mpbir D Cat
146 60 82 145 3pm3.2i J cat H ¬ x S 1 ˙ x x J x D Cat
147 14 17 146 3pm3.2i C Cat J Fn S × S J cat H ¬ x S 1 ˙ x x J x D Cat