Metamath Proof Explorer


Theorem cjnpoly

Description: Complex conjugation operator is not a polynomial with complex coefficients. Indeed; if it was, then multiplying x conjugate by x itself and adding 1 would yield a nowhere-zero non-constant polynomial, contrary to the fta . (Contributed by Ender Ting, 8-Dec-2025)

Ref Expression
Assertion cjnpoly ⊢ ¬ * ∈ Poly ⁡ ℂ

Proof

Step Hyp Ref Expression
1 cnex ⊢ ℂ ∈ V
2 1ex ⊢ 1 ∈ V
3 fconstmpt ⊢ ℂ × 1 = x ∈ ℂ ⟼ 1
4 2 3 fnmpti ⊢ ℂ × 1 Fn ℂ
5 fnresi ⊢ I ↾ ℂ Fn ℂ
6 df-idp ⊢ X p = I ↾ ℂ
7 6 fneq1i ⊢ X p Fn ℂ ↔ I ↾ ℂ Fn ℂ
8 5 7 mpbir ⊢ X p Fn ℂ
9 8 a1i ⊢ ⊤ → X p Fn ℂ
10 cjf ⊢ * : ℂ ⟶ ℂ
11 ffn ⊢ * : ℂ ⟶ ℂ → * Fn ℂ
12 10 11 ax-mp ⊢ * Fn ℂ
13 12 a1i ⊢ ⊤ → * Fn ℂ
14 1 a1i ⊢ ⊤ → ℂ ∈ V
15 inidm ⊢ ℂ ∩ ℂ = ℂ
16 9 13 14 14 15 offn ⊢ ⊤ → X p × f * Fn ℂ
17 16 mptru ⊢ X p × f * Fn ℂ
18 fnfvof ⊢ ℂ × 1 Fn ℂ ∧ X p × f * Fn ℂ ∧ ℂ ∈ V ∧ x ∈ ℂ → ℂ × 1 + f X p × f * ⁡ x = ℂ × 1 ⁡ x + X p × f * ⁡ x
19 4 17 18 mpanl12 ⊢ ℂ ∈ V ∧ x ∈ ℂ → ℂ × 1 + f X p × f * ⁡ x = ℂ × 1 ⁡ x + X p × f * ⁡ x
20 1 19 mpan ⊢ x ∈ ℂ → ℂ × 1 + f X p × f * ⁡ x = ℂ × 1 ⁡ x + X p × f * ⁡ x
21 2 fvconst2 ⊢ x ∈ ℂ → ℂ × 1 ⁡ x = 1
22 21 oveq1d ⊢ x ∈ ℂ → ℂ × 1 ⁡ x + X p × f * ⁡ x = 1 + X p × f * ⁡ x
23 fnfvof ⊢ X p Fn ℂ ∧ * Fn ℂ ∧ ℂ ∈ V ∧ x ∈ ℂ → X p × f * ⁡ x = X p ⁡ x ⁢ x ‾
24 8 12 23 mpanl12 ⊢ ℂ ∈ V ∧ x ∈ ℂ → X p × f * ⁡ x = X p ⁡ x ⁢ x ‾
25 1 24 mpan ⊢ x ∈ ℂ → X p × f * ⁡ x = X p ⁡ x ⁢ x ‾
26 6 fveq1i ⊢ X p ⁡ x = I ↾ ℂ ⁡ x
27 fvres ⊢ x ∈ ℂ → I ↾ ℂ ⁡ x = I ⁡ x
28 26 27 eqtrid ⊢ x ∈ ℂ → X p ⁡ x = I ⁡ x
29 fvi ⊢ x ∈ ℂ → I ⁡ x = x
30 28 29 eqtrd ⊢ x ∈ ℂ → X p ⁡ x = x
31 30 oveq1d ⊢ x ∈ ℂ → X p ⁡ x ⁢ x ‾ = x ⁢ x ‾
32 25 31 eqtrd ⊢ x ∈ ℂ → X p × f * ⁡ x = x ⁢ x ‾
33 32 oveq2d ⊢ x ∈ ℂ → 1 + X p × f * ⁡ x = 1 + x ⁢ x ‾
34 20 22 33 3eqtrd ⊢ x ∈ ℂ → ℂ × 1 + f X p × f * ⁡ x = 1 + x ⁢ x ‾
35 1red ⊢ x ∈ ℂ → 1 ∈ ℝ
36 cjmulrcl ⊢ x ∈ ℂ → x ⁢ x ‾ ∈ ℝ
37 0lt1 ⊢ 0 < 1
38 37 a1i ⊢ x ∈ ℂ → 0 < 1
39 cjmulge0 ⊢ x ∈ ℂ → 0 ≤ x ⁢ x ‾
40 35 36 38 39 addgtge0d ⊢ x ∈ ℂ → 0 < 1 + x ⁢ x ‾
41 40 gt0ne0d ⊢ x ∈ ℂ → 1 + x ⁢ x ‾ ≠ 0
42 34 41 eqnetrd ⊢ x ∈ ℂ → ℂ × 1 + f X p × f * ⁡ x ≠ 0
43 42 neneqd ⊢ x ∈ ℂ → ¬ ℂ × 1 + f X p × f * ⁡ x = 0
44 43 nrex ⊢ ¬ ∃ x ∈ ℂ ℂ × 1 + f X p × f * ⁡ x = 0
45 ssid ⊢ ℂ ⊆ ℂ
46 ax-1cn ⊢ 1 ∈ ℂ
47 plyconst ⊢ ℂ ⊆ ℂ ∧ 1 ∈ ℂ → ℂ × 1 ∈ Poly ⁡ ℂ
48 45 46 47 mp2an ⊢ ℂ × 1 ∈ Poly ⁡ ℂ
49 plyid ⊢ ℂ ⊆ ℂ ∧ 1 ∈ ℂ → X p ∈ Poly ⁡ ℂ
50 45 46 49 mp2an ⊢ X p ∈ Poly ⁡ ℂ
51 plymulcl ⊢ X p ∈ Poly ⁡ ℂ ∧ * ∈ Poly ⁡ ℂ → X p × f * ∈ Poly ⁡ ℂ
52 50 51 mpan ⊢ * ∈ Poly ⁡ ℂ → X p × f * ∈ Poly ⁡ ℂ
53 plyaddcl ⊢ ℂ × 1 ∈ Poly ⁡ ℂ ∧ X p × f * ∈ Poly ⁡ ℂ → ℂ × 1 + f X p × f * ∈ Poly ⁡ ℂ
54 48 52 53 sylancr ⊢ * ∈ Poly ⁡ ℂ → ℂ × 1 + f X p × f * ∈ Poly ⁡ ℂ
55 1re ⊢ 1 ∈ ℝ
56 cjre ⊢ 1 ∈ ℝ → 1 ‾ = 1
57 55 56 ax-mp ⊢ 1 ‾ = 1
58 ax-1ne0 ⊢ 1 ≠ 0
59 57 58 eqnetri ⊢ 1 ‾ ≠ 0
60 ne0p ⊢ 1 ∈ ℂ ∧ 1 ‾ ≠ 0 → * ≠ 0 𝑝
61 46 59 60 mp2an ⊢ * ≠ 0 𝑝
62 6 fveq1i ⊢ X p ⁡ 1 = I ↾ ℂ ⁡ 1
63 fvres ⊢ 1 ∈ ℂ → I ↾ ℂ ⁡ 1 = I ⁡ 1
64 46 63 ax-mp ⊢ I ↾ ℂ ⁡ 1 = I ⁡ 1
65 fvi ⊢ 1 ∈ V → I ⁡ 1 = 1
66 2 65 ax-mp ⊢ I ⁡ 1 = 1
67 62 64 66 3eqtri ⊢ X p ⁡ 1 = 1
68 67 58 eqnetri ⊢ X p ⁡ 1 ≠ 0
69 ne0p ⊢ 1 ∈ ℂ ∧ X p ⁡ 1 ≠ 0 → X p ≠ 0 𝑝
70 46 68 69 mp2an ⊢ X p ≠ 0 𝑝
71 dgrid ⊢ deg ⁡ X p = 1
72 71 eqcomi ⊢ 1 = deg ⁡ X p
73 eqid ⊢ deg ⁡ * = deg ⁡ *
74 72 73 dgrmul ⊢ X p ∈ Poly ⁡ ℂ ∧ X p ≠ 0 𝑝 ∧ * ∈ Poly ⁡ ℂ ∧ * ≠ 0 𝑝 → deg ⁡ X p × f * = 1 + deg ⁡ *
75 50 70 74 mpanl12 ⊢ * ∈ Poly ⁡ ℂ ∧ * ≠ 0 𝑝 → deg ⁡ X p × f * = 1 + deg ⁡ *
76 61 75 mpan2 ⊢ * ∈ Poly ⁡ ℂ → deg ⁡ X p × f * = 1 + deg ⁡ *
77 dgrcl ⊢ * ∈ Poly ⁡ ℂ → deg ⁡ * ∈ ℕ 0
78 nn0cn ⊢ deg ⁡ * ∈ ℕ 0 → deg ⁡ * ∈ ℂ
79 1cnd ⊢ deg ⁡ * ∈ ℕ 0 → 1 ∈ ℂ
80 78 79 addcomd ⊢ deg ⁡ * ∈ ℕ 0 → deg ⁡ * + 1 = 1 + deg ⁡ *
81 nn0p1nn ⊢ deg ⁡ * ∈ ℕ 0 → deg ⁡ * + 1 ∈ ℕ
82 80 81 eqeltrrd ⊢ deg ⁡ * ∈ ℕ 0 → 1 + deg ⁡ * ∈ ℕ
83 77 82 syl ⊢ * ∈ Poly ⁡ ℂ → 1 + deg ⁡ * ∈ ℕ
84 76 83 eqeltrd ⊢ * ∈ Poly ⁡ ℂ → deg ⁡ X p × f * ∈ ℕ
85 84 nngt0d ⊢ * ∈ Poly ⁡ ℂ → 0 < deg ⁡ X p × f *
86 0dgr ⊢ 1 ∈ ℂ → deg ⁡ ℂ × 1 = 0
87 46 86 ax-mp ⊢ deg ⁡ ℂ × 1 = 0
88 87 eqcomi ⊢ 0 = deg ⁡ ℂ × 1
89 eqid ⊢ deg ⁡ X p × f * = deg ⁡ X p × f *
90 88 89 dgradd2 ⊢ ℂ × 1 ∈ Poly ⁡ ℂ ∧ X p × f * ∈ Poly ⁡ ℂ ∧ 0 < deg ⁡ X p × f * → deg ⁡ ℂ × 1 + f X p × f * = deg ⁡ X p × f *
91 48 52 85 90 mp3an2i ⊢ * ∈ Poly ⁡ ℂ → deg ⁡ ℂ × 1 + f X p × f * = deg ⁡ X p × f *
92 91 84 eqeltrd ⊢ * ∈ Poly ⁡ ℂ → deg ⁡ ℂ × 1 + f X p × f * ∈ ℕ
93 fta ⊢ ℂ × 1 + f X p × f * ∈ Poly ⁡ ℂ ∧ deg ⁡ ℂ × 1 + f X p × f * ∈ ℕ → ∃ x ∈ ℂ ℂ × 1 + f X p × f * ⁡ x = 0
94 54 92 93 syl2anc ⊢ * ∈ Poly ⁡ ℂ → ∃ x ∈ ℂ ℂ × 1 + f X p × f * ⁡ x = 0
95 44 94 mto ⊢ ¬ * ∈ Poly ⁡ ℂ