Metamath Proof Explorer


Theorem ldualvsubval

Description: The value of the value of vector subtraction in the dual of a vector space. TODO: shorten with ldualvsub ? (Requires D to oppR conversion.) (Contributed by NM, 26-Feb-2015)

Ref Expression
Hypotheses ldualvsubval.v ⊢ V = Base W
ldualvsubval.r ⊢ R = Scalar ⁡ W
ldualvsubval.s ⊢ S = - R
ldualvsubval.f ⊢ F = LFnl ⁡ W
ldualvsubval.d ⊢ D = LDual ⁡ W
ldualvsubval.m ⊢ - ˙ = - D
ldualvsubval.w ⊢ φ → W ∈ LMod
ldualvsubval.g ⊢ φ → G ∈ F
ldualvsubval.h ⊢ φ → H ∈ F
ldualvsubval.x ⊢ φ → X ∈ V
Assertion ldualvsubval ⊢ φ → G - ˙ H ⁡ X = G ⁡ X S H ⁡ X

Proof

Step Hyp Ref Expression
1 ldualvsubval.v ⊢ V = Base W
2 ldualvsubval.r ⊢ R = Scalar ⁡ W
3 ldualvsubval.s ⊢ S = - R
4 ldualvsubval.f ⊢ F = LFnl ⁡ W
5 ldualvsubval.d ⊢ D = LDual ⁡ W
6 ldualvsubval.m ⊢ - ˙ = - D
7 ldualvsubval.w ⊢ φ → W ∈ LMod
8 ldualvsubval.g ⊢ φ → G ∈ F
9 ldualvsubval.h ⊢ φ → H ∈ F
10 ldualvsubval.x ⊢ φ → X ∈ V
11 5 7 lduallmod ⊢ φ → D ∈ LMod
12 eqid ⊢ Base D = Base D
13 4 5 12 7 8 ldualelvbase ⊢ φ → G ∈ Base D
14 4 5 12 7 9 ldualelvbase ⊢ φ → H ∈ Base D
15 eqid ⊢ + D = + D
16 eqid ⊢ Scalar ⁡ D = Scalar ⁡ D
17 eqid ⊢ ⋅ D = ⋅ D
18 eqid ⊢ inv g ⁡ Scalar ⁡ D = inv g ⁡ Scalar ⁡ D
19 eqid ⊢ 1 Scalar ⁡ D = 1 Scalar ⁡ D
20 12 15 6 16 17 18 19 lmodvsubval2 ⊢ D ∈ LMod ∧ G ∈ Base D ∧ H ∈ Base D → G - ˙ H = G + D inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ⋅ D H
21 11 13 14 20 syl3anc ⊢ φ → G - ˙ H = G + D inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ⋅ D H
22 21 fveq1d ⊢ φ → G - ˙ H ⁡ X = G + D inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ⋅ D H ⁡ X
23 eqid ⊢ + R = + R
24 eqid ⊢ Base R = Base R
25 16 lmodfgrp ⊢ D ∈ LMod → Scalar ⁡ D ∈ Grp
26 11 25 syl ⊢ φ → Scalar ⁡ D ∈ Grp
27 16 lmodring ⊢ D ∈ LMod → Scalar ⁡ D ∈ Ring
28 11 27 syl ⊢ φ → Scalar ⁡ D ∈ Ring
29 eqid ⊢ Base Scalar ⁡ D = Base Scalar ⁡ D
30 29 19 ringidcl ⊢ Scalar ⁡ D ∈ Ring → 1 Scalar ⁡ D ∈ Base Scalar ⁡ D
31 28 30 syl ⊢ φ → 1 Scalar ⁡ D ∈ Base Scalar ⁡ D
32 29 18 grpinvcl ⊢ Scalar ⁡ D ∈ Grp ∧ 1 Scalar ⁡ D ∈ Base Scalar ⁡ D → inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ∈ Base Scalar ⁡ D
33 26 31 32 syl2anc ⊢ φ → inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ∈ Base Scalar ⁡ D
34 2 24 5 16 29 7 ldualsbase ⊢ φ → Base Scalar ⁡ D = Base R
35 33 34 eleqtrd ⊢ φ → inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ∈ Base R
36 4 2 24 5 17 7 35 9 ldualvscl ⊢ φ → inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ⋅ D H ∈ F
37 1 2 23 4 5 15 7 8 36 10 ldualvaddval ⊢ φ → G + D inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ⋅ D H ⁡ X = G ⁡ X + R inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ⋅ D H ⁡ X
38 eqid ⊢ inv g ⁡ R = inv g ⁡ R
39 2 38 5 16 18 7 ldualneg ⊢ φ → inv g ⁡ Scalar ⁡ D = inv g ⁡ R
40 eqid ⊢ 1 R = 1 R
41 2 40 5 16 19 7 ldual1 ⊢ φ → 1 Scalar ⁡ D = 1 R
42 39 41 fveq12d ⊢ φ → inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D = inv g ⁡ R ⁡ 1 R
43 42 oveq1d ⊢ φ → inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ⋅ D H = inv g ⁡ R ⁡ 1 R ⋅ D H
44 43 fveq1d ⊢ φ → inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ⋅ D H ⁡ X = inv g ⁡ R ⁡ 1 R ⋅ D H ⁡ X
45 eqid ⊢ ⋅ R = ⋅ R
46 2 lmodring ⊢ W ∈ LMod → R ∈ Ring
47 7 46 syl ⊢ φ → R ∈ Ring
48 ringgrp ⊢ R ∈ Ring → R ∈ Grp
49 47 48 syl ⊢ φ → R ∈ Grp
50 2 24 40 lmod1cl ⊢ W ∈ LMod → 1 R ∈ Base R
51 7 50 syl ⊢ φ → 1 R ∈ Base R
52 24 38 grpinvcl ⊢ R ∈ Grp ∧ 1 R ∈ Base R → inv g ⁡ R ⁡ 1 R ∈ Base R
53 49 51 52 syl2anc ⊢ φ → inv g ⁡ R ⁡ 1 R ∈ Base R
54 4 1 2 24 45 5 17 7 53 9 10 ldualvsval ⊢ φ → inv g ⁡ R ⁡ 1 R ⋅ D H ⁡ X = H ⁡ X ⋅ R inv g ⁡ R ⁡ 1 R
55 2 24 1 4 lflcl ⊢ W ∈ LMod ∧ H ∈ F ∧ X ∈ V → H ⁡ X ∈ Base R
56 7 9 10 55 syl3anc ⊢ φ → H ⁡ X ∈ Base R
57 24 45 40 38 47 56 ringnegr ⊢ φ → H ⁡ X ⋅ R inv g ⁡ R ⁡ 1 R = inv g ⁡ R ⁡ H ⁡ X
58 44 54 57 3eqtrd ⊢ φ → inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ⋅ D H ⁡ X = inv g ⁡ R ⁡ H ⁡ X
59 58 oveq2d ⊢ φ → G ⁡ X + R inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ⋅ D H ⁡ X = G ⁡ X + R inv g ⁡ R ⁡ H ⁡ X
60 2 24 1 4 lflcl ⊢ W ∈ LMod ∧ G ∈ F ∧ X ∈ V → G ⁡ X ∈ Base R
61 7 8 10 60 syl3anc ⊢ φ → G ⁡ X ∈ Base R
62 24 23 38 3 grpsubval ⊢ G ⁡ X ∈ Base R ∧ H ⁡ X ∈ Base R → G ⁡ X S H ⁡ X = G ⁡ X + R inv g ⁡ R ⁡ H ⁡ X
63 61 56 62 syl2anc ⊢ φ → G ⁡ X S H ⁡ X = G ⁡ X + R inv g ⁡ R ⁡ H ⁡ X
64 59 63 eqtr4d ⊢ φ → G ⁡ X + R inv g ⁡ Scalar ⁡ D ⁡ 1 Scalar ⁡ D ⋅ D H ⁡ X = G ⁡ X S H ⁡ X
65 22 37 64 3eqtrd ⊢ φ → G - ˙ H ⁡ X = G ⁡ X S H ⁡ X