Metamath Proof Explorer


Theorem line2y

Description: Example for a vertical line G passing through two different points in "standard form". (Contributed by AV, 3-Feb-2023)

Ref Expression
Hypotheses line2.i ⊢ I = 1 2
line2.e ⊢ E = I
line2.p ⊢ P = ℝ I
line2.l ⊢ L = Line M ⁡ E
line2.g ⊢ G = p ∈ P | A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C
line2y.x ⊢ X = 1 0 2 M
line2y.y ⊢ Y = 1 0 2 N
Assertion line2y ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → G = X L Y ↔ A ≠ 0 ∧ B = 0 ∧ C = 0

Proof

Step Hyp Ref Expression
1 line2.i ⊢ I = 1 2
2 line2.e ⊢ E = I
3 line2.p ⊢ P = ℝ I
4 line2.l ⊢ L = Line M ⁡ E
5 line2.g ⊢ G = p ∈ P | A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C
6 line2y.x ⊢ X = 1 0 2 M
7 line2y.y ⊢ Y = 1 0 2 N
8 5 a1i ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → G = p ∈ P | A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C
9 1ex ⊢ 1 ∈ V
10 2ex ⊢ 2 ∈ V
11 9 10 pm3.2i ⊢ 1 ∈ V ∧ 2 ∈ V
12 c0ex ⊢ 0 ∈ V
13 12 jctl ⊢ M ∈ ℝ → 0 ∈ V ∧ M ∈ ℝ
14 1ne2 ⊢ 1 ≠ 2
15 14 a1i ⊢ M ∈ ℝ → 1 ≠ 2
16 fprg ⊢ 1 ∈ V ∧ 2 ∈ V ∧ 0 ∈ V ∧ M ∈ ℝ ∧ 1 ≠ 2 → 1 0 2 M : 1 2 ⟶ 0 M
17 0red ⊢ 1 ∈ V ∧ 2 ∈ V ∧ 0 ∈ V ∧ M ∈ ℝ ∧ 1 ≠ 2 → 0 ∈ ℝ
18 simp2r ⊢ 1 ∈ V ∧ 2 ∈ V ∧ 0 ∈ V ∧ M ∈ ℝ ∧ 1 ≠ 2 → M ∈ ℝ
19 17 18 prssd ⊢ 1 ∈ V ∧ 2 ∈ V ∧ 0 ∈ V ∧ M ∈ ℝ ∧ 1 ≠ 2 → 0 M ⊆ ℝ
20 16 19 fssd ⊢ 1 ∈ V ∧ 2 ∈ V ∧ 0 ∈ V ∧ M ∈ ℝ ∧ 1 ≠ 2 → 1 0 2 M : 1 2 ⟶ ℝ
21 11 13 15 20 mp3an2i ⊢ M ∈ ℝ → 1 0 2 M : 1 2 ⟶ ℝ
22 1 feq2i ⊢ 1 0 2 M : I ⟶ ℝ ↔ 1 0 2 M : 1 2 ⟶ ℝ
23 21 22 sylibr ⊢ M ∈ ℝ → 1 0 2 M : I ⟶ ℝ
24 reex ⊢ ℝ ∈ V
25 prex ⊢ 1 2 ∈ V
26 1 25 eqeltri ⊢ I ∈ V
27 24 26 elmap ⊢ 1 0 2 M ∈ ℝ I ↔ 1 0 2 M : I ⟶ ℝ
28 23 27 sylibr ⊢ M ∈ ℝ → 1 0 2 M ∈ ℝ I
29 28 6 3 3eltr4g ⊢ M ∈ ℝ → X ∈ P
30 29 3ad2ant1 ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → X ∈ P
31 12 jctl ⊢ N ∈ ℝ → 0 ∈ V ∧ N ∈ ℝ
32 14 a1i ⊢ N ∈ ℝ → 1 ≠ 2
33 fprg ⊢ 1 ∈ V ∧ 2 ∈ V ∧ 0 ∈ V ∧ N ∈ ℝ ∧ 1 ≠ 2 → 1 0 2 N : 1 2 ⟶ 0 N
34 11 31 32 33 mp3an2i ⊢ N ∈ ℝ → 1 0 2 N : 1 2 ⟶ 0 N
35 0re ⊢ 0 ∈ ℝ
36 prssi ⊢ 0 ∈ ℝ ∧ N ∈ ℝ → 0 N ⊆ ℝ
37 35 36 mpan ⊢ N ∈ ℝ → 0 N ⊆ ℝ
38 34 37 fssd ⊢ N ∈ ℝ → 1 0 2 N : 1 2 ⟶ ℝ
39 1 feq2i ⊢ 1 0 2 N : I ⟶ ℝ ↔ 1 0 2 N : 1 2 ⟶ ℝ
40 38 39 sylibr ⊢ N ∈ ℝ → 1 0 2 N : I ⟶ ℝ
41 24 26 pm3.2i ⊢ ℝ ∈ V ∧ I ∈ V
42 elmapg ⊢ ℝ ∈ V ∧ I ∈ V → 1 0 2 N ∈ ℝ I ↔ 1 0 2 N : I ⟶ ℝ
43 41 42 mp1i ⊢ N ∈ ℝ → 1 0 2 N ∈ ℝ I ↔ 1 0 2 N : I ⟶ ℝ
44 40 43 mpbird ⊢ N ∈ ℝ → 1 0 2 N ∈ ℝ I
45 44 7 3 3eltr4g ⊢ N ∈ ℝ → Y ∈ P
46 45 3ad2ant2 ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → Y ∈ P
47 6 fveq1i ⊢ X ⁡ 1 = 1 0 2 M ⁡ 1
48 9 12 14 3pm3.2i ⊢ 1 ∈ V ∧ 0 ∈ V ∧ 1 ≠ 2
49 fvpr1g ⊢ 1 ∈ V ∧ 0 ∈ V ∧ 1 ≠ 2 → 1 0 2 M ⁡ 1 = 0
50 48 49 mp1i ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → 1 0 2 M ⁡ 1 = 0
51 47 50 eqtrid ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → X ⁡ 1 = 0
52 7 fveq1i ⊢ Y ⁡ 1 = 1 0 2 N ⁡ 1
53 fvpr1g ⊢ 1 ∈ V ∧ 0 ∈ V ∧ 1 ≠ 2 → 1 0 2 N ⁡ 1 = 0
54 48 53 mp1i ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → 1 0 2 N ⁡ 1 = 0
55 52 54 eqtrid ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → Y ⁡ 1 = 0
56 51 55 eqtr4d ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → X ⁡ 1 = Y ⁡ 1
57 simp3 ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → M ≠ N
58 6 fveq1i ⊢ X ⁡ 2 = 1 0 2 M ⁡ 2
59 simp1 ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → M ∈ ℝ
60 14 a1i ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → 1 ≠ 2
61 fvpr2g ⊢ 2 ∈ V ∧ M ∈ ℝ ∧ 1 ≠ 2 → 1 0 2 M ⁡ 2 = M
62 10 59 60 61 mp3an2i ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → 1 0 2 M ⁡ 2 = M
63 58 62 eqtrid ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → X ⁡ 2 = M
64 7 fveq1i ⊢ Y ⁡ 2 = 1 0 2 N ⁡ 2
65 simp2 ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → N ∈ ℝ
66 fvpr2g ⊢ 2 ∈ V ∧ N ∈ ℝ ∧ 1 ≠ 2 → 1 0 2 N ⁡ 2 = N
67 10 65 60 66 mp3an2i ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → 1 0 2 N ⁡ 2 = N
68 64 67 eqtrid ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → Y ⁡ 2 = N
69 57 63 68 3netr4d ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → X ⁡ 2 ≠ Y ⁡ 2
70 56 69 jca ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → X ⁡ 1 = Y ⁡ 1 ∧ X ⁡ 2 ≠ Y ⁡ 2
71 30 46 70 3jca ⊢ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → X ∈ P ∧ Y ∈ P ∧ X ⁡ 1 = Y ⁡ 1 ∧ X ⁡ 2 ≠ Y ⁡ 2
72 71 adantl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → X ∈ P ∧ Y ∈ P ∧ X ⁡ 1 = Y ⁡ 1 ∧ X ⁡ 2 ≠ Y ⁡ 2
73 1 2 3 4 rrx2vlinest ⊢ X ∈ P ∧ Y ∈ P ∧ X ⁡ 1 = Y ⁡ 1 ∧ X ⁡ 2 ≠ Y ⁡ 2 → X L Y = p ∈ P | p ⁡ 1 = X ⁡ 1
74 72 73 syl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → X L Y = p ∈ P | p ⁡ 1 = X ⁡ 1
75 8 74 eqeq12d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → G = X L Y ↔ p ∈ P | A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C = p ∈ P | p ⁡ 1 = X ⁡ 1
76 48 49 ax-mp ⊢ 1 0 2 M ⁡ 1 = 0
77 47 76 eqtri ⊢ X ⁡ 1 = 0
78 77 a1i ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → X ⁡ 1 = 0
79 78 eqeq2d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → p ⁡ 1 = X ⁡ 1 ↔ p ⁡ 1 = 0
80 79 rabbidv ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → p ∈ P | p ⁡ 1 = X ⁡ 1 = p ∈ P | p ⁡ 1 = 0
81 80 eqeq2d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → p ∈ P | A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C = p ∈ P | p ⁡ 1 = X ⁡ 1 ↔ p ∈ P | A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C = p ∈ P | p ⁡ 1 = 0
82 rabbi ⊢ ∀ p ∈ P A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C ↔ p ⁡ 1 = 0 ↔ p ∈ P | A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C = p ∈ P | p ⁡ 1 = 0
83 1 3 line2ylem ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ → ∀ p ∈ P A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C ↔ p ⁡ 1 = 0 → A ≠ 0 ∧ B = 0 ∧ C = 0
84 83 adantr ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → ∀ p ∈ P A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C ↔ p ⁡ 1 = 0 → A ≠ 0 ∧ B = 0 ∧ C = 0
85 oveq1 ⊢ B = 0 → B ⁢ p ⁡ 2 = 0 ⋅ p ⁡ 2
86 85 3ad2ant2 ⊢ A ≠ 0 ∧ B = 0 ∧ C = 0 → B ⁢ p ⁡ 2 = 0 ⋅ p ⁡ 2
87 86 oveq2d ⊢ A ≠ 0 ∧ B = 0 ∧ C = 0 → A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = A ⁢ p ⁡ 1 + 0 ⋅ p ⁡ 2
88 simp3 ⊢ A ≠ 0 ∧ B = 0 ∧ C = 0 → C = 0
89 87 88 eqeq12d ⊢ A ≠ 0 ∧ B = 0 ∧ C = 0 → A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C ↔ A ⁢ p ⁡ 1 + 0 ⋅ p ⁡ 2 = 0
90 89 ad2antlr ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C ↔ A ⁢ p ⁡ 1 + 0 ⋅ p ⁡ 2 = 0
91 1 3 rrx2pyel ⊢ p ∈ P → p ⁡ 2 ∈ ℝ
92 91 recnd ⊢ p ∈ P → p ⁡ 2 ∈ ℂ
93 92 mul02d ⊢ p ∈ P → 0 ⋅ p ⁡ 2 = 0
94 93 adantl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → 0 ⋅ p ⁡ 2 = 0
95 94 oveq2d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A ⁢ p ⁡ 1 + 0 ⋅ p ⁡ 2 = A ⁢ p ⁡ 1 + 0
96 simp1 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ → A ∈ ℝ
97 96 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ → A ∈ ℂ
98 97 ad3antrrr ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A ∈ ℂ
99 1 3 rrx2pxel ⊢ p ∈ P → p ⁡ 1 ∈ ℝ
100 99 recnd ⊢ p ∈ P → p ⁡ 1 ∈ ℂ
101 100 adantl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → p ⁡ 1 ∈ ℂ
102 98 101 mulcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A ⁢ p ⁡ 1 ∈ ℂ
103 102 addridd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A ⁢ p ⁡ 1 + 0 = A ⁢ p ⁡ 1
104 95 103 eqtrd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A ⁢ p ⁡ 1 + 0 ⋅ p ⁡ 2 = A ⁢ p ⁡ 1
105 104 eqeq1d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A ⁢ p ⁡ 1 + 0 ⋅ p ⁡ 2 = 0 ↔ A ⁢ p ⁡ 1 = 0
106 98 101 mul0ord ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A ⁢ p ⁡ 1 = 0 ↔ A = 0 ∨ p ⁡ 1 = 0
107 eqneqall ⊢ A = 0 → A ≠ 0 → p ⁡ 1 = 0
108 107 com12 ⊢ A ≠ 0 → A = 0 → p ⁡ 1 = 0
109 108 3ad2ant1 ⊢ A ≠ 0 ∧ B = 0 ∧ C = 0 → A = 0 → p ⁡ 1 = 0
110 109 ad2antlr ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A = 0 → p ⁡ 1 = 0
111 idd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → p ⁡ 1 = 0 → p ⁡ 1 = 0
112 110 111 jaod ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A = 0 ∨ p ⁡ 1 = 0 → p ⁡ 1 = 0
113 olc ⊢ p ⁡ 1 = 0 → A = 0 ∨ p ⁡ 1 = 0
114 112 113 impbid1 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A = 0 ∨ p ⁡ 1 = 0 ↔ p ⁡ 1 = 0
115 106 114 bitrd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A ⁢ p ⁡ 1 = 0 ↔ p ⁡ 1 = 0
116 90 105 115 3bitrd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 ∧ p ∈ P → A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C ↔ p ⁡ 1 = 0
117 116 ralrimiva ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N ∧ A ≠ 0 ∧ B = 0 ∧ C = 0 → ∀ p ∈ P A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C ↔ p ⁡ 1 = 0
118 117 ex ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → A ≠ 0 ∧ B = 0 ∧ C = 0 → ∀ p ∈ P A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C ↔ p ⁡ 1 = 0
119 84 118 impbid ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → ∀ p ∈ P A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C ↔ p ⁡ 1 = 0 ↔ A ≠ 0 ∧ B = 0 ∧ C = 0
120 82 119 bitr3id ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → p ∈ P | A ⁢ p ⁡ 1 + B ⁢ p ⁡ 2 = C = p ∈ P | p ⁡ 1 = 0 ↔ A ≠ 0 ∧ B = 0 ∧ C = 0
121 75 81 120 3bitrd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ M ∈ ℝ ∧ N ∈ ℝ ∧ M ≠ N → G = X L Y ↔ A ≠ 0 ∧ B = 0 ∧ C = 0