Metamath Proof Explorer


Theorem 2itscp

Description: A condition for a quadratic equation with real coefficients (for the intersection points of a line with a circle) to have (exactly) two different real solutions. (Contributed by AV, 5-Mar-2023) (Revised by AV, 16-May-2023)

Ref Expression
Hypotheses 2itscp.a ⊢ φ → A ∈ ℝ
2itscp.b ⊢ φ → B ∈ ℝ
2itscp.x ⊢ φ → X ∈ ℝ
2itscp.y ⊢ φ → Y ∈ ℝ
2itscp.d ⊢ D = X − A
2itscp.e ⊢ E = B − Y
2itscp.c ⊢ C = D ⁢ B + E ⁢ A
2itscp.r ⊢ φ → R ∈ ℝ
2itscp.l ⊢ φ → A 2 + B 2 < R 2
2itscp.n ⊢ φ → B ≠ Y ∨ A ≠ X
2itscp.q ⊢ Q = E 2 + D 2
2itscp.s ⊢ S = R 2 ⁢ Q − C 2
Assertion 2itscp ⊢ φ → 0 < S

Proof

Step Hyp Ref Expression
1 2itscp.a ⊢ φ → A ∈ ℝ
2 2itscp.b ⊢ φ → B ∈ ℝ
3 2itscp.x ⊢ φ → X ∈ ℝ
4 2itscp.y ⊢ φ → Y ∈ ℝ
5 2itscp.d ⊢ D = X − A
6 2itscp.e ⊢ E = B − Y
7 2itscp.c ⊢ C = D ⁢ B + E ⁢ A
8 2itscp.r ⊢ φ → R ∈ ℝ
9 2itscp.l ⊢ φ → A 2 + B 2 < R 2
10 2itscp.n ⊢ φ → B ≠ Y ∨ A ≠ X
11 2itscp.q ⊢ Q = E 2 + D 2
12 2itscp.s ⊢ S = R 2 ⁢ Q − C 2
13 2 recnd ⊢ φ → B ∈ ℂ
14 13 adantr ⊢ φ ∧ B ≠ Y → B ∈ ℂ
15 4 recnd ⊢ φ → Y ∈ ℂ
16 15 adantr ⊢ φ ∧ B ≠ Y → Y ∈ ℂ
17 simpr ⊢ φ ∧ B ≠ Y → B ≠ Y
18 14 16 17 subne0d ⊢ φ ∧ B ≠ Y → B − Y ≠ 0
19 18 ex ⊢ φ → B ≠ Y → B − Y ≠ 0
20 3 recnd ⊢ φ → X ∈ ℂ
21 20 adantr ⊢ φ ∧ A ≠ X → X ∈ ℂ
22 1 recnd ⊢ φ → A ∈ ℂ
23 22 adantr ⊢ φ ∧ A ≠ X → A ∈ ℂ
24 simpr ⊢ φ ∧ A ≠ X → A ≠ X
25 24 necomd ⊢ φ ∧ A ≠ X → X ≠ A
26 21 23 25 subne0d ⊢ φ ∧ A ≠ X → X − A ≠ 0
27 26 ex ⊢ φ → A ≠ X → X − A ≠ 0
28 6 neeq1i ⊢ E ≠ 0 ↔ B − Y ≠ 0
29 5 neeq1i ⊢ D ≠ 0 ↔ X − A ≠ 0
30 28 29 anbi12i ⊢ E ≠ 0 ∧ D ≠ 0 ↔ B − Y ≠ 0 ∧ X − A ≠ 0
31 2re ⊢ 2 ∈ ℝ
32 31 a1i ⊢ φ → 2 ∈ ℝ
33 3 1 resubcld ⊢ φ → X − A ∈ ℝ
34 5 33 eqeltrid ⊢ φ → D ∈ ℝ
35 34 1 remulcld ⊢ φ → D ⁢ A ∈ ℝ
36 2 4 resubcld ⊢ φ → B − Y ∈ ℝ
37 6 36 eqeltrid ⊢ φ → E ∈ ℝ
38 37 2 remulcld ⊢ φ → E ⁢ B ∈ ℝ
39 35 38 remulcld ⊢ φ → D ⁢ A ⁢ E ⁢ B ∈ ℝ
40 32 39 remulcld ⊢ φ → 2 ⁢ D ⁢ A ⁢ E ⁢ B ∈ ℝ
41 40 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B ∈ ℝ
42 37 resqcld ⊢ φ → E 2 ∈ ℝ
43 2 resqcld ⊢ φ → B 2 ∈ ℝ
44 42 43 remulcld ⊢ φ → E 2 ⁢ B 2 ∈ ℝ
45 34 resqcld ⊢ φ → D 2 ∈ ℝ
46 1 resqcld ⊢ φ → A 2 ∈ ℝ
47 45 46 remulcld ⊢ φ → D 2 ⁢ A 2 ∈ ℝ
48 44 47 readdcld ⊢ φ → E 2 ⁢ B 2 + D 2 ⁢ A 2 ∈ ℝ
49 48 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → E 2 ⁢ B 2 + D 2 ⁢ A 2 ∈ ℝ
50 8 resqcld ⊢ φ → R 2 ∈ ℝ
51 50 46 resubcld ⊢ φ → R 2 − A 2 ∈ ℝ
52 42 51 remulcld ⊢ φ → E 2 ⁢ R 2 − A 2 ∈ ℝ
53 50 43 resubcld ⊢ φ → R 2 − B 2 ∈ ℝ
54 45 53 remulcld ⊢ φ → D 2 ⁢ R 2 − B 2 ∈ ℝ
55 52 54 readdcld ⊢ φ → E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2 ∈ ℝ
56 55 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2 ∈ ℝ
57 35 38 resubcld ⊢ φ → D ⁢ A − E ⁢ B ∈ ℝ
58 57 sqge0d ⊢ φ → 0 ≤ D ⁢ A − E ⁢ B 2
59 1 2 3 4 5 6 2itscplem1 ⊢ φ → E 2 ⁢ B 2 + D 2 ⁢ A 2 - 2 ⁢ D ⁢ A ⁢ E ⁢ B = D ⁢ A − E ⁢ B 2
60 58 59 breqtrrd ⊢ φ → 0 ≤ E 2 ⁢ B 2 + D 2 ⁢ A 2 - 2 ⁢ D ⁢ A ⁢ E ⁢ B
61 48 40 subge0d ⊢ φ → 0 ≤ E 2 ⁢ B 2 + D 2 ⁢ A 2 - 2 ⁢ D ⁢ A ⁢ E ⁢ B ↔ 2 ⁢ D ⁢ A ⁢ E ⁢ B ≤ E 2 ⁢ B 2 + D 2 ⁢ A 2
62 60 61 mpbid ⊢ φ → 2 ⁢ D ⁢ A ⁢ E ⁢ B ≤ E 2 ⁢ B 2 + D 2 ⁢ A 2
63 62 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B ≤ E 2 ⁢ B 2 + D 2 ⁢ A 2
64 44 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → E 2 ⁢ B 2 ∈ ℝ
65 47 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → D 2 ⁢ A 2 ∈ ℝ
66 52 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → E 2 ⁢ R 2 − A 2 ∈ ℝ
67 54 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → D 2 ⁢ R 2 − B 2 ∈ ℝ
68 43 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → B 2 ∈ ℝ
69 51 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → R 2 − A 2 ∈ ℝ
70 simpl ⊢ E ≠ 0 ∧ D ≠ 0 → E ≠ 0
71 sqn0rp ⊢ E ∈ ℝ ∧ E ≠ 0 → E 2 ∈ ℝ +
72 37 70 71 syl2an ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → E 2 ∈ ℝ +
73 46 43 50 ltaddsub2d ⊢ φ → A 2 + B 2 < R 2 ↔ B 2 < R 2 − A 2
74 9 73 mpbid ⊢ φ → B 2 < R 2 − A 2
75 74 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → B 2 < R 2 − A 2
76 68 69 72 75 ltmul2dd ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → E 2 ⁢ B 2 < E 2 ⁢ R 2 − A 2
77 46 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → A 2 ∈ ℝ
78 53 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → R 2 − B 2 ∈ ℝ
79 simpr ⊢ E ≠ 0 ∧ D ≠ 0 → D ≠ 0
80 sqn0rp ⊢ D ∈ ℝ ∧ D ≠ 0 → D 2 ∈ ℝ +
81 34 79 80 syl2an ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → D 2 ∈ ℝ +
82 46 43 50 ltaddsubd ⊢ φ → A 2 + B 2 < R 2 ↔ A 2 < R 2 − B 2
83 9 82 mpbid ⊢ φ → A 2 < R 2 − B 2
84 83 adantr ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → A 2 < R 2 − B 2
85 77 78 81 84 ltmul2dd ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → D 2 ⁢ A 2 < D 2 ⁢ R 2 − B 2
86 64 65 66 67 76 85 lt2addd ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → E 2 ⁢ B 2 + D 2 ⁢ A 2 < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
87 41 49 56 63 86 lelttrd ⊢ φ ∧ E ≠ 0 ∧ D ≠ 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
88 87 ex ⊢ φ → E ≠ 0 ∧ D ≠ 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
89 30 88 biimtrrid ⊢ φ → B − Y ≠ 0 ∧ X − A ≠ 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
90 19 27 89 syl2and ⊢ φ → B ≠ Y ∧ A ≠ X → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
91 90 imp ⊢ φ ∧ B ≠ Y ∧ A ≠ X → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
92 nne ⊢ ¬ A ≠ X ↔ A = X
93 eqcom ⊢ A = X ↔ X = A
94 20 22 subeq0ad ⊢ φ → X − A = 0 ↔ X = A
95 94 biimprd ⊢ φ → X = A → X − A = 0
96 93 95 biimtrid ⊢ φ → A = X → X − A = 0
97 92 96 biimtrid ⊢ φ → ¬ A ≠ X → X − A = 0
98 5 eqeq1i ⊢ D = 0 ↔ X − A = 0
99 28 98 anbi12i ⊢ E ≠ 0 ∧ D = 0 ↔ B − Y ≠ 0 ∧ X − A = 0
100 0red ⊢ φ ∧ E ≠ 0 ∧ D = 0 → 0 ∈ ℝ
101 44 adantr ⊢ φ ∧ E ≠ 0 ∧ D = 0 → E 2 ⁢ B 2 ∈ ℝ
102 52 adantr ⊢ φ ∧ E ≠ 0 ∧ D = 0 → E 2 ⁢ R 2 − A 2 ∈ ℝ
103 37 sqge0d ⊢ φ → 0 ≤ E 2
104 2 sqge0d ⊢ φ → 0 ≤ B 2
105 42 43 103 104 mulge0d ⊢ φ → 0 ≤ E 2 ⁢ B 2
106 105 adantr ⊢ φ ∧ E ≠ 0 ∧ D = 0 → 0 ≤ E 2 ⁢ B 2
107 43 adantr ⊢ φ ∧ E ≠ 0 ∧ D = 0 → B 2 ∈ ℝ
108 51 adantr ⊢ φ ∧ E ≠ 0 ∧ D = 0 → R 2 − A 2 ∈ ℝ
109 simprl ⊢ φ ∧ E ≠ 0 ∧ D = 0 → E ≠ 0
110 37 109 71 syl2an2r ⊢ φ ∧ E ≠ 0 ∧ D = 0 → E 2 ∈ ℝ +
111 74 adantr ⊢ φ ∧ E ≠ 0 ∧ D = 0 → B 2 < R 2 − A 2
112 107 108 110 111 ltmul2dd ⊢ φ ∧ E ≠ 0 ∧ D = 0 → E 2 ⁢ B 2 < E 2 ⁢ R 2 − A 2
113 100 101 102 106 112 lelttrd ⊢ φ ∧ E ≠ 0 ∧ D = 0 → 0 < E 2 ⁢ R 2 − A 2
114 oveq1 ⊢ D = 0 → D ⁢ A = 0 ⋅ A
115 114 adantl ⊢ E ≠ 0 ∧ D = 0 → D ⁢ A = 0 ⋅ A
116 22 mul02d ⊢ φ → 0 ⋅ A = 0
117 115 116 sylan9eqr ⊢ φ ∧ E ≠ 0 ∧ D = 0 → D ⁢ A = 0
118 117 oveq1d ⊢ φ ∧ E ≠ 0 ∧ D = 0 → D ⁢ A ⁢ E ⁢ B = 0 ⋅ E ⁢ B
119 38 recnd ⊢ φ → E ⁢ B ∈ ℂ
120 119 mul02d ⊢ φ → 0 ⋅ E ⁢ B = 0
121 120 adantr ⊢ φ ∧ E ≠ 0 ∧ D = 0 → 0 ⋅ E ⁢ B = 0
122 118 121 eqtrd ⊢ φ ∧ E ≠ 0 ∧ D = 0 → D ⁢ A ⁢ E ⁢ B = 0
123 122 oveq2d ⊢ φ ∧ E ≠ 0 ∧ D = 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B = 2 ⋅ 0
124 2t0e0 ⊢ 2 ⋅ 0 = 0
125 123 124 eqtrdi ⊢ φ ∧ E ≠ 0 ∧ D = 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B = 0
126 sq0i ⊢ D = 0 → D 2 = 0
127 126 adantl ⊢ E ≠ 0 ∧ D = 0 → D 2 = 0
128 127 adantl ⊢ φ ∧ E ≠ 0 ∧ D = 0 → D 2 = 0
129 128 oveq1d ⊢ φ ∧ E ≠ 0 ∧ D = 0 → D 2 ⁢ R 2 − B 2 = 0 ⋅ R 2 − B 2
130 53 recnd ⊢ φ → R 2 − B 2 ∈ ℂ
131 130 mul02d ⊢ φ → 0 ⋅ R 2 − B 2 = 0
132 131 adantr ⊢ φ ∧ E ≠ 0 ∧ D = 0 → 0 ⋅ R 2 − B 2 = 0
133 129 132 eqtrd ⊢ φ ∧ E ≠ 0 ∧ D = 0 → D 2 ⁢ R 2 − B 2 = 0
134 133 oveq2d ⊢ φ ∧ E ≠ 0 ∧ D = 0 → E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2 = E 2 ⁢ R 2 − A 2 + 0
135 52 recnd ⊢ φ → E 2 ⁢ R 2 − A 2 ∈ ℂ
136 135 addridd ⊢ φ → E 2 ⁢ R 2 − A 2 + 0 = E 2 ⁢ R 2 − A 2
137 136 adantr ⊢ φ ∧ E ≠ 0 ∧ D = 0 → E 2 ⁢ R 2 − A 2 + 0 = E 2 ⁢ R 2 − A 2
138 134 137 eqtrd ⊢ φ ∧ E ≠ 0 ∧ D = 0 → E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2 = E 2 ⁢ R 2 − A 2
139 113 125 138 3brtr4d ⊢ φ ∧ E ≠ 0 ∧ D = 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
140 139 ex ⊢ φ → E ≠ 0 ∧ D = 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
141 99 140 biimtrrid ⊢ φ → B − Y ≠ 0 ∧ X − A = 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
142 19 97 141 syl2and ⊢ φ → B ≠ Y ∧ ¬ A ≠ X → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
143 142 imp ⊢ φ ∧ B ≠ Y ∧ ¬ A ≠ X → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
144 nne ⊢ ¬ B ≠ Y ↔ B = Y
145 13 15 subeq0ad ⊢ φ → B − Y = 0 ↔ B = Y
146 145 biimprd ⊢ φ → B = Y → B − Y = 0
147 144 146 biimtrid ⊢ φ → ¬ B ≠ Y → B − Y = 0
148 6 eqeq1i ⊢ E = 0 ↔ B − Y = 0
149 148 29 anbi12i ⊢ E = 0 ∧ D ≠ 0 ↔ B − Y = 0 ∧ X − A ≠ 0
150 0red ⊢ φ ∧ E = 0 ∧ D ≠ 0 → 0 ∈ ℝ
151 47 adantr ⊢ φ ∧ E = 0 ∧ D ≠ 0 → D 2 ⁢ A 2 ∈ ℝ
152 54 adantr ⊢ φ ∧ E = 0 ∧ D ≠ 0 → D 2 ⁢ R 2 − B 2 ∈ ℝ
153 34 sqge0d ⊢ φ → 0 ≤ D 2
154 1 sqge0d ⊢ φ → 0 ≤ A 2
155 45 46 153 154 mulge0d ⊢ φ → 0 ≤ D 2 ⁢ A 2
156 155 adantr ⊢ φ ∧ E = 0 ∧ D ≠ 0 → 0 ≤ D 2 ⁢ A 2
157 46 adantr ⊢ φ ∧ E = 0 ∧ D ≠ 0 → A 2 ∈ ℝ
158 53 adantr ⊢ φ ∧ E = 0 ∧ D ≠ 0 → R 2 − B 2 ∈ ℝ
159 simprr ⊢ φ ∧ E = 0 ∧ D ≠ 0 → D ≠ 0
160 34 159 80 syl2an2r ⊢ φ ∧ E = 0 ∧ D ≠ 0 → D 2 ∈ ℝ +
161 43 recnd ⊢ φ → B 2 ∈ ℂ
162 46 recnd ⊢ φ → A 2 ∈ ℂ
163 161 162 addcomd ⊢ φ → B 2 + A 2 = A 2 + B 2
164 163 9 eqbrtrd ⊢ φ → B 2 + A 2 < R 2
165 43 46 50 ltaddsub2d ⊢ φ → B 2 + A 2 < R 2 ↔ A 2 < R 2 − B 2
166 164 165 mpbid ⊢ φ → A 2 < R 2 − B 2
167 166 adantr ⊢ φ ∧ E = 0 ∧ D ≠ 0 → A 2 < R 2 − B 2
168 157 158 160 167 ltmul2dd ⊢ φ ∧ E = 0 ∧ D ≠ 0 → D 2 ⁢ A 2 < D 2 ⁢ R 2 − B 2
169 150 151 152 156 168 lelttrd ⊢ φ ∧ E = 0 ∧ D ≠ 0 → 0 < D 2 ⁢ R 2 − B 2
170 oveq1 ⊢ E = 0 → E ⁢ B = 0 ⋅ B
171 170 adantr ⊢ E = 0 ∧ D ≠ 0 → E ⁢ B = 0 ⋅ B
172 13 mul02d ⊢ φ → 0 ⋅ B = 0
173 171 172 sylan9eqr ⊢ φ ∧ E = 0 ∧ D ≠ 0 → E ⁢ B = 0
174 173 oveq2d ⊢ φ ∧ E = 0 ∧ D ≠ 0 → D ⁢ A ⁢ E ⁢ B = D ⁢ A ⋅ 0
175 34 adantr ⊢ φ ∧ E = 0 ∧ D ≠ 0 → D ∈ ℝ
176 175 recnd ⊢ φ ∧ E = 0 ∧ D ≠ 0 → D ∈ ℂ
177 22 adantr ⊢ φ ∧ E = 0 ∧ D ≠ 0 → A ∈ ℂ
178 176 177 mulcld ⊢ φ ∧ E = 0 ∧ D ≠ 0 → D ⁢ A ∈ ℂ
179 178 mul01d ⊢ φ ∧ E = 0 ∧ D ≠ 0 → D ⁢ A ⋅ 0 = 0
180 174 179 eqtrd ⊢ φ ∧ E = 0 ∧ D ≠ 0 → D ⁢ A ⁢ E ⁢ B = 0
181 180 oveq2d ⊢ φ ∧ E = 0 ∧ D ≠ 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B = 2 ⋅ 0
182 181 124 eqtrdi ⊢ φ ∧ E = 0 ∧ D ≠ 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B = 0
183 sq0i ⊢ E = 0 → E 2 = 0
184 183 adantr ⊢ E = 0 ∧ D ≠ 0 → E 2 = 0
185 184 adantl ⊢ φ ∧ E = 0 ∧ D ≠ 0 → E 2 = 0
186 185 oveq1d ⊢ φ ∧ E = 0 ∧ D ≠ 0 → E 2 ⁢ R 2 − A 2 = 0 ⋅ R 2 − A 2
187 51 recnd ⊢ φ → R 2 − A 2 ∈ ℂ
188 187 mul02d ⊢ φ → 0 ⋅ R 2 − A 2 = 0
189 188 adantr ⊢ φ ∧ E = 0 ∧ D ≠ 0 → 0 ⋅ R 2 − A 2 = 0
190 186 189 eqtrd ⊢ φ ∧ E = 0 ∧ D ≠ 0 → E 2 ⁢ R 2 − A 2 = 0
191 190 oveq1d ⊢ φ ∧ E = 0 ∧ D ≠ 0 → E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2 = 0 + D 2 ⁢ R 2 − B 2
192 54 recnd ⊢ φ → D 2 ⁢ R 2 − B 2 ∈ ℂ
193 192 addlidd ⊢ φ → 0 + D 2 ⁢ R 2 − B 2 = D 2 ⁢ R 2 − B 2
194 193 adantr ⊢ φ ∧ E = 0 ∧ D ≠ 0 → 0 + D 2 ⁢ R 2 − B 2 = D 2 ⁢ R 2 − B 2
195 191 194 eqtrd ⊢ φ ∧ E = 0 ∧ D ≠ 0 → E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2 = D 2 ⁢ R 2 − B 2
196 169 182 195 3brtr4d ⊢ φ ∧ E = 0 ∧ D ≠ 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
197 196 ex ⊢ φ → E = 0 ∧ D ≠ 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
198 149 197 biimtrrid ⊢ φ → B − Y = 0 ∧ X − A ≠ 0 → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
199 147 27 198 syl2and ⊢ φ → ¬ B ≠ Y ∧ A ≠ X → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
200 199 imp ⊢ φ ∧ ¬ B ≠ Y ∧ A ≠ X → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
201 ioran ⊢ ¬ B ≠ Y ∨ A ≠ X ↔ ¬ B ≠ Y ∧ ¬ A ≠ X
202 10 pm2.24d ⊢ φ → ¬ B ≠ Y ∨ A ≠ X → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
203 201 202 biimtrrid ⊢ φ → ¬ B ≠ Y ∧ ¬ A ≠ X → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
204 203 imp ⊢ φ ∧ ¬ B ≠ Y ∧ ¬ A ≠ X → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
205 91 143 200 204 4casesdan ⊢ φ → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2
206 40 55 posdifd ⊢ φ → 2 ⁢ D ⁢ A ⁢ E ⁢ B < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2 ↔ 0 < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2 - 2 ⁢ D ⁢ A ⁢ E ⁢ B
207 205 206 mpbid ⊢ φ → 0 < E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2 - 2 ⁢ D ⁢ A ⁢ E ⁢ B
208 1 2 3 4 5 6 7 8 11 12 2itscplem3 ⊢ φ → S = E 2 ⁢ R 2 − A 2 + D 2 ⁢ R 2 − B 2 - 2 ⁢ D ⁢ A ⁢ E ⁢ B
209 207 208 breqtrrd ⊢ φ → 0 < S