Metamath Proof Explorer


Theorem i1fmullem

Description: Decompose the preimage of a product. (Contributed by Mario Carneiro, 19-Jun-2014)

Ref Expression
Hypotheses i1fadd.1 ⊢ φ → F ∈ dom ⁡ ∫ 1
i1fadd.2 ⊢ φ → G ∈ dom ⁡ ∫ 1
Assertion i1fmullem ⊢ φ ∧ A ∈ ℂ ∖ 0 → F × f G -1 A = ⋃ y ∈ ran ⁡ G ∖ 0 F -1 A y ∩ G -1 y

Proof

Step Hyp Ref Expression
1 i1fadd.1 ⊢ φ → F ∈ dom ⁡ ∫ 1
2 i1fadd.2 ⊢ φ → G ∈ dom ⁡ ∫ 1
3 i1ff ⊢ F ∈ dom ⁡ ∫ 1 → F : ℝ ⟶ ℝ
4 1 3 syl ⊢ φ → F : ℝ ⟶ ℝ
5 4 ffnd ⊢ φ → F Fn ℝ
6 i1ff ⊢ G ∈ dom ⁡ ∫ 1 → G : ℝ ⟶ ℝ
7 2 6 syl ⊢ φ → G : ℝ ⟶ ℝ
8 7 ffnd ⊢ φ → G Fn ℝ
9 reex ⊢ ℝ ∈ V
10 9 a1i ⊢ φ → ℝ ∈ V
11 inidm ⊢ ℝ ∩ ℝ = ℝ
12 5 8 10 10 11 offn ⊢ φ → F × f G Fn ℝ
13 12 adantr ⊢ φ ∧ A ∈ ℂ ∖ 0 → F × f G Fn ℝ
14 fniniseg ⊢ F × f G Fn ℝ → z ∈ F × f G -1 A ↔ z ∈ ℝ ∧ F × f G ⁡ z = A
15 13 14 syl ⊢ φ ∧ A ∈ ℂ ∖ 0 → z ∈ F × f G -1 A ↔ z ∈ ℝ ∧ F × f G ⁡ z = A
16 5 adantr ⊢ φ ∧ A ∈ ℂ ∖ 0 → F Fn ℝ
17 8 adantr ⊢ φ ∧ A ∈ ℂ ∖ 0 → G Fn ℝ
18 9 a1i ⊢ φ ∧ A ∈ ℂ ∖ 0 → ℝ ∈ V
19 eqidd ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ → F ⁡ z = F ⁡ z
20 eqidd ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ → G ⁡ z = G ⁡ z
21 16 17 18 18 11 19 20 ofval ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ → F × f G ⁡ z = F ⁡ z ⁢ G ⁡ z
22 21 eqeq1d ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ → F × f G ⁡ z = A ↔ F ⁡ z ⁢ G ⁡ z = A
23 22 pm5.32da ⊢ φ ∧ A ∈ ℂ ∖ 0 → z ∈ ℝ ∧ F × f G ⁡ z = A ↔ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A
24 8 ad2antrr ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → G Fn ℝ
25 simprl ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → z ∈ ℝ
26 fnfvelrn ⊢ G Fn ℝ ∧ z ∈ ℝ → G ⁡ z ∈ ran ⁡ G
27 24 25 26 syl2anc ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → G ⁡ z ∈ ran ⁡ G
28 eldifsni ⊢ A ∈ ℂ ∖ 0 → A ≠ 0
29 28 ad2antlr ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → A ≠ 0
30 simprr ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → F ⁡ z ⁢ G ⁡ z = A
31 4 ad2antrr ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → F : ℝ ⟶ ℝ
32 31 25 ffvelcdmd ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → F ⁡ z ∈ ℝ
33 32 recnd ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → F ⁡ z ∈ ℂ
34 33 mul01d ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → F ⁡ z ⋅ 0 = 0
35 29 30 34 3netr4d ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → F ⁡ z ⁢ G ⁡ z ≠ F ⁡ z ⋅ 0
36 oveq2 ⊢ G ⁡ z = 0 → F ⁡ z ⁢ G ⁡ z = F ⁡ z ⋅ 0
37 36 necon3i ⊢ F ⁡ z ⁢ G ⁡ z ≠ F ⁡ z ⋅ 0 → G ⁡ z ≠ 0
38 35 37 syl ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → G ⁡ z ≠ 0
39 eldifsn ⊢ G ⁡ z ∈ ran ⁡ G ∖ 0 ↔ G ⁡ z ∈ ran ⁡ G ∧ G ⁡ z ≠ 0
40 27 38 39 sylanbrc ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → G ⁡ z ∈ ran ⁡ G ∖ 0
41 7 ad2antrr ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → G : ℝ ⟶ ℝ
42 41 25 ffvelcdmd ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → G ⁡ z ∈ ℝ
43 42 recnd ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → G ⁡ z ∈ ℂ
44 33 43 38 divcan4d ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → F ⁡ z ⁢ G ⁡ z G ⁡ z = F ⁡ z
45 30 oveq1d ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → F ⁡ z ⁢ G ⁡ z G ⁡ z = A G ⁡ z
46 44 45 eqtr3d ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → F ⁡ z = A G ⁡ z
47 31 ffnd ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → F Fn ℝ
48 fniniseg ⊢ F Fn ℝ → z ∈ F -1 A G ⁡ z ↔ z ∈ ℝ ∧ F ⁡ z = A G ⁡ z
49 47 48 syl ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → z ∈ F -1 A G ⁡ z ↔ z ∈ ℝ ∧ F ⁡ z = A G ⁡ z
50 25 46 49 mpbir2and ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → z ∈ F -1 A G ⁡ z
51 eqidd ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → G ⁡ z = G ⁡ z
52 fniniseg ⊢ G Fn ℝ → z ∈ G -1 G ⁡ z ↔ z ∈ ℝ ∧ G ⁡ z = G ⁡ z
53 24 52 syl ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → z ∈ G -1 G ⁡ z ↔ z ∈ ℝ ∧ G ⁡ z = G ⁡ z
54 25 51 53 mpbir2and ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → z ∈ G -1 G ⁡ z
55 50 54 elind ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → z ∈ F -1 A G ⁡ z ∩ G -1 G ⁡ z
56 oveq2 ⊢ y = G ⁡ z → A y = A G ⁡ z
57 56 sneqd ⊢ y = G ⁡ z → A y = A G ⁡ z
58 57 imaeq2d ⊢ y = G ⁡ z → F -1 A y = F -1 A G ⁡ z
59 sneq ⊢ y = G ⁡ z → y = G ⁡ z
60 59 imaeq2d ⊢ y = G ⁡ z → G -1 y = G -1 G ⁡ z
61 58 60 ineq12d ⊢ y = G ⁡ z → F -1 A y ∩ G -1 y = F -1 A G ⁡ z ∩ G -1 G ⁡ z
62 61 eleq2d ⊢ y = G ⁡ z → z ∈ F -1 A y ∩ G -1 y ↔ z ∈ F -1 A G ⁡ z ∩ G -1 G ⁡ z
63 62 rspcev ⊢ G ⁡ z ∈ ran ⁡ G ∖ 0 ∧ z ∈ F -1 A G ⁡ z ∩ G -1 G ⁡ z → ∃ y ∈ ran ⁡ G ∖ 0 z ∈ F -1 A y ∩ G -1 y
64 40 55 63 syl2anc ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → ∃ y ∈ ran ⁡ G ∖ 0 z ∈ F -1 A y ∩ G -1 y
65 64 ex ⊢ φ ∧ A ∈ ℂ ∖ 0 → z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A → ∃ y ∈ ran ⁡ G ∖ 0 z ∈ F -1 A y ∩ G -1 y
66 fniniseg ⊢ F Fn ℝ → z ∈ F -1 A y ↔ z ∈ ℝ ∧ F ⁡ z = A y
67 16 66 syl ⊢ φ ∧ A ∈ ℂ ∖ 0 → z ∈ F -1 A y ↔ z ∈ ℝ ∧ F ⁡ z = A y
68 fniniseg ⊢ G Fn ℝ → z ∈ G -1 y ↔ z ∈ ℝ ∧ G ⁡ z = y
69 17 68 syl ⊢ φ ∧ A ∈ ℂ ∖ 0 → z ∈ G -1 y ↔ z ∈ ℝ ∧ G ⁡ z = y
70 67 69 anbi12d ⊢ φ ∧ A ∈ ℂ ∖ 0 → z ∈ F -1 A y ∧ z ∈ G -1 y ↔ z ∈ ℝ ∧ F ⁡ z = A y ∧ z ∈ ℝ ∧ G ⁡ z = y
71 elin ⊢ z ∈ F -1 A y ∩ G -1 y ↔ z ∈ F -1 A y ∧ z ∈ G -1 y
72 anandi ⊢ z ∈ ℝ ∧ F ⁡ z = A y ∧ G ⁡ z = y ↔ z ∈ ℝ ∧ F ⁡ z = A y ∧ z ∈ ℝ ∧ G ⁡ z = y
73 70 71 72 3bitr4g ⊢ φ ∧ A ∈ ℂ ∖ 0 → z ∈ F -1 A y ∩ G -1 y ↔ z ∈ ℝ ∧ F ⁡ z = A y ∧ G ⁡ z = y
74 73 adantr ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 → z ∈ F -1 A y ∩ G -1 y ↔ z ∈ ℝ ∧ F ⁡ z = A y ∧ G ⁡ z = y
75 eldifi ⊢ A ∈ ℂ ∖ 0 → A ∈ ℂ
76 75 ad2antlr ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 ∧ z ∈ ℝ → A ∈ ℂ
77 7 ad2antrr ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 ∧ z ∈ ℝ → G : ℝ ⟶ ℝ
78 77 frnd ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 ∧ z ∈ ℝ → ran ⁡ G ⊆ ℝ
79 simprl ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 ∧ z ∈ ℝ → y ∈ ran ⁡ G ∖ 0
80 eldifsn ⊢ y ∈ ran ⁡ G ∖ 0 ↔ y ∈ ran ⁡ G ∧ y ≠ 0
81 79 80 sylib ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 ∧ z ∈ ℝ → y ∈ ran ⁡ G ∧ y ≠ 0
82 81 simpld ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 ∧ z ∈ ℝ → y ∈ ran ⁡ G
83 78 82 sseldd ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 ∧ z ∈ ℝ → y ∈ ℝ
84 83 recnd ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 ∧ z ∈ ℝ → y ∈ ℂ
85 81 simprd ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 ∧ z ∈ ℝ → y ≠ 0
86 76 84 85 divcan1d ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 ∧ z ∈ ℝ → A y ⁢ y = A
87 oveq12 ⊢ F ⁡ z = A y ∧ G ⁡ z = y → F ⁡ z ⁢ G ⁡ z = A y ⁢ y
88 87 eqeq1d ⊢ F ⁡ z = A y ∧ G ⁡ z = y → F ⁡ z ⁢ G ⁡ z = A ↔ A y ⁢ y = A
89 86 88 syl5ibrcom ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 ∧ z ∈ ℝ → F ⁡ z = A y ∧ G ⁡ z = y → F ⁡ z ⁢ G ⁡ z = A
90 89 anassrs ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 ∧ z ∈ ℝ → F ⁡ z = A y ∧ G ⁡ z = y → F ⁡ z ⁢ G ⁡ z = A
91 90 imdistanda ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 → z ∈ ℝ ∧ F ⁡ z = A y ∧ G ⁡ z = y → z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A
92 74 91 sylbid ⊢ φ ∧ A ∈ ℂ ∖ 0 ∧ y ∈ ran ⁡ G ∖ 0 → z ∈ F -1 A y ∩ G -1 y → z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A
93 92 rexlimdva ⊢ φ ∧ A ∈ ℂ ∖ 0 → ∃ y ∈ ran ⁡ G ∖ 0 z ∈ F -1 A y ∩ G -1 y → z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A
94 65 93 impbid ⊢ φ ∧ A ∈ ℂ ∖ 0 → z ∈ ℝ ∧ F ⁡ z ⁢ G ⁡ z = A ↔ ∃ y ∈ ran ⁡ G ∖ 0 z ∈ F -1 A y ∩ G -1 y
95 15 23 94 3bitrd ⊢ φ ∧ A ∈ ℂ ∖ 0 → z ∈ F × f G -1 A ↔ ∃ y ∈ ran ⁡ G ∖ 0 z ∈ F -1 A y ∩ G -1 y
96 eliun ⊢ z ∈ ⋃ y ∈ ran ⁡ G ∖ 0 F -1 A y ∩ G -1 y ↔ ∃ y ∈ ran ⁡ G ∖ 0 z ∈ F -1 A y ∩ G -1 y
97 95 96 bitr4di ⊢ φ ∧ A ∈ ℂ ∖ 0 → z ∈ F × f G -1 A ↔ z ∈ ⋃ y ∈ ran ⁡ G ∖ 0 F -1 A y ∩ G -1 y
98 97 eqrdv ⊢ φ ∧ A ∈ ℂ ∖ 0 → F × f G -1 A = ⋃ y ∈ ran ⁡ G ∖ 0 F -1 A y ∩ G -1 y