Metamath Proof Explorer


Theorem lcfrlem31

Description: Lemma for lcfr . (Contributed by NM, 10-Mar-2015)

Ref Expression
Hypotheses lcfrlem17.h ⊢ H = LHyp ⁡ K
lcfrlem17.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
lcfrlem17.u ⊢ U = DVecH ⁡ K ⁡ W
lcfrlem17.v ⊢ V = Base U
lcfrlem17.p ⊢ + ˙ = + U
lcfrlem17.z ⊢ 0 ˙ = 0 U
lcfrlem17.n ⊢ N = LSpan ⁡ U
lcfrlem17.a ⊢ A = LSAtoms ⁡ U
lcfrlem17.k ⊢ φ → K ∈ HL ∧ W ∈ H
lcfrlem17.x ⊢ φ → X ∈ V ∖ 0 ˙
lcfrlem17.y ⊢ φ → Y ∈ V ∖ 0 ˙
lcfrlem17.ne ⊢ φ → N ⁡ X ≠ N ⁡ Y
lcfrlem22.b ⊢ B = N ⁡ X Y ∩ ⊥ ˙ ⁡ X + ˙ Y
lcfrlem24.t ⊢ · ˙ = ⋅ U
lcfrlem24.s ⊢ S = Scalar ⁡ U
lcfrlem24.q ⊢ Q = 0 S
lcfrlem24.r ⊢ R = Base S
lcfrlem24.j ⊢ J = x ∈ V ∖ 0 ˙ ⟼ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ x v = w + ˙ k · ˙ x
lcfrlem24.ib ⊢ φ → I ∈ B
lcfrlem24.l ⊢ L = LKer ⁡ U
lcfrlem25.d ⊢ D = LDual ⁡ U
lcfrlem28.jn ⊢ φ → J ⁡ Y ⁡ I ≠ Q
lcfrlem29.i ⊢ F = inv r ⁡ S
lcfrlem30.m ⊢ - ˙ = - D
lcfrlem30.c ⊢ C = J ⁡ X - ˙ F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y
lcfrlem31.xi ⊢ φ → J ⁡ X ⁡ I ≠ Q
lcfrlem31.cn ⊢ φ → C = 0 D
Assertion lcfrlem31 ⊢ φ → N ⁡ X = N ⁡ Y

Proof

Step Hyp Ref Expression
1 lcfrlem17.h ⊢ H = LHyp ⁡ K
2 lcfrlem17.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
3 lcfrlem17.u ⊢ U = DVecH ⁡ K ⁡ W
4 lcfrlem17.v ⊢ V = Base U
5 lcfrlem17.p ⊢ + ˙ = + U
6 lcfrlem17.z ⊢ 0 ˙ = 0 U
7 lcfrlem17.n ⊢ N = LSpan ⁡ U
8 lcfrlem17.a ⊢ A = LSAtoms ⁡ U
9 lcfrlem17.k ⊢ φ → K ∈ HL ∧ W ∈ H
10 lcfrlem17.x ⊢ φ → X ∈ V ∖ 0 ˙
11 lcfrlem17.y ⊢ φ → Y ∈ V ∖ 0 ˙
12 lcfrlem17.ne ⊢ φ → N ⁡ X ≠ N ⁡ Y
13 lcfrlem22.b ⊢ B = N ⁡ X Y ∩ ⊥ ˙ ⁡ X + ˙ Y
14 lcfrlem24.t ⊢ · ˙ = ⋅ U
15 lcfrlem24.s ⊢ S = Scalar ⁡ U
16 lcfrlem24.q ⊢ Q = 0 S
17 lcfrlem24.r ⊢ R = Base S
18 lcfrlem24.j ⊢ J = x ∈ V ∖ 0 ˙ ⟼ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ x v = w + ˙ k · ˙ x
19 lcfrlem24.ib ⊢ φ → I ∈ B
20 lcfrlem24.l ⊢ L = LKer ⁡ U
21 lcfrlem25.d ⊢ D = LDual ⁡ U
22 lcfrlem28.jn ⊢ φ → J ⁡ Y ⁡ I ≠ Q
23 lcfrlem29.i ⊢ F = inv r ⁡ S
24 lcfrlem30.m ⊢ - ˙ = - D
25 lcfrlem30.c ⊢ C = J ⁡ X - ˙ F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y
26 lcfrlem31.xi ⊢ φ → J ⁡ X ⁡ I ≠ Q
27 lcfrlem31.cn ⊢ φ → C = 0 D
28 25 27 eqtr3id ⊢ φ → J ⁡ X - ˙ F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y = 0 D
29 1 3 9 dvhlmod ⊢ φ → U ∈ LMod
30 21 29 lduallmod ⊢ φ → D ∈ LMod
31 eqid ⊢ LFnl ⁡ U = LFnl ⁡ U
32 eqid ⊢ Base D = Base D
33 eqid ⊢ 0 D = 0 D
34 eqid ⊢ f ∈ LFnl ⁡ U | ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ f = L ⁡ f = f ∈ LFnl ⁡ U | ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ f = L ⁡ f
35 1 2 3 4 5 14 15 17 6 31 20 21 33 34 18 9 10 lcfrlem10 ⊢ φ → J ⁡ X ∈ LFnl ⁡ U
36 31 21 32 29 35 ldualelvbase ⊢ φ → J ⁡ X ∈ Base D
37 eqid ⊢ ⋅ D = ⋅ D
38 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 lcfrlem29 ⊢ φ → F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ∈ R
39 1 2 3 4 5 14 15 17 6 31 20 21 33 34 18 9 11 lcfrlem10 ⊢ φ → J ⁡ Y ∈ LFnl ⁡ U
40 31 15 17 21 37 29 38 39 ldualvscl ⊢ φ → F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y ∈ LFnl ⁡ U
41 31 21 32 29 40 ldualelvbase ⊢ φ → F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y ∈ Base D
42 32 33 24 lmodsubeq0 ⊢ D ∈ LMod ∧ J ⁡ X ∈ Base D ∧ F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y ∈ Base D → J ⁡ X - ˙ F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y = 0 D ↔ J ⁡ X = F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y
43 30 36 41 42 syl3anc ⊢ φ → J ⁡ X - ˙ F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y = 0 D ↔ J ⁡ X = F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y
44 28 43 mpbid ⊢ φ → J ⁡ X = F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y
45 44 fveq2d ⊢ φ → L ⁡ J ⁡ X = L ⁡ F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y
46 1 3 9 dvhlvec ⊢ φ → U ∈ LVec
47 15 lvecdrng ⊢ U ∈ LVec → S ∈ DivRing
48 46 47 syl ⊢ φ → S ∈ DivRing
49 1 2 3 4 5 6 7 8 9 10 11 12 13 lcfrlem22 ⊢ φ → B ∈ A
50 4 8 29 49 lsatssv ⊢ φ → B ⊆ V
51 50 19 sseldd ⊢ φ → I ∈ V
52 15 17 4 31 lflcl ⊢ U ∈ LMod ∧ J ⁡ Y ∈ LFnl ⁡ U ∧ I ∈ V → J ⁡ Y ⁡ I ∈ R
53 29 39 51 52 syl3anc ⊢ φ → J ⁡ Y ⁡ I ∈ R
54 17 16 23 drnginvrn0 ⊢ S ∈ DivRing ∧ J ⁡ Y ⁡ I ∈ R ∧ J ⁡ Y ⁡ I ≠ Q → F ⁡ J ⁡ Y ⁡ I ≠ Q
55 48 53 22 54 syl3anc ⊢ φ → F ⁡ J ⁡ Y ⁡ I ≠ Q
56 eqid ⊢ ⋅ S = ⋅ S
57 17 16 23 drnginvrcl ⊢ S ∈ DivRing ∧ J ⁡ Y ⁡ I ∈ R ∧ J ⁡ Y ⁡ I ≠ Q → F ⁡ J ⁡ Y ⁡ I ∈ R
58 48 53 22 57 syl3anc ⊢ φ → F ⁡ J ⁡ Y ⁡ I ∈ R
59 15 17 4 31 lflcl ⊢ U ∈ LMod ∧ J ⁡ X ∈ LFnl ⁡ U ∧ I ∈ V → J ⁡ X ⁡ I ∈ R
60 29 35 51 59 syl3anc ⊢ φ → J ⁡ X ⁡ I ∈ R
61 17 16 56 48 58 60 drngmulne0 ⊢ φ → F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ≠ Q ↔ F ⁡ J ⁡ Y ⁡ I ≠ Q ∧ J ⁡ X ⁡ I ≠ Q
62 55 26 61 mpbir2and ⊢ φ → F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ≠ Q
63 15 17 16 31 20 21 37 46 39 38 62 ldualkrsc ⊢ φ → L ⁡ F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y = L ⁡ J ⁡ Y
64 45 63 eqtrd ⊢ φ → L ⁡ J ⁡ X = L ⁡ J ⁡ Y
65 64 fveq2d ⊢ φ → ⊥ ˙ ⁡ L ⁡ J ⁡ X = ⊥ ˙ ⁡ L ⁡ J ⁡ Y
66 1 2 3 4 5 14 15 17 6 31 20 21 33 34 18 9 10 7 lcfrlem14 ⊢ φ → ⊥ ˙ ⁡ L ⁡ J ⁡ X = N ⁡ X
67 1 2 3 4 5 14 15 17 6 31 20 21 33 34 18 9 11 7 lcfrlem14 ⊢ φ → ⊥ ˙ ⁡ L ⁡ J ⁡ Y = N ⁡ Y
68 65 66 67 3eqtr3d ⊢ φ → N ⁡ X = N ⁡ Y