Metamath Proof Explorer


Theorem dv11cn

Description: Two functions defined on a ball whose derivatives are the same and which are equal at any given point C in the ball must be equal everywhere. (Contributed by Mario Carneiro, 31-Mar-2015)

Ref Expression
Hypotheses dv11cn.x ⊢ X = A ball ⁡ abs ∘ − R
dv11cn.a ⊢ φ → A ∈ ℂ
dv11cn.r ⊢ φ → R ∈ ℝ *
dv11cn.f ⊢ φ → F : X ⟶ ℂ
dv11cn.g ⊢ φ → G : X ⟶ ℂ
dv11cn.d ⊢ φ → dom ⁡ F ℂ ′ = X
dv11cn.e ⊢ φ → ℂ D F = ℂ D G
dv11cn.c ⊢ φ → C ∈ X
dv11cn.p ⊢ φ → F ⁡ C = G ⁡ C
Assertion dv11cn ⊢ φ → F = G

Proof

Step Hyp Ref Expression
1 dv11cn.x ⊢ X = A ball ⁡ abs ∘ − R
2 dv11cn.a ⊢ φ → A ∈ ℂ
3 dv11cn.r ⊢ φ → R ∈ ℝ *
4 dv11cn.f ⊢ φ → F : X ⟶ ℂ
5 dv11cn.g ⊢ φ → G : X ⟶ ℂ
6 dv11cn.d ⊢ φ → dom ⁡ F ℂ ′ = X
7 dv11cn.e ⊢ φ → ℂ D F = ℂ D G
8 dv11cn.c ⊢ φ → C ∈ X
9 dv11cn.p ⊢ φ → F ⁡ C = G ⁡ C
10 4 ffnd ⊢ φ → F Fn X
11 5 ffnd ⊢ φ → G Fn X
12 1 ovexi ⊢ X ∈ V
13 12 a1i ⊢ φ → X ∈ V
14 inidm ⊢ X ∩ X = X
15 10 11 13 13 14 offn ⊢ φ → F − f G Fn X
16 0cn ⊢ 0 ∈ ℂ
17 fnconstg ⊢ 0 ∈ ℂ → X × 0 Fn X
18 16 17 mp1i ⊢ φ → X × 0 Fn X
19 subcl ⊢ x ∈ ℂ ∧ y ∈ ℂ → x − y ∈ ℂ
20 19 adantl ⊢ φ ∧ x ∈ ℂ ∧ y ∈ ℂ → x − y ∈ ℂ
21 20 4 5 13 13 14 off ⊢ φ → F − f G : X ⟶ ℂ
22 21 ffvelcdmda ⊢ φ ∧ x ∈ X → F − f G ⁡ x ∈ ℂ
23 8 anim1ci ⊢ φ ∧ x ∈ X → x ∈ X ∧ C ∈ X
24 cnxmet ⊢ abs ∘ − ∈ ∞Met ⁡ ℂ
25 blssm ⊢ abs ∘ − ∈ ∞Met ⁡ ℂ ∧ A ∈ ℂ ∧ R ∈ ℝ * → A ball ⁡ abs ∘ − R ⊆ ℂ
26 24 2 3 25 mp3an2i ⊢ φ → A ball ⁡ abs ∘ − R ⊆ ℂ
27 1 26 eqsstrid ⊢ φ → X ⊆ ℂ
28 4 ffvelcdmda ⊢ φ ∧ x ∈ X → F ⁡ x ∈ ℂ
29 5 ffvelcdmda ⊢ φ ∧ x ∈ X → G ⁡ x ∈ ℂ
30 4 feqmptd ⊢ φ → F = x ∈ X ⟼ F ⁡ x
31 5 feqmptd ⊢ φ → G = x ∈ X ⟼ G ⁡ x
32 13 28 29 30 31 offval2 ⊢ φ → F − f G = x ∈ X ⟼ F ⁡ x − G ⁡ x
33 32 oveq2d ⊢ φ → ℂ D F − f G = dx ∈ X F ⁡ x − G ⁡ x d ℂ x
34 cnelprrecn ⊢ ℂ ∈ ℝ ℂ
35 34 a1i ⊢ φ → ℂ ∈ ℝ ℂ
36 fvexd ⊢ φ ∧ x ∈ X → F ℂ ′ ⁡ x ∈ V
37 30 oveq2d ⊢ φ → ℂ D F = dx ∈ X F ⁡ x d ℂ x
38 dvfcn ⊢ F ℂ ′ : dom ⁡ F ℂ ′ ⟶ ℂ
39 6 feq2d ⊢ φ → F ℂ ′ : dom ⁡ F ℂ ′ ⟶ ℂ ↔ F ℂ ′ : X ⟶ ℂ
40 38 39 mpbii ⊢ φ → F ℂ ′ : X ⟶ ℂ
41 40 feqmptd ⊢ φ → ℂ D F = x ∈ X ⟼ F ℂ ′ ⁡ x
42 37 41 eqtr3d ⊢ φ → dx ∈ X F ⁡ x d ℂ x = x ∈ X ⟼ F ℂ ′ ⁡ x
43 31 oveq2d ⊢ φ → ℂ D G = dx ∈ X G ⁡ x d ℂ x
44 7 41 43 3eqtr3rd ⊢ φ → dx ∈ X G ⁡ x d ℂ x = x ∈ X ⟼ F ℂ ′ ⁡ x
45 35 28 36 42 29 36 44 dvmptsub ⊢ φ → dx ∈ X F ⁡ x − G ⁡ x d ℂ x = x ∈ X ⟼ F ℂ ′ ⁡ x − F ℂ ′ ⁡ x
46 40 ffvelcdmda ⊢ φ ∧ x ∈ X → F ℂ ′ ⁡ x ∈ ℂ
47 46 subidd ⊢ φ ∧ x ∈ X → F ℂ ′ ⁡ x − F ℂ ′ ⁡ x = 0
48 47 mpteq2dva ⊢ φ → x ∈ X ⟼ F ℂ ′ ⁡ x − F ℂ ′ ⁡ x = x ∈ X ⟼ 0
49 fconstmpt ⊢ X × 0 = x ∈ X ⟼ 0
50 48 49 eqtr4di ⊢ φ → x ∈ X ⟼ F ℂ ′ ⁡ x − F ℂ ′ ⁡ x = X × 0
51 33 45 50 3eqtrd ⊢ φ → ℂ D F − f G = X × 0
52 51 dmeqd ⊢ φ → dom ⁡ F − f G ℂ ′ = dom ⁡ X × 0
53 snnzg ⊢ 0 ∈ ℂ → 0 ≠ ∅
54 dmxp ⊢ 0 ≠ ∅ → dom ⁡ X × 0 = X
55 16 53 54 mp2b ⊢ dom ⁡ X × 0 = X
56 52 55 eqtrdi ⊢ φ → dom ⁡ F − f G ℂ ′ = X
57 eqimss2 ⊢ dom ⁡ F − f G ℂ ′ = X → X ⊆ dom ⁡ F − f G ℂ ′
58 56 57 syl ⊢ φ → X ⊆ dom ⁡ F − f G ℂ ′
59 0red ⊢ φ → 0 ∈ ℝ
60 51 fveq1d ⊢ φ → F − f G ℂ ′ ⁡ x = X × 0 ⁡ x
61 c0ex ⊢ 0 ∈ V
62 61 fvconst2 ⊢ x ∈ X → X × 0 ⁡ x = 0
63 60 62 sylan9eq ⊢ φ ∧ x ∈ X → F − f G ℂ ′ ⁡ x = 0
64 63 abs00bd ⊢ φ ∧ x ∈ X → F − f G ℂ ′ ⁡ x = 0
65 0le0 ⊢ 0 ≤ 0
66 64 65 eqbrtrdi ⊢ φ ∧ x ∈ X → F − f G ℂ ′ ⁡ x ≤ 0
67 27 21 2 3 1 58 59 66 dvlipcn ⊢ φ ∧ x ∈ X ∧ C ∈ X → F − f G ⁡ x − F − f G ⁡ C ≤ 0 ⋅ x − C
68 23 67 syldan ⊢ φ ∧ x ∈ X → F − f G ⁡ x − F − f G ⁡ C ≤ 0 ⋅ x − C
69 32 fveq1d ⊢ φ → F − f G ⁡ C = x ∈ X ⟼ F ⁡ x − G ⁡ x ⁡ C
70 fveq2 ⊢ x = C → F ⁡ x = F ⁡ C
71 fveq2 ⊢ x = C → G ⁡ x = G ⁡ C
72 70 71 oveq12d ⊢ x = C → F ⁡ x − G ⁡ x = F ⁡ C − G ⁡ C
73 eqid ⊢ x ∈ X ⟼ F ⁡ x − G ⁡ x = x ∈ X ⟼ F ⁡ x − G ⁡ x
74 ovex ⊢ F ⁡ C − G ⁡ C ∈ V
75 72 73 74 fvmpt ⊢ C ∈ X → x ∈ X ⟼ F ⁡ x − G ⁡ x ⁡ C = F ⁡ C − G ⁡ C
76 8 75 syl ⊢ φ → x ∈ X ⟼ F ⁡ x − G ⁡ x ⁡ C = F ⁡ C − G ⁡ C
77 4 8 ffvelcdmd ⊢ φ → F ⁡ C ∈ ℂ
78 77 9 subeq0bd ⊢ φ → F ⁡ C − G ⁡ C = 0
79 69 76 78 3eqtrd ⊢ φ → F − f G ⁡ C = 0
80 79 adantr ⊢ φ ∧ x ∈ X → F − f G ⁡ C = 0
81 80 oveq2d ⊢ φ ∧ x ∈ X → F − f G ⁡ x − F − f G ⁡ C = F − f G ⁡ x − 0
82 22 subid1d ⊢ φ ∧ x ∈ X → F − f G ⁡ x − 0 = F − f G ⁡ x
83 81 82 eqtrd ⊢ φ ∧ x ∈ X → F − f G ⁡ x − F − f G ⁡ C = F − f G ⁡ x
84 83 fveq2d ⊢ φ ∧ x ∈ X → F − f G ⁡ x − F − f G ⁡ C = F − f G ⁡ x
85 27 sselda ⊢ φ ∧ x ∈ X → x ∈ ℂ
86 27 8 sseldd ⊢ φ → C ∈ ℂ
87 86 adantr ⊢ φ ∧ x ∈ X → C ∈ ℂ
88 85 87 subcld ⊢ φ ∧ x ∈ X → x − C ∈ ℂ
89 88 abscld ⊢ φ ∧ x ∈ X → x − C ∈ ℝ
90 89 recnd ⊢ φ ∧ x ∈ X → x − C ∈ ℂ
91 90 mul02d ⊢ φ ∧ x ∈ X → 0 ⋅ x − C = 0
92 68 84 91 3brtr3d ⊢ φ ∧ x ∈ X → F − f G ⁡ x ≤ 0
93 22 absge0d ⊢ φ ∧ x ∈ X → 0 ≤ F − f G ⁡ x
94 22 abscld ⊢ φ ∧ x ∈ X → F − f G ⁡ x ∈ ℝ
95 0re ⊢ 0 ∈ ℝ
96 letri3 ⊢ F − f G ⁡ x ∈ ℝ ∧ 0 ∈ ℝ → F − f G ⁡ x = 0 ↔ F − f G ⁡ x ≤ 0 ∧ 0 ≤ F − f G ⁡ x
97 94 95 96 sylancl ⊢ φ ∧ x ∈ X → F − f G ⁡ x = 0 ↔ F − f G ⁡ x ≤ 0 ∧ 0 ≤ F − f G ⁡ x
98 92 93 97 mpbir2and ⊢ φ ∧ x ∈ X → F − f G ⁡ x = 0
99 22 98 abs00d ⊢ φ ∧ x ∈ X → F − f G ⁡ x = 0
100 62 adantl ⊢ φ ∧ x ∈ X → X × 0 ⁡ x = 0
101 99 100 eqtr4d ⊢ φ ∧ x ∈ X → F − f G ⁡ x = X × 0 ⁡ x
102 15 18 101 eqfnfvd ⊢ φ → F − f G = X × 0
103 ofsubeq0 ⊢ X ∈ V ∧ F : X ⟶ ℂ ∧ G : X ⟶ ℂ → F − f G = X × 0 ↔ F = G
104 12 4 5 103 mp3an2i ⊢ φ → F − f G = X × 0 ↔ F = G
105 102 104 mpbid ⊢ φ → F = G