Metamath Proof Explorer


Theorem itg1ge0a

Description: The integral of an almost positive simple function is positive. (Contributed by Mario Carneiro, 11-Aug-2014)

Ref Expression
Hypotheses itg10a.1 ⊢ φ → F ∈ dom ⁡ ∫ 1
itg10a.2 ⊢ φ → A ⊆ ℝ
itg10a.3 ⊢ φ → vol * ⁡ A = 0
itg1ge0a.4 ⊢ φ ∧ x ∈ ℝ ∖ A → 0 ≤ F ⁡ x
Assertion itg1ge0a ⊢ φ → 0 ≤ ∫ 1 ⁡ F

Proof

Step Hyp Ref Expression
1 itg10a.1 ⊢ φ → F ∈ dom ⁡ ∫ 1
2 itg10a.2 ⊢ φ → A ⊆ ℝ
3 itg10a.3 ⊢ φ → vol * ⁡ A = 0
4 itg1ge0a.4 ⊢ φ ∧ x ∈ ℝ ∖ A → 0 ≤ F ⁡ x
5 i1frn ⊢ F ∈ dom ⁡ ∫ 1 → ran ⁡ F ∈ Fin
6 1 5 syl ⊢ φ → ran ⁡ F ∈ Fin
7 difss ⊢ ran ⁡ F ∖ 0 ⊆ ran ⁡ F
8 ssfi ⊢ ran ⁡ F ∈ Fin ∧ ran ⁡ F ∖ 0 ⊆ ran ⁡ F → ran ⁡ F ∖ 0 ∈ Fin
9 6 7 8 sylancl ⊢ φ → ran ⁡ F ∖ 0 ∈ Fin
10 i1ff ⊢ F ∈ dom ⁡ ∫ 1 → F : ℝ ⟶ ℝ
11 1 10 syl ⊢ φ → F : ℝ ⟶ ℝ
12 11 frnd ⊢ φ → ran ⁡ F ⊆ ℝ
13 12 ssdifssd ⊢ φ → ran ⁡ F ∖ 0 ⊆ ℝ
14 13 sselda ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 → k ∈ ℝ
15 i1fima2sn ⊢ F ∈ dom ⁡ ∫ 1 ∧ k ∈ ran ⁡ F ∖ 0 → vol ⁡ F -1 k ∈ ℝ
16 1 15 sylan ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 → vol ⁡ F -1 k ∈ ℝ
17 14 16 remulcld ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 → k ⁢ vol ⁡ F -1 k ∈ ℝ
18 0le0 ⊢ 0 ≤ 0
19 i1fima ⊢ F ∈ dom ⁡ ∫ 1 → F -1 k ∈ dom ⁡ vol
20 1 19 syl ⊢ φ → F -1 k ∈ dom ⁡ vol
21 mblvol ⊢ F -1 k ∈ dom ⁡ vol → vol ⁡ F -1 k = vol * ⁡ F -1 k
22 20 21 syl ⊢ φ → vol ⁡ F -1 k = vol * ⁡ F -1 k
23 22 ad2antrr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → vol ⁡ F -1 k = vol * ⁡ F -1 k
24 11 ffnd ⊢ φ → F Fn ℝ
25 fniniseg ⊢ F Fn ℝ → x ∈ F -1 k ↔ x ∈ ℝ ∧ F ⁡ x = k
26 24 25 syl ⊢ φ → x ∈ F -1 k ↔ x ∈ ℝ ∧ F ⁡ x = k
27 26 ad2antrr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → x ∈ F -1 k ↔ x ∈ ℝ ∧ F ⁡ x = k
28 simprl ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ x ∈ ℝ ∧ F ⁡ x = k → x ∈ ℝ
29 eldif ⊢ x ∈ ℝ ∖ A ↔ x ∈ ℝ ∧ ¬ x ∈ A
30 4 ex ⊢ φ → x ∈ ℝ ∖ A → 0 ≤ F ⁡ x
31 30 ad2antrr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ x ∈ ℝ ∧ F ⁡ x = k → x ∈ ℝ ∖ A → 0 ≤ F ⁡ x
32 simprr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ x ∈ ℝ ∧ F ⁡ x = k → F ⁡ x = k
33 32 breq2d ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ x ∈ ℝ ∧ F ⁡ x = k → 0 ≤ F ⁡ x ↔ 0 ≤ k
34 0red ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ x ∈ ℝ ∧ F ⁡ x = k → 0 ∈ ℝ
35 14 adantr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ x ∈ ℝ ∧ F ⁡ x = k → k ∈ ℝ
36 34 35 lenltd ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ x ∈ ℝ ∧ F ⁡ x = k → 0 ≤ k ↔ ¬ k < 0
37 33 36 bitrd ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ x ∈ ℝ ∧ F ⁡ x = k → 0 ≤ F ⁡ x ↔ ¬ k < 0
38 31 37 sylibd ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ x ∈ ℝ ∧ F ⁡ x = k → x ∈ ℝ ∖ A → ¬ k < 0
39 29 38 biimtrrid ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ x ∈ ℝ ∧ F ⁡ x = k → x ∈ ℝ ∧ ¬ x ∈ A → ¬ k < 0
40 28 39 mpand ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ x ∈ ℝ ∧ F ⁡ x = k → ¬ x ∈ A → ¬ k < 0
41 40 con4d ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ x ∈ ℝ ∧ F ⁡ x = k → k < 0 → x ∈ A
42 41 impancom ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → x ∈ ℝ ∧ F ⁡ x = k → x ∈ A
43 27 42 sylbid ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → x ∈ F -1 k → x ∈ A
44 43 ssrdv ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → F -1 k ⊆ A
45 2 ad2antrr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → A ⊆ ℝ
46 3 ad2antrr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → vol * ⁡ A = 0
47 ovolssnul ⊢ F -1 k ⊆ A ∧ A ⊆ ℝ ∧ vol * ⁡ A = 0 → vol * ⁡ F -1 k = 0
48 44 45 46 47 syl3anc ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → vol * ⁡ F -1 k = 0
49 23 48 eqtrd ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → vol ⁡ F -1 k = 0
50 49 oveq2d ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → k ⁢ vol ⁡ F -1 k = k ⋅ 0
51 14 recnd ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 → k ∈ ℂ
52 51 adantr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → k ∈ ℂ
53 52 mul01d ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → k ⋅ 0 = 0
54 50 53 eqtrd ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → k ⁢ vol ⁡ F -1 k = 0
55 18 54 breqtrrid ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ k < 0 → 0 ≤ k ⁢ vol ⁡ F -1 k
56 14 adantr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ 0 ≤ k → k ∈ ℝ
57 16 adantr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ 0 ≤ k → vol ⁡ F -1 k ∈ ℝ
58 simpr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ 0 ≤ k → 0 ≤ k
59 20 ad2antrr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ 0 ≤ k → F -1 k ∈ dom ⁡ vol
60 mblss ⊢ F -1 k ∈ dom ⁡ vol → F -1 k ⊆ ℝ
61 59 60 syl ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ 0 ≤ k → F -1 k ⊆ ℝ
62 ovolge0 ⊢ F -1 k ⊆ ℝ → 0 ≤ vol * ⁡ F -1 k
63 61 62 syl ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ 0 ≤ k → 0 ≤ vol * ⁡ F -1 k
64 22 ad2antrr ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ 0 ≤ k → vol ⁡ F -1 k = vol * ⁡ F -1 k
65 63 64 breqtrrd ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ 0 ≤ k → 0 ≤ vol ⁡ F -1 k
66 56 57 58 65 mulge0d ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 ∧ 0 ≤ k → 0 ≤ k ⁢ vol ⁡ F -1 k
67 0red ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 → 0 ∈ ℝ
68 55 66 14 67 ltlecasei ⊢ φ ∧ k ∈ ran ⁡ F ∖ 0 → 0 ≤ k ⁢ vol ⁡ F -1 k
69 9 17 68 fsumge0 ⊢ φ → 0 ≤ ∑ k ∈ ran ⁡ F ∖ 0 k ⁢ vol ⁡ F -1 k
70 itg1val ⊢ F ∈ dom ⁡ ∫ 1 → ∫ 1 ⁡ F = ∑ k ∈ ran ⁡ F ∖ 0 k ⁢ vol ⁡ F -1 k
71 1 70 syl ⊢ φ → ∫ 1 ⁡ F = ∑ k ∈ ran ⁡ F ∖ 0 k ⁢ vol ⁡ F -1 k
72 69 71 breqtrrd ⊢ φ → 0 ≤ ∫ 1 ⁡ F