Metamath Proof Explorer


Theorem aks4d1p8d2

Description: Any prime power dividing a positive integer is less than that integer if that integer has another prime factor. (Contributed by metakunt, 13-Nov-2024)

Ref Expression
Hypotheses aks4d1p8d2.1 ⊢ φ → R ∈ ℕ
aks4d1p8d2.2 ⊢ φ → N ∈ ℕ
aks4d1p8d2.3 ⊢ φ → P ∈ ℙ
aks4d1p8d2.4 ⊢ φ → Q ∈ ℙ
aks4d1p8d2.5 ⊢ φ → P ∥ R
aks4d1p8d2.6 ⊢ φ → Q ∥ R
aks4d1p8d2.7 ⊢ φ → ¬ P ∥ N
aks4d1p8d2.8 ⊢ φ → Q ∥ N
Assertion aks4d1p8d2 ⊢ φ → P P pCnt R < R

Proof

Step Hyp Ref Expression
1 aks4d1p8d2.1 ⊢ φ → R ∈ ℕ
2 aks4d1p8d2.2 ⊢ φ → N ∈ ℕ
3 aks4d1p8d2.3 ⊢ φ → P ∈ ℙ
4 aks4d1p8d2.4 ⊢ φ → Q ∈ ℙ
5 aks4d1p8d2.5 ⊢ φ → P ∥ R
6 aks4d1p8d2.6 ⊢ φ → Q ∥ R
7 aks4d1p8d2.7 ⊢ φ → ¬ P ∥ N
8 aks4d1p8d2.8 ⊢ φ → Q ∥ N
9 prmnn ⊢ P ∈ ℙ → P ∈ ℕ
10 3 9 syl ⊢ φ → P ∈ ℕ
11 10 nnred ⊢ φ → P ∈ ℝ
12 3 1 pccld ⊢ φ → P pCnt R ∈ ℕ 0
13 11 12 reexpcld ⊢ φ → P P pCnt R ∈ ℝ
14 prmnn ⊢ Q ∈ ℙ → Q ∈ ℕ
15 4 14 syl ⊢ φ → Q ∈ ℕ
16 15 nnred ⊢ φ → Q ∈ ℝ
17 13 16 remulcld ⊢ φ → P P pCnt R ⁢ Q ∈ ℝ
18 1 nnred ⊢ φ → R ∈ ℝ
19 13 recnd ⊢ φ → P P pCnt R ∈ ℂ
20 19 mulridd ⊢ φ → P P pCnt R ⋅ 1 = P P pCnt R
21 1red ⊢ φ → 1 ∈ ℝ
22 10 nnrpd ⊢ φ → P ∈ ℝ +
23 12 nn0zd ⊢ φ → P pCnt R ∈ ℤ
24 22 23 rpexpcld ⊢ φ → P P pCnt R ∈ ℝ +
25 prmgt1 ⊢ Q ∈ ℙ → 1 < Q
26 4 25 syl ⊢ φ → 1 < Q
27 21 16 24 26 ltmul2dd ⊢ φ → P P pCnt R ⋅ 1 < P P pCnt R ⁢ Q
28 20 27 eqbrtrrd ⊢ φ → P P pCnt R < P P pCnt R ⁢ Q
29 10 nnzd ⊢ φ → P ∈ ℤ
30 29 12 zexpcld ⊢ φ → P P pCnt R ∈ ℤ
31 15 nnzd ⊢ φ → Q ∈ ℤ
32 1 nnzd ⊢ φ → R ∈ ℤ
33 30 31 gcdcomd ⊢ φ → P P pCnt R gcd Q = Q gcd P P pCnt R
34 0lt1 ⊢ 0 < 1
35 34 a1i ⊢ φ → 0 < 1
36 0red ⊢ φ → 0 ∈ ℝ
37 36 21 ltnled ⊢ φ → 0 < 1 ↔ ¬ 1 ≤ 0
38 35 37 mpbid ⊢ φ → ¬ 1 ≤ 0
39 16 recnd ⊢ φ → Q ∈ ℂ
40 39 exp1d ⊢ φ → Q 1 = Q
41 40 eqcomd ⊢ φ → Q = Q 1
42 41 oveq2d ⊢ φ → Q pCnt Q = Q pCnt Q 1
43 1zzd ⊢ φ → 1 ∈ ℤ
44 pcid ⊢ Q ∈ ℙ ∧ 1 ∈ ℤ → Q pCnt Q 1 = 1
45 4 43 44 syl2anc ⊢ φ → Q pCnt Q 1 = 1
46 42 45 eqtrd ⊢ φ → Q pCnt Q = 1
47 8 adantr ⊢ φ ∧ P = Q → Q ∥ N
48 breq1 ⊢ P = Q → P ∥ N ↔ Q ∥ N
49 48 adantl ⊢ φ ∧ P = Q → P ∥ N ↔ Q ∥ N
50 49 bicomd ⊢ φ ∧ P = Q → Q ∥ N ↔ P ∥ N
51 50 biimpd ⊢ φ ∧ P = Q → Q ∥ N → P ∥ N
52 47 51 mpd ⊢ φ ∧ P = Q → P ∥ N
53 7 adantr ⊢ φ ∧ P = Q → ¬ P ∥ N
54 52 53 pm2.65da ⊢ φ → ¬ P = Q
55 54 neqcomd ⊢ φ → ¬ Q = P
56 pcelnn ⊢ P ∈ ℙ ∧ R ∈ ℕ → P pCnt R ∈ ℕ ↔ P ∥ R
57 3 1 56 syl2anc ⊢ φ → P pCnt R ∈ ℕ ↔ P ∥ R
58 5 57 mpbird ⊢ φ → P pCnt R ∈ ℕ
59 prmdvdsexpb ⊢ Q ∈ ℙ ∧ P ∈ ℙ ∧ P pCnt R ∈ ℕ → Q ∥ P P pCnt R ↔ Q = P
60 4 3 58 59 syl3anc ⊢ φ → Q ∥ P P pCnt R ↔ Q = P
61 60 notbid ⊢ φ → ¬ Q ∥ P P pCnt R ↔ ¬ Q = P
62 55 61 mpbird ⊢ φ → ¬ Q ∥ P P pCnt R
63 10 12 nnexpcld ⊢ φ → P P pCnt R ∈ ℕ
64 pceq0 ⊢ Q ∈ ℙ ∧ P P pCnt R ∈ ℕ → Q pCnt P P pCnt R = 0 ↔ ¬ Q ∥ P P pCnt R
65 4 63 64 syl2anc ⊢ φ → Q pCnt P P pCnt R = 0 ↔ ¬ Q ∥ P P pCnt R
66 62 65 mpbird ⊢ φ → Q pCnt P P pCnt R = 0
67 46 66 breq12d ⊢ φ → Q pCnt Q ≤ Q pCnt P P pCnt R ↔ 1 ≤ 0
68 67 notbid ⊢ φ → ¬ Q pCnt Q ≤ Q pCnt P P pCnt R ↔ ¬ 1 ≤ 0
69 38 68 mpbird ⊢ φ → ¬ Q pCnt Q ≤ Q pCnt P P pCnt R
70 69 adantr ⊢ φ ∧ p = Q → ¬ Q pCnt Q ≤ Q pCnt P P pCnt R
71 simpr ⊢ φ ∧ p = Q → p = Q
72 71 oveq1d ⊢ φ ∧ p = Q → p pCnt Q = Q pCnt Q
73 71 oveq1d ⊢ φ ∧ p = Q → p pCnt P P pCnt R = Q pCnt P P pCnt R
74 72 73 breq12d ⊢ φ ∧ p = Q → p pCnt Q ≤ p pCnt P P pCnt R ↔ Q pCnt Q ≤ Q pCnt P P pCnt R
75 74 notbid ⊢ φ ∧ p = Q → ¬ p pCnt Q ≤ p pCnt P P pCnt R ↔ ¬ Q pCnt Q ≤ Q pCnt P P pCnt R
76 70 75 mpbird ⊢ φ ∧ p = Q → ¬ p pCnt Q ≤ p pCnt P P pCnt R
77 76 4 rspcime ⊢ φ → ∃ p ∈ ℙ ¬ p pCnt Q ≤ p pCnt P P pCnt R
78 rexnal ⊢ ∃ p ∈ ℙ ¬ p pCnt Q ≤ p pCnt P P pCnt R ↔ ¬ ∀ p ∈ ℙ p pCnt Q ≤ p pCnt P P pCnt R
79 78 a1i ⊢ φ → ∃ p ∈ ℙ ¬ p pCnt Q ≤ p pCnt P P pCnt R ↔ ¬ ∀ p ∈ ℙ p pCnt Q ≤ p pCnt P P pCnt R
80 77 79 mpbid ⊢ φ → ¬ ∀ p ∈ ℙ p pCnt Q ≤ p pCnt P P pCnt R
81 pc2dvds ⊢ Q ∈ ℤ ∧ P P pCnt R ∈ ℤ → Q ∥ P P pCnt R ↔ ∀ p ∈ ℙ p pCnt Q ≤ p pCnt P P pCnt R
82 31 30 81 syl2anc ⊢ φ → Q ∥ P P pCnt R ↔ ∀ p ∈ ℙ p pCnt Q ≤ p pCnt P P pCnt R
83 82 notbid ⊢ φ → ¬ Q ∥ P P pCnt R ↔ ¬ ∀ p ∈ ℙ p pCnt Q ≤ p pCnt P P pCnt R
84 80 83 mpbird ⊢ φ → ¬ Q ∥ P P pCnt R
85 coprm ⊢ Q ∈ ℙ ∧ P P pCnt R ∈ ℤ → ¬ Q ∥ P P pCnt R ↔ Q gcd P P pCnt R = 1
86 4 30 85 syl2anc ⊢ φ → ¬ Q ∥ P P pCnt R ↔ Q gcd P P pCnt R = 1
87 84 86 mpbid ⊢ φ → Q gcd P P pCnt R = 1
88 33 87 eqtrd ⊢ φ → P P pCnt R gcd Q = 1
89 pcdvds ⊢ P ∈ ℙ ∧ R ∈ ℕ → P P pCnt R ∥ R
90 3 1 89 syl2anc ⊢ φ → P P pCnt R ∥ R
91 30 31 32 88 90 6 coprmdvds2d ⊢ φ → P P pCnt R ⁢ Q ∥ R
92 30 31 zmulcld ⊢ φ → P P pCnt R ⁢ Q ∈ ℤ
93 dvdsle ⊢ P P pCnt R ⁢ Q ∈ ℤ ∧ R ∈ ℕ → P P pCnt R ⁢ Q ∥ R → P P pCnt R ⁢ Q ≤ R
94 92 1 93 syl2anc ⊢ φ → P P pCnt R ⁢ Q ∥ R → P P pCnt R ⁢ Q ≤ R
95 91 94 mpd ⊢ φ → P P pCnt R ⁢ Q ≤ R
96 13 17 18 28 95 ltletrd ⊢ φ → P P pCnt R < R