Metamath Proof Explorer


Theorem dvcncxp1

Description: Derivative of complex power with respect to first argument on the complex plane. (Contributed by Brendan Leahy, 18-Dec-2018)

Ref Expression
Hypothesis dvcncxp1.d ⊢ D = ℂ ∖ −∞ 0
Assertion dvcncxp1 ⊢ A ∈ ℂ → dx ∈ D x A d ℂ x = x ∈ D ⟼ A ⁢ x A − 1

Proof

Step Hyp Ref Expression
1 dvcncxp1.d ⊢ D = ℂ ∖ −∞ 0
2 cnelprrecn ⊢ ℂ ∈ ℝ ℂ
3 2 a1i ⊢ A ∈ ℂ → ℂ ∈ ℝ ℂ
4 difss ⊢ ℂ ∖ −∞ 0 ⊆ ℂ
5 1 4 eqsstri ⊢ D ⊆ ℂ
6 5 sseli ⊢ x ∈ D → x ∈ ℂ
7 1 logdmn0 ⊢ x ∈ D → x ≠ 0
8 6 7 logcld ⊢ x ∈ D → log ⁡ x ∈ ℂ
9 8 adantl ⊢ A ∈ ℂ ∧ x ∈ D → log ⁡ x ∈ ℂ
10 6 7 reccld ⊢ x ∈ D → 1 x ∈ ℂ
11 10 adantl ⊢ A ∈ ℂ ∧ x ∈ D → 1 x ∈ ℂ
12 mulcl ⊢ A ∈ ℂ ∧ y ∈ ℂ → A ⁢ y ∈ ℂ
13 efcl ⊢ A ⁢ y ∈ ℂ → e A ⁢ y ∈ ℂ
14 12 13 syl ⊢ A ∈ ℂ ∧ y ∈ ℂ → e A ⁢ y ∈ ℂ
15 ovexd ⊢ A ∈ ℂ ∧ y ∈ ℂ → e A ⁢ y ⁢ A ∈ V
16 1 logcn ⊢ log ↾ D : D ⟶cn ℂ
17 cncff ⊢ log ↾ D : D ⟶cn ℂ → log ↾ D : D ⟶ ℂ
18 16 17 mp1i ⊢ A ∈ ℂ → log ↾ D : D ⟶ ℂ
19 18 feqmptd ⊢ A ∈ ℂ → log ↾ D = x ∈ D ⟼ log ↾ D ⁡ x
20 fvres ⊢ x ∈ D → log ↾ D ⁡ x = log ⁡ x
21 20 mpteq2ia ⊢ x ∈ D ⟼ log ↾ D ⁡ x = x ∈ D ⟼ log ⁡ x
22 19 21 eqtrdi ⊢ A ∈ ℂ → log ↾ D = x ∈ D ⟼ log ⁡ x
23 22 oveq2d ⊢ A ∈ ℂ → ℂ D log ↾ D = dx ∈ D log ⁡ x d ℂ x
24 1 dvlog ⊢ ℂ D log ↾ D = x ∈ D ⟼ 1 x
25 23 24 eqtr3di ⊢ A ∈ ℂ → dx ∈ D log ⁡ x d ℂ x = x ∈ D ⟼ 1 x
26 simpl ⊢ A ∈ ℂ ∧ y ∈ ℂ → A ∈ ℂ
27 efcl ⊢ x ∈ ℂ → e x ∈ ℂ
28 27 adantl ⊢ A ∈ ℂ ∧ x ∈ ℂ → e x ∈ ℂ
29 simpr ⊢ A ∈ ℂ ∧ y ∈ ℂ → y ∈ ℂ
30 1cnd ⊢ A ∈ ℂ ∧ y ∈ ℂ → 1 ∈ ℂ
31 3 dvmptid ⊢ A ∈ ℂ → dy ∈ ℂ y d ℂ y = y ∈ ℂ ⟼ 1
32 id ⊢ A ∈ ℂ → A ∈ ℂ
33 3 29 30 31 32 dvmptcmul ⊢ A ∈ ℂ → dy ∈ ℂ A ⁢ y d ℂ y = y ∈ ℂ ⟼ A ⋅ 1
34 mulrid ⊢ A ∈ ℂ → A ⋅ 1 = A
35 34 mpteq2dv ⊢ A ∈ ℂ → y ∈ ℂ ⟼ A ⋅ 1 = y ∈ ℂ ⟼ A
36 33 35 eqtrd ⊢ A ∈ ℂ → dy ∈ ℂ A ⁢ y d ℂ y = y ∈ ℂ ⟼ A
37 dvef ⊢ ℂ D exp = exp
38 eff ⊢ exp : ℂ ⟶ ℂ
39 38 a1i ⊢ A ∈ ℂ → exp : ℂ ⟶ ℂ
40 39 feqmptd ⊢ A ∈ ℂ → exp = x ∈ ℂ ⟼ e x
41 40 oveq2d ⊢ A ∈ ℂ → ℂ D exp = dx ∈ ℂ e x d ℂ x
42 37 41 40 3eqtr3a ⊢ A ∈ ℂ → dx ∈ ℂ e x d ℂ x = x ∈ ℂ ⟼ e x
43 fveq2 ⊢ x = A ⁢ y → e x = e A ⁢ y
44 3 3 12 26 28 28 36 42 43 43 dvmptco ⊢ A ∈ ℂ → dy ∈ ℂ e A ⁢ y d ℂ y = y ∈ ℂ ⟼ e A ⁢ y ⁢ A
45 oveq2 ⊢ y = log ⁡ x → A ⁢ y = A ⁢ log ⁡ x
46 45 fveq2d ⊢ y = log ⁡ x → e A ⁢ y = e A ⁢ log ⁡ x
47 46 oveq1d ⊢ y = log ⁡ x → e A ⁢ y ⁢ A = e A ⁢ log ⁡ x ⁢ A
48 3 3 9 11 14 15 25 44 46 47 dvmptco ⊢ A ∈ ℂ → dx ∈ D e A ⁢ log ⁡ x d ℂ x = x ∈ D ⟼ e A ⁢ log ⁡ x ⁢ A ⁢ 1 x
49 6 adantl ⊢ A ∈ ℂ ∧ x ∈ D → x ∈ ℂ
50 7 adantl ⊢ A ∈ ℂ ∧ x ∈ D → x ≠ 0
51 simpl ⊢ A ∈ ℂ ∧ x ∈ D → A ∈ ℂ
52 49 50 51 cxpefd ⊢ A ∈ ℂ ∧ x ∈ D → x A = e A ⁢ log ⁡ x
53 52 mpteq2dva ⊢ A ∈ ℂ → x ∈ D ⟼ x A = x ∈ D ⟼ e A ⁢ log ⁡ x
54 53 oveq2d ⊢ A ∈ ℂ → dx ∈ D x A d ℂ x = dx ∈ D e A ⁢ log ⁡ x d ℂ x
55 1cnd ⊢ A ∈ ℂ ∧ x ∈ D → 1 ∈ ℂ
56 49 50 51 55 cxpsubd ⊢ A ∈ ℂ ∧ x ∈ D → x A − 1 = x A x 1
57 49 cxp1d ⊢ A ∈ ℂ ∧ x ∈ D → x 1 = x
58 57 oveq2d ⊢ A ∈ ℂ ∧ x ∈ D → x A x 1 = x A x
59 49 51 cxpcld ⊢ A ∈ ℂ ∧ x ∈ D → x A ∈ ℂ
60 59 49 50 divrecd ⊢ A ∈ ℂ ∧ x ∈ D → x A x = x A ⁢ 1 x
61 56 58 60 3eqtrd ⊢ A ∈ ℂ ∧ x ∈ D → x A − 1 = x A ⁢ 1 x
62 61 oveq2d ⊢ A ∈ ℂ ∧ x ∈ D → A ⁢ x A − 1 = A ⁢ x A ⁢ 1 x
63 51 59 11 mul12d ⊢ A ∈ ℂ ∧ x ∈ D → A ⁢ x A ⁢ 1 x = x A ⁢ A ⁢ 1 x
64 59 51 11 mulassd ⊢ A ∈ ℂ ∧ x ∈ D → x A ⁢ A ⁢ 1 x = x A ⁢ A ⁢ 1 x
65 63 64 eqtr4d ⊢ A ∈ ℂ ∧ x ∈ D → A ⁢ x A ⁢ 1 x = x A ⁢ A ⁢ 1 x
66 52 oveq1d ⊢ A ∈ ℂ ∧ x ∈ D → x A ⁢ A = e A ⁢ log ⁡ x ⁢ A
67 66 oveq1d ⊢ A ∈ ℂ ∧ x ∈ D → x A ⁢ A ⁢ 1 x = e A ⁢ log ⁡ x ⁢ A ⁢ 1 x
68 62 65 67 3eqtrd ⊢ A ∈ ℂ ∧ x ∈ D → A ⁢ x A − 1 = e A ⁢ log ⁡ x ⁢ A ⁢ 1 x
69 68 mpteq2dva ⊢ A ∈ ℂ → x ∈ D ⟼ A ⁢ x A − 1 = x ∈ D ⟼ e A ⁢ log ⁡ x ⁢ A ⁢ 1 x
70 48 54 69 3eqtr4d ⊢ A ∈ ℂ → dx ∈ D x A d ℂ x = x ∈ D ⟼ A ⁢ x A − 1