Metamath Proof Explorer


Theorem pell1qrgaplem

Description: Lemma for pell1qrgap . (Contributed by Stefan O'Rear, 18-Sep-2014)

Ref Expression
Assertion pell1qrgaplem ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + 1 + D ≤ A + D ⁢ B

Proof

Step Hyp Ref Expression
1 nnrp ⊢ D ∈ ℕ → D ∈ ℝ +
2 1 ad2antrr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ∈ ℝ +
3 1rp ⊢ 1 ∈ ℝ +
4 3 a1i ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 ∈ ℝ +
5 2 4 rpaddcld ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + 1 ∈ ℝ +
6 5 rpsqrtcld ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + 1 ∈ ℝ +
7 6 rpred ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + 1 ∈ ℝ
8 2 rpsqrtcld ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ∈ ℝ +
9 8 rpred ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ∈ ℝ
10 nn0re ⊢ A ∈ ℕ 0 → A ∈ ℝ
11 10 adantr ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → A ∈ ℝ
12 11 ad2antlr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → A ∈ ℝ
13 nn0re ⊢ B ∈ ℕ 0 → B ∈ ℝ
14 13 adantl ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → B ∈ ℝ
15 14 ad2antlr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → B ∈ ℝ
16 9 15 remulcld ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ⁢ B ∈ ℝ
17 2 rpred ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ∈ ℝ
18 1re ⊢ 1 ∈ ℝ
19 18 a1i ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 ∈ ℝ
20 15 resqcld ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → B 2 ∈ ℝ
21 19 20 resubcld ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 − B 2 ∈ ℝ
22 17 21 remulcld ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ⁢ 1 − B 2 ∈ ℝ
23 0red ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 0 ∈ ℝ
24 17 23 remulcld ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ⋅ 0 ∈ ℝ
25 12 resqcld ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → A 2 ∈ ℝ
26 sq1 ⊢ 1 2 = 1
27 26 a1i ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 2 = 1
28 nnge1 ⊢ B ∈ ℕ → 1 ≤ B
29 28 adantl ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B ∈ ℕ → 1 ≤ B
30 simplrl ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → 1 < A + D ⁢ B
31 oveq1 ⊢ B = 0 → B 2 = 0 2
32 31 adantl ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → B 2 = 0 2
33 sq0 ⊢ 0 2 = 0
34 32 33 eqtrdi ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → B 2 = 0
35 34 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → D ⁢ B 2 = D ⋅ 0
36 2 rpcnd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ∈ ℂ
37 36 adantr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → D ∈ ℂ
38 37 mul01d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → D ⋅ 0 = 0
39 35 38 eqtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → D ⁢ B 2 = 0
40 39 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → A 2 − D ⁢ B 2 = A 2 − 0
41 simplrr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → A 2 − D ⁢ B 2 = 1
42 12 recnd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → A ∈ ℂ
43 42 sqcld ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → A 2 ∈ ℂ
44 43 adantr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → A 2 ∈ ℂ
45 44 subid1d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → A 2 − 0 = A 2
46 40 41 45 3eqtr3d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → 1 = A 2
47 26 46 eqtr2id ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → A 2 = 1 2
48 nn0ge0 ⊢ A ∈ ℕ 0 → 0 ≤ A
49 48 adantr ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → 0 ≤ A
50 49 ad2antlr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 0 ≤ A
51 0le1 ⊢ 0 ≤ 1
52 51 a1i ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 0 ≤ 1
53 sq11 ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ 1 ∈ ℝ ∧ 0 ≤ 1 → A 2 = 1 2 ↔ A = 1
54 12 50 19 52 53 syl22anc ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → A 2 = 1 2 ↔ A = 1
55 54 adantr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → A 2 = 1 2 ↔ A = 1
56 47 55 mpbid ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → A = 1
57 simpr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → B = 0
58 57 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → D ⁢ B = D ⋅ 0
59 8 rpcnd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ∈ ℂ
60 59 adantr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → D ∈ ℂ
61 60 mul01d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → D ⋅ 0 = 0
62 58 61 eqtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → D ⁢ B = 0
63 56 62 oveq12d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → A + D ⁢ B = 1 + 0
64 1p0e1 ⊢ 1 + 0 = 1
65 63 64 eqtrdi ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → A + D ⁢ B = 1
66 30 65 breqtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → 1 < 1
67 18 ltnri ⊢ ¬ 1 < 1
68 pm2.24 ⊢ 1 < 1 → ¬ 1 < 1 → 1 ≤ B
69 66 67 68 mpisyl ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 ∧ B = 0 → 1 ≤ B
70 simplrr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → B ∈ ℕ 0
71 elnn0 ⊢ B ∈ ℕ 0 ↔ B ∈ ℕ ∨ B = 0
72 70 71 sylib ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → B ∈ ℕ ∨ B = 0
73 29 69 72 mpjaodan ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 ≤ B
74 nn0ge0 ⊢ B ∈ ℕ 0 → 0 ≤ B
75 74 adantl ⊢ A ∈ ℕ 0 ∧ B ∈ ℕ 0 → 0 ≤ B
76 75 ad2antlr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 0 ≤ B
77 19 15 52 76 le2sqd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 ≤ B ↔ 1 2 ≤ B 2
78 73 77 mpbid ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 2 ≤ B 2
79 27 78 eqbrtrrd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 ≤ B 2
80 19 20 suble0d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 − B 2 ≤ 0 ↔ 1 ≤ B 2
81 79 80 mpbird ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 − B 2 ≤ 0
82 21 23 2 lemul2d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 − B 2 ≤ 0 ↔ D ⁢ 1 − B 2 ≤ D ⋅ 0
83 81 82 mpbid ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ⁢ 1 − B 2 ≤ D ⋅ 0
84 22 24 25 83 leadd2dd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → A 2 + D ⁢ 1 − B 2 ≤ A 2 + D ⋅ 0
85 5 rpcnd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + 1 ∈ ℂ
86 85 sqsqrtd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + 1 2 = D + 1
87 simprr ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → A 2 − D ⁢ B 2 = 1
88 87 eqcomd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 = A 2 − D ⁢ B 2
89 88 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + 1 = D + A 2 - D ⁢ B 2
90 15 recnd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → B ∈ ℂ
91 90 sqcld ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → B 2 ∈ ℂ
92 36 91 mulcld ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ⁢ B 2 ∈ ℂ
93 36 43 92 addsub12d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + A 2 - D ⁢ B 2 = A 2 + D - D ⁢ B 2
94 19 recnd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 ∈ ℂ
95 36 94 91 subdid ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ⁢ 1 − B 2 = D ⋅ 1 − D ⁢ B 2
96 36 mulridd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ⋅ 1 = D
97 96 oveq1d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ⋅ 1 − D ⁢ B 2 = D − D ⁢ B 2
98 95 97 eqtr2d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D − D ⁢ B 2 = D ⁢ 1 − B 2
99 98 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → A 2 + D - D ⁢ B 2 = A 2 + D ⁢ 1 − B 2
100 93 99 eqtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + A 2 - D ⁢ B 2 = A 2 + D ⁢ 1 − B 2
101 86 89 100 3eqtrd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + 1 2 = A 2 + D ⁢ 1 − B 2
102 36 mul01d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ⋅ 0 = 0
103 102 oveq2d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → A 2 + D ⋅ 0 = A 2 + 0
104 43 addridd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → A 2 + 0 = A 2
105 103 104 eqtr2d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → A 2 = A 2 + D ⋅ 0
106 84 101 105 3brtr4d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + 1 2 ≤ A 2
107 6 rpge0d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 0 ≤ D + 1
108 7 12 107 50 le2sqd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + 1 ≤ A ↔ D + 1 2 ≤ A 2
109 106 108 mpbird ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + 1 ≤ A
110 59 mulridd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ⋅ 1 = D
111 19 15 8 lemul2d ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → 1 ≤ B ↔ D ⋅ 1 ≤ D ⁢ B
112 73 111 mpbid ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ⋅ 1 ≤ D ⁢ B
113 110 112 eqbrtrrd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D ≤ D ⁢ B
114 7 9 12 16 109 113 le2addd ⊢ D ∈ ℕ ∧ A ∈ ℕ 0 ∧ B ∈ ℕ 0 ∧ 1 < A + D ⁢ B ∧ A 2 − D ⁢ B 2 = 1 → D + 1 + D ≤ A + D ⁢ B