Metamath Proof Explorer


Theorem itgsplitioo

Description: The S. integral splits on open intervals with matching endpoints. (Contributed by Mario Carneiro, 2-Sep-2014)

Ref Expression
Hypotheses itgsplitioo.1 ⊢ φ → A ∈ ℝ
itgsplitioo.2 ⊢ φ → C ∈ ℝ
itgsplitioo.3 ⊢ φ → B ∈ A C
itgsplitioo.4 ⊢ φ ∧ x ∈ A C → D ∈ ℂ
itgsplitioo.5 ⊢ φ → x ∈ A B ⟼ D ∈ 𝐿 1
itgsplitioo.6 ⊢ φ → x ∈ B C ⟼ D ∈ 𝐿 1
Assertion itgsplitioo ⊢ φ → ∫ A C D dx = ∫ A B D dx + ∫ B C D dx

Proof

Step Hyp Ref Expression
1 itgsplitioo.1 ⊢ φ → A ∈ ℝ
2 itgsplitioo.2 ⊢ φ → C ∈ ℝ
3 itgsplitioo.3 ⊢ φ → B ∈ A C
4 itgsplitioo.4 ⊢ φ ∧ x ∈ A C → D ∈ ℂ
5 itgsplitioo.5 ⊢ φ → x ∈ A B ⟼ D ∈ 𝐿 1
6 itgsplitioo.6 ⊢ φ → x ∈ B C ⟼ D ∈ 𝐿 1
7 elicc2 ⊢ A ∈ ℝ ∧ C ∈ ℝ → B ∈ A C ↔ B ∈ ℝ ∧ A ≤ B ∧ B ≤ C
8 1 2 7 syl2anc ⊢ φ → B ∈ A C ↔ B ∈ ℝ ∧ A ≤ B ∧ B ≤ C
9 3 8 mpbid ⊢ φ → B ∈ ℝ ∧ A ≤ B ∧ B ≤ C
10 9 simp2d ⊢ φ → A ≤ B
11 9 simp1d ⊢ φ → B ∈ ℝ
12 1 11 leloed ⊢ φ → A ≤ B ↔ A < B ∨ A = B
13 10 12 mpbid ⊢ φ → A < B ∨ A = B
14 13 ord ⊢ φ → ¬ A < B → A = B
15 1 rexrd ⊢ φ → A ∈ ℝ *
16 iooss1 ⊢ A ∈ ℝ * ∧ A ≤ B → B C ⊆ A C
17 15 10 16 syl2anc ⊢ φ → B C ⊆ A C
18 17 sselda ⊢ φ ∧ x ∈ B C → x ∈ A C
19 18 4 syldan ⊢ φ ∧ x ∈ B C → D ∈ ℂ
20 19 6 itgcl ⊢ φ → ∫ B C D dx ∈ ℂ
21 20 addlidd ⊢ φ → 0 + ∫ B C D dx = ∫ B C D dx
22 21 eqcomd ⊢ φ → ∫ B C D dx = 0 + ∫ B C D dx
23 oveq1 ⊢ A = B → A C = B C
24 itgeq1 ⊢ A C = B C → ∫ A C D dx = ∫ B C D dx
25 23 24 syl ⊢ A = B → ∫ A C D dx = ∫ B C D dx
26 oveq1 ⊢ A = B → A B = B B
27 iooid ⊢ B B = ∅
28 26 27 eqtrdi ⊢ A = B → A B = ∅
29 itgeq1 ⊢ A B = ∅ → ∫ A B D dx = ∫ ∅ D dx
30 28 29 syl ⊢ A = B → ∫ A B D dx = ∫ ∅ D dx
31 itg0 ⊢ ∫ ∅ D dx = 0
32 30 31 eqtrdi ⊢ A = B → ∫ A B D dx = 0
33 32 oveq1d ⊢ A = B → ∫ A B D dx + ∫ B C D dx = 0 + ∫ B C D dx
34 25 33 eqeq12d ⊢ A = B → ∫ A C D dx = ∫ A B D dx + ∫ B C D dx ↔ ∫ B C D dx = 0 + ∫ B C D dx
35 22 34 syl5ibrcom ⊢ φ → A = B → ∫ A C D dx = ∫ A B D dx + ∫ B C D dx
36 14 35 syld ⊢ φ → ¬ A < B → ∫ A C D dx = ∫ A B D dx + ∫ B C D dx
37 9 simp3d ⊢ φ → B ≤ C
38 11 2 leloed ⊢ φ → B ≤ C ↔ B < C ∨ B = C
39 37 38 mpbid ⊢ φ → B < C ∨ B = C
40 39 ord ⊢ φ → ¬ B < C → B = C
41 2 rexrd ⊢ φ → C ∈ ℝ *
42 iooss2 ⊢ C ∈ ℝ * ∧ B ≤ C → A B ⊆ A C
43 41 37 42 syl2anc ⊢ φ → A B ⊆ A C
44 43 sselda ⊢ φ ∧ x ∈ A B → x ∈ A C
45 44 4 syldan ⊢ φ ∧ x ∈ A B → D ∈ ℂ
46 45 5 itgcl ⊢ φ → ∫ A B D dx ∈ ℂ
47 46 addridd ⊢ φ → ∫ A B D dx + 0 = ∫ A B D dx
48 47 eqcomd ⊢ φ → ∫ A B D dx = ∫ A B D dx + 0
49 oveq2 ⊢ B = C → A B = A C
50 itgeq1 ⊢ A B = A C → ∫ A B D dx = ∫ A C D dx
51 49 50 syl ⊢ B = C → ∫ A B D dx = ∫ A C D dx
52 oveq2 ⊢ B = C → B B = B C
53 27 52 eqtr3id ⊢ B = C → ∅ = B C
54 itgeq1 ⊢ ∅ = B C → ∫ ∅ D dx = ∫ B C D dx
55 53 54 syl ⊢ B = C → ∫ ∅ D dx = ∫ B C D dx
56 31 55 eqtr3id ⊢ B = C → 0 = ∫ B C D dx
57 56 oveq2d ⊢ B = C → ∫ A B D dx + 0 = ∫ A B D dx + ∫ B C D dx
58 51 57 eqeq12d ⊢ B = C → ∫ A B D dx = ∫ A B D dx + 0 ↔ ∫ A C D dx = ∫ A B D dx + ∫ B C D dx
59 48 58 syl5ibcom ⊢ φ → B = C → ∫ A C D dx = ∫ A B D dx + ∫ B C D dx
60 40 59 syld ⊢ φ → ¬ B < C → ∫ A C D dx = ∫ A B D dx + ∫ B C D dx
61 indir ⊢ A B ∪ B ∩ B C = A B ∩ B C ∪ B ∩ B C
62 11 rexrd ⊢ φ → B ∈ ℝ *
63 15 62 jca ⊢ φ → A ∈ ℝ * ∧ B ∈ ℝ *
64 63 adantr ⊢ φ ∧ A < B ∧ B < C → A ∈ ℝ * ∧ B ∈ ℝ *
65 62 41 jca ⊢ φ → B ∈ ℝ * ∧ C ∈ ℝ *
66 65 adantr ⊢ φ ∧ A < B ∧ B < C → B ∈ ℝ * ∧ C ∈ ℝ *
67 11 adantr ⊢ φ ∧ A < B ∧ B < C → B ∈ ℝ
68 67 leidd ⊢ φ ∧ A < B ∧ B < C → B ≤ B
69 ioodisj ⊢ A ∈ ℝ * ∧ B ∈ ℝ * ∧ B ∈ ℝ * ∧ C ∈ ℝ * ∧ B ≤ B → A B ∩ B C = ∅
70 64 66 68 69 syl21anc ⊢ φ ∧ A < B ∧ B < C → A B ∩ B C = ∅
71 incom ⊢ B ∩ B C = B C ∩ B
72 67 ltnrd ⊢ φ ∧ A < B ∧ B < C → ¬ B < B
73 eliooord ⊢ B ∈ B C → B < B ∧ B < C
74 73 simpld ⊢ B ∈ B C → B < B
75 72 74 nsyl ⊢ φ ∧ A < B ∧ B < C → ¬ B ∈ B C
76 disjsn ⊢ B C ∩ B = ∅ ↔ ¬ B ∈ B C
77 75 76 sylibr ⊢ φ ∧ A < B ∧ B < C → B C ∩ B = ∅
78 71 77 eqtrid ⊢ φ ∧ A < B ∧ B < C → B ∩ B C = ∅
79 70 78 uneq12d ⊢ φ ∧ A < B ∧ B < C → A B ∩ B C ∪ B ∩ B C = ∅ ∪ ∅
80 un0 ⊢ ∅ ∪ ∅ = ∅
81 79 80 eqtrdi ⊢ φ ∧ A < B ∧ B < C → A B ∩ B C ∪ B ∩ B C = ∅
82 61 81 eqtrid ⊢ φ ∧ A < B ∧ B < C → A B ∪ B ∩ B C = ∅
83 82 fveq2d ⊢ φ ∧ A < B ∧ B < C → vol * ⁡ A B ∪ B ∩ B C = vol * ⁡ ∅
84 ovol0 ⊢ vol * ⁡ ∅ = 0
85 83 84 eqtrdi ⊢ φ ∧ A < B ∧ B < C → vol * ⁡ A B ∪ B ∩ B C = 0
86 15 62 41 3jca ⊢ φ → A ∈ ℝ * ∧ B ∈ ℝ * ∧ C ∈ ℝ *
87 ioojoin ⊢ A ∈ ℝ * ∧ B ∈ ℝ * ∧ C ∈ ℝ * ∧ A < B ∧ B < C → A B ∪ B ∪ B C = A C
88 86 87 sylan ⊢ φ ∧ A < B ∧ B < C → A B ∪ B ∪ B C = A C
89 88 eqcomd ⊢ φ ∧ A < B ∧ B < C → A C = A B ∪ B ∪ B C
90 4 adantlr ⊢ φ ∧ A < B ∧ B < C ∧ x ∈ A C → D ∈ ℂ
91 5 adantr ⊢ φ ∧ A < B ∧ B < C → x ∈ A B ⟼ D ∈ 𝐿 1
92 ssun1 ⊢ A B ⊆ A B ∪ B
93 92 a1i ⊢ φ ∧ A < B ∧ B < C → A B ⊆ A B ∪ B
94 ioossre ⊢ A B ⊆ ℝ
95 94 a1i ⊢ φ ∧ A < B ∧ B < C → A B ⊆ ℝ
96 67 snssd ⊢ φ ∧ A < B ∧ B < C → B ⊆ ℝ
97 95 96 unssd ⊢ φ ∧ A < B ∧ B < C → A B ∪ B ⊆ ℝ
98 uncom ⊢ A B ∪ B = B ∪ A B
99 98 difeq1i ⊢ A B ∪ B ∖ A B = B ∪ A B ∖ A B
100 difun2 ⊢ B ∪ A B ∖ A B = B ∖ A B
101 99 100 eqtri ⊢ A B ∪ B ∖ A B = B ∖ A B
102 difss ⊢ B ∖ A B ⊆ B
103 101 102 eqsstri ⊢ A B ∪ B ∖ A B ⊆ B
104 ovolsn ⊢ B ∈ ℝ → vol * ⁡ B = 0
105 67 104 syl ⊢ φ ∧ A < B ∧ B < C → vol * ⁡ B = 0
106 ovolssnul ⊢ A B ∪ B ∖ A B ⊆ B ∧ B ⊆ ℝ ∧ vol * ⁡ B = 0 → vol * ⁡ A B ∪ B ∖ A B = 0
107 103 96 105 106 mp3an2i ⊢ φ ∧ A < B ∧ B < C → vol * ⁡ A B ∪ B ∖ A B = 0
108 ssun1 ⊢ A B ∪ B ⊆ A B ∪ B ∪ B C
109 108 88 sseqtrid ⊢ φ ∧ A < B ∧ B < C → A B ∪ B ⊆ A C
110 109 sselda ⊢ φ ∧ A < B ∧ B < C ∧ x ∈ A B ∪ B → x ∈ A C
111 110 90 syldan ⊢ φ ∧ A < B ∧ B < C ∧ x ∈ A B ∪ B → D ∈ ℂ
112 93 97 107 111 itgss3 ⊢ φ ∧ A < B ∧ B < C → x ∈ A B ⟼ D ∈ 𝐿 1 ↔ x ∈ A B ∪ B ⟼ D ∈ 𝐿 1 ∧ ∫ A B D dx = ∫ A B ∪ B D dx
113 112 simpld ⊢ φ ∧ A < B ∧ B < C → x ∈ A B ⟼ D ∈ 𝐿 1 ↔ x ∈ A B ∪ B ⟼ D ∈ 𝐿 1
114 91 113 mpbid ⊢ φ ∧ A < B ∧ B < C → x ∈ A B ∪ B ⟼ D ∈ 𝐿 1
115 6 adantr ⊢ φ ∧ A < B ∧ B < C → x ∈ B C ⟼ D ∈ 𝐿 1
116 85 89 90 114 115 itgsplit ⊢ φ ∧ A < B ∧ B < C → ∫ A C D dx = ∫ A B ∪ B D dx + ∫ B C D dx
117 112 simprd ⊢ φ ∧ A < B ∧ B < C → ∫ A B D dx = ∫ A B ∪ B D dx
118 117 oveq1d ⊢ φ ∧ A < B ∧ B < C → ∫ A B D dx + ∫ B C D dx = ∫ A B ∪ B D dx + ∫ B C D dx
119 116 118 eqtr4d ⊢ φ ∧ A < B ∧ B < C → ∫ A C D dx = ∫ A B D dx + ∫ B C D dx
120 119 ex ⊢ φ → A < B ∧ B < C → ∫ A C D dx = ∫ A B D dx + ∫ B C D dx
121 36 60 120 ecased ⊢ φ → ∫ A C D dx = ∫ A B D dx + ∫ B C D dx