Metamath Proof Explorer


Theorem isosctrlem2

Description: Lemma for isosctr . Corresponds to the case where one vertex is at 0, another at 1 and the third lies on the unit circle. (Contributed by Saveliy Skresanov, 31-Dec-2016)

Ref Expression
Assertion isosctrlem2 ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → ℑ ⁡ log ⁡ 1 − A = ℑ ⁡ log ⁡ − A 1 − A

Proof

Step Hyp Ref Expression
1 1cnd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 ∈ ℂ
2 simpl1 ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → A ∈ ℂ
3 1 2 negsubd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 + − A = 1 − A
4 1rp ⊢ 1 ∈ ℝ +
5 4 a1i ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 ∈ ℝ +
6 simpl3 ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → ¬ 1 = A
7 simpl2 ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → A = 1
8 1 2 1 sub32d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 - A - 1 = 1 - 1 - A
9 1m1e0 ⊢ 1 − 1 = 0
10 9 oveq1i ⊢ 1 - 1 - A = 0 − A
11 df-neg ⊢ − A = 0 − A
12 10 11 eqtr4i ⊢ 1 - 1 - A = − A
13 8 12 eqtrdi ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 - A - 1 = − A
14 1cnd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → 1 ∈ ℂ
15 simp1 ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → A ∈ ℂ
16 14 15 subcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → 1 − A ∈ ℂ
17 16 adantr ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 − A ∈ ℂ
18 ax-1cn ⊢ 1 ∈ ℂ
19 subeq0 ⊢ 1 ∈ ℂ ∧ A ∈ ℂ → 1 − A = 0 ↔ 1 = A
20 18 19 mpan ⊢ A ∈ ℂ → 1 − A = 0 ↔ 1 = A
21 20 biimpd ⊢ A ∈ ℂ → 1 − A = 0 → 1 = A
22 21 con3dimp ⊢ A ∈ ℂ ∧ ¬ 1 = A → ¬ 1 − A = 0
23 22 neqned ⊢ A ∈ ℂ ∧ ¬ 1 = A → 1 − A ≠ 0
24 23 3adant2 ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → 1 − A ≠ 0
25 24 adantr ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 − A ≠ 0
26 17 25 recrecd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 1 1 − A = 1 − A
27 14 16 24 div2negd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − 1 − 1 − A = 1 1 − A
28 27 adantr ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → − 1 − 1 − A = 1 1 − A
29 15 negcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − A ∈ ℂ
30 29 16 24 cjdivd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − A 1 − A ‾ = − A ‾ 1 − A ‾
31 15 cjnegd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − A ‾ = − A ‾
32 fveq2 ⊢ A = 0 → A = 0
33 abs0 ⊢ 0 = 0
34 32 33 eqtrdi ⊢ A = 0 → A = 0
35 eqtr2 ⊢ A = 1 ∧ A = 0 → 1 = 0
36 34 35 sylan2 ⊢ A = 1 ∧ A = 0 → 1 = 0
37 ax-1ne0 ⊢ 1 ≠ 0
38 neneq ⊢ 1 ≠ 0 → ¬ 1 = 0
39 37 38 mp1i ⊢ A = 1 ∧ A = 0 → ¬ 1 = 0
40 36 39 pm2.65da ⊢ A = 1 → ¬ A = 0
41 40 adantl ⊢ A ∈ ℂ ∧ A = 1 → ¬ A = 0
42 df-ne ⊢ A ≠ 0 ↔ ¬ A = 0
43 oveq1 ⊢ A = 1 → A 2 = 1 2
44 sq1 ⊢ 1 2 = 1
45 43 44 eqtrdi ⊢ A = 1 → A 2 = 1
46 45 adantl ⊢ A ∈ ℂ ∧ A = 1 → A 2 = 1
47 absvalsq ⊢ A ∈ ℂ → A 2 = A ⁢ A ‾
48 47 adantr ⊢ A ∈ ℂ ∧ A = 1 → A 2 = A ⁢ A ‾
49 46 48 eqtr3d ⊢ A ∈ ℂ ∧ A = 1 → 1 = A ⁢ A ‾
50 49 3adant3 ⊢ A ∈ ℂ ∧ A = 1 ∧ A ≠ 0 → 1 = A ⁢ A ‾
51 50 oveq1d ⊢ A ∈ ℂ ∧ A = 1 ∧ A ≠ 0 → 1 A = A ⁢ A ‾ A
52 simp1 ⊢ A ∈ ℂ ∧ A = 1 ∧ A ≠ 0 → A ∈ ℂ
53 52 cjcld ⊢ A ∈ ℂ ∧ A = 1 ∧ A ≠ 0 → A ‾ ∈ ℂ
54 simp3 ⊢ A ∈ ℂ ∧ A = 1 ∧ A ≠ 0 → A ≠ 0
55 53 52 54 divcan3d ⊢ A ∈ ℂ ∧ A = 1 ∧ A ≠ 0 → A ⁢ A ‾ A = A ‾
56 51 55 eqtrd ⊢ A ∈ ℂ ∧ A = 1 ∧ A ≠ 0 → 1 A = A ‾
57 42 56 syl3an3br ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ A = 0 → 1 A = A ‾
58 41 57 mpd3an3 ⊢ A ∈ ℂ ∧ A = 1 → 1 A = A ‾
59 58 eqcomd ⊢ A ∈ ℂ ∧ A = 1 → A ‾ = 1 A
60 59 3adant3 ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → A ‾ = 1 A
61 60 negeqd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − A ‾ = − 1 A
62 31 61 eqtrd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − A ‾ = − 1 A
63 62 oveq1d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − A ‾ 1 − A ‾ = − 1 A 1 − A ‾
64 cjsub ⊢ 1 ∈ ℂ ∧ A ∈ ℂ → 1 − A ‾ = 1 ‾ − A ‾
65 18 64 mpan ⊢ A ∈ ℂ → 1 − A ‾ = 1 ‾ − A ‾
66 1red ⊢ A ∈ ℂ → 1 ∈ ℝ
67 66 cjred ⊢ A ∈ ℂ → 1 ‾ = 1
68 67 oveq1d ⊢ A ∈ ℂ → 1 ‾ − A ‾ = 1 − A ‾
69 65 68 eqtrd ⊢ A ∈ ℂ → 1 − A ‾ = 1 − A ‾
70 69 adantr ⊢ A ∈ ℂ ∧ A = 1 → 1 − A ‾ = 1 − A ‾
71 59 oveq2d ⊢ A ∈ ℂ ∧ A = 1 → 1 − A ‾ = 1 − 1 A
72 70 71 eqtrd ⊢ A ∈ ℂ ∧ A = 1 → 1 − A ‾ = 1 − 1 A
73 72 3adant3 ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → 1 − A ‾ = 1 − 1 A
74 73 oveq2d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − 1 A 1 − A ‾ = − 1 A 1 − 1 A
75 30 63 74 3eqtrd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − A 1 − A ‾ = − 1 A 1 − 1 A
76 40 3ad2ant2 ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → ¬ A = 0
77 76 neqned ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → A ≠ 0
78 1cnd ⊢ A ∈ ℂ ∧ A ≠ 0 → 1 ∈ ℂ
79 simpl ⊢ A ∈ ℂ ∧ A ≠ 0 → A ∈ ℂ
80 simpr ⊢ A ∈ ℂ ∧ A ≠ 0 → A ≠ 0
81 78 79 80 divnegd ⊢ A ∈ ℂ ∧ A ≠ 0 → − 1 A = − 1 A
82 81 oveq1d ⊢ A ∈ ℂ ∧ A ≠ 0 → − 1 A 1 − 1 A = − 1 A 1 − 1 A
83 15 77 82 syl2anc ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − 1 A 1 − 1 A = − 1 A 1 − 1 A
84 14 negcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − 1 ∈ ℂ
85 84 15 77 divcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − 1 A ∈ ℂ
86 15 77 reccld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → 1 A ∈ ℂ
87 14 86 subcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → 1 − 1 A ∈ ℂ
88 16 24 cjne0d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → 1 − A ‾ ≠ 0
89 73 88 eqnetrrd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → 1 − 1 A ≠ 0
90 85 87 15 89 77 divcan5d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → A ⁢ − 1 A A ⁢ 1 − 1 A = − 1 A 1 − 1 A
91 84 15 77 divcan2d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → A ⁢ − 1 A = − 1
92 15 14 86 subdid ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → A ⁢ 1 − 1 A = A ⋅ 1 − A ⁢ 1 A
93 15 mulridd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → A ⋅ 1 = A
94 15 77 recidd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → A ⁢ 1 A = 1
95 93 94 oveq12d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → A ⋅ 1 − A ⁢ 1 A = A − 1
96 92 95 eqtrd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → A ⁢ 1 − 1 A = A − 1
97 91 96 oveq12d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → A ⁢ − 1 A A ⁢ 1 − 1 A = − 1 A − 1
98 83 90 97 3eqtr2d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − 1 A 1 − 1 A = − 1 A − 1
99 subcl ⊢ A ∈ ℂ ∧ 1 ∈ ℂ → A − 1 ∈ ℂ
100 99 negnegd ⊢ A ∈ ℂ ∧ 1 ∈ ℂ → − − A − 1 = A − 1
101 negsubdi2 ⊢ A ∈ ℂ ∧ 1 ∈ ℂ → − A − 1 = 1 − A
102 101 negeqd ⊢ A ∈ ℂ ∧ 1 ∈ ℂ → − − A − 1 = − 1 − A
103 100 102 eqtr3d ⊢ A ∈ ℂ ∧ 1 ∈ ℂ → A − 1 = − 1 − A
104 15 14 103 syl2anc ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → A − 1 = − 1 − A
105 104 oveq2d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − 1 A − 1 = − 1 − 1 − A
106 75 98 105 3eqtrd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − A 1 − A ‾ = − 1 − 1 − A
107 106 adantr ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → − A 1 − A ‾ = − 1 − 1 − A
108 29 16 24 divcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − A 1 − A ∈ ℂ
109 108 adantr ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → − A 1 − A ∈ ℂ
110 simpr ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → ℑ ⁡ − A 1 − A = 0
111 109 110 reim0bd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → − A 1 − A ∈ ℝ
112 111 cjred ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → − A 1 − A ‾ = − A 1 − A
113 112 111 eqeltrd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → − A 1 − A ‾ ∈ ℝ
114 107 113 eqeltrrd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → − 1 − 1 − A ∈ ℝ
115 28 114 eqeltrrd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 1 − A ∈ ℝ
116 16 24 recne0d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → 1 1 − A ≠ 0
117 116 adantr ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 1 − A ≠ 0
118 115 117 rereccld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 1 1 − A ∈ ℝ
119 26 118 eqeltrrd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 − A ∈ ℝ
120 1red ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 ∈ ℝ
121 119 120 resubcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 - A - 1 ∈ ℝ
122 13 121 eqeltrrd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → − A ∈ ℝ
123 2 122 negrebd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → A ∈ ℝ
124 123 absord ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → A = A ∨ A = − A
125 eqeq1 ⊢ A = 1 → A = A ↔ 1 = A
126 125 biimpd ⊢ A = 1 → A = A → 1 = A
127 eqeq1 ⊢ A = 1 → A = − A ↔ 1 = − A
128 127 biimpd ⊢ A = 1 → A = − A → 1 = − A
129 126 128 orim12d ⊢ A = 1 → A = A ∨ A = − A → 1 = A ∨ 1 = − A
130 7 124 129 sylc ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 = A ∨ 1 = − A
131 130 ord ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → ¬ 1 = A → 1 = − A
132 6 131 mpd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 = − A
133 132 5 eqeltrrd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → − A ∈ ℝ +
134 5 133 rpaddcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 + − A ∈ ℝ +
135 3 134 eqeltrrd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → 1 − A ∈ ℝ +
136 135 relogcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → log ⁡ 1 − A ∈ ℝ
137 136 reim0d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → ℑ ⁡ log ⁡ 1 − A = 0
138 133 135 rpdivcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → − A 1 − A ∈ ℝ +
139 138 relogcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → log ⁡ − A 1 − A ∈ ℝ
140 139 reim0d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → ℑ ⁡ log ⁡ − A 1 − A = 0
141 137 140 eqtr4d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A = 0 → ℑ ⁡ log ⁡ 1 − A = ℑ ⁡ log ⁡ − A 1 − A
142 16 24 logcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → log ⁡ 1 − A ∈ ℂ
143 142 adantr ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → log ⁡ 1 − A ∈ ℂ
144 143 imcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → ℑ ⁡ log ⁡ 1 − A ∈ ℝ
145 144 recnd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → ℑ ⁡ log ⁡ 1 − A ∈ ℂ
146 108 adantr ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → − A 1 − A ∈ ℂ
147 15 77 negne0d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − A ≠ 0
148 29 16 147 24 divne0d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − A 1 − A ≠ 0
149 148 adantr ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → − A 1 − A ≠ 0
150 146 149 logcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → log ⁡ − A 1 − A ∈ ℂ
151 150 imcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → ℑ ⁡ log ⁡ − A 1 − A ∈ ℝ
152 151 recnd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → ℑ ⁡ log ⁡ − A 1 − A ∈ ℂ
153 106 fveq2d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → log ⁡ − A 1 − A ‾ = log ⁡ − 1 − 1 − A
154 153 adantr ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → log ⁡ − A 1 − A ‾ = log ⁡ − 1 − 1 − A
155 logcj ⊢ − A 1 − A ∈ ℂ ∧ ℑ ⁡ − A 1 − A ≠ 0 → log ⁡ − A 1 − A ‾ = log ⁡ − A 1 − A ‾
156 108 155 sylan ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → log ⁡ − A 1 − A ‾ = log ⁡ − A 1 − A ‾
157 16 24 reccld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → 1 1 − A ∈ ℂ
158 157 116 logcld ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → log ⁡ 1 1 − A ∈ ℂ
159 158 negnegd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − − log ⁡ 1 1 − A = log ⁡ 1 1 − A
160 isosctrlem1 ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → ℑ ⁡ log ⁡ 1 − A ≠ π
161 logrec ⊢ 1 − A ∈ ℂ ∧ 1 − A ≠ 0 ∧ ℑ ⁡ log ⁡ 1 − A ≠ π → log ⁡ 1 − A = − log ⁡ 1 1 − A
162 16 24 160 161 syl3anc ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → log ⁡ 1 − A = − log ⁡ 1 1 − A
163 162 negeqd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → − log ⁡ 1 − A = − − log ⁡ 1 1 − A
164 27 fveq2d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → log ⁡ − 1 − 1 − A = log ⁡ 1 1 − A
165 159 163 164 3eqtr4rd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → log ⁡ − 1 − 1 − A = − log ⁡ 1 − A
166 165 adantr ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → log ⁡ − 1 − 1 − A = − log ⁡ 1 − A
167 154 156 166 3eqtr3rd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → − log ⁡ 1 − A = log ⁡ − A 1 − A ‾
168 167 fveq2d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → ℑ ⁡ − log ⁡ 1 − A = ℑ ⁡ log ⁡ − A 1 − A ‾
169 143 imnegd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → ℑ ⁡ − log ⁡ 1 − A = − ℑ ⁡ log ⁡ 1 − A
170 150 imcjd ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → ℑ ⁡ log ⁡ − A 1 − A ‾ = − ℑ ⁡ log ⁡ − A 1 − A
171 168 169 170 3eqtr3d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → − ℑ ⁡ log ⁡ 1 − A = − ℑ ⁡ log ⁡ − A 1 − A
172 145 152 171 neg11d ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A ∧ ℑ ⁡ − A 1 − A ≠ 0 → ℑ ⁡ log ⁡ 1 − A = ℑ ⁡ log ⁡ − A 1 − A
173 141 172 pm2.61dane ⊢ A ∈ ℂ ∧ A = 1 ∧ ¬ 1 = A → ℑ ⁡ log ⁡ 1 − A = ℑ ⁡ log ⁡ − A 1 − A