Metamath Proof Explorer


Theorem itgpowd

Description: The integral of a monomial on a closed bounded interval of the real line. Co-authors TA and MC. (Contributed by Jon Pennant, 31-May-2019) (Revised by Thierry Arnoux, 14-Jun-2019)

Ref Expression
Hypotheses itgpowd.1 ⊢ φ → A ∈ ℝ
itgpowd.2 ⊢ φ → B ∈ ℝ
itgpowd.3 ⊢ φ → A ≤ B
itgpowd.4 ⊢ φ → N ∈ ℕ 0
Assertion itgpowd ⊢ φ → ∫ A B x N dx = B N + 1 − A N + 1 N + 1

Proof

Step Hyp Ref Expression
1 itgpowd.1 ⊢ φ → A ∈ ℝ
2 itgpowd.2 ⊢ φ → B ∈ ℝ
3 itgpowd.3 ⊢ φ → A ≤ B
4 itgpowd.4 ⊢ φ → N ∈ ℕ 0
5 nn0p1nn ⊢ N ∈ ℕ 0 → N + 1 ∈ ℕ
6 4 5 syl ⊢ φ → N + 1 ∈ ℕ
7 6 nncnd ⊢ φ → N + 1 ∈ ℂ
8 iccssre ⊢ A ∈ ℝ ∧ B ∈ ℝ → A B ⊆ ℝ
9 1 2 8 syl2anc ⊢ φ → A B ⊆ ℝ
10 ax-resscn ⊢ ℝ ⊆ ℂ
11 9 10 sstrdi ⊢ φ → A B ⊆ ℂ
12 11 sselda ⊢ φ ∧ x ∈ A B → x ∈ ℂ
13 4 adantr ⊢ φ ∧ x ∈ A B → N ∈ ℕ 0
14 12 13 expcld ⊢ φ ∧ x ∈ A B → x N ∈ ℂ
15 11 resmptd ⊢ φ → x ∈ ℂ ⟼ x N ↾ A B = x ∈ A B ⟼ x N
16 expcncf ⊢ N ∈ ℕ 0 → x ∈ ℂ ⟼ x N : ℂ ⟶cn ℂ
17 4 16 syl ⊢ φ → x ∈ ℂ ⟼ x N : ℂ ⟶cn ℂ
18 rescncf ⊢ A B ⊆ ℂ → x ∈ ℂ ⟼ x N : ℂ ⟶cn ℂ → x ∈ ℂ ⟼ x N ↾ A B : A B ⟶cn ℂ
19 11 17 18 sylc ⊢ φ → x ∈ ℂ ⟼ x N ↾ A B : A B ⟶cn ℂ
20 15 19 eqeltrrd ⊢ φ → x ∈ A B ⟼ x N : A B ⟶cn ℂ
21 cnicciblnc ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ x ∈ A B ⟼ x N : A B ⟶cn ℂ → x ∈ A B ⟼ x N ∈ 𝐿 1
22 1 2 20 21 syl3anc ⊢ φ → x ∈ A B ⟼ x N ∈ 𝐿 1
23 14 22 itgcl ⊢ φ → ∫ A B x N dx ∈ ℂ
24 6 nnne0d ⊢ φ → N + 1 ≠ 0
25 7 14 22 itgmulc2 ⊢ φ → N + 1 ⁢ ∫ A B x N dx = ∫ A B N + 1 ⁢ x N dx
26 eqidd ⊢ φ ∧ x ∈ A B → t ∈ A B ⟼ N + 1 ⁢ t N = t ∈ A B ⟼ N + 1 ⁢ t N
27 oveq1 ⊢ t = x → t N = x N
28 27 oveq2d ⊢ t = x → N + 1 ⁢ t N = N + 1 ⁢ x N
29 28 adantl ⊢ φ ∧ x ∈ A B ∧ t = x → N + 1 ⁢ t N = N + 1 ⁢ x N
30 simpr ⊢ φ ∧ x ∈ A B → x ∈ A B
31 7 adantr ⊢ φ ∧ x ∈ A B → N + 1 ∈ ℂ
32 ioossicc ⊢ A B ⊆ A B
33 32 a1i ⊢ φ → A B ⊆ A B
34 33 sselda ⊢ φ ∧ x ∈ A B → x ∈ A B
35 34 14 syldan ⊢ φ ∧ x ∈ A B → x N ∈ ℂ
36 31 35 mulcld ⊢ φ ∧ x ∈ A B → N + 1 ⁢ x N ∈ ℂ
37 26 29 30 36 fvmptd ⊢ φ ∧ x ∈ A B → t ∈ A B ⟼ N + 1 ⁢ t N ⁡ x = N + 1 ⁢ x N
38 37 itgeq2dv ⊢ φ → ∫ A B t ∈ A B ⟼ N + 1 ⁢ t N ⁡ x dx = ∫ A B N + 1 ⁢ x N dx
39 reelprrecn ⊢ ℝ ∈ ℝ ℂ
40 39 a1i ⊢ φ → ℝ ∈ ℝ ℂ
41 10 a1i ⊢ φ → ℝ ⊆ ℂ
42 41 sselda ⊢ φ ∧ t ∈ ℝ → t ∈ ℂ
43 1nn0 ⊢ 1 ∈ ℕ 0
44 43 a1i ⊢ φ → 1 ∈ ℕ 0
45 4 44 nn0addcld ⊢ φ → N + 1 ∈ ℕ 0
46 45 adantr ⊢ φ ∧ t ∈ ℝ → N + 1 ∈ ℕ 0
47 42 46 expcld ⊢ φ ∧ t ∈ ℝ → t N + 1 ∈ ℂ
48 4 nn0cnd ⊢ φ → N ∈ ℂ
49 48 adantr ⊢ φ ∧ t ∈ ℝ → N ∈ ℂ
50 1cnd ⊢ φ ∧ t ∈ ℝ → 1 ∈ ℂ
51 49 50 addcld ⊢ φ ∧ t ∈ ℝ → N + 1 ∈ ℂ
52 4 adantr ⊢ φ ∧ t ∈ ℝ → N ∈ ℕ 0
53 42 52 expcld ⊢ φ ∧ t ∈ ℝ → t N ∈ ℂ
54 51 53 mulcld ⊢ φ ∧ t ∈ ℝ → N + 1 ⁢ t N ∈ ℂ
55 simpr ⊢ φ ∧ t ∈ ℂ → t ∈ ℂ
56 45 adantr ⊢ φ ∧ t ∈ ℂ → N + 1 ∈ ℕ 0
57 55 56 expcld ⊢ φ ∧ t ∈ ℂ → t N + 1 ∈ ℂ
58 57 fmpttd ⊢ φ → t ∈ ℂ ⟼ t N + 1 : ℂ ⟶ ℂ
59 ssidd ⊢ φ → ℂ ⊆ ℂ
60 7 adantr ⊢ φ ∧ t ∈ ℂ → N + 1 ∈ ℂ
61 4 adantr ⊢ φ ∧ t ∈ ℂ → N ∈ ℕ 0
62 55 61 expcld ⊢ φ ∧ t ∈ ℂ → t N ∈ ℂ
63 60 62 mulcld ⊢ φ ∧ t ∈ ℂ → N + 1 ⁢ t N ∈ ℂ
64 63 fmpttd ⊢ φ → t ∈ ℂ ⟼ N + 1 ⁢ t N : ℂ ⟶ ℂ
65 dvexp ⊢ N + 1 ∈ ℕ → dt ∈ ℂ t N + 1 d ℂ t = t ∈ ℂ ⟼ N + 1 ⁢ t N + 1 - 1
66 6 65 syl ⊢ φ → dt ∈ ℂ t N + 1 d ℂ t = t ∈ ℂ ⟼ N + 1 ⁢ t N + 1 - 1
67 1cnd ⊢ φ → 1 ∈ ℂ
68 48 67 pncand ⊢ φ → N + 1 - 1 = N
69 68 oveq2d ⊢ φ → t N + 1 - 1 = t N
70 69 oveq2d ⊢ φ → N + 1 ⁢ t N + 1 - 1 = N + 1 ⁢ t N
71 70 mpteq2dv ⊢ φ → t ∈ ℂ ⟼ N + 1 ⁢ t N + 1 - 1 = t ∈ ℂ ⟼ N + 1 ⁢ t N
72 66 71 eqtrd ⊢ φ → dt ∈ ℂ t N + 1 d ℂ t = t ∈ ℂ ⟼ N + 1 ⁢ t N
73 72 feq1d ⊢ φ → dt ∈ ℂ t N + 1 d ℂ t : ℂ ⟶ ℂ ↔ t ∈ ℂ ⟼ N + 1 ⁢ t N : ℂ ⟶ ℂ
74 64 73 mpbird ⊢ φ → dt ∈ ℂ t N + 1 d ℂ t : ℂ ⟶ ℂ
75 74 fdmd ⊢ φ → dom ⁡ dt ∈ ℂ t N + 1 d ℂ t = ℂ
76 10 75 sseqtrrid ⊢ φ → ℝ ⊆ dom ⁡ dt ∈ ℂ t N + 1 d ℂ t
77 dvres3 ⊢ ℝ ∈ ℝ ℂ ∧ t ∈ ℂ ⟼ t N + 1 : ℂ ⟶ ℂ ∧ ℂ ⊆ ℂ ∧ ℝ ⊆ dom ⁡ dt ∈ ℂ t N + 1 d ℂ t → ℝ D t ∈ ℂ ⟼ t N + 1 ↾ ℝ = dt ∈ ℂ t N + 1 d ℂ t ↾ ℝ
78 40 58 59 76 77 syl22anc ⊢ φ → ℝ D t ∈ ℂ ⟼ t N + 1 ↾ ℝ = dt ∈ ℂ t N + 1 d ℂ t ↾ ℝ
79 72 reseq1d ⊢ φ → dt ∈ ℂ t N + 1 d ℂ t ↾ ℝ = t ∈ ℂ ⟼ N + 1 ⁢ t N ↾ ℝ
80 78 79 eqtrd ⊢ φ → ℝ D t ∈ ℂ ⟼ t N + 1 ↾ ℝ = t ∈ ℂ ⟼ N + 1 ⁢ t N ↾ ℝ
81 resmpt ⊢ ℝ ⊆ ℂ → t ∈ ℂ ⟼ t N + 1 ↾ ℝ = t ∈ ℝ ⟼ t N + 1
82 10 81 mp1i ⊢ φ → t ∈ ℂ ⟼ t N + 1 ↾ ℝ = t ∈ ℝ ⟼ t N + 1
83 82 oveq2d ⊢ φ → ℝ D t ∈ ℂ ⟼ t N + 1 ↾ ℝ = dt ∈ ℝ t N + 1 d ℝ t
84 resmpt ⊢ ℝ ⊆ ℂ → t ∈ ℂ ⟼ N + 1 ⁢ t N ↾ ℝ = t ∈ ℝ ⟼ N + 1 ⁢ t N
85 10 84 mp1i ⊢ φ → t ∈ ℂ ⟼ N + 1 ⁢ t N ↾ ℝ = t ∈ ℝ ⟼ N + 1 ⁢ t N
86 80 83 85 3eqtr3d ⊢ φ → dt ∈ ℝ t N + 1 d ℝ t = t ∈ ℝ ⟼ N + 1 ⁢ t N
87 tgioo4 ⊢ topGen ⁡ ran ⁡ . = TopOpen ⁡ ℂ fld ↾ 𝑡 ℝ
88 eqid ⊢ TopOpen ⁡ ℂ fld = TopOpen ⁡ ℂ fld
89 iccntr ⊢ A ∈ ℝ ∧ B ∈ ℝ → int ⁡ topGen ⁡ ran ⁡ . ⁡ A B = A B
90 1 2 89 syl2anc ⊢ φ → int ⁡ topGen ⁡ ran ⁡ . ⁡ A B = A B
91 40 47 54 86 9 87 88 90 dvmptres2 ⊢ φ → dt ∈ A B t N + 1 d ℝ t = t ∈ A B ⟼ N + 1 ⁢ t N
92 ioossre ⊢ A B ⊆ ℝ
93 92 10 sstri ⊢ A B ⊆ ℂ
94 93 a1i ⊢ φ → A B ⊆ ℂ
95 cncfmptc ⊢ N + 1 ∈ ℂ ∧ A B ⊆ ℂ ∧ ℂ ⊆ ℂ → t ∈ A B ⟼ N + 1 : A B ⟶cn ℂ
96 7 94 59 95 syl3anc ⊢ φ → t ∈ A B ⟼ N + 1 : A B ⟶cn ℂ
97 resmpt ⊢ A B ⊆ ℂ → t ∈ ℂ ⟼ t N ↾ A B = t ∈ A B ⟼ t N
98 93 97 mp1i ⊢ φ → t ∈ ℂ ⟼ t N ↾ A B = t ∈ A B ⟼ t N
99 expcncf ⊢ N ∈ ℕ 0 → t ∈ ℂ ⟼ t N : ℂ ⟶cn ℂ
100 4 99 syl ⊢ φ → t ∈ ℂ ⟼ t N : ℂ ⟶cn ℂ
101 rescncf ⊢ A B ⊆ ℂ → t ∈ ℂ ⟼ t N : ℂ ⟶cn ℂ → t ∈ ℂ ⟼ t N ↾ A B : A B ⟶cn ℂ
102 94 100 101 sylc ⊢ φ → t ∈ ℂ ⟼ t N ↾ A B : A B ⟶cn ℂ
103 98 102 eqeltrrd ⊢ φ → t ∈ A B ⟼ t N : A B ⟶cn ℂ
104 96 103 mulcncf ⊢ φ → t ∈ A B ⟼ N + 1 ⁢ t N : A B ⟶cn ℂ
105 91 104 eqeltrd ⊢ φ → dt ∈ A B t N + 1 d ℝ t : A B ⟶cn ℂ
106 ioombl ⊢ A B ∈ dom ⁡ vol
107 106 a1i ⊢ φ → A B ∈ dom ⁡ vol
108 48 adantr ⊢ φ ∧ t ∈ A B → N ∈ ℂ
109 1cnd ⊢ φ ∧ t ∈ A B → 1 ∈ ℂ
110 108 109 addcld ⊢ φ ∧ t ∈ A B → N + 1 ∈ ℂ
111 11 sselda ⊢ φ ∧ t ∈ A B → t ∈ ℂ
112 4 adantr ⊢ φ ∧ t ∈ A B → N ∈ ℕ 0
113 111 112 expcld ⊢ φ ∧ t ∈ A B → t N ∈ ℂ
114 110 113 mulcld ⊢ φ ∧ t ∈ A B → N + 1 ⁢ t N ∈ ℂ
115 cncfmptc ⊢ N + 1 ∈ ℂ ∧ A B ⊆ ℂ ∧ ℂ ⊆ ℂ → t ∈ A B ⟼ N + 1 : A B ⟶cn ℂ
116 7 11 59 115 syl3anc ⊢ φ → t ∈ A B ⟼ N + 1 : A B ⟶cn ℂ
117 11 resmptd ⊢ φ → t ∈ ℂ ⟼ t N ↾ A B = t ∈ A B ⟼ t N
118 rescncf ⊢ A B ⊆ ℂ → t ∈ ℂ ⟼ t N : ℂ ⟶cn ℂ → t ∈ ℂ ⟼ t N ↾ A B : A B ⟶cn ℂ
119 11 100 118 sylc ⊢ φ → t ∈ ℂ ⟼ t N ↾ A B : A B ⟶cn ℂ
120 117 119 eqeltrrd ⊢ φ → t ∈ A B ⟼ t N : A B ⟶cn ℂ
121 116 120 mulcncf ⊢ φ → t ∈ A B ⟼ N + 1 ⁢ t N : A B ⟶cn ℂ
122 cnicciblnc ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ t ∈ A B ⟼ N + 1 ⁢ t N : A B ⟶cn ℂ → t ∈ A B ⟼ N + 1 ⁢ t N ∈ 𝐿 1
123 1 2 121 122 syl3anc ⊢ φ → t ∈ A B ⟼ N + 1 ⁢ t N ∈ 𝐿 1
124 33 107 114 123 iblss ⊢ φ → t ∈ A B ⟼ N + 1 ⁢ t N ∈ 𝐿 1
125 91 124 eqeltrd ⊢ φ → dt ∈ A B t N + 1 d ℝ t ∈ 𝐿 1
126 11 resmptd ⊢ φ → t ∈ ℂ ⟼ t N + 1 ↾ A B = t ∈ A B ⟼ t N + 1
127 expcncf ⊢ N + 1 ∈ ℕ 0 → t ∈ ℂ ⟼ t N + 1 : ℂ ⟶cn ℂ
128 45 127 syl ⊢ φ → t ∈ ℂ ⟼ t N + 1 : ℂ ⟶cn ℂ
129 rescncf ⊢ A B ⊆ ℂ → t ∈ ℂ ⟼ t N + 1 : ℂ ⟶cn ℂ → t ∈ ℂ ⟼ t N + 1 ↾ A B : A B ⟶cn ℂ
130 11 128 129 sylc ⊢ φ → t ∈ ℂ ⟼ t N + 1 ↾ A B : A B ⟶cn ℂ
131 126 130 eqeltrrd ⊢ φ → t ∈ A B ⟼ t N + 1 : A B ⟶cn ℂ
132 1 2 3 105 125 131 ftc2 ⊢ φ → ∫ A B dt ∈ A B t N + 1 d ℝ t ⁡ x dx = t ∈ A B ⟼ t N + 1 ⁡ B − t ∈ A B ⟼ t N + 1 ⁡ A
133 91 fveq1d ⊢ φ → dt ∈ A B t N + 1 d ℝ t ⁡ x = t ∈ A B ⟼ N + 1 ⁢ t N ⁡ x
134 133 ralrimivw ⊢ φ → ∀ x ∈ A B dt ∈ A B t N + 1 d ℝ t ⁡ x = t ∈ A B ⟼ N + 1 ⁢ t N ⁡ x
135 itgeq2 ⊢ ∀ x ∈ A B dt ∈ A B t N + 1 d ℝ t ⁡ x = t ∈ A B ⟼ N + 1 ⁢ t N ⁡ x → ∫ A B dt ∈ A B t N + 1 d ℝ t ⁡ x dx = ∫ A B t ∈ A B ⟼ N + 1 ⁢ t N ⁡ x dx
136 134 135 syl ⊢ φ → ∫ A B dt ∈ A B t N + 1 d ℝ t ⁡ x dx = ∫ A B t ∈ A B ⟼ N + 1 ⁢ t N ⁡ x dx
137 eqidd ⊢ φ → t ∈ A B ⟼ t N + 1 = t ∈ A B ⟼ t N + 1
138 simpr ⊢ φ ∧ t = B → t = B
139 138 oveq1d ⊢ φ ∧ t = B → t N + 1 = B N + 1
140 1 rexrd ⊢ φ → A ∈ ℝ *
141 2 rexrd ⊢ φ → B ∈ ℝ *
142 ubicc2 ⊢ A ∈ ℝ * ∧ B ∈ ℝ * ∧ A ≤ B → B ∈ A B
143 140 141 3 142 syl3anc ⊢ φ → B ∈ A B
144 2 recnd ⊢ φ → B ∈ ℂ
145 144 45 expcld ⊢ φ → B N + 1 ∈ ℂ
146 137 139 143 145 fvmptd ⊢ φ → t ∈ A B ⟼ t N + 1 ⁡ B = B N + 1
147 simpr ⊢ φ ∧ t = A → t = A
148 147 oveq1d ⊢ φ ∧ t = A → t N + 1 = A N + 1
149 lbicc2 ⊢ A ∈ ℝ * ∧ B ∈ ℝ * ∧ A ≤ B → A ∈ A B
150 140 141 3 149 syl3anc ⊢ φ → A ∈ A B
151 1 recnd ⊢ φ → A ∈ ℂ
152 151 45 expcld ⊢ φ → A N + 1 ∈ ℂ
153 137 148 150 152 fvmptd ⊢ φ → t ∈ A B ⟼ t N + 1 ⁡ A = A N + 1
154 146 153 oveq12d ⊢ φ → t ∈ A B ⟼ t N + 1 ⁡ B − t ∈ A B ⟼ t N + 1 ⁡ A = B N + 1 − A N + 1
155 132 136 154 3eqtr3d ⊢ φ → ∫ A B t ∈ A B ⟼ N + 1 ⁢ t N ⁡ x dx = B N + 1 − A N + 1
156 7 adantr ⊢ φ ∧ x ∈ A B → N + 1 ∈ ℂ
157 156 14 mulcld ⊢ φ ∧ x ∈ A B → N + 1 ⁢ x N ∈ ℂ
158 1 2 157 itgioo ⊢ φ → ∫ A B N + 1 ⁢ x N dx = ∫ A B N + 1 ⁢ x N dx
159 38 155 158 3eqtr3rd ⊢ φ → ∫ A B N + 1 ⁢ x N dx = B N + 1 − A N + 1
160 25 159 eqtrd ⊢ φ → N + 1 ⁢ ∫ A B x N dx = B N + 1 − A N + 1
161 7 23 24 160 mvllmuld ⊢ φ → ∫ A B x N dx = B N + 1 − A N + 1 N + 1