Description: Lemma for itg2mono . We show that for any constant t less than one, t x. S.1 H is less than S , and so S.1 H <_ S , which is one half of the equality in itg2mono . Consider the sequence A ( n ) = { x | t x. H <_ F ( n ) } . This is an increasing sequence of measurable sets whose union is RR , and so ` H |`A ( n ) has an integral which equals S.1 H in the limit, by itg1climres . Then by taking the limit in ` ( t x. H ) |`A ( n ) <_ F ( n ) , we get t x. S.1 H <_ S as desired. (Contributed by Mario Carneiro, 16-Aug-2014) (Revised by Mario Carneiro, 23-Aug-2014)
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Hypotheses | itg2mono.1 | |
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itg2mono.2 | |
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itg2mono.3 | |
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itg2mono.4 | |
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itg2mono.5 | |
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itg2mono.6 | |
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itg2mono.7 | |
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itg2mono.8 | |
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itg2mono.9 | |
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itg2mono.10 | |
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itg2mono.11 | |
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Assertion | itg2monolem1 | |